Fifty students study two of the three languages, so let’s say that 50 students study both Spanish and Latin.. This means that zero students study both Spanish and French, zero students s
Trang 18 A You are told that: 12v = 3w
Multiply by 2: 8v = 2w
The question asks for the value of: 2w − 8v
Substitute for 2w: 8v − 8v = 0
Alternatively, you can try finding values for v and w
that work, like 1 and 4, and plug them into 2w − 8v
and into the choices and find the match
(Chapter 8, Lesson 1: Solving Equations)
9 C 2x + 1 > 5
Subtract 1: 2x > 4
Divide by 2: x > 2
Interpret the absolute value: x > 2 OR x < −2
You are told that x is negative, so x < −2 is the answer
(Chapter 8, Lesson 6: Inequalities, Absolute Values,
and Plugging In)
Substitute −2 for x: −(−2)2− 8(−2) − 5
Square −2: −(4) − 8(−2) − 5
Simplify: −4 + 16 − 5 = 7
When evaluating −x2, don’t forget to square the value
before taking its opposite!
(Chapter 8, Lesson 1: Solving Equations)
11 D
Cross-multiply: 15 ≤ 2m
Divide by 2: 7.5 ≤ m
Since m is greater than or equal to 7.5, (D) is the answer.
(Chapter 8, Lesson 6: Inequalities, Absolute Values,
and Plugging In)
12 B First find the price after the 6% sales tax:
$60.00 × 06 = $3.60 tax
$60.00 + $3.60 = $63.60 price with tax
(A simpler way is just to multiply 60 by 1.06.)
Now find how much change Theo received:
$70.00 − $63.60 = $6.40 change
(Chapter 7, Lesson 5: Percents)
13 A Write an equation for the first sentence
n − m = r Because none of the answer choices contain m, solve
for m in terms of r and n: n − m = r
Subtract r: n − r = m
Now write an expression for what the question asks for:
s + 2m Substitute for m: s + 2(n − r)
Distribute: s + 2n − 2r
Alternatively, you can substitute numbers for n, m,
and r, making sure they “work,” and get a numerical
answer to the question
(Chapter 8, Lesson 1: Solving Equations)
5 2 3
m≤
14 D Two points on line l are (0, 0) and (10, y).
Find the slope of the line:
Cross-multiply: 5y= 30 Divide by 5: y= 6
Since y= 6, the height of the triangle is 6 Find the area:
A=1⁄2(base)(height)
Substitute 48 for A: 48=1⁄2(base)(6) Simplify: 48 = 3(base) Divide by 3: 16 = base = x Now find x + y = 16 + 6 = 22.
(Chapter 10, Lesson 4: Coordinate Geometry)
15 A Ellen travels the first 15 miles at 30 miles per hour Find out how much time that takes:
d = (rate)(time)
Plug in known values: 15 = 30t
Divide by 30: 1⁄2hour = t The rest of the trip, which is (y− 15) miles long, she travels at an average speed of 40 miles per hour:
d = (rate)(time) Plug in known values: (y − 15) = 40t
Divide by 40:
Add the two values together to find the total time:
(Chapter 9, Lesson 4: Rate Problems)
16 B Set up the relationship in equation form:
Plug in what you’re given:
Divide by 16: 1⁄2= k
Write the new equation:
Plug in new values:
(Chapter 11, Lesson 4: Variation)
y= ( ) ( ) = =
1
28 4
4 16
1 4 2
y m n
= ( ) ( )
1 2 2
8 16
12
= ( ) ( )
k
n
= 2
1 2
15 40 + −y
y
t
−15= 40
= −
− =
−
2 1
2 1
0
10 0 10
3 5
Trang 217 D a + b = s
a − b = t
Add straight down: 2a = s + t
Divide by 2:
a + b = s
a − b = t
Subtract straight down: 2b = s − t
Divide by 2:
Find the
product:
(Chapter 8, Lesson 2: Systems)
