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In order to facilitate this implementation, the expressions from Chapter 4 are put into a form that is capable of generating dimensionless stresses and displacements.. Using this form, w

Trang 1

Section A.2 Evaluation of the Coefficients in the Potentials 85

(due to the fact that Cauchy’s Integral Theorem, which guarantees path

inde-pendence in a simply-connected region, is not necessarily satisfied for contours

around the hole) It follows that



L

where C c is some complex constant (the same reasoning applies here as was

used to show that the value B cin (A.13) is constant)

Proceeding as before (see the reasoning used to determine equation (A.17)),

the integral of ∗

(z)can be written as

 z

z0

(z) dz= C c

2πilog(z − z c )+∗∗ϕ (z), (A.20) where∗∗

ϕ (z)is a single-valued analytic function Substituting (A.20) in (A.18)

and expanding gives

ϕ(z) = A c z log(z − z c ) − A c z c log(z − z c ) − A c (z − z c )

+ C c

2πilog(z − z c )+∗∗ϕ (z) + C. (A.21)

Combining logarithmic terms and incorporating all single-valued analytic terms

in a new analytic function,ϕ(z)

, results in

ϕ(z) = A c z log(z − z c ) + γ c log(z − z c )+ϕ(z),∗ (A.22)

where the constant γ c and the new single-valued analytic function ∗

ϕ(z)have been introduced for convenience

The multi-valued nature of the potential ψ(z) can be determined by noting

that (z) = ψ(z)is single-valued (this is because the stresses on the left-hand

side of (2.5) and the function ϕ(z)on the right-hand side of the same equation

are all single valued) With the same reasoning used to determine (A.17) and

(A.20), it can be shown that the integral of (z) can be written as

ψ (z)=

 z

z0

(z) dz = γ clog(z − z c )+ψ (z).∗ (A.23)

where γ

cis a complex constant and ∗

ψ (z)is a single-valued analytic function

All that remains for a full determination of the multi-valued nature of the

poten-tials in a region with a hole is to determine the unknown coefficients in (A.22)

and (A.23) This is accomplished as follows

In order to ensure that the displacements associated with the multi-valued

potentials given by (A.22) and (A.23) are single-valued, equation (2.1) must not

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86 Multi-Valued Complex Potentials Appendix A

become multi-valued anywhere in the region Substituting (A.22) and (A.23)

in (2.1) gives

2µ(u + iv) = κA c z log(z − z c ) + γ c log(z − z c )+ϕ(z)



− z



A c log(z − z c )+ A c z

z − z c + γ c

z − z c +ϕ∗(z)

− γ

c log(z − z c )ψ (z).

(A.24)

Separating the multi-valued parts from the single-valued parts results in

2µ(u + iv) = (κA c z + κγ c ) log(z − z c )

− (zA c + γ

c ) log(z − z c ) + f (z), (A.25)

where

f (z) = κ ϕ(z)∗ − A c zz

z − z czγ c

z − z c − z ϕ∗(z)ψ (z),∗ (A.26)

which is single-valued Denoting by r zc the distance from z to z c, denoting by

ϑ zc the argument of z − z c(see Figure A.3), and splitting the logarithms into their real and imaginary parts yields

2µ(u + iv) = (κzA c + κγ c )( ln r zc + iϑ zc )

− (zA c + γ

c )( ln r zc − iϑ zc ) + f (z). (A.27)

After collecting terms, we have

2µ(u + iv) = (κzA c + κγ c − zA c − γ

c ) ln r zc + i(κzA c + κγ c + zA c + γ

c )ϑ zc + f (z). (A.28) The function ϑ zc in this expression increases continuously along each circuit

around the point z c The other functions in (A.28) are single-valued It follows

that the coefficient of ϑ zcmust be set to zero in order to ensure single-valued displacements:

A c (κ + 1)z + κγ c + γ

As a result

and

κγ c + γ

The coefficients γ c and γ

ccan be related to the resultant force on the hole through use of (2.6) We take an integration path consisting of a complete circuit

around L hin a clockwise direction (see Figure A.3) Note that this integration path is chosen such that the region is to the left, as specified for (2.6) Denoting

by[ ]L the increase undergone by the expression inside the brackets along the

Trang 3

Section A.2 Evaluation of the Coefficients in the Potentials 87

..

..

.. . . .

