osi network layer chapter 5 ppt

... Trang 1OSI network layerCCNA Exploration Semester 1 CCNA Exploration Semester 1 Chapter 5 Trang 2OSI network layerTCP, UDP IP Ethernet, WAN technologies ... Data stream Trang 3Network layer topicsrouted protocol Routing – sending packets the right way Trang 4Purpose of layer 3destination, then route it. Trang 5Layer 3 protocolA layer 3 protocol such ... data to the appropriate upper-layer protocol.
01 ICMP
06 TCP
17 UDP
17 UDP
UNIX: 255
Linux: 64 or 255 depending upon vendor and version
Microsoft Windows 95: 32
Microsoft Vista: 128

Ngày tải lên: 01/04/2014, 12:20

... Trang 1THE SEA WOLF JACK LONDON CHAPTER 5 But my first night in the hunters' steerage was also my last Next day Johansen, the new mate, ... to take place I set the breakfast-table in the cabin, and at seven o'clock waited on the Trang 5hunters and officers The storm had evidently broken during the night, though a huge sea was still ... more money, of becoming the mates of ships, of finding fortunes - in short, of being in a better position for preying on their fellows, of having all night in, good grub and somebody else to do

Ngày tải lên: 02/07/2014, 16:21

... of shade tolerance over b0 C: 0.53, H: 0.15 m3ha1 b 2 Exponent of H volume allometry C: 1.47, H: 1.59 m 3 ha1 e 1 Maximum ABEFaat zero height C: 5.54, H: 1.71 kg kg1 e2 Shape factor for ABEF ... (solid line) and hardwoods (dashed line) (Eq 5.4) d Whole patch mortality rate (proportion of asymptotic value) as a function of patch height (Eqs 5.5, 5.6) Trang 9American Foresters (Eyre 1980) ... ofcarbon stocks 5.5 The Spectrum of Carbon Trajectories in North American Forests successional stages (pioneer, transition, early old-growth, and late old-growth) areshown in Fig 5.5 Distributions

Ngày tải lên: 03/07/2014, 13:20

... divided by 5 (It used to be OEX divided by 10 until $OEX split 2-for-1 a couple of years ago.) As shown in Table 5.2, the cost of hedging through December 1998 (using the OLX op-tions) is 5.3% of ... exact makeup of the S&P 500 or the OEX (S&P 100) indices, then you could eas-ily compute the number of options or futures that would be re-quired to hedge your position However, no individual ... puts to hedge the GOGO stock, and $OEX historical volatility is 15% Then the adjusted volatility of GOGO stock is 4.0 (60 divided by 15) Consequently if you owned $80,000 worth of GOGO stock, you

Ngày tải lên: 03/07/2014, 19:20

... Trang 1OSI Network LayerNetwork Fundamentals – Chapter 5 Trang 2– Examine the most common Network layer protocol, Internet Protocol (IP), and its features ... 25Why Separate Hosts into Networks? – Hierarchical Addressingnetworks over internetworks, Network layer addressing schemes are hierarchical. ƒ Using hierarchical addressing means that the layer ... Network layer, or OSI Layer 3, provides services to exchange the individual pieces of data over the network between identified end devices. –Unlike the Transport layer (OSI Layer 4), which manages

Ngày tải lên: 05/07/2014, 00:20

... distribution defined by the median Hinges are similar to quartiles The Examination Marks 95.0 85.0 75.0 65.0 55.0 45.0 Trang 8difference between hinges and quartiles is that hinges are defined in termsof ... 5,000questionnaires a total of 500 were returned undelivered; 450 were returned Trang 16as refusals, with a total of 2,756 usable returns, making a response rate of61.9 per cent Table 5.7 shows the stratified ... distribution ordistributions from two or more groups FIGURE 5.1 A stem and leaf display of ESP data (source: Abelson,1995: 82) TABLE 5.2 Frequency distribution table for grouped dataInterval Midpoint