The answer is in terms of y alone, so find m and n in
Take the 4th root: y1/4= m
y = n3 Take the cube root: y1/3= n
Find the product mn: mn = (y1/4)(y1/3) = y1/3 + 1/4
Add exponents: mn = y7/12
(Chapter 11, Lesson 6: Negative and Fractional
Exponents)
19 A This question deals with similar triangles:
Set up ratio:
Cross-multiply: 6x= 48
Divide by 6: x= 8
Area of big triangle =1⁄2(base)(height) =1⁄2(12)(6) = 36
Area of small triangle =1⁄2(base)(height) =1⁄2(8)(4) = 16
Shaded area = area of big triangle − area of small
triangle = 36 − 16 = 20
(Chapter 10, Lesson 6: Similar Figures)
(Chapter 10, Lesson 5: Areas and Perimeters)
20 A Set up a Venn diagram to visualize the
information
6
12
4
=
x
( )( )=a b ⎛s t+ s t s t
⎝⎜
⎞
⎠⎟
−
⎛
⎝⎜
⎞
⎠⎟=
−
⎛
⎝⎜
⎞
⎠⎟
2 2
b= −s t 2
a= +s t 2
Notice that 1⁄3the number of sedans must equal 1⁄5the number of convertibles Say the number of
convert-ible sedans is x If this is 1⁄3the number of sedans, then
there must be 3x sedans in total, and 3x − x = 2x of these are not convertibles Similarly, if x is 1⁄5the
num-ber of convertibles, then there must be 5x convertibles altogether, and 5x − x = 4x of these are not sedans So
now your diagram can look like this:
So there must be a total of 2x + x + 4x = 7x cars at the
dealership The only choice that is a multiple of 7 is (A): 28
(Chapter 9, Lesson 5: Counting Problems)
Section 4
1 E
Perimeter of a square = 4s
36 = 4s
Divide by 4: 9 = s
Area of a square = (s)2 Area = (9)2= 81
(Chapter 10, Lesson 5: Areas and Perimeters)
2 C
Cross-multiply: b = 10a Try positive integer values of a to see how many work:
There are nine integer pairs that satisfy the equation (Chapter 9, Lesson 3: Numerical Reasoning Problems)
3 E The ten bathrooms cost $20 each to clean:
Total cost = $20 × 10 = $200
To clean each bathroom twice would cost:
$200 × 2 = $400 There are 30 offices, and they cost $15 each to clean:
Total cost = $15 × 30 = $450
To clean each office once and each bathroom twice will cost: $400 + $450 = $850
(Chapter 11, Lesson 5: Data Analysis)
a
b= 1 10
both
2
3s
1
3s 1
5c
4
5c
sedans convertibles
x
sedans convertibles
both
s
s
6 12
4
x
Trang 34 A Remember the “difference of squares”
factor-ing formula: a2− b2= (a − b)(a + b)
Substitute: 10 = (2)(a + b)
Divide by 2: 5 = a + b
(Chapter 8, Lesson 5: Factoring)
5 A
To find the value of f(14), find all the factors of 14:
1, 2, 7, 14 There are two prime factors, 2 and 7
2 + 7 = 9
f(14) = 9
To find the value of f(6), find all the factors of 6:
1, 2, 3, 6 There are two prime factors, 2 and 3
2 + 3 = 5
f(6) = 5
f(14) − f(6) = 9 − 5 = 4
(Chapter 11, Lesson 2: Functions)
6 D First write an equation to find the average
Multiply by 4: a + b + c + d = 80
If you want a to be as large as possible, make b, c, and
d as small as possible You are told that they are all
different positive integers: a + b + c + d = 80
Let b = 1, c = 2, d = 3: a + 1 + 2 + 3 = 80
Combine like terms: a+ 6 = 80
(Chapter 9, Lesson 2: Mean/Median/Mode Problems)
7 B Let the radius of circle A = a and the radius of
circle B = b It is given that a = 2b The circumference
of a circle can be found with the equation C = 2πr.
