fundamental of electric circuits 3rd edition solutions manual chapter 9

... lamp, (b) the cost of operating the light for one non-leap year if electricity costs 12 cents per kWh Chapter 1, Solution 28 A0.25 2436530pt W b) Chapter 1, Problem 29 An electric stove with ... 45W, 60W, Trang 15Chapter 1, Problem 19 Find I in the network of Fig 1.30 I 1A + + Trang 17hr 60 4 kW 1.2 Trang 18Chapter 1, Problem 26 A flashlight battery has a rating of 0.8 ampere-hours ... Trang 1Chapter 1, Problem 1 How many coulombs are represented by these amounts of electrons: 10482 1024 Trang 21600900 e10q(0) t40sin10eq(t) -30t 30t -Chapter 1, Problem 4 A current of 3.2

Ngày tải lên: 13/09/2018, 13:31

... 5 1 0 1 1 5 4 0 0 4 7 1 1 0 1 4 4 3 2 1 309 2 209 1 7708 01 B A V i.e Trang 39v v 10 v 100 40 v 120 v v 7 6 9 7 o 1 5 54 49 7 6 9 7 = + 8440 7 720 9 280 280 7 − = Δ 5 8440 1 = − = − Δ Δ Io ... Fig 3.92 Figure 3.92 Chapter 3, Solution 46 For loop 1, 12 8 11 0 8 77 i2 − i2 = ⎯ ⎯→ i2= A and i1 = i 72 = 1 217 A Trang 62Rework Prob 3.19 using mesh analysis Chapter 3, Problem 3.19 Use ... 3.89 Trang 59Use mesh analysis to obtain io in the circuit of Fig 3.90 Solving (1) to (3), i1 = -3.067, i3 = -1.3333; io = i1 – i3 = -1.7333 A Trang 60Find current i in the circuit in Fig 3.91

Ngày tải lên: 13/09/2018, 13:31

... 55/7 i2 = [5/(5 + 55/7)]2 = 7/9, io3 = [-10/(10 + 4)]i = -5/9 2 io = (12/9) – (6/9) – (5/9) = 1/9 = 111.11 mA Trang 25Use superposition to obtain v in the circuit of Fig 4.85 Check your result ... shown below 120 Trang 46Chapter 4, Problem 31 Determine v in the circuit of Fig 4.99 using source transformation x Figure 4.99 Chapter 4, Solution 31 Transform the dependent source so that we have ... resistor R in the circuit of Fig 4.139 Figure 4.139 Trang 109Find the Thevenin’s equivalent circuit across the terminals of R 5, 40) =+ + W77.20833.104 304 2 2 x R V p Th Th Chapter 4, Problem 74.

Ngày tải lên: 13/09/2018, 13:31

... ( R A R R v v ⋅ + + + = + 9 10 10 1 001 , 100 000 , 100 0.9999990 Trang 5Using the same parameters for the 741 op amp in Example 5.1, find vo in the op amp Trang 6Chapter 5, Solution 6 + - Av ... (V0 – (–AVd))/100 But Vd = V1 and A = 100,000, V1 – V0 = 1000 (V0 + 100,000V1) 0= 1001V0 + 99,999,999[(10VS + V0)/12] 0 = 83,333,332.5 VS + 8,334,334.25 V0 which gives us (V0/ VS) = –10 (for ... = va - 2 = 1 - 2 = -1V Trang 10Chapter 5, Problem 9 Determine vo for each of the op amp circuits in Fig 5.48 Chapter 5, Solution 9 + – Figure 5.48 for Prob 5.9 (a) Let va and vb be respectively

Ngày tải lên: 13/09/2018, 13:31

... 400 75 23 x 17.39μF in parallel with Ca = 17.39 + 5 = 22.39μF Hence Ceq = 22.39μF Trang 28Chapter 6, Problem 29.Determine Ceq for each circuit in Fig 6.61 Figure 6.61 Trang 29(a) C in series ... Chapter 6, Solution 54 ( 10 0 6 12 ) ) 3 9 ( 4 = 4 + 12 ( 0 + 4 ) = 4 + 3 Leq = 7H Trang 49Find Leq in each of the circuits of Fig 6.77 Figure 6.77 Chapter 6, Solution 55 (a) L//L = 0.5L, ... 20 15 10 5 t (s) 0 2 4 6 8 Trang 9Find the voltage across the capacitors in the circuit of Fig 6.49 under dc Trang 10Chapter 6, Problem 14.Series-connected 20-pF and 60-pF