Ngày tải lên: 06/07/2014, 00:20

... replace (r m)S I 0 50 100 150 200 250 300 0 50 100 150 200 250 R S I Figure 5.6 Solutions of various forms of the SIR model (a) The basic SIR model for an epidemic (b ¼ 0.005, v ¼ 0.3; true for ... Exercise 5.4 (M/H)Conduct an eigenvalue analysis of the steady state in Eqs (5.19) Note that there will be three eigenvalues How are they to be interpreted? Exercise 5.5 (E/M)How do Eqs (5.19) change ... population that is infected, i(t)¼ I(t)/N Setting I(t) ¼ Ni(t) in 0 50 100 150 200 250 Time Figure 5.1 The solution of the SI model (Eq (5.1)) is logistic growth if bN > v and decline of the number

Ngày tải lên: 06/07/2014, 13:20

... periods (figures 5.1– 5.2): the Lower Congo (~900 Ma), the Sturtian (~750 –700 Ma), the Varangerian (~650 – 600 Ma), and the lower Sinian (~600 –540 Ma) (Hambrey and Harland 1985; Eyles 1993; Meert ... latitudes (e.g., Hambrey and Harland 1985; Schmidt 05-C1099 8/10/00 2:05 PM Page 91 Trang 3Figure 5.2 Locations of some glaciogenic deposits formed during the 1000 –540 Ma interval.Source: Modified from ... they can also occur under warm clicli-matic conditions, such as in the 05-C1099 8/10/00 2:05 PM Page 95 Trang 7Figure 5.5 Clast of boulder size in Neoproterozoic diamictite, Passo da Arciasequence

Ngày tải lên: 06/07/2014, 21:20

... model is given in the Fig. 5-3. The network operator configures his network device with network prefixes in way that reflects the topology of his network. Chapter 5 83 Fig. 5-3, ATM addressing hierarchy. ... interface between private and public ATM network (see the Fig. 5-6). ATM Basics 86 Fig. 5-4, The UNI setup process 5.3 PNNI Protocol Private Network-Network Interface (PNNI) was developed to ... ATM networks the functions of MTP 1 and MTP 2 are performed by the physical layer, ATM layer and SAAL (CP of AAL 5, SSCF, SSCOP) The specific user part pertinent to B-ICI.. .Chapter 5 As

Ngày tải lên: 05/08/2014, 19:21

... CONTENTS 5.1 Introduction5.2 Bioavailability5.3 Uptake5.3.1 Uptake from Water5.3.2 Uptake from Sediment5.3.3 Uptake from Food5.4 Fate of Xenobiotics after Uptake by Estuarine Animals5.4.1 Biotransformation ... Bioconcentration factor (BCF) = C a/C w = K U/K D (5.4) log10 BCF – 0.85 log10 P – 0.70 (5.5)where P = octanol–water partition coefficient FIGURE 5.5 Uptake of contaminants by fish from water (k1) ... cytochrome P-450 S-reduced P-450 S-oxid P-450 S-P-450 H 2 O O 2 -2eNADPH cytochrome P-450 reductase -O 2 Trang 14or other nucleophilic centers can undergo glycosylation, as shown in Figure 5.9,where

Ngày tải lên: 08/08/2014, 10:22

... process in this chapter, and to describe the specific processes in the following chapter 5.1 STAFF Setting up any production process requires at least two people in managerial positions to be ... mixers bearing in mind the adjustments required for different mixes, loads, etc Fig 5.1 Pan-type mixer. Trang 55.5 REINFORCEMENT AND HARDWAREReinforcement cages are best made on a jig This ensures ... handling hardware should be designed carefully as shown in Figs 5.3 and 5.4, and not treated as an afterthought as seen in Fig 5.5 3 Lifting cast-in devices should be integral with the reinforcement

Ngày tải lên: 08/08/2014, 10:23

... the power/energy figure 5.3 Use of these circuit parameterswith equations (5.14), (5.16) and (5.21) leads to the power waveforms and ‘energy’ surfaces as given in figure 5.5 The axis scaling has ... P e = 0.25 + 0.25 = 0.5W, which corresponds to the power P = 0.5W (supplied by the current source), as shown in figure 5.3 The reactive component sum is equal to Q L +Q e = 1.116 −0.25 = 0.866VA, ... discussed in section 2.5 The variables according to equations (5.3), (5.4) may also be written as Trang 3Figure 5.2 Phasor diagramof phasors i, u An observation of figure 5.2 learns that we can