The sum of their circumferences is 36π:
36π = 2πa + 2πb
Divide by π: 36 = 2a + 2b
Substitute for a: 36 = 2(2b) + 2b
Simplify: 36 = 4b + 2b
Combine like terms: 36 = 6b
Divide by 6: 6 = b
Solve for a: a = 2(b) = 2(6) = 12
(Chapter 10, Lesson 5: Areas and Perimeters)
a b c+ + + =d
8 C This is a visualization problem The six possi-ble planes are illustrated below Notice that the six faces of the cube “don’t count,” because each of those contains four edges of the cube
(Chapter 10, Lesson 7: Volumes and 3-D Geometry)
9 16 Set up an equation: 2x− 10 = 22
Divide by 2: x = 16
(Chapter 8, Lesson 1: Solving Equations)
10 36
There are 180° on one side of a line:
2y + y + y + y = 180°
Combine like terms: 5y= 180°
Divide by 5: y= 36°
(Chapter 10, Lesson 1: Lines and Angles)
2y°
y° y°
y°
Trang 415 25 First calculate how many grams of sucrose
there are in 200 grams of a 10% mixture
(200 grams)(.10) = 20 grams of sucrose
Since you will be adding x grams of sucrose, the total
weight of sucrose will be 20 + x grams, and the total
weight of the mixture will be 200 + x grams Since the
fraction that will be sucrose is 20%,
Cross-multiply: (20 + x)(100) = 20(200 + x)
Distribute: 2,000 + 100x = 4,000 + 20x
Subtract 2,000: 100x = 2,000 + 20x Subtract 20x: 80x= 2,000
(Chapter 7, Lesson 5: Percents) (Chapter 7, Lesson 4: Ratios and Proportions)
16 24 First calculate how long the race took.
distance = rate × time
16 = (8)(time)
Divide by 8: 2 hours = time = 120 minutes
Next, find the new rate that is 25% faster:
new rate= (8)(1.25) = 10 mph Calculate how long the new race would take:
distance = rate × time
16 = (10)(time)
Divide by 10: 1.6 hours = time = 96 minutes
So she can improve her time by (120 − 96) = 24 minutes (Chapter 9, Lesson 4: Rate Problems)
20 200
20 100
+ + =
x x
11 5 Think simple: What’s the simplest way to turn
8x + 4y into 2x + y? Just divide by 4!
8x + 4y = 20
Divide by 4: 2x + y = 5
(Chapter 8, Lesson 1: Solving Equations)
(Chapter 6, Lesson 4: Simplifying Problems)
12 12 Just substitute x = 3 and y = 5 into the
equa-tion and solve for m:
3m− 15 = 21
(Chapter 8, Lesson 1: Solving Equations)
(Chapter 11, Lesson 2: Functions)
13 15 Ratios such as 4:5 can also be written as 4x:5x.
So the number of men m is 4x and the number of
women w is 5x.
Plug those values into the equation w = m + 3
5x = 4x + 3 Subtract 4x: x= 3
Plug 3 in to 5x: w = 5x = 5(3) = 15
(Chapter 7, Lesson 4: Ratios and Proportions)
14 8 or 12 y = ⎟ 2x − b⎟
Plug in (5, 2): 2=⎟ 2(5) − b⎟
Simplify: 2 =⎟ 10 − b⎟
(10 − b) = 2 or (10 − b) = −2
Subtract 10: −b = −8 or −b = −12
Multiply by −1: b = 8 or b = 12
(Chapter 8, Lesson 6: Inequalities, Absolute Values,
and Plugging In)
Trang 517 52
Break a shape like
this into
recogniz-able four-sided
figures and
trian-gles that are easier
to deal with
The area of the
rectangle on the
left is 7 × 4 = 28
The area of the rectangle on the right is 5 × 4 = 20
The sum of those two areas is 28 + 20 = 48 The
area remaining for the triangle is the difference
78 − 48 = 30 Set up an equation for the area of a
triangle to solve for x:
Area =1⁄2(base)(height)
30 =1⁄2(5)(height) Divide by 1⁄2: 60 = 5(height)
Divide by 5: 12 = height
To find the hypotenuse of
the right triangle, set up
the Pythagorean theorem
and solve:
52+ 122= c2
25 + 144 = c2
169 = c2
c= 13
(Or just notice that it’s a 5-12-13 triangle!)
To find the perimeter of the figure, add up all of the
sides:
13 + 12 + 4 + 5 + 7 + 4 + 7 = 52
(Chapter 10, Lesson 5: Areas and Perimeters)
(Chapter 10, Lesson 3: The Pythagorean Theorem)
18 225 Set up a three-circle Venn diagram to
visual-ize this information
Fifty students study two of the three languages, so let’s say that 50 students study both Spanish and Latin (It
doesn’t matter which two languages those 50 students
take; the result turns out the same.) This means that zero students study both Spanish and French, zero students study both French and Latin, and zero students study all three languages
There are 120 Spanish students in all There are there-fore 120 − 50 = 70 students who study Spanish alone There are 80 French students in all, all of whom study just French, and there are 75 total Latin students in-cluding 75 − 50 = 25 students who study only Latin This means that there are 70 + 50 + 80 + 25 = 225 sophomores at Hillside High School
(Chapter 9, Lesson 5: Counting Problems)
Section 5
1 C The clients were forced to seek more reliable
investment advice, so the manager must have
man-aged their funds badly ineptitude= lack of skill
2 E Vartan is Armenian; he was born in Iran and educated in Lebanon and is now president of the
American Brown University He has a lot of worldly experience perpetual = lasting forever; authoritative = showing authority; cosmopolitan= worldly
3 D They didn’t consider it in great detail, so the
reading must have been without great care verbatim=
word for word; meandering = wandering; tormented = feeling anguish or pain; cursory= quick and without
care; substantial= of substance, quite large
Latin
25 0
0
4
7
7
28
5
5 20
4 7
7
4 28
5
5 20
12
4 13
Trang 64 A If the pathogens (infectious agents) spread
more quickly in close quarters, the crowding would be
a problem This would cause the disease to spread.
squalor = horrible or dirty conditions; circulation =
moving of something around from place to place;
poverty = state of being poor; deterioration = wearing
down; congestion = crowdedness; proximity =
close-ness; resilience= ability to recover from a challenge
5 E The purpose of research is to find answers to
questions of interest Therefore, the research
endeav-ors (attempts) to determine or understand the
mecha-nisms by which our brains do things If the data must
be turned into coherent and understandable
informa-tion, it must not have been coherent to begin with, but
rather just a big rush of information enhance= make
better; attenuate = reduce in amount; dearth = scarcity,
lack; elucidate = make clear; deluge = huge flood
6 D The fruits mentioned in line 10 refer to the
means of acquiring food and shelter, because they are
described as the fruits for maintaining human life.
7 B The question is whether one can get quick
re-turns of interest (make money) from the capital of
knowledge and learning (from one’s education) (lines
13–15)
8 A The pointing of dogs is mentioned as an
in-stinctive tendency to the performance of an action
(lines 1–2)
9 E Inherited tendencies tend to show themselves
in the behavior of an organism The paragraph
men-tions the calf and the caterpillar as examples of
or-ganisms with instincts that show themselves in later
behavior
10 D The final paragraph begins with The best life is
the one in which the creative impulses play the largest part
and the possessive impulses the smallest (lines 56–58).