.

x

y

ϑ zc

r zc

z c

L h

Figure A.3: Integration path

integration path, integrating along L hin (2.6) and substituting equations (A.22)

and (A.23) gives



γ c log(z − z c )+ϕ(z)∗ + zγ c

z − z c + z ϕ∗(z) + γ

c log(z − z c )+ψ (z)



L h

= i



L h

(t x + it y ) ds = i( F h x+ iF h y ), (A.32)

whereF h x + i F h y is the resultant force on the hole, and where we have utilized

(A.30) Using the same notation as above, the logarithms can be split into their

real and imaginary parts, resulting in



i(γ c − γ

c )ϑ zc + (γ c + γ

c ) ln r zc + g(z)



L h

= i( F h x+ iF h y ), (A.33) where

g(z)= zγ c

z − z c +ϕ(z)+ z ϕ∗(z)+ψ (z).∗ (A.34)

We note that ϑ zcdecreases by an amount 2π upon making a complete circuit

around L h , and that ln r zc and g(z) each return to their original values upon

making a complete circuit around L h The result is that

(γ c − γ

c )( −2π) = F h x+ iF h y (A.35)

Solving for γ c and γ

cusing (A.31) and (A.35), applying (A.30), and substituting the results in (A.22) and (A.23) finally yields

ϕ(z)= −

h

F x+ iF h y

2π(1 + κ) log(z − z c )+ϕ(z),∗ (A.36)

Trang 4

88 Multi-Valued Complex Potentials Appendix A

and

ψ (z)=κ(

h

F x− iF h y )

2π(1 + κ) log(z − z c )+ψ (z).∗ (A.37)

The potentials ϕ(z) and ψ(z) for a finite plane with multiple holes can be

obtained by a superimposition of the potentials for a single hole (given by (A.36) and (A.36)) This is due to the fact that the coefficients of the logarithms (or more precisely, the integrals (A.13), (A.19), and (A.23) and the resultant force, given by the integral (A.32)) are not effected by the presence of other holes It

follows that the potentials for a finite plane with m holes can be written as

ϕ(z)= −

m



k=1

k

F x+ iF k y

2π(1 + κ)log(z − z k )+ϕn (z), (A.38)

ψ (z)=

m



k=1

κ(

k

F x− iF k y )

2π(1 + κ) log(z − z k )+ψn (z), (A.39)

where the values z kdenote points within their respective holes The functions

ϕ (z)and ∗

ψ (z)denote new arbitrary single-valued analytic functions

Trang 5

Appendix B

IMPLEMENTATION IN A COMPUTER PROGRAM

The focus of this appendix is the implementation of the results from Chap-ter 4 in a compuChap-ter program In order to facilitate this implementation, the expressions from Chapter 4 are put into a form that is capable of generating dimensionless stresses and displacements Using this form, we take the deriva-tives of the potentials and use them to write out the equations for the stresses and displacements explicitly

In order to generate dimensionless expressions for the stresses and the

displace-ments, we divide the complex potentials by a constant P that has dimensions

of force per unit length This will generate dimensionless complex potentials

on the basis of (2.1) – (2.5) The constant P will be defined according to the

parameters appearing in the solution of particular problems

We start this process for the results derived in Chapter 4 by dividing the

values of the coefficients in the Laurent expansions (4.27) and (4.28) by P We

make the following definitions:

p k= a k

P , q k = b k

P , r k = c k

P , s k= d k

where a k and b k are the coefficients in the Laurent expansion (4.27), given by

(4.49), (4.50), and (4.55) The coefficients c k and d k in the Laurent expan-sion (4.28) are given by (4.35) – (4.37) Dividing the Laurent expanexpan-sions (4.27)

and (4.28) by P results in

ϕ0(ζ ) = p0+



k=1

p k ζ k+



k=1

ψ0(ζ ) = r0+∞

k=1

r k ζ k+∞

k=1

89

Trang 6

90 Implementation in a Computer Program Appendix B

where

ϕ0(ζ )=ϕ m0(ζ )

ψ0(ζ )=ψ m0(ζ )

Dividing (4.35) – (4.37) by P gives

r0= B0

P − p0−1

2p1−1

r k= B−k

P − q k−1

2(k + 1)p k+1+1

2(k − 1)p k−1, k > 0, (B.6)

s k= Bk

P − p k+1

2(k − 1)q k−1−1

2(k + 1)q k+1, k > 0. (B.7)

