2 6 transformation of mathematical models with matlab

... Trang 1GV: ng« thÞ lan h ¬ngTrang 2Unit 7: The world of workLesson 3: A4: A student’s work Lucky number: make questions with the words given: Trang 3Unit 7: The world of workLesson 3: A4: A student’s ... F? 1 Students have to work hard at school and at home 2 Hoa often has five periods a day and five days a week 3 Hoa has about two hours of homework every week 4 She has to study her lessons again ... check your predictions Trang 5Unit 7: The world of workLesson 3: A4 : A student’s work Read the text and answer the questions: Trang 6Unit 7: The world of workLesson 3: A4: A student’s work Answer

Ngày tải lên: 19/04/2021, 21:36

... for Na–Y: Si, 21.76, Na, 7.5, Al, 8.61%, Si/Al = 2.53.; ICP results for Cu–Y: Si, 21.46, Na, 3.25, Al, 8.46, Cu, 3.66 %, Si/Al = 2.53 3.5 Preparation of the encapsulated complex (2) The metal ... [Cu(dipic)(H2O)2]n] / [Cu(dipic)(H2O)2]n]/YThis work [Cu(dipic)(H2O)2]n] (1)) (0.015 mmol), (([Cu(dipic)(H2O)2]n/Y) (2) (0.015 mmol (0.038 g) catalyst); substrate 1.0 mmol, CH3CN = 2 mL, H2O2 4 mmol, ... [Cu(dipic)(H2O)2]n] (1) and [Cu(dipic)(H2O)2]n/Y (2).a a Reaction conditions: catalyst: ((Fe3O4@SiO2/[Cu(tyr)2]n) (2) (0.0023 mmol catalyst), ([Cu(tyr)2]n (1)) (0.0023 mmol)); substrate 1.0 mmol, CH3CN 2

Ngày tải lên: 12/01/2022, 23:36

... ọc là: i h 𝑃(𝑋 = 4) = 𝐶3/ 𝑝 (1 − 𝑝)/ 3$/ = 𝐶!&/ 0,28/ 0,72!! = 0,2262 Vậy xác suất 4 ngư i sờ ẽ hoàn thành 4 năm đại học là 0,2262 b Xác suất ba hoặc nhiều hơn s hoàn thành 4 năm đẽ ại ... 𝐶'".' 0,22.0,818 ≈ 0,2061 Vậy xác suất có hai hoặc ít hơn hai sinh viên sẽ rút lui xấp xỉ là 0,2061 b) Xác suất để có đúng bốn sinh viên rút lui là: P(X= 4) = 𝐶'"./ %0,2 0,84 16 ≈ 0,2182 Vậy ... 2NHÓM A2 1 SINH VIÊN THỰC HIỆN Trang 3NHÓM A2 2 NỘI DUNG 7.37 The weights of newborn babies in Foxboro Hospital are normally distributed with a mean of 6.9 pounds and a standard deviation of

Ngày tải lên: 17/04/2022, 06:35

... Hoàng Yến Trang 2SINH VIÊN THỰC HIỆN1 Đào Thị Thuỳ Trang 23A4050366 dtrang2k20406@gmail.com 2 Nguyễn Tiểu Yến 23A7510161 yenguyen2002@gmail.com 3 Dương Phương Anh 23A4030005 pa25962002@gmail.com ... thành bốn năm đại học là: ( = 4) = 3/. /.(1− )3$/ = !&/ 0,28/ 0,72!! = 0,2262 Vậy xác suất 4 người sẽ hoàn thành 4 năm đại học là 0,2262 b Xác suất ba hoặc nhiều hơn sẽ hoàn thành 4 năm đại học ... '"'..0,22.0,818 ≈ 0,2061 Vậy xác suất có hai hoặc ít hơn hai sinh viên sẽ rút lui xấp xỉ là 0,2061 b) Xác suất để có đúng bốn sinh viên rút lui là: P(X= 4) = '"/..%0,24 0,8 16 ≈ 0,2182 Vậy

Ngày tải lên: 17/04/2022, 10:57

... 2 (cont’) Example 2 (cont’) Trang 54Block diagram algebra Block diagram algebra – – Example 2 (cont’) Example 2 (cont’) H G G B + = H G 2 1 2 2 11 1 * G H G G H G =+ =+ = 2 2 1 3 3 2 3 2 1 2 ... 1 2 2 2 2 3 11 * H G H G G G G G H G H G G G G G = = Trang 55Block diagram algebra Block diagram algebra – – Example 2 (cont’) Example 2 (cont’) H G G 3 1 3 3 3 2 2 2 1 3 3 2 1 3 3 2 2 2 1 ... Trang 21Transfer function of some type of controllers (cont’)s 2 1 2 R R 1 2 R R C R R T < + = R R α © H T Hoang - www4.hcmut.edu.vn/~hthoang/ Trang 22Transfer function of some type of controllers