11 D Lines 22–26 say that the food and clothing of
one man is not the food and clothing of another; if the
supply is insufficient, what one man has is obtained at
the expense of some other man Therefore, food and
clothing exist in finite amounts and can be used up
12 E This section of the passage discusses matters
such as good-will (line 38), science (line 31), and
paint-ing pictures or writpaint-ing poems (lines 35–36) as thpaint-ings
that are not denied to someone else when one person
possesses them
13 E This sentence discusses the possessive
im-pulses (line 49) as distinct from the creative imim-pulses
discussed in the next sentence The impulse of
prop-erty in lines 51–52 is the desire to possess propprop-erty.
14 C This statement echoes the point made in lines
71–72 that spiritual possessions cannot be taken in this
way, that is, by force.
15 D Lines 58–59 say This is no new discovery and
go on to cite the Gospel as a prior source expressing the same opinions as Russell’s
16 B The author’s main point is that creativity is of higher value than possessiveness The invention mentioned in answer choice (B) was created to make money for its inventor (a possessive and materialis-tic motive) but has the side effect of benefitting all of humankind
17 A The passage discusses the perspective one
Native American has on the appearance of the new
superstition (line 44) It discusses how some villagers
have taken to the new religion and also mentions one fellow tribe member’s attempting to convert the main character
18 E In saying that men of the same color are like the
ivory keys of one instrument where each represents all the rest, yet varies from them in pitch and quality of voice (lines 4–7), the author is saying that people of
the same race possess important differences
19 D The author describes the preacher as
mouth[ing] most strangely the jangling phrases of a bigoted creed (lines 11–12), indicating that she
consid-ers him to be an intolerant pconsid-erson She describes
her-self as having compassion (line 7) and respect (line 10),
but does not attribute these qualities to the preacher
20 B Lines 13–14 say that our tribe is one large
fam-ily, where every person is related to all the others.
21 C Both the preacher and the author’s mother
have become followers of the new superstition (line 44).
22 C In saying that a pugilist commented upon a
re-cent article of mine, grossly perverting the spirit of my pen (lines 66–68), the author is saying that the pugilist
distorted the author’s words in a grotesque way
Trang 723 E The author characterizes herself as a wee child
toddling in a wonder world (lines 72–73), indicating
that she is in awe of the world around her Although
one might expect her to be vengeful in response to the
pugilist (line 66) who grossly pervert[ed] the spirit of
[her] pen (line 68), there is no indication in the
para-graph that she is vengeful
24 A The author says in lines 68–72 that still I would
not forget that the pale-faced missionary and the
aborig-ine are both God’s creatures, though small indeed in
their own conceptions of Infinite Love In other
words, the author respects the missionary but believes
he is small-minded
Section 6
1 D The verb must agree with the plural subject
claims Choice (D) is most concise and correct.
(Chapter 15, Lesson 1: Subject-Verb Disagreement)
2 A The original sentence is best
3 B The participial phrase opening the sentence
modifies Sartre himself, not his writing This being
the case, the phrase dangles
(Chapter 15, Lesson 7: Dangling and Misplaced
Participles)
4 C Choice (C) best follows the law of parallelism
(Chapter 15, Lesson 3: Parallelism)
5 A The original sentence is best
6 B Choice (B) is the most concise, logical, and
complete
(Chapter 12, Lesson 9: Write Concisely)
7 C The original phrasing contains an incomplete
thought Choice (C) is by far the most concise and direct
(Chapter 15, Lesson 15: Coordinating Ideas)
8 E The participle having spread modifies the
dis-ease, not the doctors.
(Chapter 15, Lesson 7: Dangling and Misplaced
Participles)
9 C The original phrasing contains an incomplete
thought Choice (C) is by far the most concise and direct
(Chapter 15, Lesson 15: Coordinating Ideas)
10 D The participle singing modifies Anita, not her
hoarseness Furthermore, the participle is in the
wrong form; it should be in the perfect form having
sung, because only the previous singing could have
contributed to her hoarseness
(Chapter 15, Lesson 7: Dangling and Misplaced Participles)
(Chapter 15, Lesson 9: Tricky Tenses)
11 A The original sentence is best
12 A The word quick is an adjective and can thus
modify only a noun But since it modifies the verb
turned, the adverb quickly is needed here.