Ngày tải lên: 13/09/2018, 13:31

... reserved No part of this Manual may be displayed, reproduced or distributed in any form or by any means, without the prior Chapter 7, Problem 12 The switch in the circuit of Fig 7.92 has been closed ... capacitor voltage for t < 0 and t > 0 for each of the circuits in Fig 7.106 Figure 7.106 For Prob 7.39 Trang 34Chapter 7, Solution 39 (a) Before t = 0, = + = ( 20 ) 1 4 1 ) t ( t ( v ... part of this Manual may be displayed, reproduced or distributed in any form or by any means, without the prior (a) What is the time constant of the circuit? (b) What is v( ∞ ) the final value of

Ngày tải lên: 13/09/2018, 13:31

... s1,2 =  D r D2  Zo2  5 r 52  32 = -9, -1 v(t) = [Ae-t + Be-9t], v(0) = 16 = A + B (1) i = Cdv/dt = C[-Ae-t - 9Be-9t] i(0) = 0 = C[-A – 9B] or A = -9B (2) From (1) and (2), B = -2 and A = ... 1 RC x LC Z 936 1 25 0 4 case Io(0) = i(0) = initial inductor current = 20/5 = 4A Vo(0) = v(0) = initial capacitor voltage = 0 V ) 936 1 sin 936 1 cos ( ) sin cos 936 1 sin 936 1 cos )( ... o 00 00 Z ! D 21 21 t32.372t679.21 2o2 e e 928 6 ) t ( i A 928 6 A to leads This 240 A 32 37 A 679 2 dt ) 0 ( di , A A 0 ) 0 ( i e A e A ) t ( i 32 37 , 679 2 3 10 20 300 20  r  Z  D

Ngày tải lên: 13/09/2018, 13:31

... Fig 9.75 Figure 9.75 For Prob 9.68. Chapter 9, Solution 68 4 j - 1 j 3 1 2 j 5 Trang 51Find the equivalent admittance Yeq of the circuit in Fig 9.76 Figure 9.76 For Prob 9.69. Chapter 9, Solution ... circuit of Fig 9.60 4 x 6 j Z , 1 j 1 45 6569 5 90 8 4 j 4 4 x − = 5 1 j 5 1 4 j 4 ) 5 1 j 5 9 ( ) 10 Z //( 2 A 67 21 873 8 33 8 7623 6 30 60 Z 30 60 Trang 39In the circuit of Fig 9.61, find ... ( = Z 6 0 j 2 2 1 2 j 2 - 1 2 j - 1 1 Trang 56Calculate the value of Zab in the network of Fig 9.79 Figure 9.79 For Prob 9.72. Trang 57Transform the delta connections to wye connections as

Ngày tải lên: 13/09/2018, 13:31

... impedance of the air-core transformer circuit of Fig 13.102 Trang 51 j12Ω j10 Ω j4 Ω 1<0o V I1 I2 - -j2Ω For loop 1, 2 )101( For loop 2, 2 1 1 1 )2104 = j I Z 1 1.6154 9.077 9.219 79.91 ... = -3.5503 +j1.4793 A 4.157923.15 0 2 2 1 o Trang 69Chapter 13, Problem 49 Find current i x in the ideal transformer circuit shown in Fig 13.114 Figure 13.114 For Prob 13.49 Trang 70At node ... 5.15∠–11.89° S = 0.5vsI1* = (20∠0°)(5.15∠11.89°) = 103∠11.89° VA (b) I2 = –I1/n, n = 2.5 I3 = –I2/n’, n = 3 I3 = I1/(nn’) = 5.15∠–11.89°/(2.5x3) = 0.6867∠–11.89° p = 0.5|I2|2(18) = 9(0.6867)2

Ngày tải lên: 13/09/2018, 13:31

... = ω 14 47 j 1 0 ) 10 9 )( 10 357 2 ( j 1 1 0 C j 1 × × + = ω + ) C j 1 R ( || ) L j || R ( ) Z ) 14 47 j 1 0 ( ) 0212 0 j 9996 0 ( ) 14 47 j 1 0 )( 0212 0 j 9996 0 ( ) ( 0 − + = ω ... For the “tank” circuit in Fig 14.79, find the resonant frequency 21 o ( ) 2 ( 88 ) x 10 176 X 10 2 = ω nF 89 19 10 x 2 x 10 x 8 1 BR 1 C RC 3o 2o 10 x 89 19 x ) 10 X 176 ( 1 C 1 L LC 1 − π ... LC 1 − = ω 2 6 - 2 6 - 0 ) 10 9 ( ) 1 0 ( ) 10 9 )( 02 0 ( = ω0 2 357 krad / s (b) At s ω = ω0 = 2 357 krad / , 14 47 j ) 10 20 )( 10 357 2 ( j L 0212 0 j 9996 0 14 47 j 1 14 47 j L