On the basis of (4.42) – (4.47) and (4.51), the only parameters in (4.49), (4.50), and (4.55) that are not dimensionless areβ k i13andβ k i13 These parameters have the dimensions of the Fourier coefficientsBkandAk Dividing equations (4.49)

and (4.50) through by P results in

p k =β k011p0+β k012p0+

k−1



i=0

k

β i13

P k = 1, 2, 3, , (B.8)

q k =β k021p0+β k022p0+

k−1



i=0

k

β i23

P k = 1, 2, 3, (B.9)

The expression for a0, equation (4.55), cannot be implemented in a computer

program unless the limit k → ∞ is replaced by an expression like k = k I, where

k I is some large integer, say 10,000 Dividing (4.55) by P and replacing the

symbol∞ with k Iresults in

p0=

k I

β012

kI−1

i=0

k I

β i13

Pk β I021

kI−1

i=0

k I

β i23 P

k I

β021

k I

β011−k β I022

k I

β012

We now have complete and dimensionless expressions forϕ

0(ζ )and ∗

ψ0(ζ )

which can be programmed into a computer

Finally, we convert the complete potentials given by (4.56) and (4.57) to their dimensionless forms This gives

ϕ(ζ )= −κ(

h

F x+ iF hy )

2π(1 + κ) log(

i2a

1− ζ )

h

F x+ iF hy

2π(1 + κ)log(

i2aζ

1− ζ ) + p0+∞

k=1

p k ζ k+∞

k=1

q k ζ −k ,

(B.11)

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Section B.2 Dimensionless Coordinates 91

and

ψ (ζ )=

h

F x− iF hy

2π(1 + κ) log(−

i2a

1− ζ )+

κ(

h

F x− iF hy )

2π(1 + κ) log(−

i2aζ

1− ζ ) + r0+∞

k=1

r k ζ k+∞

k=1

s k ζ −k ,

(B.12)

where

h

F x+ iF hy=

h

F x+ iF h y

ϕ(ζ )= ϕ m (ζ )

ψ (ζ )= ψ m (ζ )

P . (B.13)

The coordinates in the z-plane can be written in dimensionless form by dividing

(4.7) by h, the depth of the tunnel This results in

z=ω(ζ )∗ = −ia∗1+ ζ

where∗

z = z/h and ω(ζ )∗ are the dimensionless coordinates and dimensionless

mapping function, respectively, and where we have defined the parameter

a= 1− α2

This parameter is simply the dimensionless form of (4.8) The dimensionless

coordinates ∗

z can be obtained by using (B.14) instead of (4.7) to map the

coordinates back from the ζ -plane.

It is most convenient to calculate (2.1) and (2.4) – (2.5) in the ζ -plane and then

to relate the resulting values to the dimensionless coordinates∗

zthrough use

of (B.14) In order to perform these calculations we will need expressions for

ϕ(z), ϕ∗(z), andψ∗(z) in terms of ζ The derivative of ϕ(z) with respect to z

in terms of ζ was derived in (4.14) Similar results can be obtained for

ϕ(z) and ∗

ψ(z) They are

ϕ(z)= 1

h

W1(ζ ) ϕ∗(ζ ), ψ∗(z)= 1

h

W1(ζ )

ψ(ζ ), (B.16) where we have defined the (dimensionless) function

W1(ζ )= h

ω(ζ ) = i(1− ζ)2

2∗

a

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92 Implementation in a Computer Program Appendix B

The chain rule can be used twice to determine∗

ϕ(z) in terms of ζ :

ϕ(ζ )= d

ϕ(z)ω(ζ ) = d

dz

ϕ(z)· dz

dζ ·ω(ζ )+ϕ∗(z)ω(ζ ). (B.18)

It follows that

ϕ(z)= 1

h2[W∗1(ζ )]2 ∗ϕ(ζ )− 1

h2

W3(ζ ) ∗

ϕ(ζ ), (B.19)

where we have defined the (dimensionless) function

W3(ζ ) = h2 ω(ζ )

(ζ )]3 = −(1− ζ)3

2∗

a2

The derivatives of (B.11) and (B.12) with respect to ζ are:

ϕ(ζ )= −κ(

h

F x+ iF hy )

2π(1 + κ) ·

1

1− ζ

h

F x+ iF hy

2π(1 + κ)·

1

ζ (1− ζ)

+ ∞

k=1

kp k ζ k−1−∞

k=1

ψ(ζ )=

h

F x− iF hy

2π(1 + κ)·

1

1− ζ +

κ(

h

F x− iF hy )

2π(1 + κ) ·

1

ζ (1− ζ )

