computer misuse threats and vulnerabilities

... UyenCE140422 LAB 5 Identify Threats and Vulnerabilities in an IT Infrastructure 1 Required Setup and Tools Students will need access to the Internet to correlate found software vulnerabilities on the ... the IT infrastructure with the Common Vulnerabilities and Exposures (CVE) online listing located at: http://cve.mitre.org/ Using the online tool to find the vulnerabilities of OWASP 2 Part 1: Using ... theweb page in supportedweb browsers) Medium Refer to your dataclassification standardfor proper handling ofdata and use of TCP/IPapplications Never useTCP/IP applicationsfor confidential data

Ngày tải lên: 09/05/2024, 10:57

... Chapter 7 Product Security Vulnerabilities 117 Definition of Security Vulnerability 118 Severe and Minor Vulnerabilities 120 Chaining Vulnerabilities 122 Fixing Theoretical Vulnerabilities, or Do ... of computer misuses are from the early 1960s It is interesting to note how common knowledge says that computer incidents are associ-ated with hackers and script kiddies—that these hacker and ... [Accessed September 27,2010] Anderson, R and Nagaraja, S., 2009 "Computer Laboratory—Technical reports: Computer Capers: Tales of Electronic Thievery, Embezzlement, and Fraud, Thomas Whiteside,

Ngày tải lên: 30/05/2014, 23:08

... 1Understanding New Threats and Challenges from Hydropower Development toBiodiversity and Community Rights in the 3S River Basin April 2012 Mark Grimsditch Trang 2Understanding New Threats and Challenges ... region’s water Ň ows and quality, land use and forest cover, and would block important Į sh migraƟ on routes and change aquaƟ c habitat required for the migraƟ on, spawning and feeding of Į sh ... concessions and reserved land.72 The reservoir will Ň ood more than 1,200 ha of agricultural land, which is 24% of the agricultural land in Sesan District, and although this will be replaced by land

Ngày tải lên: 21/06/2014, 20:21

... is to Trang 72 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUESbe cut-off to a manageable size such as 0.29, 0.286, 0.2857, etc The process of cutting off super-flouts digits and retaining ... becomes 7327 × 106 Error = True value – Approximate value A computer has a finite word length and so only a fixed number of digits are stored and used during computation This would mean that even in ... error is given by δX = δx1 – δx2 and Relative error is X x1 x2 But we know that δ ≤ δ + δX x1 x2 and 1 2 X δ ≤ + therefore on taking modulus of relative errors and absolute errors to get its maximum

Ngày tải lên: 04/07/2014, 15:20

... negative as shown in the figure then the root lies in between x2 and x1, and the third approximation to the root is x3 = (x2+ x1)/2 and so on This method is simple but slowly convergent It is also ... initial guess values (approximation) a and b (where (a > b)) such that f(a) f(b) < 0. Step 2: Evaluate the mid point x1 of a and b given by x1 = 1 2 (a + b) and also evaluate f(x1) Step 3: If ... e e + = Trang 2Here e i and e i + 1 are the errors in i th and (i + 1) th iterations respectively Comparing the above equation with 1 lim i k e A e + We get k = 1 and A = 0.5 Thus the Bisection

Ngày tải lên: 04/07/2014, 15:20

... 1 f (2) On expanding f(î å )+ n and f(î å+ n−1) in Taylor’s series about the point î in (2), and using f( )ξ = 0, we obtain 1 2 1 1 2 2 1 1 2 1 2 n − − + − On simplifying, and neglecting higher ... Regula-Falsi and Secant method. Sol Solution by Regula-Falsi method: Here f(x) = x3 – 2x – 5 then f(2) = – 1, f(3) = 16 and f(2) f(3) < 0 Therefore initial approximations are taken as x0 = 2, x1 = 3 and ... not bracket the root and it is not even necessary to bracket the root to start the iteration Hence, it is obvious that the iteration may not always coverage on the other hand, it generally converges

Ngày tải lên: 04/07/2014, 15:20

... the approximated values of p and q. Since R and S are both functions of the two parameters p and q then the improved values are given by S(p + ∆p, q + ∆q) = 0 Expand equation (4) by Taylor’s ... pb n–2 + qb n–3 and b n = a n – pb n–1 – qb n–2 Therefore a n = b n – pb n–1 – qb n–2 So equation (7) becomes R = b n–1 and S = b n + pb n–1 (9) For partial derivaties of R and S equation (8) ... get p Since R = b n–1 and S = b n + pbn–1, therefore p p − − 2 Trang 10Similarly ∆q = ( )− 2 b C b b C C C C b Then the improved values of p and q are given by p1 = p + ∆p and q1 = q + ∆q The method

