46.2 On the Impossibility of Perpetual Motion of the Second Kind 3551 It is not possible to construct an ideal heat pump in which heat can flow from a colder body to a warmer body without
Trang 1By transforming from an extensive expression for the work done, for
ex-ample,
δA = + HdmH + ,
to the corresponding intensive quantity, e.g.,
δA := δA − d(HmH ) = − mH dH + , one obtains, instead of the Helmholtz free energy F (T , V, m H , N ), the Gibbs free energy
Fg (T , V, H, N ) := F (T , V, m H (T , V, H, N ), N ) − mHH ,1
with
dF g=−pdV + μdN − mH dH − SdT
and the corresponding relations
∂F g
∂H =−mH , ∂F g
∂T =−S ,
etc The second law is now
dF g ≤ δA − SdT The Gibbs free energy F g (T , V, H, N ), and not Helmholtz free energy
F (T , V, mH, N ), is appropriate for Hamiltonians with a Zeeman term, e.g.,
the Ising Hamiltonian (42.5), because the magnetic field is already taken into account in the energy values Whereas for non-magnetic systems one can show that
F (T , V, N ) ≡ −kBT · ln Z(T, V, N) ,
for magnetic systems
Fg (T , V, H, N ) ≡ −kBT · ln Z (T , V, H, N ) , with
Z (T , V, H, N ) ≡
l
e−βE l (V,H,N ) 2
46.2 On the Impossibility of Perpetual Motion
of the Second Kind
The following six statements can be regarded as equivalent formulations of the second law of thermodynamics:
1 Similarly, for magnetic systems one may also distinguish, e.g.,
be-tween a Helmholtz enthalpy IHelmholtz(T, p, m H , N ) and a Gibbs enthalpy
IGibbs(T, p, H, N ).
2
Here the prime is usually omitted
Trang 246.2 On the Impossibility of Perpetual Motion of the Second Kind 355
1) It is not possible to construct an ideal heat pump in which heat can flow
from a colder body to a warmer body without any work being done to accomplish this flow This formulation is due to Robert Clausius (1857)
In other words, energy will not flow spontaneously from a low temperature object to a higher temperature object
2) An alternative statement due to William Thomson, later Lord Kelvin,
is essentially that you cannot create an ideal heat engine which extracts
heat and converts it all to useful work
Thus a perpetual motion machine of the second kind, which is a hypotheti-cal device undergoing a cyclic process that does nothing more than convert heat into mechanical (or other) work, clearly does not exist, since it would contradict the second law of thermodynamics On the other hand, as we shall
see later, a cyclically operating (or reciprocating) real heat pump is perfectly feasible, where an amount of heat Q2 is absorbed at a low temperature T2
and a greater amount of heat Q1 = Q2+ ΔQ is given off at a higher tem-perature T1 (> T2), but – to agree with the first law of thermodynamics –
the difference ΔQ must be provided by mechanical work done on the system (hence the term “heat pump”).
3a) All Carnot heat engines3 (irrespective of their operating substance) have
the same maximum efficiency
η := ΔA
Q1
=Q1− Q2
Q1
, where η ≤ T1− T2
T1
is also valid The equal sign holds for a reversible process
The following (apparently reciprocal) statement is also valid:
3b)All Carnot heat pumps have the same maximum efficiency
η := Q1
ΔA =
Q1
Q1− Q2
, with η ≤ T1
T1− T2
.
The equal sign again applies for a reversible process
The efficiencies η and η are defined in a reciprocal way, and in the
op-timum case also give reciprocal values However the inequalities are not reciprocal; the irreversibility of statistical physics expresses itself here, since in both cases we have the inequality sign≤, due to, for example,
frictional losses
Figure 46.1 shows the (T , V )-diagram for a Carnot process Depending on
whether we are considering a Carnot heat engine or a Carnot heat pump
the cycle (which comprises two isotherms and two adiabatics) runs either clockwise or anticlockwise.
3
Usually more practical than Carnot machines are Stirling machines, for which the adiabatics of the Carnot cycle (see below) are replaced by isochores, i.e.,
V = constant.
Trang 3Fig 46.1 Carnot process in a (V, T )
rep-resentation Carnot cycle (running clock-wise:→ heat engine; running anticlockwise:
→ heat pump) in a (V, T )-diagram with
isotherms at T1 = 2 and T2 = 1.5 (arbi-trary units) and adiabatics T · V 5/3 = 1.5 and 0.5, as for an ideal gas Further
expla-nation is given in the text
We shall now calculate the value of the optimal efficiency for a Carnot cycle
η opt. = 1/η
opt.
by assuming that the working substance is an ideal gas Firstly, there is an
isothermal expansion from the upper-left point 1 to the upper-right point
1 in Fig 46.1 at constant temperature T1 The heat absorbed during this expansion is Q1 Then we have a further expansion from 1 down to 2, i.e., from the upper-right to the lower-right (i.e., from T1= 2 to T2= 1.5), which occurs adiabatically according to
pV κ = T V κ −1 = const , where κ = C p
Cv =
5
3 , down to point 2 at the lower temperature T2 Subsequently there is an isothermal compression to the left, i.e., from 2 → 2 at T2, with heat
released Q2 Then the closed cycle W is completed with an adiabatic
compression leading from 2 up to the initial point 1 It follows that
W
dU ≡ 0 ;
on the other hand we have
W
dU = Q1− Q2− ΔA , where the last term is the work done by the system.
