SOLIDWORKS bài tập vẽ 2D 3D

tổng hợp những bài vẽ 2D 3D solidworks cơ bản tới nâng cao giúp khả năng vẽ , thiết kế nâng cao hơntổng hợp những bài vẽ 2D 3D solidworks cơ bản tới nâng cao giúp khả năng vẽ , thiết kế nâng cao hơn

Alhamdulillah, Forever thankful to Prophet Muhammad (Sallallahu ^Alayhi Wa Sallam)

and Almighty Allah

Shaik.ameer.shameer

SolidWorks Exercises For Beginners

ACKNOWLEDGEMENTS:

My heartfelt thanks to all the talented and hardworking professional people who gave

their best effort for this book Special thanks to

• Stefen for motivating us to produce this book

• Alissa for editing and offering suggestions to this book

• Lohith for making sure diagrams are good and workable

• To all the working people for making this world a better place

• To my family mom, dad, wife (Afsana), daughter (Aliza), my brother Akbar and

Nasir and my friends for making me the best person i am today

Who should take this book?

This book is for any one (CAD beginners, 3D printing hobbyist, Engineers)

who want to learn/master the use of mechanical or aeronautical CAD software through

practice Even though this book has no instructions on “how to use command’s” , you

should see this book as a “practice manual for designers” who wants to take CAD

learning from beginning to advanced level by practicing the diagrams given in this book

How is this book designed?

Every chapter has command based and real-life industrial problems.

• Command based problems are designed to make sure you are learning and

using all the commands

• Real life problems are designed to make sure you don’t get problems when you

are in industry/office taking up real tasks

Problems are designed according to the difficulty level, so every command

based and real-life industrial problems will go through simple problems first then through

difficult problems Using this approach students will have a proper understanding of how

problems work I strongly urge you to solve simple problems completely instead of

directly going to tough problems so you can learn the basics first.

Refer below DIAGRAM: 1 to get a better understanding of this book design.

DIAGRAM: 1

CHAPTER

SIMPLE PROBLEMS TO DIFFICULT PROBLEMS

SIMPLE PROBLEMS TO DIFFICULT PROBLEMS

2) REAL LIFE INDUSTRIAL

PROBLEMS

1) COMMAND BASED

PROBLEMS

Copyright © SHAIK.AMEER.SHAMEER.

All rights reserved No part of this publication may be reproduced,

distributed, or transmitted in any form or by any means, including

photocopying, recording, or other electronic or mechanical methods, without

the prior written permission of the publisher, except in the case of brief

quotations embodied in critical reviews and certain other noncommercial uses

permitted by copyright law.

There are few part of the book which are taken from few websites and they

are modified to present them properly and for better understand The

information presented in this book belongs to their respective owners In no

circumstance we encourage others to steal the authority of the respective

owners.

TABLE OF CONTENTS:

⦁ UNIT 1: 2D-Modelling

⦁ COMMAND BASED MODELS

CHAPTER 1: Level - Easy Models: .07

CHAPTER 2: Level - Better Models: .09

CHAPTER 3: Level - Medium Models: .10

CHAPTER 4: Level - Hard Models: .11

CHAPTER 5: Level - Puzzles and Minimal Dimension: .14

⦁ INDUSTRIAL MODELS CHAPTER 6: Level - Mechanical Models: .17

CHAPTER 7: Level - Aeronautical Models: .27

⦁ UNIT 2: 3D-Modelling ⦁ COMMAND BASED MODELS: CHAPTER 8: Level - Easy Models: .38

CHAPTER 9: Level - Better Models: .41

CHAPTER 10: Level - Medium Models: 45

CHAPTER 11: Level - Hard Models: .48

⦁ INDUSTRIAL MODELS CHAPTER 12: Level - Industrial Models: 51

⦁ UNIT 3: Assembly ⦁ CHAPTER 13: Level - Piston Assembly: .85

⦁ CHAPTER 14: Level - Caster Assembly: .94

⦁ CHAPTER 15: Level - Crane Hook Assembly: .99

⦁ CHAPTER 16: Level - Butterfly valve Assembly: .104

⦁ UNIT 4: Sheet Metal Design CHAPTER 17: Level - Industrial Models: .109

"After solving all the given problems in this book, i can assure any student to solve the industrial drafting problems with easy or with little effort" shaik.ameer.shameer(author)

Any feedback can be sent to "shameer6691@gmail.com" with subject

"improvement"

UNIT 1: 2D-MODELLING.