(Chapter 15, Lesson 12: Other Modifier Problems)
13 B This sentence violates the law of parallelism
If she is known for her initiative, she should also be known for devoting her own time.
(Chapter 15, Lesson 3: Parallelism)
14 C Since the Medieval era is long past, its
begin-ning is “completed” or, in grammar terms, “perfect.”
So this phrase should be the “perfect” form of the
in-finitive: to have begun.
(Chapter 15, Lesson 9: Tricky Tenses)
15 B The word neither is almost always part of the phrase neither of or neither A nor B So choice (B) should read nor even.
(Chapter 15, Lesson 10: Idiom Errors)
16 D The word less is used to compare only
quanti-ties that can’t be counted If the quantiquanti-ties are
count-able, as accidents are, the word should be fewer.
(Chapter 15, Lesson 4: Comparison Problems)
17 B To convey the proper sequence of events, the
perfect tense is required: had spent.
(Chapter 15, Lesson 9: Tricky Tenses)
18 A The subject of the verb has is the plural noun
newspapers (The sentence is “inverted,” because the
subject follows the verb.) The proper form of the verb,
then, is have.
(Chapter 15, Lesson 1: Subject-Verb Disagreement) (Chapter 15, Lesson 2: Trimming Sentences)
19 B The original sentence has a “comma splice” that incorrectly joins two sentences with only a
comma A better phrasing is dream that led.
(Chapter 15, Lesson 15: Coordinating Ideas)
Trang 820 C The subject of the verb is the singular noun
movement, so the proper verb form is has led.
(Chapter 15, Lesson 1: Subject-Verb Disagreement)
(Chapter 15, Lesson 2: Trimming Sentences)
21 E The sentence is correct as written
22 D This is a prepositional phrase, so the
pro-noun is the object of the preposition and should be
in the objective case The correct phrasing is for
Maria and me.
(Chapter 15, Lesson 6: Pronoun Case)
23 A The word successive means consecutive, so it
does not make sense in this context The right word is
successful.
(Chapter 15, Lesson 11: Diction Errors)
24 E The sentence is correct as written
25 C The word underneath means that it is
physi-cally below something else It should be changed to
under.
(Chapter 15, Lesson 10: Idiom Errors)
26 E The sentence is correct as written
27 B The subject of the verb were is arrogance,
which is singular It should instead be was.
(Chapter 15, Lesson 1: Subject-Verb Disagreement)
28 B The sentence mentions there are numerous
strains of the bacteria, which means that more should
instead be most.
(Chapter 15, Lesson 4: Comparison Problems)
29 C The subject company is singular Therefore,
they should instead be it.
(Chapter 15, Lesson 5: Pronoun-Antecedent
Disagreement)
30 D Choice (D) is most consistent, logical, and
concise
31 A Choice (A) is most logical
(Chapter 12, Lesson 7: Write Logically)
32 B The first paragraph ends with the description
of an idea The second paragraph begins with an illustration of how students experience this idea in their daily lives and then goes on to explain how it can
help them get through their brain freezes Choice (B)
is the best introduction to the paragraph, because it explains that a student using the phenomenon can improve his or her studies
(Chapter 12, Lesson 7: Write Logically)
33 C The sentence begins using the pronoun you,
so that usage should be maintained throughout the sentence Choice (D) is incorrect because a person has only one brain
(Chapter 15, Lesson 5: Pronoun-Antecedent Disagreement)
34 E Sentence 11 concludes a discussion of Isaac Asimov’s “eureka” experience The additional sen-tence expands upon that idea, relating it back to the lives of students
(Chapter 12, Lesson 7: Write Logically)
35 C Choice (C) is the most concise and logical revision
(Chapter 12, Lesson 7: Write Logically) (Chapter 12, Lesson 9: Write Concisely)
Section 7
1 B Set up a ratio to solve this problem:
Cross-multiply: 4x= 200 Divide by 4: x= 50 cents (Chapter 7, Lesson 4: Ratios and Proportions)
2 C Solve for b: 2b= 8
b= 3 Plug in 3: 3b= 33= 27 (Chapter 8, Lesson 3: Working with Exponentials)
3 A The sum of a, b, and 18 is 6 greater than the sum of a, b, and 12 Since there are three terms in the group, it follows that the average of a, b, and 18 would
be 6 ÷ 3 = 2 greater than the average of a, b, and 12.