The efficiency
η := ΔA
Q ≡ Q1− Q2
Q
Trang 446.2 On the Impossibility of Perpetual Motion of the Second Kind 357 can now be obtained by calculating the work done during the isothermal expansion
A1→1 =
1
1
pdV ≡ Q1,
since for an ideal gas
ΔU1→1 = 0
Furthermore
1
1
pdV = N kBT1
1
1
dV
V , i.e. Q1= N k B T1ln
V1
V1
.
Similarly one can show that
Q2= N k B T2lnV2
V2
.
For the adiabatic sections of the process
(1 , T
1)→ (2 , T
2) and (2, T2)→ (1, T1)
we have
T1V1κ = T2V2κ and T1V1κ = T2V2κ ,
where
κ :=C P
CV − 1 = 2
3 .
We then obtain
V1
V1
=V2
V2
and η = 1 − T2ln
V 2
V2
T1lnV 1
V1
,
finally giving
η = 1 − T2
T1
,
as stated
We shall now return to the concept of entropy by discussing a fourth
equivalent version of the second law:
4) The quantity
S :=
2
1
δQrev
T
is a variable of state (where “rev” stands for “reversible”), i.e., the integral does not depend on the path Using this definition of the state variable
Trang 5entropy we may write:
dS ≥ δQ
T ,
with the equality symbol for reversible heat flow
We now wish to show the equivalence between 4) and 3) by considering
a Carnot heat engine According to 4) we have
δQ
Q1
T1 − Q2
T2 ,
but from 3) for a reversible process
η = 1 − Q1
Q2 ≡ 1 − T2
T1
, i.e.,
δQrev
T ≡ 0
For an irreversible process the amount of heat given out at the lower
tem-perature T2is greater than in the reversible case Thus
dS > δQ
rev
One may approximate general reciprocating (or cyclic) processes by in-troducing Carnot coordinates as indicated in Fig 46.2 below:
Fig 46.2 Carnot coordinates This (V, T ) diagram shows a single curved line
segment in the upper-right hand part of the diagram and two sets of four horizontal
isotherms and four non-vertically curved adiabatics, respectively, forming a grid
N of so-called Carnot coordinates For an asymptotic improvement of the grid
the single curve is extended to the bounding line ∂G of a two-dimensional region
G, and since the internal contributions cancel each other in a pairwise manner,
one may show analogously to Stokes’s integral theorem that the following is valid:H
∂G
δQrev
Carnot processes∈N
δQrev
T Finally, instead of P
∈N
one may also write the integralR
Trang 647 Shannon’s Information Entropy
What actually is entropy ? Many answers seem to be rather vague: Entropy
is a measure of disorder, for example An increase in entropy indicates loss of information, perhaps However the fact that entropy is a quantitative
mea-sure of information, which is very important in both physics and chemistry, becomes clear when addressing the following questions:
– How large is the number N of microstates or configurations of a fluid consisting of N molecules (ν = 1, , N , e.g., N ∼ 1023), where each
molecule is found with a probability p j in one of f different orthogonal states ψ j (j = 1, , f )?
– How large is the number N of texts of length N (= number of digits
per text) which can be transmitted through a cable, where each digit originates from an alphabet{Aj}j=1, ,f of length f and the various A j occur with the probabilities (= relative frequencies) p j?
– How many times N must a language student guess the next letter of
a foreign-language text of length N , if he has no previous knowledge of the language and only knows that it has f letters A j with probabilities
pj , j = 1, , f ?
These three questions are of course identical in principle, and the answer
is (as shown below):
N = 2 N ·I= eN·S kB , where I = 1
NldN
is the so-called Shannon information entropy Apart from a normalization
factor, which arose historically, this expression is identical to the entropy used
by physicists Whereas Shannon and other information theorists used binary logarithms ld (logarithms to the base 2) physicists adopt natural logarithms (to the base e = exp(1) = 2.781 , ln x = (0.693 ) · ldx) Then we have
S
kB =
1
N lnN , which apart from unessential factors is the same as I Proof of the above
relation between N and I (or S
k B) is obtained by using some “permutation
gymnastics” together with the so-called Stirling approximation, i.e., as
fol-lows
Trang 7The number of configurations is
N1!N2!· · Nf!
because, for a length of text N there are N ! permutations where exchange
gives in general a new text, except when the digits are exchanged amongst each other We then use the Stirling approximation: for
2πN
N e
N
·
1 +O
1
N
;
i.e., by neglecting terms which do not increase exponentially with N , we may
write
N ! ≈
N e
N
Thus
N ∼=
N
e
(N1+N2+ +N f)
N
1
e
N1
· ·N f
e
N f , or
lnN ∼=−
f
j=1
N j · ln
Nj N
≡ −N
f
j=1
p j · ln pj ,
which gives
N ∼= eN · S
kB , with S
kB ≡ −
f
j=1
pj · ln pj (47.1)
Using the same basic formula for S one can also calculate the thermody-namic entropy S(T ), e.g., with the Boltzmann-Gibbs probabilities
pj= e
−βE j
Z(T ) ,
in agreement with the expressions
Z(T ) =
j
e−βE j , U (T ) = − d ln Z
dβ , F (T ) = −kBT · ln Z(T ) ,
with F (T ) = U (T ) − T · S(T ) , i.e S(T ) ≡ − ∂F
∂T .