⦁ COMMAND BASED MODELS:

CHAPTER 1: Level - Easy Models

CHAPTER 2: Level - Better Models

CHAPTER 3: Level - Medium Models

CHAPTER 4: Level - Hard Models

CHAPTER 5: Level - Puzzles and Minimal Dimension

⦁ INDUSTRIAL MODELS

CHAPTER 6: Level - Mechanical Models

CHAPTER 7: Level - Aeronautical Models

NOTE:

⦁ This unit 2d models are designed according to the difficulty level

⦁ First you will solve simple models and then proceed to complex

models

⦁ Hidden lines are shown only when necessary so as to avoid the

printing ink problem (with too many lines)

⦁ Initially model dimensions are given in isometric 3d view and then

dimensions are given in 2d views (industrial standard)

⦁ Number of problems in chapter increases as the difficulty level

increases

CHAPTER-1: EASY MODEL'S

COMMANDS USED : LINE, INCLINED LINE.

20 30

10

60 15

10

4) 3)

CHAPTER 2 COMMANDS PLUS

MIRROR, ROTATE PATTERN, RECTANGLE PATTERN

6) 5)

NOTE: 18 TEETHS ARE EQUALLY SPACED

SYMMETRY LINE

T

T T

T

T T

T

T T

T

Commands Used:

Chapter 03 Plus Tangency Concept (T).

symbol T- stands for tangency between two curves Any complex smooth curve can

be made using two or more curves 99% cases complex curves are formed by

connecting two or more curves by tangency nature.

NOTE: symbol T is given only for better

understanding In later chapter's no symbol

will be given.

R15

R12

R8 R5

T T

T T T

T T

T

TRI-TANGENT ARC

T

T T

T

T T

T T

13)

T T

14)

line and ortho mode used

all lines are of 1 unit

1.00

47°

center radius center diameter or two point circle quadrant & intersection point used

sweep angle of 38 degree

arc center at midpoint of line

center star angle arc

R0.50

tan tan radius

· inscribed(A) and circumscribed(B) polygon of 5 sides with center on

circle center and radius 0.5 ( all three objects )

point on circumscribed polygon

center, start, end arc

line of 1 unit length line of 0.15 unit

center ellipse with

center on line center and end point on line end points

axis end ellipse

with ends on line center and end point

45°

20°

1.50 0.50

elliptical arc with major radius of

1.50 and minor radius of 0.50

C D

A B C

35°

1.25

0.75

Rectangle copy rotated through

35 degree from initial position

0.90 0.90

scale factor of 1.5 with reference to original

scale factor of 0.5 with reference to original

Rectangle and Scale command used

Line and offset command used

Rectangle and Rectangular array used

R2 R3 R4 R5

1.50

0.80

R0.15 0.35

Circle, Poly line , Path array used with a gap of 0.35 in between objects

0.31 R0.15

0.05

R0.80

rotate items option

enabled in polar array

rotate items option Disabled in polar array

rotate items option Disabled in polar array

End point of R35 is at dim 11

INDUSTRIAL AND REAL LIFE MODELS

POINT A.

connecting r60 and r53

NOTE: tangency symbol T is

not given in any of the industrial

problems This is how models are

presented in industry and we want to

make sure students have the industry

150

30

40

R25 R30

R15

R58 R40

06) Cam Shaft Pulley

TOTAL NO OF TEETHS = 40

R57

All of them have same dimension

All fillet radius of 5units

R45 R38

Chapter 7

Aeronautical Models

80 R5

117°

28 12

8 12 3.5

12°

R40 R37

R20

R15

7 R6

16.5 7.3

15

R18 R15 3

13.5 3.75

29.69 16.22

23.23 22.94

This arc is TANGENT to line A,B horizontal line

at height of 205 (Line C)

C

UNIT 2: 3D MODELLING.

⦁ COMMAND BASED MODELS:

CHAPTER 8: Level - Easy Models

CHAPTER 9: Level - Better Models

CHAPTER 10: Level - Medium Models

CHAPTER 11: Level - Hard Models

⦁ INDUSTRIAL MODELS

CHAPTER 12: Level - Industry Models

NOTE:

⦁ These unit 3d models are designed according to the difficulty level

⦁ First, you will solve simple models and then proceed to complex models

⦁ Hidden lines are shown only when necessary so as to avoid the printing

ink problem (with too many lines)

⦁ Initially, model dimensions are given in isometric 3d view and then

dimensions are given in 2d views (industrial standard)

CHAPTER 8 : Easy 3D Models

commands used : Pad and Pocket

Dimensions provided in easy isometric view

4)

R27.50 R17.50 R5 R12

10)

Chapter 09 : Better models

commands used : shaft and groove.

