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A.4 The Numerator Determinant The numerator determinant N k is formed from the characteristic determi-nant by replacing the kth column in the characteristic determidetermi-nant with th

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A.2 Cramer's Method

The value of each unknown variable in the set of equations is expressed as

the ratio of two determinants If we let N, with an appropriate subscript,

represent the numerator determinant and A represent the denominator

determinant, then the /cth unknown x k is

N,

The denominator determinant A is the same for every unknown variable

and is called the characteristic determinant of the set of equations The

numerator determinant N k varies with each unknown Equation A.4 is

referred to as Cramer's method for solving simultaneous equations

A.3 The Characteristic Determinant

Once we have organized the set of simultaneous equations into an ordered array, as illustrated by Eqs A.l and A.3, it is a simple matter to form the characteristic determinant This determinant is the square array made up from the coefficients of the unknown variables For example, the characteristic determinants of Eqs A.l and A.3 are

A =

21

- 3

- 8

- 9

6

- 4

- 1 2

- 2

22

(A.5)

and

A =

2

0

7

- 1

4

0

0

3

2

(A.6)

respectively

A.4 The Numerator Determinant

The numerator determinant N k is formed from the characteristic

determi-nant by replacing the kth column in the characteristic determidetermi-nant with

the column of values appearing on the right-hand side of the equations For example, the numerator determinants for evaluating / j , /2, and 1*3 in Eqs A.l are

A/, =

- 3 3

50

- 9

6

- 4

- 1 2

- 2

22

(A.7)

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N-> =

21 - 3 3 - 1 2

- 3 3 - 2

- 8 50 22

(A.8)

and

N3 =

21

- 3

- 8

- 9

6

- 4

- 3 3

3

50

(A.9)

The numerator determinants for the evaluation of t?j, v 2 , and ?;3 in

Eqs A.3 are

N, =

4

16

5

- 1

4

0

0

3

2

(A.10)

and

A r ,

2

0

7

4

16

5

0

3

2

7V 3

2

0

7

- 1

4

0

4

16

5

(A.ll)

(A.12)

A.5 The Evaluation of a Determinant

The value of a determinant is found by expanding it in terms of its minors

The minor of any element in a determinant is the determinant that

remains after the row and column occupied by the element have been deleted For example, the minor of the element 6 in Eq A.7 is

•33 - 1 2

50 22 while the minor of the element 22 in Eq A.7 is

- 3 3

3

The cofactor of an element is its minor multiplied by the

sign-controlling factor

- l( / + / ),

where i and j denote the row and column, respectively, occupied by the

element Thus the cofactor of the element 6 in Eq A.7 is

_ j (2+2) - 3 3 - 1 2

50 22

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and the cofactor of the clement 22 is

_l(3+3) - 3 3 - 9

3 6

The cofactor of an element is also referred to as its signed minor

The sign-controlling factor — l((+y) will equal +1 or —1 depending on

whether i + j is an even or odd integer Thus the algebraic sign of a

cofac-tor alternates between + 1 and —1 as we move along a row or column For

a 3 X 3 determinant, the plus and minus signs form the checkerboard pat-tern illustrated here:

+

A determinant can be expanded along any row or column Thus the first

step in making an expansion is to select a row i or a column j Once a row

or column has been selected, each element in that row or column is multi-plied by its signed minor, or cofactor The value of the determinant is the sum of these products As an example, let us evaluate the determinant in

Eq A.5 by expanding it along its first column Following the rules just explained, we write the expansion as

A = 21(1) - 2

22 - 3 ( - 1 ) -9 - 1 2

•4 22 - 8 ( 1 )

•9 - 1 2

6 - 2 (A.13)

The 2 X 2 determinants in Eq A.13 can also be expanded by minors The minor of an element in a 2 x 2 determinant is a single element It fol-lows that the expansion reduces to multiplying the upper-left element by the lower-right element and then subtracting from this product the product

of the lower-left element times the upper-right element Using this obser-vation, we evaluate Eq A.13 to

A = 21(132 - 8 ) + 3(-198 - 48) - 8(18 + 72)

Had we elected to expand the determinant along the second row of ele-ments, we would have written

A = - 3 ( - 1 ) - 1 2

22 +6(+1)

21

- 8

- 1 2

22 - 2 ( - 1 )

21

- 8

- 9

- 4

= 3(-198 - 48) + 6(462 - 96) + 2 ( - 8 4 - 72)