(Chapter 9, Lesson 2: Mean/Median/Mode Problems)
4apples 10
20 cents
apples
x cents
=
Trang 94 B If you have the patience, you can write out a
quick calendar for yourself to track the days:
Or you can use the simple fact that successive
Tues-days (like any other Tues-days) are always 7 Tues-days apart
Therefore, if the 1st of the month is a Tuesday, so are
the 8th, the 15th, the 22nd, and the 29th Therefore, the
30th is a Wednesday and the 31st is a Thursday
(Chapter 9, Lesson 3: Numerical Reasoning Problems)
5 A From the given information: m = 8n
0 < m + n < 50 Substitute for m: 0 < 8n + n < 50
Combine like terms: 0 < 9n < 50
Divide by 9: 0 < n < 55⁄9
Since n must be an integer, n can be 1, 2, 3, 4, or 5.
(Chapter 8, Lesson 6: Inequalities, Absolute Values,
and Plugging In)
6 D First find the value of y: y% of 50 is 32.
Simplify:
Cross-multiply: 50y= 3,200
Divide by 50: y= 64
What is 200% of 64?
Interpret: 2.00 × 64 = 128
(Chapter 7, Lesson 5: Percents)
Plug in 16 for x: g(16) = 16 + 161/2
Take square root of 16: g(16) = 16 + 4
Combine like terms: g(16) = 20
(Chapter 11, Lesson 2: Functions)
8 C The slope of the line is −3⁄4, so use the slope
equation and the coordinates of point A (0, 12) to find
the coordinates of point B (x, 0):
Cross-multiply: 4(−12) = −3(x)
Simplify: −48 = −3x
Divide by −3: 16 = x
The base of the triangle is 16, and its height is 12
Area =1⁄2(base)(height) Substitute: Area =1⁄2(16)(12)
Simplify: Area = 96
(Chapter 10, Lesson 4: Coordinate Geometry)
= −
− = −− = − = −
0 12 0
12 3 4
y
100×50=32
9 A Find the sum of each repetition of the pattern:
−1 + 1 + 2 = 2 Next, determine how many times the pattern repeats in the first 25 terms: 25 ÷ 3 = 8 with a remainder of 1
Multiply the sum of the pattern by 8 to obtain the sum
of the first 24 terms: 2 × 8 = 16 The 25th term is −1, which makes the sum 16 + −1 = 15 (Chapter 11, Lesson 1: Sequences)
10 D The ratio of white marbles to blue marbles is
4 to b The probability of randomly selecting a white
marble from the jar is 1⁄4 This means that one out of every four marbles in the jar is white and three out of every four marbles are blue If there are four white marbles, then there are 4 × 3 = 12 blue marbles (Chapter 7, Lesson 4: Ratios and Proportions)
11 B Area =1⁄2(base)(height)
Substitute: 10 =1⁄2(base)(height) Divide by 1⁄2: 20 = (base)(height) The base and the height are both integers Find all the
“factor pairs” of 20: 1, 20; 2, 10; and 4, 5 Plug each pair into the Pythagorean theorem to find the least possible length of the hypotenuse:
a2+ b2= c2
42+ 52= c2 Combine like terms: 41 = c2 Take square root:
a2+ b2= c2
22+ 102= c2 Combine like terms: 104 = c2 Take square root:
a2+ b2= c2
12+ 202= c2 Combine like terms: 401 = c2 Take square root:
is the shortest possible hypotenuse
(Chapter 10, Lesson 5: Areas and Perimeters) (Chapter 10, Lesson 3: The Pythagorean Theorem)
