Electrical Electronic Circuits (Lab).Pdf

Exercise 2: Given the following circuit, students rearrange the circuit to clarify its serial and/or parallel topology.. Then, apply the knowledge you’ve learned to find the equivalent r

ELECTRICAL ELECTRONIC CIRCUITS (lab)

According to the Kirchhoff’s Voltage Law

We have the first equation

4i+2vạ~4—vạ—12=0 (1) According to the Ohm’s law

We have the second equation:

Vo=—Gi (2) From (1) and (2) we have:

B Simulation:

Exercise 2:

Given the following circuit, students rearrange the circuit to clarify its serial and/or parallel topology Then, apply the knowledge you’ve learned to find the equivalent resistance value between two circuit terminals A and F Finally, perform the simulation to check if the current through the whole circuit is correctly calculated

Between the nodes C and D have two branches

The first branch has the resistor R,with 40

The second branch has three serial resistors R,, R, and R., so this branch has the total of resistance value is:

Ry =R,t+Ryt R= 4+54+3=120

= (Re x Ras)

Oe Rot Rus (4+12) The resistor R;1s serial with Rep:

R, =R,+R„y=3+3=69

Has the resistor R; is parallel to R,,,

R,xR Rex 7 2a) _6%6

Result:

Rep =32 Ryp=3Q R,p=6Q

Exercise 3:

Given the following circuit, students rearrange the circuit to clarify its serial and/or parallel topology Next, apply the knowledge you’ve learned to find the equivalent resistance value between two circuit terminals A and F, the voltage values at A, B, C, D, and E Finally, perform the simulation to check your calculation

Between the nodes D and E have two branches

The first one has two serial resistors R, and R;:

And the resistor R6 1s parallel to this branch:

The resistance value of:

The resistor ; is serial with Rcz:

Ry =R,+R(y=2+4=6k@

And the resistor Ri is parallel to R,, :

The resistance value of:

The resistor R, is serial with R pp:

R, =R,+Rgp=9+3=12kQ And the resistor R8 is parallel to R7BE:

The resistance value of:

U,=9V U„„=U,=U¿=12—-9=3V=V,

U, 3 -3

=~=~=05.10°A

= RGR 0.5.10 1,;=1,-1,=1.10 °-0.5.10 °=0.5.10° A

V ,=U4=13*14=0.5.10 °x3k=1.5V

B Simulation

Rt

12Vdc

The selected resistor: E12, tolerance 10%, standard series 1Q

c Using the resistor selected in (b), determine the voltage across the 3.9k resistor The value of V; according to the selected resistor R:

Exercise 6;

Given the following circuit Apply the knowledge you’ve learned to transform it into another form in which you can find total equivalent resistance R,, more easily Next, find the value of the current 1 through the circuit and perform a simulation to check it out

through the circuit

Ry=R,+R,=30[Q)

R„=R,+R,=20 |Ø,

Ray Rs, _ 30 x20

¬ _ =12(Q

Rous R;+R¿ 30+20 |

Ryg=R,+ Ret Roys = 13+15+12 =40 [Ø)

Then, using the Ohm’s law, we can easily calculate the current:

Exercise 7:

Given the following circuit Apply the knowledge you’ ve learned to transform it into another form in which you can find total equivalent resistance more easily Next, find the value of the current IS through the circuit and perform a simulation to check it out

Figure 1.24: Transform the circuit, then find the equivalent resistance and the current IS

through the circuit

R _ Ri Ry _ 36% 18

4 R,+R, 36+18 =12(kQ)

R,.R

= 3 š_12x9_ 36 (rø) R,+R, 12+9 7

120 Ryys= Rog t+ Ryg= — kQ) J

Exercise 8:

Given the following circuit with p2, p3, and p4 are absorbing powers of unknown electrical elements First, use the knowledge you’ ve learned to identify whether they are active or passive elements (supplying or absorbing power) To an element absorbing power, use a pure resistor with a proper value as a representative To a power element, use an ideal DC voltage source with the corresponding value as a representative Next, redraw the circuit and calculate the power that each element absorbs Note that here we use the passive sign convention Then, perform a simulation with the elements

determined by the previous step

=> So this is Power supplied element

Therefore, the power of P2, Ps, Ps respectively are 100W, 280W, -32W

B Simulation:

Exercise 9:

Given the following circuit Find the voltage v and the current 1x According to the result, determine the elements whose absorbing power respectively pl and p2 are active or passive (calculations are required) Note that here we use the passive sign convention If an element consumes power, use a pure resistor with an appropriate value as a representative [fit is a power supply element, use a corresponding ideal

DC voltage source to represent it Perform a simulation to check how the circuit works

0 volt

Figure 1.26: Find the unknown elements and variables, then check them out by

simulation

A Calculation:

According to the: KVL Laws:

We have first loop from the left circuit:

—10+V+4=0 =V=6(V)

Checking the second loop from the right circuit:

—4+16+3i,=0©=i,=4(A) Therefore, the result for V=6(V)_andi,=4(A)},

Let’s calculate the p:

The recipe of energy p is p=V <I

So that, from the circuit, we can see:

p=4V *i,=4*|—4]=—16(W)

= Itis the element that consumes power

#Calculating the Liz:

At the branch AB, we have the resistor 12 Ohm and v=6V:

6

#Calculating the Inc:

= ltis the element that supply power

#Calculating the Ucn;

Exercise 10:

Given the following circuit Find the voltage V You can do this in any way but remember

to explain it in detail Then simulate the circuit to check the result

30 Q

WW R7

From this circuit, we calculate the 8, ,R,, R.:

At the wire BE, R.7 connect to Ry and this connection is parallel with Rb:

= Rapeg= Rat Rog 4 12= 86 6

3 And for calculating the parallel:

=ÑR — Rages x Ry 3870 a7c4b Razeat Ry 221

After the calculation, we will only have this circuit:

So that, we have the total of Rica: