ccna 2 practice final exam answers 4 0
CCNA 2 FINAL 2012 EXAM – V1 potx
... 1 72. 16.1 .0 / 24 [1 10/ 10 12] via 1 92. 168 . 20 0. 1, 00 :00 :22 , Serial0 /0/ 0 R 1 72. 16.1 .0 / 24 [ 1 20 /1] via 1 92. 168 . 20 0. 1, 00 :00 :17, Serial0 /0/ 0 I 1 72. 16.1 .0 / 24 [ 100 /11 92] via 1 92. 168 . 20 0. 1, 00 :00 :09 , Serial0 /0/ 0 16. ... 1 72. 16.1 .0 / 24 [1 10/ 10 12] via 1 92. 168 . 20 0. 1, 00 :00 :22 , Serial0 /0/ 0 R 1 72. 16.1 .0 / 24 [ 1 20 /1] via 1 92. 168 . 20 0. 1, 00 :00 :17, Serial0 /0/ 0 I 1 72. 16.1 .0 / 24 [ 100 /11 92] via 1 92. 168 . 20 0. 1, 00 :00 :09 , Serial0 /0/ 0 ... via 1 72. 16 .2. 1, 00 :00 : 24 , Serial0 /0/ 1 R 1 92. 168.9 .0 / 24 [ 1 20 /1] via 1 72. 16.1 .2, 00 :00 : 24 , Serial0 /0/ 0 R 1 92. 168. 100 .0 / 24 [ 1 20 /1] via 1 72. 16.1.1, 00 :00 : 24 , Serial0 /0/ 0 R 1 92. 168 .2. 0 / 24 [ 1 20 /1] via...
Ngày tải lên: 16/03/2014, 07:20
Tài liệu CCNA 2.0 Exam 640-507 Edition 3 pdf
... bits Subnet mask Subnets Hosts Range 2 255 .25 5.1 92. 0 2 16,3 82 64 3 25 5 .25 5 .22 4. 0 6 81 90 32 4 25 5 .25 5 . 24 0. 0 14 40 94 16 5 25 5 .25 5 . 24 8 .0 30 20 46 8 7 http:\\troytec.com Router> This ... of 32 binary bits, where each bit is either a 0 or 1. We write the 32 bits into four 8-bit numbers (octets) separated by a periods. For Example: 1 100 000 1 . 00 001 0 10 . 00 0111 10 . 00 000 0 10 (IP ... or 128 + 64 + 1 = 193 Using the same table to translate the other three octets would give us the following result. 00 001 0 10 = 8 + 2 = 10 00 0111 10 = 16 + 8 + 4 + 2 = 30 00 000 0 10 = 2 ...
Ngày tải lên: 10/12/2013, 15:15
Tài liệu Take Assessment - ENetwork Final Exam - Network Fundamentals (Version 4.0) pdf
... 1 72. 16. 128 .0 through 1 72. 16.159 .25 5? 1 72. 16. 128 .0 25 5 .25 5 .25 5 .22 4 1 72. 16. 128 .0 25 5 .25 5 .0. 0 1 72. 16. 128 .0 25 5 .25 5.1 92. 0 1 72. 16. 128 .0 25 5 .25 5 .22 4. 0 1 72. 16. 128 .0 25 5 .25 5 .25 5.1 92 36 During the encapsulation ... secret VTY 29 As network administrator, what is the subnet mask that allows 5 10 hosts given the IP address 1 72. 30. 0 .0? 25 5 .25 5 .0. 0 25 5 .25 5 . 24 8 .0 25 5 .25 5 .25 2 .0 25 5 .25 5 .25 4. 0 25 5 .25 5 .25 5 .0 25 5 .25 5 .25 5. 128 30 ... Mask: 25 5 .25 5 .25 5 . 24 8; Default Gateway: 1 92. 168. 100 .18 IP address: 1 92. 168. 100 .22 ; Subnet Mask: 25 5 .25 5 .25 5 . 24 0; Default Gateway: 10. 1.1.5 IP address: 1 92. 168. 100 . 30; Subnet Mask: 25 5 .25 5 .25 5 . 24 0; ...
Ngày tải lên: 13/12/2013, 19:16
CCNA 2 Chapter 4 ppt
... network 1 14. 125 .16 .0 is accessible in 2 hops. Router C will learn of the loss of connectivity to network 1 14. 125 .16 .0 from RouterB. RouterB will include network 123 . 92. 76 .0 and 136. 125 .85 .0 in its ... hop count CCNA 2 Chapter 4 1. What actions will occur after RouterA loses connectivity to network 1 14. 125 .16 .0? (Choose two.) RouterB will include network 123 . 92. 76 .0 and 136. 125 .85 .0 in its update ... before all routers know all networks? 1 2 3 4 5 6 Refer to the exhibit. What path will packets from the 1 92. 168.1 .0 / 24 network travel to reach the 10. 0 .0. 0/8 network if RIP is the active routing...
Ngày tải lên: 22/06/2014, 16:20
Unit 2: Making arrangementsPeriod 11: Lesson 4: ReadI. Objectives:- To help Ss practice potx
Ngày tải lên: 08/08/2014, 02:20
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