Solving singular second-order initial/boundary value problems in reproducing kernel Hilbert space Boundary Value Problems 2012, 2012:3 doi:10.1186/1687-2770-2012-3 Er Gao gao.nudter@gmai
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Solving singular second-order initial/boundary value problems in reproducing
kernel Hilbert space
Boundary Value Problems 2012, 2012:3 doi:10.1186/1687-2770-2012-3
Er Gao (gao.nudter@gmail.com)Songhe Song (shsong31@gmail.com)Xinjian Zhang (xjz_20075@163.com)
ISSN 1687-2770
Article type Research
Submission date 13 January 2011
Acceptance date 16 January 2012
Publication date 16 January 2012
Article URL http://www.boundaryvalueproblems.com/content/2012/1/3
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Trang 2Solving singular second-order initial/boundary value problems in
reproducing kernel Hilbert space
Er Gao*, Songhe Song** and Xinjian Zhang***
Department of Mathematics and Systems Science, College of Science,National University of Defense Technology, Changsha 410073, China
sin-Mathematics Subject Classification (2000) 35A24, 46E20, 47B32
Trang 31 Introduction
Initial and boundary value problems of ordinary differential equationsplay an important role in many fields Various applications of boundary tophysical, biological, chemical, and other branches of applied mathematicsare well documented in the literature The main idea of this paper is topresent a new algorithm for computing the solutions of singular second-orderinitial/boundary value problems (IBVPs) of the form:
the problems are anti-periodic BVPs
Trang 4Such problems have been investigated in many researches Specially, theexistence and uniqueness of the solution of (1.1) have been discussed in [1–5].And in recent years, there are also a large number of special-purpose methodsare proposed to provide accurate numerical solutions of the special form of(1.1), such as collocation methods [6], finite-element methods [7], Galerkin-wavelet methods [8], variational iteration method [9], spectral methods [10],finite difference methods [11], etc.
On the other hands, reproducing kernel theory has important tions in numerical analysis, differential equation, probability and statistics,machine learning and precessing image Recently, using the reproducing ker-nel method, Cui and Geng [12, 13, 14, 15, 16] have make much effort to solvesome special boundary value problems
applica-According to our method, which is presented in this paper, some ducing kernel Hilbert spaces have been presented in the first step And in thesecond step, the homogeneous IBVPs is deal with in the RKHS Finally, oneanalytic approximation of the solutions of the second-order BVPs is given byreproducing kernel method under the assumption that the solution to (1.1)
Trang 5contin-uous real valued functions, 𝑢′ ∈ 𝐿2[0, 1]} The inner product in 𝑊1
2[0, 1] isgiven by
and the norm∥𝑢∥𝑊1 is denoted by ∥𝑢∥𝑊1 = √(𝑢, 𝑢)𝑊1 From [17][18],
𝑊21[0, 1] is a reproducing kernel Hilbert space and the reproducing kernelis
Trang 6and its corresponding reproducing kernel 𝐾2(𝑡, 𝑠).
2.3 The RKHS 𝐻23[0, 1]
Inner space 𝐻3
2[0, 1] is defined as 𝐻3
2[0, 1] = {𝑢(𝑥)∣𝑢, 𝑢′, 𝑢′′ are absolutelycontinuous real valued functions, 𝑢′′′ ∈ 𝐿2[0, 1], and 𝑎1𝑢(0)+𝑏1𝑢′(0)+𝑐1𝑢(1) =
0, 𝑎2𝑢(1) + 𝑏2𝑢′(1) + 𝑐2𝑢′(0) = 0}
It is clear that 𝐻23[0, 1] is the complete subspace of 𝑊23[0, 1], so 𝐻23[0, 1] is
a RKHS If 𝑃 , which is the orthogonal projection from 𝑊3
Trang 7The proof of the Theorem 2.1 is complete.