· dimensions are given only on 2d view and isometric view is only for helping students decode 2d views.what is Third angle projection?

The third angle projection is a method of orthographic projection and this is a technique inportraying a 3D design using a series of 2D views and in the third angle projection object isplaced in the third quadrant and between the observer and the object, projection plane lies

How views are presented in Third angle projection?

Isometric view

Important points to note in Third angle projection

· Over the front view top view comes

· Under the top view front view always comes

· To the right of the front view right side view always come

· To the left of the front view left side view always comes

· To the side of the observer the view is always formed

· To the object and observer the view is always in the middle

Third angle projection symbol:

Third Angle

Note : This symbol can be found

in any part of the page

This book uses Third angle projection to solve problems.

50

G G

T

T

60

20 R10

chapter 10 : Medium Models

Commands Used - Mirror, Shell and Rib.

Chapter 11: Hard Models

Commands Used - Fillet, Chamfer, Linear and Circular Pattern

Dimension style : Dimension given in 2d view and isometric view for refrence.

1)

2)

50

150 R20 30

Part 2 : DEFAULT HOLDER

Part 3 : LOCKING MECHANISM

TOP VIEW

ISOMETRIC VIEW

TAKE 36.24 DEGREE AS REFRENCE AND CONSTRUCT A

SPIRAL OF "R15" HEIGHT 103.49 AND 6 TURN WITH

EQUAL HEIGHT DRAW A CIRCLE OF R3 AND USE SPIRAL

AS GUIDE TO CONSTRUCT A SPRING.

Part 6 : HOUSING

TOP VIEW

ISOMETRIC VIEW

9.71

DETAIL E SCALE 2 : 1.5

Part 8 :

TOP VIEW

ISOMETRIC VIEW

Part 9 : CUTTING BLADE

TOP VIEW

ISOMETRIC VIEW

26 teeths in total span around 360 degree.

intersecting point of r67.5 arc

and angle 60 line.

Part 10 : Modular wheel set

TOP VIEW

ISOMETRIC VIEW

Part 11 : Monster Clutch Mechanism

ISOMETRIC VIEW

TOP VIEW

Part 13 :

FRONT VIEW

TOP VIEW

ISOMETRIC VIEW

Part 14 : Parking Tripod

ISOMETRIC VIEW

TOP VIEW

R3.50 5

12

DETAIL B SCALE 1 : 1

25 34 3 25 34

7 SECTION E-E

Part 16 : Gear box cover

TOP VIEW

Part 17 : Gear shaft

ISOMETRIC VIEW

SET OF 18 TOOTH

20 R2

Part 18 : CLUTCH COVER

TOP VIEW

ISOMETRIC VIEW

C C

Part 19 : ENGINE V BLOCK

FRONT VIEW TOP VIEW

ISOMETRIC VIEW

28

SECTION C-C SCALE 1 : 2

Part 20 :

TOP VIEW

ISOMETRIC VIEW

G G

100

11

SECTION G-G SCALE 1 : 1.2

R22.50 R50

Part 22 :OIL PAN TOP CASING

TOP VIEW

ISOMETRIC VIEW

IN NEXT PAGE.

ISOMETRIC VIEW

C C

IS IN NEXT PAGE

2) draw a rectangle (12x21) on the plane

as shown in figure and cut it to 27.50 units.

ISOMETRIC VIEW (normal view)

ISOMETRIC VIEW (back view)

mid point of guide curve.

ISOMETRIC VIEW

cut through this central axis.

Part 26 : Crank Shaft.

ISOMETRIC VIEW

same size and rotated through 90 degree.

-) A

line A-B passing through section B-B line.

Part 27 : Compressor Blade's

TOP VIEW

15 blades equal spacing

Isometric view on next page.

how to solve instruction

in next page.

(R20 and R30 are tangent to each other)

R20 tangent to length 20 line,R30

tangent to length 40 line.

1) DRAW A CIRCLE OF DIA 215 AND

PAD IT TO 10 UNITS TO CREATE A

BASE.