Ngày tải lên: 05/07/2022, 13:53

... 2 (cont’) Example 2 (cont’) Trang 54Block diagram algebra Block diagram algebra – – Example 2 (cont’) Example 2 (cont’) H G G B + = H G 2 1 2 2 11 1 * G H G G H G =+ =+ = 2 2 1 3 3 2 3 2 1 2 ... 1 2 2 2 2 3 11 * H G H G G G G G H G H G G G G G = = Trang 55Block diagram algebra Block diagram algebra – – Example 2 (cont’) Example 2 (cont’) H G G 3 1 3 3 3 2 2 2 1 3 3 2 1 3 3 2 2 2 1 ... Trang 21Transfer function of some type of controllers (cont’)s 2 1 2 R R 1 2 R R C R R T < + = R R α © H T Hoang - www4.hcmut.edu.vn/~hthoang/ Trang 22Transfer function of some type of controllers

Ngày tải lên: 21/10/2022, 17:39

... common with other eukaryotes, the level of Fru-2,6-P2 in higher plants is determined by the relative activities of 6-phosphofructo-2-kinase (6PF2K) and fructose-2,6-bis-phosphatase (Fru-2,6-P2ase), ... 1865 275074, Tel.: +44 1865 275000, E-mail: nick.kruger@plants.ox.ac.uk Abbreviations: Fru-2,6-P 2 , fructose 2,6-bisphosphate; Fru-2,6-P 2 ase, fructose-2,6-bisphosphatase; Fru-6-P, fructose 6-phosphate; ... modulation of 6-phosphofructo-2-kinase and fructose-2,6-bisphosphatase activities of the bifunc-tional enzyme Keywords: fructose 2,6-bisphosphate; 6-phosphofructo-2-kinase; fructose-2,6-bisphosphatase;

Ngày tải lên: 22/02/2014, 04:20

... subfractions H2-2-1, H2-2-2, H2-3-1 and H2-3-2 (not shown) For identification of their isomeric structures, high mannose-type compounds H2-2-1 and H2-3-1 were rechromatographed by RP-HPLC to-gether with ... 3.2.1.52); a- L -fucosidase (EC 3.2.1.51); endo-b-N-acetylglucosaminidase H (EC 3.2.1.96); a- D -galactosidase (EC 3.2.1.22); b- D -galactosidase (EC 3.2.1.23); a- D -mannosidase (EC 3.2.1.24); ... H2-3-2 F1-5 F1–5 a F2-1 F2-2 F2–2 a F3-1 F4-1 F4-2 F4-3 F4-4 F5-1 F5-2 F5–2 b -3)GlcNAc(1-a After b-galactosidase treatment b After a-mannosidase treatment. Trang 9In contrast, MALDI-TOF-MS of

Ngày tải lên: 31/03/2014, 08:20

... possibility of a sharp decline in the hazard of Published: 26 June 2009 Journal of the International AIDS Society 2009, 12:9 doi:10.1186/1758-2652-12-9 Received: 21 October 2008 Accepted: 26 June 2009 ... λ1 1ρ1 2 ρ2 ρ1 ρ2 1 1 1 ii−c2i)[ ρ 3 logt i+ ( ρ 1 − ρ 2 ) loga1 + ( ρ 2 − ρ 3 ) loga2 ] (ρ λ1, 1) (ρ λ2, 2) (ρ λ3, 3) λ2=λ1+ ρ1−ρ2 λˆ3=λˆ2+( ˆρ2−ρˆ )3 −2{ ( )La −L( )}a ≤χm2;1−α χm;12 α − Trang ... models Biometrics 2000, 56:256-262. 10. Home-Based AIDS Care Project, NCT00119093 [http://clini caltrials.gov/ct2/show/ NCT00119093?spons=%22Ministry+of+Health%2C+Uganda%22&sp ons_ex=Y&rank=8]

Ngày tải lên: 20/06/2014, 08:20

... ||ξ||2= ||ξ+ξ||2= ||ξ||2+||ξ||2 ||ξ||2 = ||ξ||2− ||ξ||2 = ∞ −∞|ψ(λ)|2F X (d λ) −  ∞ −∞ |ψ(λ)|2F η (d λ) = ∞ −∞|ψ(λ)|2F X (d λ) −  ∞ −∞ |ψ(λ)| · |B(λ)|2F X (d λ) = ∞ −∞χ E(λ)|ψ(λ)|2F ... characteristics of ξ in the space of L2 (FX(dl)),ψ(λ) is spectral characteristics ofξin the space of L2 (Fh(dl)), then 1) whenλ ∈ E, 2) ||ξ||2=  E |ψ(λ)|2F X (d λ) (3 13) Proof 1) According ... (λ)ϕ(λ)|2F(dλ) 1 2 =  ∞ −∞|f (λ)|2· |ϕ(λ)|2F(dλ) 12 ≤ M ∞ −∞|f (λ)|2· F(dλ) 1 2 = M −∞∞f (λ)Z(dλ)  Lemma 2 L{A t } = H η (t) (3 3) whereL(A t)is the linear closed manifold of At Proof