Ngày tải lên: 13/09/2018, 13:31

... 5 ) + 4 e-tsin( 5 ) (b) 29 s 4 s C Bs s A ) 29 s 4 s ( s 29 s 7 s 5 ) s ( 2 + + + + = + + + + = s C s B ) 29 s 4 s ( A 29 s 7 s 2 2 2 2 5 5 ) 2 s ( ) 2 s ( 4 s 1 29 s 4 s 3 s 4 s 1 ) s ( F + ... 9 s ) 3 s 6 s )( 9 s ( ) s ( + + + + = + + + = ) 9 s ( D ) s 9 s ( C ) 3 s 6 s ( B ) s 3 s 6 s ( A 4 1 A = , B = 1 12 , C = - 1 12 , D = 5 12 3 s 6 s 5 s - 9 s 1 s ) s ( F + + + + + + = 5.449 ... transform of the function in Fig 15.27 ( ) ( ) se e 1 5 s32 ss Trang 15Obtain the Laplace transform of f(t) in Fig 15.28 = ) s ( e 5 e 3 e 3 5 s 1 − + − Trang 16Find the Laplace transform of f(t)

Ngày tải lên: 13/09/2018, 13:31

... Trang 7e e 3779 0 ee e 3779 0 e ) 646 2 j )( 3229 1 j 5 1 ( ) 3229 1 j 5 0 ( 3229 1 j 5 0 s ) 646 2 j )( 3229 1 j 5 . 1 ( ) 3229 1 j 5 0 ( 2 s 1 ) 3229 1 j 5 0 s )( 3229 1 j 5 0 ... produces: [ 24 e 24 e cos( 0 5995 t ) 5 004 e sin( 0 5995 t ) ] u ( t ) ) 9 s 4 7 s ( F Es ) 1 s ( D ) 8 9 s 4 7 s )( 1 s ( 1 s 2 s 3 4 9 V 22 2 1 + + + + + = + + + 9 s 4 7 s ( D 1 s 2 s D 4 3 ... Trang 30Chapter 16, Problem 19 In the circuit of Fig 16.53, let i(0) = 1 A, v0(0) and vs = 4e−2tu (t) V Find v0(t) for t > 0 Figure 16.53 For Prob 16.19 Trang 31Chapter 16, Solution 19 We

Ngày tải lên: 13/09/2018, 13:31

... by Iliffe Books Ltd 195 9 Second edition 196 1 Third edition 196 5 Fourth edition 196 9 Fifth edition 197 5 Sixth edition 198 1 Seventh edition 199 0 Eighth edition 199 4 Ninth edition 2000 © S W Amos ... Amos, S W (Stanley William) Principles of transistor circuits/ S W Amos – 9th ed p cm ISBN 7506 4427 Transistor circuits I Title TK7871.9A45 199 4 621.381Ј528–dc20 93 –50682 Composition by Genesis Typesetting, ... Principles of T ransistor Circuits This Page Intentionally Left Blank Principles of Transistor Circuits Ninth Edition Introduction to the Design of Amplifiers, Receivers and Digital Circuits S...

Ngày tải lên: 28/12/2013, 22:19

... V 28 93 6 93 7 93 9 94 1 Operations Involving Particulate Solids Properties and Handling of Particulate Solids 94 5 Characterization of Solid Particles Properties of Masses of Particles 94 5 95 1 Storage ... Symbols Problems References 29 977 Mechanical Separations 98 6 Screening 98 6 98 1 98 3 98 4 Screening Equipment Filtration; General Considerations 99 1 Cake Filters 99 3 Centrifugal Filters / Filter ... Crystallization 90 2 Crystal Geometry Equilibria and Yields Nucleation Crystal Growth Crystallization Equipment Crystallizer Design: Crystal Size Distribution 27 896 90 3 898 90 0 90 4 91 1 91 8 92 1 92 7 MSMPR...

Ngày tải lên: 01/04/2014, 11:53

... are a student using this Manual, you are using it without permission Page 19 - PROPRIETARY MATERIAL © The McGraw-Hill Companies, Inc All rights reserved No part of this Manual may be displayed, ... are a student using this Manual, you are using it without permission Page 29 - PROPRIETARY MATERIAL © The McGraw-Hill Companies, Inc All rights reserved No part of this Manual may be displayed, ... Companies, Inc All rights reserved No part of this Manual may be displayed, reproduced or distributed in any form or by any means, without the prior written permission of the publisher, or used beyond...

Ngày tải lên: 01/04/2014, 11:53

... DC CIRCUITS Chapter Basic Concepts Chapter Basic Laws Chapter Methods of Analysis Chapter Circuit Theorems Chapter Operational Amplifier Chapter Capacitors and Inductors Chapter First-Order Circuits ... 2 49 Step Response of an RC Circuit 257 Step Response of an RL Circuit 263 First-order Op Amp Circuits 268 Transient Analysis with PSpice 273 Applications 276 7 .9. 1 7 .9. 2 7 .9. 3 7 .9. 4 340 350 9. 1 ... not the study of various uses and applications of circuits Rather our major concern is the analysis of the circuits By the analysis of a circuit, we mean a study of the behavior of the circuit:...

Ngày tải lên: 08/05/2014, 15:37

... Procedures 275 276 292 311 Objects and Classes 9. 1 Object-Oriented Programming 9. 2 Inheritance 9. 3 The Language 9. 4 The Interpreter 9. 5 A Typed Language 9. 6 The Type Checker 325 326 3 29 334 336 352 ... code of the second edition of chapter Ryan Newton, in addition to reading a draft of the second edition, assumed the onerous task of suggesting a difficulty level for each exercise for that edition ... elements of List -of- Int () is a list of integers, because of property of definition 1.1.4 or the first rule of definition 1.1.5 (14 ()) is a list of integers, because of property of definition 1.1.4,...

Ngày tải lên: 11/06/2014, 13:24

... height in the late 199 0s with articles reporting the isolation of the first lines of human embryonic stem cells (Thomson et al., 199 8; Solter and Gearhart, 199 9; Vogel, 199 9) Since then considerable ... monitoring of a tissueengineered construct using 1H NMR spectroscopy Cell Transplant 14, 1 39 1 49 Vats, A., et al (2005) Stem cells Lancet 366, 592 –602 Vogel, G ( 199 9) Harnessing the power of stem ... 77251-1 892 Derrick C Wan Stanford University School of Medicine Department of Surgery Stanford, CA 94 305-5148 xxvii Hai Zhang Department of Restorative Dentistry School of Dentistry University of...

Ngày tải lên: 29/06/2014, 09:21

... differentiation of T-cell progenitors from endogeneous or exogenous sources (Jenkinson and Owen, 199 0; Yeoman et al., 199 3; Barcena et al., 199 4; Plum et al., 199 4; Cumano et al., 199 6) The technique of reaggregate ... methallylsulfonate (AN 69) (Lanza et al., 199 2; Mikos et al., 199 4; Prevost et al., 199 7; Delaunay et al., 199 8; Sambanis, 2000) Typical values of device thickness or fiber diameter are 0.5–1 mm Advantages of membrane ... number of viable, metabolically active cells in the capsule volume This number of viable cells is maintained through equilibration of cell growth and death processes (Papas et al., 199 9a, 199 9b)...

Ngày tải lên: 29/06/2014, 09:21

... using, 98 -99 circuit analysis using, 90 ,93 -99 ,106-1 09, 1 29 defined, 93 dependent sources and, 95 -96 equations, 93 -94 frequency-domain circuits, 332-333 mesh-current method, comparison of, 106-1 09 sinusoidal ... using, 90 ,99 -1 09, 1 29 defined, 100 dependent sources and, 102-103 equations, 99 -102, 190 , 192 frequency-domain circuits, 333-334 mutual inductance (M) and, 190 - 192 node-voltage method, comparison of, ... analysis of a circuit with, 480-481 circuit parameters of, 1 89- 190 , 194 - 196 ,203-204 coefficient of coupling and, 197 ,204 dot convention for polarity, 190 - 192 , 195 - 196 ,204 energy (w) storage and, 197 -200,204...

Ngày tải lên: 06/07/2014, 16:20