2) DRAW A PLANE"X" ALONG LINE "A-O-B" (PERPENDICULAR

TO ARROW MARKS SHOWN IN RIGHT HAND SIDE OF LAST PAGE.)

3) SEKTCH A PROFILE "Y" SHOWN IN DIA-(1) ON PLANE X BY MATCHING

CENTER "O" POSITION ON BOTH PLANE AND DIAGRAM.

details of center 0 is shown in last page.

CENTER "0".

DIAGRAM - 1 (PROFILE "Y")

4) PAD(thickness) THE PROFILE "Y"TO 107.5

UNITS (touching the outer end of circular

cyclinder of R107.5 drawn in step-1.)

5) DRAW THE DIA 30 CYLINDER FROM TOP OF

R107.5 CYCLINDER AND MAKE A CUT OF

DIA 25 THROUGHOUT.(dia 30 and 25 should be of

height 50)

6) DRAW THE CUTTING PROFILE (c-c-c)(refer

section B-B) PERPENDICULAR TO THE

PAD( drawn in step 4) AND CUT PAD (drawn

in step 4) NOW YOU WILL HAVE DESIRED

COMPRESSOR BLADE SHAPE.

35 31.32

UNIT 3: ASSEMBLY MODELLING.

⦁ INDUSTRIAL MODELS:

CHAPTER 13: PISTON CRANKSHAFT ASSEMBLY

CHAPTER 14: CASTER ASSEMBLY

CHAPTER 15: CRANE-HOOK ASSEMBLY

CHAPTER 16: BUTTERFLY VALVE ASSEMBLY

NOTE:

⦁ Every Assemblied view, Exploded view and Isometric view is given in the

chapter last

⦁ All Assembled views have suitable constraints between respective parts

⦁ First two Assembly explained with diagram's on how to solve

⦁ Students are advised to take last two assembly as home work and solve on

their own to improve solving ability

⦁ Hidden lines are shown only when necessary so as to avoid the printing

ink problem (with too many lines)

⦁ All the well known assembly's are given for practice

⦁ Different parts have different shading to identify parts easily

Only industrial models are given for practice ( command based models are

not given because there are very few commands to practice.)

41.5 48

34

7 R5

48

23 R2

R2 R2

CHAPTER 13): Piston-CrankShaft Assembly

part-1)

FRONT VIEW

B

Rotated isometric view Rotated isometric view

15 30.7

8.9 10.9

S S

30.7

5

21

SECTION S-S

RIGHT VIEW

71.8

1X45

7.5 4.9

1X45 1.9X45

90°

1

20°

ISOMETRIC VIEW

65

3

15.4 17.6

FRONT VIEW

10

10X 6

5 12.5

HOW TO SOLVE ANY ASSEMBLY:

1.1) Take any part and fix it in 3d space This part will act as a refrence for other parts in assembly.

1.2) There are three important constraints in any assembly

1)concentric 2)distance 3)touch.

Z Z

AXIS A

10

SECTION Z-Z

1 3

4 4

6 5

5 2

3.1) Part2 dia 21 is concentric with Part5 dia 21

STEP-3

STEP-4 & 5

4.2) Part4 dia15 outer surface and Part2 dia 15 outer surface match with surface-A.

4.1) Part 4 dia15 is concentric with Part 2 dia15

5.2) Part4 and Part2 surface are at offset

of 10 units.

5.1) Part 4 dia15 is concentric with Part 6 dia15

2X 15 1 2X 11 THRU

22

38

A A

FRONT VIEW

40 R100

ASSEMBLED VIEW

1

4 5

3 2

Axis A

22

3 5

16 1.5

3

5 4

22

4

2

surface -A

1.2) part3 dia22 is concentric

with part5 dia 22.

1.3) part3 center is coincident

with part5 center along with

axis-A.

STEP-2:

2.2) part4 surface is at offset of 1.5

units from part3 surface.

2.1) part4 dia16 is concentric

with part5 dia 16.

3.2) part4 surface and part3 surface are

coincident at surface-A.

3.1) part4 dia22 is concentric

with part2 dia 22.

STEP-3:

4.2) part1 surface and part2 surface are

4.1) part1 dia12 is concentric with part2 dia11(same with other 3 bores.)

STEP-4:

76

38 3X R18

Part - 3 RIGHT VIEW