The relative error made in this calculation is
O
ln√ 2πN
which for N
Trang 847 Shannon’s Information Entropy 361
To end this section we shall mention two further, particularly neat for-mulations of the second law:
5) A spontaneously running process in a closed system can only be reversed
by doing work on the system
This is equivalent to stating:
6) Heat only flows spontaneously from a higher to a lower temperature This last formulation due to Max Planck goes back to Robert Clausius (see above).1 At the same time he recognized that it is not easy to prove the second law in a statistical-physical way This is possible, but only using stochastic methods.2
Work done on a closed system, δA > 0, always leads to the release of heat from the system, δQ < 0, since
dU ( ≡ δA + δQ) = 0
The entropy must therefore have increased along the “ first leg of the cycle ”, since5
dS = 0 The requirement that we are dealing with a closed system, i.e., dU = 0, is thus unnecessarily special, since one can always modify an open system, e.g., with heat input, δQ > 0, to be a closed one by including
the heat source In this sense, closed modified systems are the “ most general ” type of system, and we shall see in the following sections in what ways they may play an important part
1 We should like to thank Rainer H¨ollinger for pointing this out
2
see, e.g., the script Quantenstatistik by U.K.
Trang 9in Phenomenological Thermodynamics
48.1 Closed Systems and Microcanonical Ensembles
The starting point for the following considerations is a closed system,
corre-sponding to the so-called microcanonical ensemble The appropriate function
of state is S(U, V, N ) The relevant extremum principle is S = max., so that!
ΔS > 0 until equilibrium is reached Furthermore
dS = δQ
rev
dU − δA
dU + pdV − μdN
1
T =
∂S
∂U
V,N
T =
∂S
∂V
U,N
and μ
T =−
∂S
∂N
U,V
The probabilities p j are given by
pj= 1
N , if U − δU < Ej ≤ U otherwise p j = 0 Here, δU is, e.g., an instrumental uncertainty, and
N (= N (U − δU, U))
is the total number of states with
U − δU < Ej ≤ U
We shall see below that the value ofδU U is not significant unless it is extremely small in magnitude
48.2 The Entropy of an Ideal Gas
from the Microcanonical Ensemble
Inserting the relation
pj ≡ N1 for U − δU < Ej ≤ U ,
Trang 10364 48 Canonical Ensembles in Phenomenological Thermodynamics
otherwise≡ 0, into the relation for S gives
S = kB · ln N , with
N = N (U − δU, U) = V N
h 3N N ! ·
⎧
⎪
⎪
U −δU< p21+ +p2 N
d3N p
⎫
⎪
⎪ .
The braced multidimensional integral in p-space is the difference in volume
between two spherical shells inR 3N (p) with radii
R1(U ) := √
2mU and R2(U − δU) :=2m · (U − δU)
This gives
N = V N
h 3N N ! Ω(3N )(2m)
3N/2 ·"U 3N/2 − (U − δU) 3N/2#
,
where Ω(d) is the volume of a unit sphere in d-dimensional space.
Here it is important to note that the whole second term, (U − δU) 3N/2,
can be neglected compared to the first one, U 3N/2, except for extremely small
δU , since normally we have
U − δU U
3N/2
1 ,
because N is so large1, i.e., one is dealing with an exponentially small ratio
We therefore have
N ≡ N (U) = V N Ω(3N )(2mU ) 3N/2
S = k BlnN = kB N ·
ln V
V0 +
3
2ln
U
U0+ ln
s0V0U03
.
Here, V0 and U0 are volume and energy units (the exact value is not signifi-cant; so they can be arbitrarily chosen) The additional factor appearing in the formula, the “atomic entropy constant”
s
0:= ln
s0V0U03
is obtained from the requirement that (for N
N · ln[s0V0U03]= ln!
,
(2m) 3N/2 Ω(3N )
h 3N N ! V
N
0 U 3N2
0
-.
1 E.g., one should replace U by 1 and (U − δU) by 0.9 und study the sequence
(U − δU) N
for N = 1, 2, 3, 4,
... V0 and U0 are volume and energy units (the exact value is not signifi-cant; so they can be arbitrarily chosen) The additional factor appearing in the formula,...6) Heat only flows spontaneously from a higher to a lower temperature This last formulation due to Max Planck goes back to Robert Clausius (see above).1 At the same time he...
Trang 847 Shannon’s Information Entropy 361
To end this section we shall mention two further, particularly