Now, 𝐻23[0, 1] is a RKHS if endowed the inner product with the innerproduct below
Trang 83 The reproducing kernel method
In this section, the representation of analytical solution of (1.1) is given
in the reproducing kernel space 𝐻23[0, 1]
Note 𝐿𝑢 = 𝑝(𝑥)𝑢′′(𝑥) + 𝑞(𝑥)𝑢′(𝑥) + 𝑟(𝑥)𝑢(𝑥) in (1.1) It is clear that
𝐿 : 𝐻23[0, 1] → 𝑊21[0, 1] is a bounded linear operator
Put 𝜑𝑖(𝑥) = 𝐾1(𝑥𝑖, 𝑥), Ψ𝑖(𝑥) = 𝐿∗𝜑𝑖(𝑥), where 𝐿∗ is the adjoint operator
2[0, 1]
The orthogonal system {Ψ𝑖(𝑥)}∞𝑖=1 of 𝐻3
2[0, 1] can be derived from Gram–Schmidt orthogonalization process of {Ψ𝑖(𝑥)}∞𝑖=1, and
Trang 9Proof From Lemma 3.1, {Ψ𝑖(𝑥)}∞𝑖=1is the complete system of 𝐻3
The approximate solution of the (1.1) is
If (1.1) is linear, that is 𝐹 (𝑥, 𝑢(𝑥)) = 𝐹 (𝑥), then the approximate solution
of (1.1) can be obtained directly from (3.3) Else, the approximate processcould be modified into the following form:
Next, the convergence of 𝑢𝑛(𝑥) will be proved
Lemma 3.2 There exists a constant 𝑀 , satisfied ∣𝑢(𝑥)∣ ≤ 𝑀 ∥𝑢∥𝐻3, for all𝑢(𝑥) ∈ 𝐻23[0, 1]
Proof For all 𝑥 ∈ [0, 1] and 𝑢 ∈ 𝐻23[0, 1], there are
∣𝑢(𝑥)∣ = ∣(𝑢(⋅), 𝐾3(⋅, 𝑥))∣ ≤ ∥𝐾3(⋅, 𝑥)∥𝐻3 ⋅ ∥𝑢∥𝐻3
Trang 10Since 𝐾3(⋅, 𝑥) ∈ 𝐻3
2[0, 1], note
𝑀 = max
𝑥∈[0,1]∥𝐾3(⋅, 𝑥)∥𝐻3.That is, ∣𝑢(𝑥)∣ ≤ 𝑀 ∥𝑢∥𝐻3
By Lemma 3.2, it is easy to obtain the following lemma
Lemma 3.3 If 𝑢𝑛 −→ ¯∥⋅∥ 𝑢(𝑛 → ∞), ∥𝑢𝑛∥ is bounded, 𝑥𝑛 → 𝑦(𝑛 → ∞) and
𝐹 (𝑥, 𝑢(𝑥)) is continuous, then 𝐹 (𝑥𝑛, 𝑢𝑛−1(𝑥𝑛)) → 𝐹 (𝑦, ¯𝑢(𝑦))
Theorem 3.2 Suppose that ∥𝑢𝑛∥ is bounded in (3.3) and (1.1) has a uniquesolution If {𝑥𝑖}∞
𝑖=1 is dense on [0, 1], then the 𝑛-term approximate solution
𝑢𝑛(𝑥) derived from the above method converges to the analytical solution 𝑢(𝑥)
of (1.1)
Proof First, we will prove the convergence of 𝑢𝑛(𝑥)
From (3.4), we infer that
∥𝑢𝑛∥ is convergent and there exists a constant ℓ such that
Trang 11In view of (𝑢𝑚− 𝑢𝑚−1) ⊥ (𝑢𝑚−1− 𝑢𝑚−2) ⊥ ⋅ ⋅ ⋅ ⊥ (𝑢𝑛+1− 𝑢𝑛), it follows that
Secondly, we will prove that ¯𝑢 is the solution of (1.1)
Taking limits in (3.2), we get
¯𝑢(𝑥) =
Trang 12Moreover, it is easy to see by induction that
(𝐿¯𝑢)(𝑥𝑗) = 𝐹 (𝑥𝑗, 𝑢𝑗−1(𝑥𝑗)), 𝑗 = 1, 2, (3.6)Since {𝑥𝑖}∞
𝑖=1 is dense on [0, 1], for all 𝑌 ∈ [0, 1], there exists a subsequence{𝑥𝑛𝑗}∞
