... of installation Trang 17Table 2: Method of installationWithout fixings 40, 46, 15, 16 56 -0 -50, 51, 52, 53 6, 7, 8, 9, 12, 13, 14 10, 11 Cable ducting 30, 31, 32, 33, 34 30, 31, 32, 33, 34 ... Rubber Al 93 1.95·10 -2 5.41·10 -2 1.38·10 -1 2.98·10 2 4.53·10 2 7.62·10 2 1.19·10 3 PVC Al 76 1.44·10 1 2.83·10 1 5.21·10 1 8.32·10 1 1.30·10 2 1.98·10 2 3.33·10 2 5.20·10 2 Cu 143 5.11·10 1 ... (PTTA) IEC 60092-303 1980 Electrical installations in ships Part 303: Equipment - Transformers for power and lighting IEC 60092-301 1980 Electrical installations in ships Part 301: Equipment -
Ngày tải lên: 08/04/2021, 03:43
... 220 105 154 264 330 52.5 84 63 84 143 220 396 63 84 143 220 396 63 94.5 105 176 105 143 220 286 40 63 52.5 63 105 187 330 52.5 63 105 187 330 52.5 73.5 105 143 84 105 187 220 7.7 13.6 40 52.5 84 ... range of ABB SACE circuit breakers for the protection against residual current and earth fault In PR222 LSIG PR223 LSIG PR331 PR332 PR333 (2) LSIG PR332 PR333 (2) LSIRc PR121 PR122 PR123 LSIG PR122 ... PR120/V for Emax and PR330/V for X1 PR221 PR222 PR223 PR231 PR232 PR331 PR332 PR333 PR121 PR122 PR123 Protection against overload Standard trip curve according to IEC 60255-3 Protection against
Ngày tải lên: 21/05/2016, 18:20
ABB electrical installation handbook 2006
... Cable ducting 30, 31, 32, 33, 34 30, 31, 32, 33, 34 0 36 36 Support wire - - - - - From Tables 2 and 3 it is possible to identify the installation identification number,the method of installation ... (PTTA) IEC 60092-303 1980 Electrical installations in ships Part 303: Equipment - Transformers for power and lighting IEC 60092-301 1980 Electrical installations in ships Part 301: Equipment - ... and test requirements IEC 60092-352 2005 Electrical installations in ships - Part 352: Choice and installation of electrical cable IEC 60364-5-52 2001 Electrical installations of buildings - Part
Ngày tải lên: 08/04/2021, 03:41
EC&M’s Electrical Calculations Handbook - Chapter 3 potx
... Panel. 424,700 = 460 x I (1.00) x 3 P = E x I (cos o ) x 3 = I = I 533 amperes = line current at 100% power factor 460 x (1.00) x 3 424,700 796.74 424,700 Figure 3-13 Solve for feeder current at ... CAPACITORS AT THE MOTOR. 10.328 kVAR 10.328 kVAR 10.328 kVAR TOTAL CAPACITOR SIZE: Trang 22Real Power (Kilowatts), Apparent Power(Kilovoltamperes), Demand, and the Electrical Utility Bill Although ... Table 430-150: Step 2: Solve for motor current for ten motors, in accordance with NEC 430-24. Figure 3-11 Solve for feeder current given motor horsepower and age and quantity of motors. Trang 23volt-The
Ngày tải lên: 13/08/2014, 02:21
International auditing and assurance standards board handbook volume 3
... may include: 3.1 Engagement Level From the Auditor 3.1.1 Auditor’s Reports to Users of Audited Financial Statements 3.1.2 Auditor’s Reports to Those Charged with Governance 3.1.3 Auditor’s Reports ... Trang 19From Audit Regulators 3.1.7 Regulators Providing Information on Individual audits 3.2 Firm and National Levels From the Audit Firm 3.2.1 Transparency Reports 3.2.2 Annual and Other Reports ... Annual and Other Reports From Audit Regulators 3.2.3 Providing an Aggregate View on the Results of Audit Firm Inspections 3.1 Outputs – Engagement Level 3.1.1 Auditor’s Reports to Users of Audited
Ngày tải lên: 01/04/2017, 08:47
doe fundamentals handbook - thermodynamics, heat transfer, and fluid flow - volume 3 of 3
... 27 Summary 30 HEAD LOSS 31 Head Loss 31 Friction Factor 31 Darcy’s Equation 32 Minor Losses 34 Equivalent Piping Length 34 Summary 36 NATURAL CIRCULATION 37 Forced and ... control volume are equal to all mass flow rates out of thecontrol volume plus the rate of change of mass within the control volume This principle isexpressed mathematically by Equation 3-4 Trang 33Fluid ... Circulation 37 Thermal Driving Head 37 Conditions Required for Natural Circulation 38 Example of Natural Circulation Cooling 39 Flow Rate and Temperature Difference 39 Summary
Ngày tải lên: 17/03/2014, 15:00
Electrical installation work 6th ed
... information Glossary of terms Index vii ix xi 33 47 81 131 153 179 197 199 203 211 This page intentionally left blank Preface The 6th edition of Advanced Electrical Installation Work has been completely ... Science and Technology Rights Department in Oxford, UK; phone: (44) (0) 1865 843830; fax: (44) (0) 1865 853333; e-mail: permissions@elsevier.co.uk You may also complete your request on-line ... Advanced Electrical Installation Work ii To Joyce, Samantha and Victoria Advanced Electrical Installation Work Sixth Edition Trevor Linsley Senior
Ngày tải lên: 13/12/2013, 00:57
Tài liệu Spoken english elementary handbook part 3 pptx
... Students 2.9 Connected Sentence Cards 3 Instructions 3.1 Activity Template (Blank) 3.2 Sample Lesson Plan 3.3 Sound Connections Demo 3.6 Going Further 3.15 Connected Speech Templates 4 ... Exchanges 6 Instructions 6.1 Activity Template (Blank) 6.3 Multi-Purpose Texts 7 Instructions 7.1 Reading Race – Lesson Plan 7.3 Discussion Questions 8 Instructions 8.1 Activity Template ... used in the starting sentence? (Answer: present perfect) (8 marks) Question 14 If you were given £3,000 to spend only on clothes and shoes, what would you buy and where would you go shopping? (4
Ngày tải lên: 13/12/2013, 21:15
Tài liệu Corporate Finance handbook Chapter 3 ppt
... realised Trang 32 Funds are getting bigger The natural response to this is to look forbigger opportunities The result has been that competition for thelargest buy-outs is very tight 3 Funds are ... second stage capital injection of £3 mil-lion in December 1990, which was used to reduce some of thebank debt The investors increased their equity stake to 32.5% inthe process The trading year ... involved closure costs of circa £1 million In the year end pro-31 August 1991 the following trading result ensued: Sales £71.0million Loss (£3.1million) The compounding effect of very high interest
Ngày tải lên: 14/12/2013, 15:15
Instrumentation and control fundamentals handbook volume 2 of 2
... Ionization Regions 30 Figure 16 Ionization Chamber 31 Figure 17 Minimizing Gamma Influence by Size and Volume 32 Figure 18 Minimizing Gamma Influence with Boron Coating Area 33 Trang 17Radiation ... Figure 30 Analog and Digital Displays 56 Figure 31 Single and Two-Stage Amplifier Circuits 58 Figure 32 Biased Diode Discriminator 59 Figure 33 Log Count Rate Meter 60 Figure 34 Period ... and Control handbook consists of seven modules that are contained in two volumes The following is a brief description of the information presented in each module of the handbook Volume 1 of 2
Ngày tải lên: 28/12/2013, 22:07
The electrical engineering handbook CH107
... (1) Between tasks and adjacent darker surroundings 3 to 1 3 to 1 5 to 1 (2) Between tasks and adjacent lighter surroundings 1 to 3 1 to 3 1 to 5 (3) Between tasks and more remote darker surfaces ... important Important Critical Reflectance of task background, % >70% 30 to 70% <30% Source: IES Lighting Handbook, Application Volume. Note: Weighting factors are based upon worker and task information. ... Lighting Handbook, Application Volume. (room length room width) Trang 5TABLE 107.3 Weighting Factors for Selecting Specific Illuminance Within Ranges A, B, and CAverage room reflectance 1 >70% 30
Ngày tải lên: 30/12/2013, 22:33
The electrical engineering handbook CH053
... superconductors and their properties are listed in Table 53.2 Al 1.18 50 1600 0.18 110.5 In 3.41 65 360 0.54 123.0 Sn 3.72 50 230 0.59 130.5 Pb 7.20 40 90 1.35 180.0 Nb 9.25 85 40 1.50 198.0 Source: R.J ... “Superconductivity”The Electrical Engineering Handbook Ed Richard C Dorf Boca Raton: CRC Press LLC, 2000 Trang 2© 2000 by CRC Press LLC53 Superconductivity 53.1 Introduction 53.2 General Electromagnetic ... superelectron velocity by Js = n*q*vs, the kinetic energy term can be rewritten (53.3) where L is defined as (53.4) the volume of phase space indicated w = 1 + mo + n m vs 2 1 n * 1 m * s s 2 1
Ngày tải lên: 30/12/2013, 22:33
The electrical engineering handbook CH055
... Planck constant (6.624 3 10–34 J s–1), k the Boltzmann constant (1.38 3 10–23 J K–1), DH the activation energy of the relaxation process, R the universal gas constant (8.314 3 103 J K–1 kmol–1), and ... higher voltages in the electrical power area necessarily requires detailed knowledge of how the electrical losses vary as a function of the electrical field Since most electrical power apparatus ... Insulators”The Electrical Engineering Handbook Ed Richard C Dorf Boca Raton: CRC Press LLC, 2000 Trang 2Dielectrics and Insulators 55.1 Introduction 55.2 Dielectric Losses 55.3 Dielectric Breakdown
Ngày tải lên: 30/12/2013, 22:33
The electrical engineering handbook CH056
... another A usable ouput refers to an optical, electrical, or mechanical signal In the context of electrical engineering, however, a usable output refers to an electrical output signal The measurand ... Sensors • 114.3 Chemical Sensors • 114.4 Bioan-alytical Sensors • 114.5 Applications References ANSI, “Electrical Transducer Nomenclature and Terminology,” ANSI Standard MC6.1-1975 (ISA S37.1), Research ... thermometer produces a change in volume of mercury in response to a temperature change via thermal expansion, but the output is a mechanical displace-ment and not an electrical signal Another transduction
Ngày tải lên: 30/12/2013, 22:33
The electrical engineering handbook CH057
... 12 3 2 44 1 2 44 1 3 44 1 2 12 1 2 11 2 2 12 3 2 44 2 3 44 1 3 44 2 3 12 1 2 12 2 2 11 3 2 22 22 22 fM fM fM fMM fMM fMM fMfMfM fMM fMM fMM fM fM fM « @- é ë ê ê ê ù û ú ú ú ee e e e 0 13 13 0 ... ê ê ù û ú ú ú ee eee eee eee 0 11 12 13 12 22 23 13 23 33 * ** « = é ë ê ê ê ù û ú ú ú ee e e e 0 00 00 00 r r r + +- -+ +- é ë ê ê ê ù û ú ú ú e 0 13 12 13 11 12 11 0 0 0 jfM jfM jfM jfM jfM ... (min/cm-Gauss) 1300 nm 10.5 a –806 1550 nm 9.2 –600 Saturated magnetooptic rotation (degree/mm) 1300 nm 20.6 –136.4 1550 nm 18.5 –93.8 Thickness for 45-degree rotation (mm) 1300 nm 2.14 0.33 1550 nm 2.43 0.48
Ngày tải lên: 30/12/2013, 22:33
The electrical engineering handbook CH089
... 1988, pp 225–232. M Leonard, “Speech poised to join man-machine interface,” Elec Des., pp 43–48, Sept 26, 1991. S Sherr, Electronic Displays, New York: Wiley, 1979, pp 323, 388–389. Further Information ... 0.5–2.0 Scanning width (in.) 4.1–36 gray shades 32–256 Scan time (s/page) 1–30 Voice Active vocabulary 13–5000 words Trang 20Scanners: Means for converting hard copy into electrical signals that can ... Keyboard Parameter Values Parameter Snap Switch Elastomer Foam Pad Key travel 3.8 mm 3.2 mm 3.8 mm Force >60 gm >50 gm >30 gm Life 10 million cycles 10 million cycles 10 million cycles Feedback
Ngày tải lên: 30/12/2013, 22:33
The electrical engineering handbook SN12
... 29352 74463 41505 87236 69428 05253 81039 3u3 = 1.44224 95703 07408 38232 16383 10780 10958 83918 69253 49935 loge3 = 1.09861 22886 68109 69139 52452 36922 52570 46474 90557 82275 log103 = 0.47712 ... 44010 89358 61883 44909 99876 15113 53136 99407 24079 logep = 1.14472 98858 49400 17414 34273 51353 05871 16472 94812 91531 log10p = 0.49714 98726 94133 85435 12682 88290 89887 36516 78324 38044 ... 22835 05702 51464 70151 loge2 = 0.69314 71805 59945 30941 72321 21458 17656 80755 00134 36026 log102 = 0.30102 99956 63981 19521 37388 94724 49302 67881 89881 46211 u3 = 1.73205 08075 68877 29352
Ngày tải lên: 31/12/2013, 21:25
The electrical engineering handbook CH007
... written in matrix form as C v i i i3 3˙ – = 3 = 2 4 L i v v v4 4˙ = 4 = 3 – 1 v1 = R i1 1 = R i1(4 + ig - i3) R R g 2 2 2 3 2 R v R g g 3 2 -è ç ö ø ÷ R g 2 3 2 g 3 3 3 2 4 R v R i R i R v R g g 4 ... of the branches R1, C3, and v g The subnetwork C3i 5 v g is another example of a normal tree Step 3 The tree branches R1, C3, and v g are assigned the voltage symbols v1, v3, and v g ; and the ... symbols i2, i4, i3, and i g , respectively The controlled current source i5 is given the current symbol i3 because its current is controlled by the current of the branch C3, which is i3 Step 4 Applying
Ngày tải lên: 31/12/2013, 21:25
The electrical engineering handbook CH003
... – 4 + I3 + I4 = 0 –I1 – I4 – 2 = 0 Using Ohm’s law these equations can be expressed as Solving these equations, using any convenient method, yields V1 = –8/3 V, V2 = 10/3 V, and V3 = 8/3 V Applying ... Then, two current divisions giveI^C The current ^I in the circuit of Fig 3.12(a) is ^ I = I^V + I^C = 0 + j3 + (3 + j0) = 3 + j3 A The Network Theorems of Thévenin and Norton If interest is to be ... Fig 3.14(b) results The Thévenin equivalent voltage is the voltage across the 40–W resistor The current through the 40-W resistor was found in Example 3.1 to be I = 3 + j3 W Thus, ^ VT = 40(3 +
Ngày tải lên: 31/12/2013, 21:26
The electrical engineering handbook CH004
... (in W, H, mF). 0.10 1.0316 1.1474 1.0316 0.25 1.3034 1.1463 1.3034 0.50 1.5963 1.0967 1.5963 0.10 1.1468 1.3712 1.9750 1.3712 1.1468 0.25 1.3824 1.3264 2.2091 1.3264 1.3824 0.50 1.7058 1.2296 ... of John Wiley and Sons Limited. s s s s s s s s s s s s s s s a + 1 2 1 2 6131 3 4142 2 6131 1 3 2361 5 2361 5 2361 3 2361 2 12 kHz = + n Trang 6There is an extremely important difference between ... 2 3 p p p H F H TABLE 4.2 Thomson Polynomials w –3dB (rad/s) s + 1 1.0000 s3 +6s2 + 15s +15 1.7557 s4 + 10s3 + 45s2 + 105s + 105 2.1139 s5 + 15s4 +105s3 + 420s2 + 945s + 945 2.4274 Source: Handbook
Ngày tải lên: 31/12/2013, 21:26
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