At the end of the lec ture You should be able to ~Understand the behaviour of beams with openings under bending and shear «Design the opening using Mechanism Approach, Plasticity T
Trang 1National University of Smgapore
Trang 2In this lec ture
Trang 3
At the end of the lec ture
You should be able to
~Understand the behaviour of beams
with openings under bending and
shear
«Design the opening using Mechanism
Approach, Plasticity Truss Method or
«»Detail the reinforcement to satisfy serviceability and ultimate limit statess, nus
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CONCRETE BEAMS
Trang 5Ad d1t1o na Ì re Íe renc es
+» Mansur, M.A., Tan, K.H and Lee, S.L., "A Design
Method for Reinforced Concrete Beams with Large Openings", Journal of the American Concrete Institute, Proceedings, Vol 82, No 4, USA,
July/August 1985, pp 517-524
+ Tan, K.H and Mansur, M.A., "Design Procedure for
Reinforced Concrete Beams with Web Openings’,
ACI Structural Journal, Vol 93, No 4, USA, July-
August 1996, pp 404-411
« Mansur, M.A., Huang, L.M., Tan, K.H and Lee, S.L.,
"Analysis and Design of R/C Beams with Large Web Openings", Journal of the Institution of
Engineers, Singapore, Vol 31, No 4, July/August
1991, pp 59-67
© Tan KH, NUS
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© Tan KH
NUS
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© Tan KH
NUS
Trang 11Note: All dimensions are in mm
Trang 24Apoliod Shear, V (xy)
—e— tom measured sirains
—— assuming compression chord
cumes total applied shea
chords
© Tan KH
NUS
Trang 26- opening depth < D/2
© Tan KH
NUS
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principal tensile stress direction
stress concentration congestion of reinforcement
© Tan KH
NUS
Trang 29Allowoble wWmax for interior
Trang 30— 2 general approaches:
mechanism approach
truss model approach
® applied loads are transferred across opening to supports by a truss system
> lower bound approaches
© Tan KH
NUS
Trang 323 Determine N,, in chord members
and hinge moments (M,) from
and (M,,) are related to N,, by the
respective M-N interaction diagrams
© Tan KH
NUS
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(MyÌt,‡ (Modest (Mle ¢ (My)y,3
*/h (a] Interaction diagram (b) Interaction diagram ic) Graph of WyÝ, M
Trang 344 Calculate V in chord members
Trang 36A simply supported reinforced concrete beam,
300 mm wide and 600 mm deep, contains a rectangular opening and is subjected to a
Trang 37Assume point of contraflexure at midpoint
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© Tan KH
NUS
Trang 43be cot >, I kK £,— [“— di, COt >,
(a) Arrangement of diagonal reinforcement
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General Principles
Idealize structure as comprising
concrete struts and reinforcement ties,
joined at nodes
- deformation capacity of concrete
- angle between struts and ties
© Tan KH
NUS
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© Tan KH (c) Shear force diagram (kN)
NUS
Trang 49Top chord takes 91% of total shear
Stirrup force = 3.3 times shear
(Model may be simplified.)
Trang 50
Bot steel: 590 mm“ (2T20)
© Tan KH
NUS
Trang 53CAIC ULATION OF DEFLEC TIONS
Trang 54|, based on a fully cracked section)
of one end of opening lổ„=2ð = =
w.r.t the other end 12 E.( Ïị + ly)
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Calculate the midspan service load deflection of the
beam described in the Example
SOLUTION service load, P, = P,,/ 1.7 = 52.8/ 1.7 = 31.1 KN;
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Midspan deflection, 6,,, of the beam is 11 PL5/144E°I,
where /can be conservatively estimated as the moment of inertia of the beam at a section through
the opening That is,
Trang 57Corner reinft.: | Rigorous:
Mechanism |e factor of 2 e N, M from
~ 25-50% diagram
e diagonal bars |¢ V
~ 50-75% Simplified:
e pt of contra- flexure at midspan
® Vv/Vb = k/lb
- e check Vu
Plasticity truss against Veruss
method (AM) ® Asn, Ast
(eg fy/2) e check stress
at each opening