Ngày tải lên: 20/06/2014, 22:20

... of Mathematical Neuroscience (2011) 1:2 Page 11 of 28where= 1 2π  2π0  σ2 g(0) + g(φ) + 2h(0) ∂2 ∂ψ2and Trang 12Page 12 of 28 Bressloff, LaiA number of general results regarding finite size ... Trang 1Journal of Mathematical Neuroscience (2011) 1:2DOI 10.1186/2190-8567-1-2 Stochastic synchronization of neuronal populations with intrinsic and extrinsic noise Paul C Bressloff · Yi Ming ... mean-field tion (6) for this so-called E-I network reduces to the pair of equations (dropping thebar on¯x k and setting M= 2) Trang 13Journal of Mathematical Neuroscience (2011) 1:2 Page 13 of 28Fig 1

Ngày tải lên: 21/06/2014, 04:20

... α2 exp{−b2 C1α1− 1} a2 , β1 min  exp{b1− A1α1− C2α2}b1− C2α2 b1− C2α2} A1  , β2 min  exp −B2− A2α2 c1β1 −B2 c1β1 −B2 c1β1 A2 cf 6, Application 4.1 Trang 4We now make the following ... l0and x2k0 1 ≥ x2k0 Then −b2k0 − a2k0x2k0  c1k0k0 s−∞ K1k0− sx1s ≥ 0. 2.12 Hence, x2k0 ≤ −b2k0  c1k0 k0 s−∞ K1k0− sx1s −b2 C1α1 a2 . 2.13 It follows that x2k0 ... x1n exp{b1− C2α2− A1x1n}. 2.17 In particular, with n  l0, we have b1− A1x1l0 − C2α2≤ 0, 2.18 which implies that x1l0 ≥ b1− C2α2 Then, x1l0 1 ≥ b1− C2α2 A1 expb1− C2α2− A1α1 

Ngày tải lên: 21/06/2014, 20:20

... ×10 2 Number of patch 0 2 4 6 8 10 ×10 2 Number of patch Patch histogram (b) 0 2 4 6 8 10 12 ×10−2 Number of aspect 0 2 4 6 8 10 12 14 ×10−2 Number of aspect P(z | d) (c) 0 1 2 3 4 ×10−2 0 200 ... ProcessingVolume 2009, Article ID 602920, 20 pages doi:10.1155/2009/602920 Research Article Contextual Classification of Image Patches with Latent Aspect Models Florent Monay,1Pedro Quelhas,2Jean-Marc ... 200 400 600 800 1000 Number of patch 0 2 4 6 8 10 ×10−2 0 200 400 600 800 1000 Number of patch P(v | z k) . z1 z60 (d) Figure 7: Two images and their decomposition into a mixture ofN A =60 aspects,

Ngày tải lên: 22/06/2014, 00:20

... shows that when n < 8, B/C < 2, while for n = 8, B/C = 2.30121 > 2 The proof that H 6= 2C follows the same pattern Finally, after verifying that 2B 6= H + C for n < 8, we observe ... 3n−42 ) and (2, 1, n2); and also, if n is even and ≤ 8, (0, 5, 8−n2 ). Proof: This follows the pattern of Proposition 4 of [5] When n is odd, there is no second split, so that (in light of [2] ... This triangle has angles (90◦ , 6427◦ , 3847◦ ), and vertex vectors (0, 2, 6), (0, 5, 1), (1, 0, 7), (1, 3, 2), (2, 1, 3), and (4, 0, 0) Its area is 1/56 that of the sphere In this section we

Ngày tải lên: 07/08/2014, 13:21

... can be reached by the signal, as in Figures 2.22 and 2.23, it is safer to use VIA or TO to specify which instance must receive the signal Figure 2.22 shows how to use VIA to send signal red through ... Figure 2.23 shows the use of TO to send signal red to a certain instance of process screen, which has a maximum of three instances Before the output of red, variable p must be filled with the Pid of ... 2.26 Newtype with literals 2 As opposed to C, SDL arrays indexes may not start at 0. Trang 82.4.4.2 StructStruct is used inside a NEWTYPE to define a data structure, as illustrated in Figure 2.27