Ngày tải lên: 04/07/2014, 15:20

... Second approximation: Using p1 = –1.8949 and q1 = 1.74974 for second approximation, then p2 = p1 + ∆p and q2 = q1 + ∆q. Now to obtain the values of b i and C i we use the following procedure: ... Third approximation: Using p2 = –1.99409 and q2 = 1.98192 for third approximation, then p3 = p2 + ∆p and q3 = q2 + ∆q. Now to obtain the values of b i and C i we use the following procedure: − ... method we find the values of p and q: First approximation: Let p0 and q0 be the initial approximations, then the first approximation can be obtained p1 = p0 + ∆p and q1 = q0 + ∆q Because given

Ngày tải lên: 04/07/2014, 15:20

... – 1 2) g(x + 1 2) ] Therefore right hand side is =   +    − +  −    +  ( ) ( ) ( ) 1/2 1/2 −   +   −  (b) We know E = e hD and ∇ = 1 – E–1, therefore ∇2 = (1 – e ... 1 n       or 0 m e nx ∞ − ∆ n    , where for ∆m e –nx , n is to be regarded variable and x is to be regarded as constant. Now, ∆m e –nx = ∆m–1 [e –(n+1)x – e –nx] = ∆m–1 e –nx (e ... Example 23 Show that: u 0 – u 1 + u 2 – = 1 2 u 0 – 1 4 ∆u 0 + 1 8 ∆2 u 0 – Sol On taking left hand side = u 0 – u 1 + u 2 – u 3+ = u 0 – Eu 0 + E 2 u 0 – E 3 u0 + = (1 – E + E2 – E3 + )u0

Ngày tải lên: 04/07/2014, 15:20

... argument half way between the arguments of q and r is A+ 1 B 24 , where A is the arithmetic mean of q, r and B is the arithmetic mean of 3q – 2p – s and 3r – 2s – p. Sol On taking h being the interval ...  u x and 2 2 x x u E u   If u x = x 3 and the interval of differencing is unity Find out the expression for both [Ans 6h2 (3x – h), 2 3 3 + + ] 13 If f(x) = e ax , show that f(0) and its ... + + − = −161 p+ +(q r)161 +12−161 s Again A = arithmetic mean of q and r = 1( ) 2 q r+ B = Arithmetic mean of 3q – 2p – s and 3r – 2s – p is 2 q− p s− + r− − =s p 2 q r s p+ − − 24 q r q r

Ngày tải lên: 04/07/2014, 15:20

... tabulated value) and for x = 1, (second tabulated value) and by solving these two we get the two missing values for given function f(x) Similarly method proceeds to find three and more missing ... x–1 + ∆ux–2 + ∆2u x−3 + + ∆n−1u x n− + ∆n u x n− , shift the last term of right hand side and then solve left hand side u x – n x n u − ∆ = (1 – ∆n E –n )u x = 1 n E   ∆  −       u ... (1) On putting x = 1 and x = 2 in equation (1), we get (7) 6 (6) 15 (5) 20 (4) 15 (3) 6 (2) (1) 0 Putting the value of f(8), f(7), f(6), f(4), f(2), f(1) in equation (1) and (2), we get 343 –

Ngày tải lên: 04/07/2014, 15:20

... multiply –3 by 1 and 2 by 1 and add them to get the sum –1 which is to be written below 3 The remainder –10 is the value of D. 4 Add the terms of corresponding columns of (a) and get 2, –1 and 2 of (b) ... in the left hand side column and write zero below the coefficients of highest power of x (in this case we have written zero below 2 which is coefficient of x3) 3 Now multiply 2 by 1 and 0 by 1, ... apply the steps (1) and (3): in this way we get (2 × 2) + (0 × 2) = 4 which is to be written below –1 The remainder 2 of (b) is equal to C. 6 Apply step (4) on (b) and get 2 and 3 of (c). 7 Again