12 B −1 < y < 0 This means that y is a negative decimal fraction.
Answer choices (A), (C), and (E) will all be negative num-bers Answer choices (B) and (D) are positive numnum-bers When you raise a simple fraction to a positive number
larger than 1, it gets smaller y4< y2, which makes (B) the
greatest value Pick a value like y= −1⁄2and see
(Chapter 9, Lesson 3: Numerical Reasoning Problems)
41
401= c
104= c
41= c
Su M T W Th F Sa
16 17 18
23 24 25
20 21 22
30 31
27 28 29
26
Trang 1013 E Any statement of the form “If A is true, then B
is true” is logically equivalent to “If B is not true, then
A is not true.” Try this with some common-sense
examples of such statements For instance, saying “If
I am under 16 years old, then I am not allowed to drive”
is the same as saying “If I am allowed to drive, then I
must not be under 16 years old.” The statement in (E)
is logically equivalent to the original
(Chapter 6, Lesson 7: Thinking Logically)
14 E If each bus contained only the minimum
number of students, the buses would accommodate
6 × 30 = 180 students But since you have 200 students
to accommodate, you have 20 more students to place
To maximize the number of 40-student buses, place
10 more students in two of the buses Therefore, a
maximum of two buses can have 40 students
(Chapter 9, Lesson 3: Numerical Reasoning Problems)
15 D The volume of a cylinder is equal to πr2h Let’s
say that the radius of cylinder A is a and the radius of
cylinder B is b Since the height of cylinder B is twice
the height of cylinder A, if the height of cylinder A is
h, then the height of cylinder B is 2h The volume of
A is twice that of B: πa2h = 2πb2(2h)
Simplify: πa2h = 4πb2h
Divide by π: a2h = 4b2h
Take the square root of both sides: a = 2b
Divide by b:
(Chapter 10, Lesson 7: Volumes and 3-D Geometry)
16 C The key is to find a pattern among the many
possible solutions Pick some values for x to see if you
can see a pattern For instance, if x= 3, then the
gar-den looks like this:
In this case w = 8 But if x = 4, the garden looks like this:
a
b= 2 1
And here, w= 12 You might notice that the value of
w has increased by 4 Does this pattern continue?
Let’s try x= 5 to check:
Sure enough, w= 16, and it seems that the pattern
continues and w is always a multiple of 4 Only choice
(C), 40, is a multiple of 4, so that must be the correct answer
(Chapter 6, Lesson 3: Finding Patterns)
Section 8
1 B A reputable scientist is well known and well respected Saying the evidence is - at best indicates
that there is not much evidence at all It must be
flimsy Reputable scientists would not likely admit that
a phenomenon exists if the evidence is weak meager=
scanty, deficient; regret = feel bad about an action,
wish it hadn’t happened; paltry= lacking worth
2 D The concept that the Earth is round is now
ac-cepted as an inarguable truth It can be inferred that it
was at some point a fact that was thought to be wrong
incontrovertible = cannot be questioned; mellifluous = smooth flowing; dubious= doubtful
3 B A profound break of a political party or religion
into factions is a schism (The Latin word schisma=
split.) unanimity = full agreement; schism = division into factions; caucus = meeting of party members;
someone; prognostication= prediction
4 C As the father of the American public school
system, Horace Mann would pressure or push the Massachusetts legislature to institute a system for
en-suring or guaranteeing universal access to eduction petitioned = requested, lobbied for; vouchsafing =
con-ceding, granting
5 A Since the light from most stars takes millions
of years to reach us, it is plausible to imagine that by the time we see the light the star might actually no longer be there This would make the present
exis-tence of these stars questionable debatable =
dis-putable; methodical = systematic; indecorous = not proper; imperious= acting as if one is superior to
an-other; profuse= abundant