Ngày tải lên: 07/08/2014, 21:20

... 0 . 26 40 0 .29 60 0 .28 00 0 . 26 40 0 .29 60 0 .28 00 0 . 26 40 z = 0. 360 0 z = 0. 360 0 0 .24 80 z = 0. 360 0 0 .24 80 0.3440 0 .23 20 >> z(10) = NU 12( 0.9, 0 .20 0, 0. 360 ) z = 0. 360 0 0 .23 20 0.3440 0 .21 60 >> z(11) = NU 12( 1, ... 0.3 120 >> z(8) = NU 12( 0.7, 0 .20 0, 0. 360 ) 0.3440 0. 328 0 0.3 120 >> z(9) = NU 12( 0.8, 0 .20 0, 0. 360 ) 0. 328 0 0.3 120 z = 0. 360 0 z = 0. 360 0 0 .29 60 z = 0. 360 0 0 .29 60 0 .28 00 0 .29 60 0 .28 00 0 . 26 40 0 .29 60 0 .28 00 ... 73.1340 4. 62 ) y = 4. 62 0 0 27 .4580 50 .29 60 164 .4 860 187. 324 0 >> y(10) = E1(0.9, 23 3, 73.1340 4. 62 ) y = 4. 62 0 0 27 .4580 50 .29 60 73.1340 164 .4 860 187. 324 0 21 0.1 62 0 >> y(11) = E1(1, 23 3, 4. 62 ) y = Columns...

Ngày tải lên: 08/04/2014, 10:21

... 122 IV 6. 1 Conclusion 122 6 .2 Future Work 125 6 .2. 1 Model Improvement 125 6 .2. 2 Abnormalities of Ultradian Oscillations 127 Bibliography ... plasma of insulin 0. 02 min-1 [ 26 , 70] m3 Plasma insulin degradation rate 0 . 26 8 min-1 [ 26 ] m4 ISF insulin clearance rate 0.03 min-1 [ 26 ] τ1 HGP delay 20 2 IS delay 10 35 Table 3 .6 Distribution volumes ... 4 .2. 2 Non-Compartmental Models 69 4.3 Modeling Glucose-Insulin System with Subcutaneously-Injected Insulin 72 4.3.1 Model of Glucose and Insulin Subsystems 72 4.3 .2 Models of...

Ngày tải lên: 08/09/2015, 18:34

... 10-10 A S 26 0· 06 1·3 2 4 2 0 14 60 6 0 5·5 5'5 5·0 12 70 0·55 2 8 30 42 35 - AS 26 mg prot.jrnl, '5 4·0 4·4 13 16 % yield 100 53 42 33 26 18 The method of preparation and assay of the fractions ... activity of >"dg and on the transforming activity of > dg DNA Gal» DNase concentration (in mixture) Adg DNA Whole Mg fLg/m! 10 10- 10-' 10-" 10-' o o o o o 16 26 4 24 5 22 9 26 1 197 22 1 22 0 24 6 Whole ... extraction of Adg labeled with 35S only 0·1 % of the phage sulfur appears in the aqueous phase 26 0 23 6 1 .2 2.4 ~ x ~ 24 0 320 26 0 28 0 Wavelength (miL) FIG The ultraviolet absorption spectra of >'dg...

Ngày tải lên: 28/05/2016, 11:25

... 431.599 06, 4 52. 07844, 4 02. 68 0 86, 417 .28 243, 4 52. 163 93, 409 .69 67, 427 .70734, 441 .69 62 8 and 434.4 168 6 The large absolute values of the solutions are due to multicollinearity associated with genetic ... model, solutions are 1.354 022 6 for the age effect, - 36. 19053 for the sex effect, and 0 .6 0 26 59, -0 .24 7433, -1.0305 72, -0 .27 69 59, 1.1075 823 , 0 .64 57 529 , 3 .65 89 865 for the BV of animals 1-7, respectively ... animals 1-7 are 99.91, 99 .66 , 99.91, 98.30, 98 .66 , 99 .66 and 99.91, respectively Whereas true PEV for the same animals computed by means of [11] or [ 12] (or direct inversion of the MME) are: 79.94,...

Ngày tải lên: 09/08/2014, 18:22

... area………………………………………………………… 1 .6 Outline of the thesis……………………………………………………… 13 14 14 19 21 23 25 26 26 27 31 Methodology……….… ……… …………………………………………… 33 2. 1 Introduction …………… …………………………………………… 2. 2 Literature review………………………………………………………… ... 103 6. 1 Introduction……………………………………… …………………… 6 .2 Discussions.……… ……………………… ….………………………… 6 .2. 1 Innovative aspects……………………………….…… ………… 6 .2. 2 Generic applicability of the methodology………………………… 6 .2. 3 ... of the output value………………………………… 4.5.5 Testing the consistency of the scenarios…………………………… 4 .6 Results…………………………………………………………………… 4.7 Discussion and conclusions……………………………………………… 65 66 66 67 69 ...

Ngày tải lên: 06/11/2012, 10:35