Ngày tải lên: 04/07/2014, 15:20

... the arguments at q and r is A+ B , 24 where A is the arithmetic mean of q and r and B is arithmetic mean of 3q – 2p – s and 3r – 2s – p. Sol Given A is the arithmetic mean of q and r 2 q r+ Also, ... 0.7880 Example 7 Following are the marks obtained by 492 candidates in a certain examination: Marks No of Candidates Find out (a) No of candidates, if they secure more than 48 but less than 50 ... arithmetic means of 3q – 2p – s and 3r – 2s – p. q− p s− + − −r s p q− p− +s r = q r+ − p s+ Let quantities p, q, r and s corresponds to argument a, a + h, a + 2h and a + 3h respectively then the

Ngày tải lên: 04/07/2014, 15:20

... dissertation is to come up with a better understanding of network security applications and standards Focus will be on applications and standards that are widely used and have been widely deployed -1- 1.3 ... village, different threats like viruses and hackers, eavesdropping and fraud, undeniably there is no time at which security does not matter Volatile growth in computer systems and networks has ... 15 16 16 16 17 19 20 21 21 21 21 22 23 23 24 24 NETWORK SECURITY THREATS AND VULNERABILITIES 3.1 Security Threats 3.2 Security Vulnerabilities 3.3 Unauthorized Access 3.4 Inappropriate Access...

Ngày tải lên: 23/07/2014, 00:25

... Two major threats to wireless client devices are (1) loss or theft, and (2) compromise Loss or theft of laptops and PDAs is a serious problem laptops and PDAs often store confidential and proprietary ... Multimedia and Ubiquitous Engineering Vol 3, No 3, July, 2008 6.2 Use anti-virus and anti-spyware software, and a firewall Computers on a wireless network need the same protections as any computer ... assessing and managing risk This paper discussed the threats and vulnerabilities associated with each of the three basic technology components of wireless networks (clients, access points, and the...

Ngày tải lên: 28/03/2014, 22:20

... about information and communication technology goods exports include telecommunications, audio and video, computer and related equipment; electronic components; and other information and communication ... is huge and profitable, the competition is truly fierce between leading providers including Dell, Hewlett-Packard, IBM, Sony, Toshiba, Acer and Apple As the demands for computer and computer- related ... continue the cycle of R&D and product development for a new product Standards-based innovation: This way mean the computer maker will based on standardized technology and market demand to build their...

Ngày tải lên: 31/03/2013, 12:56

... small investment I transferred US1000 and I haven't heard anything since! Neither have lots more people, I understand!" C "I have a computer and Internet at home and this Internet company said I could ... European hotel * and transport companies and 16 attacks * the ATM systems in Britain and abroad These crimes require technological 17 expertise, capital investment in technology and global * to ... checks), the resale of high-value goods and monetary instruments, and investment in real estate and legitimate businesses, particularly in the leisure and tourism industries Shell companies,...

Ngày tải lên: 25/10/2013, 15:20

... renowned computer virus and security researcher He has been actively conducting research on computer viruses for more than 15 years, and he focused on the subject of computer viruses and virus ... electronic versions and/ or custom covers and content particular to your business, training goals, marketing focus, and branding interests For more information, please contact: U S Corporate and Government ... 10 Exploits, Vulnerabilities, and Buffer Overflow Attacks Section 10.1 Introduction Section 10.2 Background Section 10.3 Types of Vulnerabilities Section 10.4 Current and Previous Threats Section...

Ngày tải lên: 17/02/2014, 15:20

... by Nadia Islam Spivak and Sarah Crow, and comprised of Betty Dow, Kathy Rollins, and Sachin Shahria with technical support from David Horowitz and Roula Yazigi Indira Chand and Merrell Tuck-Primdahl ... Economic Prospects (GEP), and as a result forecasts have been significantly downgraded  The global economy is now expected to expand 2.5 and 3.1 percent in 2012 and 2013 (3.4 and 4.0 percent when ... Developing countries Net private and official inflows Net private inflows (equity + debt) East Asia and Pacific Europe and Central Asia Latin America and Caribbean Middle East and N Africa South Asia...

Ngày tải lên: 06/03/2014, 09:22

... prevent unauthorized computer access and use computer access and use Identify safeguards against hardware theft Identify safeguards against hardware theft and vandalism and vandalism Explain the ... disorders and injuries due to computer use disorders and injuries due to computer use Next Computer Security Risks What is a computer security risk?  Action that causes loss of or damage to computer ... Theft and Vandalism What are hardware theft and hardware vandalism?  Hardware theft is act of stealing computer equipment     Cables sometimes used to lock equipment Some notebook computers...

Ngày tải lên: 07/03/2014, 14:20