+



k=1

kr k ζ k−1−



k=1

and

ϕ(ζ )= −κ(

h

F x+ iF hy )

2π(1 + κ) ·

1

(1− ζ)2+

h

F x+ iF hy

2π(1 + κ)·

1− 2ζ [ζ(1 − ζ)]2 + ∞

k=1

k(k − 1)p k ζ k−2+∞

k=1

k(k + 1)q k ζ −k−2 . (B.23)

Expressions for the displacements in terms of ζ can be obtained by dividing (2.1) by P and substituting (4.7), (B.16), (B.19), and (B.21) – (B.23) in the

resulting expression This gives

P (u + iv) = κ ϕ(ζ )∗ −ω(ζ )∗ ∗

W1(ζ )

ϕ(ζ )ψ (ζ ).∗ (B.24) Expressions for the stresses can be obtained by multiplying (2.4) and (2.5) by

h/Pand substituting the same expressions in the result This yields

h

P (σ xx + σ yy )= 2

∗

W1(ζ ) ϕ∗(ζ )+W∗1(ζ ) ϕ∗(ζ )

Trang 9

Section B.4 Comparison of Numerical and Analytical Solutions 93

and

h

P (σ yy − σ xx + 2iσ xy )

= 2



ω(ζ )[W∗1(ζ )]2 ∗ϕ(ζ )ω(ζ )∗ ∗

W3(ζ ) ϕ∗(ζ )+W∗1(ζ )

ψ(ζ )

. (B.26)

The dimensionless stresses and displacements have been fully determined in

terms of the mapping parameter ζ The dimensionless coordinates x/ h and y/ h

corresponding to the values calculated using (B.24) - (B.26) can be obtained by

mapping ζ to

zwith (B.14)

A computer program implementing the equations in the preceding sections is

approximately 40% slower than code which determines p0, p k and q kby solving

the system of equations (4.38) - (4.39) numerically and examining the behavior

of p k for large values of k and different values of p0, as performed by

Ver-ruijt [42] It should be noted that part of this difference is due to the fact that

in Verruijt’s implementation it is assumed that all the coefficients are purely

imaginary (so that all calculations involve only real variables) whereas the

cal-culations in this implementation are fully complex (making it possible to include

a non-vertical resultant force acting on the tunnel) It may be noted that both

the numerical and the analytical computation of the coefficients of the

Lau-rent series result in extremely small errors in the normalized displacements and

stresses Even so, there are some small differences between the two techniques,

as can be seen in Table B.1, and as will be discussed below

Table B.1: Comparison of solutions for the ground loss problem with ν = 0.3 and with

no resultant forces acting on the boundaries The values have been normalized through

use of the parameter P = 2µu g , where u gis the maximum convergence of the tunnel

Solution r/ h Num Terms Max Error in u/u g Max σsurface·h/(2µu g )

Trang 10

94 Implementation in a Computer Program Appendix B

Based on the ground loss problem with no resultant forces acting on the boundaries, the fully analytical solution is approximately one order of

mag-nitude more accurate for common tunnel depths (r/ h < 0.5) and about one order of magnitude less accurate for extremely shallow tunnels (r/ h > 0.8) The surface stresses (σ yy and σ xy) in the new solution are on the average of

one order of magnitude more accurate for all values of r/ h As noted earlier,

however, both solutions are very accurate and the differences discussed here are negligible in comparison to the small errors in the boundary conditions

Trang 11

Appendix C

THE OVALIZATION BOUNDARY CONDITION

It is the purpose of this appendix to derive the transformed Fourier expansion

of the boundary conditions for the ovalization of a circular tunnel used in this

thesis The transformation is made from the physical z-plane containing the tunnel to the conformally mapped annulus in the ζ -plane (see Figure C.1) using

the mapping function (4.7) presented in Chapter 4 The results are written in the

form of the given displacement expansion G(ασ )introduced in (4.31) This solution was first published in [35]

The displacements for the ovalization of a tunnel in the z-plane are given in terms of the polar coordinates r and θ (see the left side of Figure C.1) by

where u r and u θ are the radial and tangential displacements along the tunnel

boundary, and where u ois the maximum displacement of the tunnel boundary

.

..

.

.

.....

.

. . .

. . . x y r h θ L h .. ...

.....

.

.

.

.

.

.

ξ

η

σ

1

α ϑ

Figure C.1: Ovalization of a tunnel in the z-plane; conformal mapping the ζ -plane.

95

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