That is, ¯𝑢 is the solution of (1.1)
The proof is complete
In fact, 𝑢𝑛(𝑥) is just the orthogonal projection of exact solution ¯𝑢(𝑥) ontothe space Span{Ψ𝑖}𝑛
𝑖=1
4 Numerical example
In this section, some examples are studied to demonstrate the validityand applicability of the present method We compute them and compare theresults with the exact solution of each example
Example 4.1 Consider the following IBVPs:
𝑢(1) + 𝑢′(1) + 𝑢′(0) = 0,
Trang 13where 𝑓 (𝑥) = 10𝑥𝑒10(𝑥−𝑥 ) + 40𝑒10(𝑥−𝑥 ) (1−2𝑥)(𝑥−𝑥 )+ 𝑥2(1 − 𝑥)(𝑒20(𝑥−𝑥 ) +20𝑒10(𝑥−𝑥2)2(1 − 2𝑥)2− 40𝑒10(𝑥−𝑥 2 ) 2
(𝑥 − 𝑥2) + 400𝑒10(𝑥−𝑥2)2(1 − 2𝑥)2(𝑥 − 𝑥2)2).The exact solution is 𝑢(𝑥) = 𝑒10(𝑥−𝑥 2 ) 2
− 1 Using our method, take 𝑎3 =
1, 𝑏3 = 𝑐3 = 0 and 𝑛 = 21, 51, 𝑁 = 5, 𝑥𝑖 = 𝑛−1𝑖−1 The numerical results aregiven in Tables 1 and 2
Example 4.2 Consider the following IBVPs:
1, 2, 3 and 4
Contributions
Er Gao gives the main idea and proves the most of the theorems andpropositions in the paper He also takes part in the work of numerical exper-iment of the main results Xinjian Zhang suggests some ideas for the prove
of the main theorems Songhe Song mainly accomplishes most part of thenumerical experiments All authors read and approved the final manuscript
Competing interests
The authors declare that they have no competing interests
Trang 14The work is supported by NSF of China under Grant Numbers 10971226
The reproducing kernel of 𝐻3
Trang 16Λ7 = (6𝑎22(𝑎1𝑠(−2𝑐3+ 𝑏3𝑠) + 𝑏1(2𝑐3− 𝑎3𝑠2)) + 3𝑎2(2𝑐1𝑐2(−2𝑐3+ 𝑎3𝑠2)+ 𝑏2(−𝑏3𝑐1+ 20𝑏1𝑐3 + 6𝑐1𝑐3+ 𝑎3𝑐1𝑠 − 20𝑎1𝑐3𝑠 − 10𝑐1𝑐3𝑠 − 10𝑎3𝑏1𝑠2+ 10𝑎1𝑏3𝑠2− 3𝑎3𝑐1𝑠2+ 5𝑏3𝑐1𝑠2)) + 5𝑏2(3𝑐1𝑐2(−2𝑐3+ 𝑎3𝑠2)
+ 𝑏2(−2𝑏3𝑐1+ 16𝑏1𝑐3+ 10𝑐1𝑐3+ 2𝑎3𝑐1𝑠 − 16𝑎1𝑐3𝑠 − 16𝑐1𝑐3𝑠 − 8𝑎3𝑏1𝑠2+ 8𝑎1𝑏3𝑠2− 5𝑎3𝑐1𝑠2+ 8𝑏3𝑐1𝑠2)))(2𝑏1𝑐3+ 2𝑐1𝑐3+ 𝑎3𝑐1𝑡 − 2𝑎1𝑐3𝑡
− 2𝑐1𝑐3𝑡 − 𝑎3𝑏1𝑡2 − 𝑎3𝑐1𝑡2+ 𝑏3(𝑎1𝑡2+ 𝑐1(−1 + 𝑡2)))
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Trang 19Figure 4
The relative error of Example 4.2 (𝑛 = 51, 𝑁 = 5)
Tables
Table 1
Numerical results for Example 4.1 (𝑛 = 21, 𝑁 = 5)
Trang 20𝑥 True solution 𝑢(𝑥) Approximate solution 𝑢 11 Absolute error Relative error
Trang 210.0020
0.0025
Trang 220.0015
0.0020
0.0025
Trang 240.2 0.4 0.6 0.8 1.0 0.0003
0.0004
0.0005