The numerical values of the determinants N u N 2 , and N 3 given by Eqs A.7, A.8, and A.9 are

Trang 4

and

N 2 = 2292,

N 3 = 3438

(A.17)

(A.18)

It follows from Eqs A.15 through A.18 that the solutions for i\, i 2 , and i 3 in

Eq A.l are

i2 = -/ = 2A, (A.19)

and

N 3

h = ~T = 3 A

We leave you to verify that the solutions for v h v 2 , and v 3 in Eqs A.3 are

49

v 2 = ^ | = -23.6 V,

and

„ - ^ f U 36.8 V

A.6 Matrices

A system of simultaneous linear equations can also be solved using matrices In what follows, we briefly review matrix notation, algebra, and terminology.1

A matrix is by definition a rectangular array of elements; thus

A =

#ii a n a u

(l 2 \ (l 22 & 2 T,

_ " m l "-ml " m 3

«1»

ttln

(A.21)

is a matrix with m rows and n columns We describe A as being a matrix of order m by n, or m X «, where m equals the number of rows and n the

1 An excellent introductory-level text in matrix applications to circuit analysis is Lawrence P

Huelsman, Circuits, Matrices, and Linear Vector Spaces (New York: McGraw-Hill, 1963)

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number of columns We always specify the rows first and the columns

sec-ond The elements of the matrix — «n, a12, «13, • • —can be real numbers,

complex numbers, or functions We denote a matrix with a boldface

capi-tal letter

The array in Eq A.21 is frequently abbreviated by writing

A [ a ij\mii >

where a tj is the element in the /th row and theyth column

If m — 1, A is called a row matrix, that is,

A « [flu a n a l3 ••• a h! )

If /2 = 1, A is called a column matrix, that is,

(A.22)

(A.23)

«11

«21

. a m\

If m = n, A is called a square matrix For example, if m = n = 3, the

square 3 by 3 matrix is

A = «21 «22 «23 • (A.25)

«11

«21

«31

«12

«22

«32

«13

«23

«33

Also note that we use brackets [] to denote a matrix, whereas we use

vertical lines 11 to denote a determinant It is important to know the

differ-ence A matrix is a rectangular array of elements A determinant is a

func-tion of a square array of elements Thus if a matrix A is square, we can

define the determinant of A For example, if

2 1

6 15 then

A,7 Matrix Algebra

The equality, addition, and subtraction of matrices apply only to matrices

of the same order Two matrices are equal if, and only if, their

correspon-ding elements are equal In other words, A = B if, and only if, a^ = b,j for

all i and ;* For example, the two matrices in Eqs A.26 and A.27 arc equal

because a n = b n ,a u = b 12 ,a 2 i = 62i,and«22 = ^22:

"36

4 -20

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B = 36 - 2 0

4 16

If A and B are of the same order, then

(A.27)

implies

For example, if

4 - 6 10

and

B 16 10 - 3 0

then

20 4 - 2 0

The equation

implies

djj = atj - bjj

For the matrices in Eqs A.30 and A.31, we would have

(A.34)

Matrices of the same order are said to be conformable for addition and

subtraction

Multiplying a matrix by a scalar k is equivalent to multiplying each element by the scalar Thus A = kB if, and only if, a- t ; = kbn It should be

noted that k may be real or complex As an example, we will multiply the

matrix D in Eq A.35 by 5 The result is

Matrix multiplication can be performed only if the number of columns in the first matrix is equal to the number of rows in the second matrix In other words, the product AB requires the number of columns in

A to equal the number of rows in B.The order of the resulting matrix will

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712 The Solution of Linear Simultaneous Equations

be the number of rows in A by the number of columns in B Thus if

C = AB, where A is of order m X p and B is of order /; x n, then C will

be a matrix of order m X n When the number of columns in A equals the

number of rows in B, we say A is conformable to B for multiplication

An element in C is given by the formula

(A.37)

The formula given by Eq A.37 is easy to use if one remembers that matrix multiplication is a row-by-column operation Hence to get the /th, / t h term in C, each element in the /th row of A is multiplied by the corre-sponding element in the / t h column of B, and the resulting products are summed The following example illustrates the procedure We are asked to find the matrix C when

and

B

~4

0 _1

2~

3

- 2 _

(A.39)

First we note that C will be a 2 X 2 matrix and that each element in C will require summing three products

To find Cj! we multiply the corresponding elements in row 1 of matrix A with the elements in column 1 of matrix B and then sum the products We can visualize this multiplication and summing process by extracting the corresponding row and column from each matrix and then lining them up element by element So to find Cu we have

Row 1 of A Column 1 of B

6

4

3

0

2

1 therefore

C n = 6 X 4 + 3 x 0 + 2 X 1 = 26

To find C p we visualize

Row 1 of A 6 Column 2 of B 2 - 2 '

thus

C12 = 6 X 2 + 3 X 3 + 2 X ( - 2 ) = 17

For C 2 \ we have

Row 2 of A Column 1 of B

1

4

4

0

6

1

Trang 8

and

C 2 \ = 1 X 4 + 4 X 0 + 6 X 1 = 10

Finally, for C 2 2 we have

Row 2 of A 1

from which

C 22 = 1 X 2 + 4 X 3 + 6 X ( - 2 ) = 2

It follows that

AB = 26 17

In general, matrix multiplication is not commutative, that is,

AB & BA As an example, consider the product BA for the matrices in

Eqs A.38 and A.39 The matrix generated by this multiplication is of order

3 X 3 , and each term in the resulting matrix requires adding two products Therefore if D = BA, we have

D =

26

3

4

20

12

- 5

20

18

- 1 0

(A.41)

Obviously, C =£ D We leave you to verify the elements in Eq A.41 Matrix multiplication is associative and distributive Thus

and

A(B + C) = AB + AC,

(A + B)C = AC + BC

(A.43)

(A.44)

In Eqs A.42, A.43, and A.44, we assume that the matrices are conformable for addition and multiplication

We have already noted that matrix multiplication is not commutative There are two other properties of multiplication in scalar algebra that do not carry over to matrix algebra

First, the matrix product AB = 0 does not imply either A = 0 or

B = 0 (Note: A matrix is equal to zero when all its elements are zero.) For

example, if

A = 1 0

2 0 and B =

'0 0'

4 8 then

AB "0 0

0 0

Trang 9

Hence the product is zero, but neither A nor B is zero

Second, the matrix equation AB = AC does not imply B = C For example, if

2 0_ B = U 8 V, , and C =

"3 4 .5 6

then

6 8 b u t B 56 C

The transpose of a matrix is formed by interchanging the rows and

columns For example, if

A =

1 2 3

4 5 6

7 8 9

, then Ar =

1 4 7

2 5 8

3 6 9

The transpose of the sum of two matrices is equal to the sum of the transposes, that is,

T _ A T

The transpose of the product of two matrices is equal to the product

of the transposes taken in reverse order In other words,

Equation A.46 can be extended to a product of any number of matri-ces For example,

T _ nTr-TttTAT

can be symmetric

A.8 Identity, Adjoint, and

Inverse Matrices

An identity matrix is a square matrix where a(/ = 0 for i <£ y, and a i} = 1

for i = j In other words, all the elements in an identity matrix are zero

except those along the main diagonal, where they are equal to l.Thus

and

1

0

0'

1,

1

0

0

0

1

0

0

0

1

1

0

0

0

0

1

0

0

0

0

1

0

0~

0

0 1_

Trang 10

are all identity matrices Note that identity matrices are always square We will use the symbol U for an identity matrix

The adjoint of a matrix A of order n X n is defined as

where A,y is the cofactor of % (See Section A.5 for the definition of a cofactor.) It follows from Eq A.48 that one can think of finding the adjoint of a square matrix as a two-step process First construct a matrix made up of the cofactors of A, and then transpose the matrix of cofactors

As an example we will find the adjoint of the 3 x 3 matrix

1

3

1

2

2

1

3

1

5 The cofactors of the elements in A are

A „ = 1 ( 1 0 - 1) = 9,

A]3 = 1(3 + 2) = 5,

A21 = -1(10 - 3) = - 7 ,

A22 = 1(5 + 3) = 8,

A23 = -1(1 +2) = - 3 ,

A31 = 1(2 - 6) = - 4 ,

A32 = -1(1 - 9) = 8,

A33 = 1(2 - 6) = - 4

The matrix of cofactors is

B

9

- 7

- 4

- 1 6

S

8

5

- 3

- 4

It follows that the adjoint of A is

9

- 1 6

5

- 7

8

- 3

- 4

8

- 4

One can check the arithmetic of finding the adjoint of a matrix by using the theorem

Equation A.49 tells us that the adjoint of A times A equals the determi-nant of A times the identity matrix, or for our example

det A = 1(9) + 3(-7) - 1(-4) = - 8

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