Ngày tải lên: 09/08/2014, 06:22

... generated by p(α)= 1+ α + α3= 0are shown in Table 5.2 Table 5.2 Field elements of GF(2 3 ) forq= 7 Trang 5Suppose users i and j select X i = 2 and X j = 5, respectively Both X i and X j arekept secret, ... (mod 11)≡ 9 Trang 14y k (mod p)r x (mod p) s r x Figure 5.4 The ElGamal encryption scheme. Table 5.5 ElGamal encryption algorithm Trang 15To decipher the messagem, first compute:To sign a message ... 1 (relatively prime) The public key is described by Figure 5.5 illustrates the ElGamal signature scheme based on Table 5.6 Example 5.9 To sign a messagem, first choose a primep= 11and two random

Ngày tải lên: 09/08/2014, 06:23

... Trang 1CHAPTER 5 Insect Growth Regulators Nancy E Beckage CONTENTS 5.1 Overview 5.2 Ecdysteroid Agonists 5.3 Juvenile Hormone Agonists 5.4 Azadirachtin References 5.1 OVERVIEW Insect ... oviposited, because the treated females lack an oviposition-stimulating factor, which is necessary for the deposition of eggs (Hatakoshi, 1992) Thus, reproduction may be inhibited through oviposition ... EcR/ultraspiracle Figure 5.1 Structures of 20-hydroxyecdysone and the bisacylhydrazine ecdysteroid agonists. Reprinted with permission from Dhadialla et al (1998). LA4139/ch05/frame Page 125 Thursday, April

Ngày tải lên: 11/08/2014, 04:20

... Different Analyst Table 5-4 Individual Error Matrix Kappa Analysis Results Table 5-5 Kappa Analysis Results for the Pairwise Comparison of the Error Matrices Trang 11Table 5-5 presents the results ... Table 5-4 are both 20 or more, and so bothclassifications are significantly better than random Table 5-3 An Error Matrix Using the Same Imagery and Classification Algorithm as in Table 5-1 Except ... correct pixels in the deciduous category (i.e., 65) by the total number of pixels classified as deciduous (i.e., 115 or the row total) reveals a value of 57% In other words, although 87% of the deciduous

Ngày tải lên: 11/08/2014, 06:22

... Trang 1CHAPTER 5 Risk AssessmentHarriet M Ammann, R Vincent Miller, Heriberto Robles, and Richard C Pleus5.5.1 Medical Evaluation and Surveillance 5.5.2 Hazards in Indoor Air 5.5.3 Chemicals ... Origin) 5.6 Biological Contaminants (Bioaerosols) 5.10.2 Secondary Metabolism, Antibiotics, and Mycotoxins 5.11 Source Discovery and Risk Assessment 5.12 Air Sampling and Risk Assessment 5.13 Agents ... 5.13 Agents and Agent Mode of Action 5.13.1 Chemical Agents: Toxicity Trang 25.16.1 Medical Assessments 5.16.2 At-Risk Groups References and Resources This chapter discusses general concepts of

Ngày tải lên: 11/08/2014, 09:21

... popula-tion (i.e., the number of individuals in various risk intervals, such as between 10–4and 10–5 or 10–5 and 10–6) This is calculated by combining the population distri-bution with the concentration ... translated into a biologically effective dose assome or all of the contaminant is absorbed or deposited in the body, a process thatcan depend upon numerous factors including chemical and physical ... weknow that these media are often interconnected and that some air pollutants, forexample, can deposit onto and contaminate water bodies, the earth’s surface, andplant and animal life These different

Ngày tải lên: 11/08/2014, 09:21

... and development of roots (55).This activity was consistently higher at the beginning of colonization and the logarithmicstage of development of mycorrhizal fungus (55) The increase in fungal ... enzymes, and the charides produced may act as signal molecules (15,54) oligosac-The plant cell wall contains glucanases and glycosidases that hydrolyze xyloglucaninto monosaccharides Endo-β-1,4-glucanase ... penetrate the plant cell wall at the site of contact during the establishment of intracellular symbiosis (25) indicates that Trang 3hydrolytic enzymes may be involved in the AM colonization process However,

Ngày tải lên: 11/08/2014, 15:20