EXERCISE NUMBER 4 ELEARNING SUBJECT ELECTROMAGNETIC TRANSIENT PROCESS MISSION CALCULATE, SOFTWARE SIMULATION

YIETNAM GENERAL CONFEDERATION OF LABOURTON DUC THANG UNIYERSITY FACULTY OF ELECTRICAL & ELECTRONICS ENGINEERING SUBJECT: ELECTROMAGNETIC TRANSIENT PROCESS MISSION: CALCULATE, SOFTWARE SI

YIETNAM GENERAL CONFEDERATION OF LABOUR

TON DUC THANG UNIYERSITY FACULTY OF ELECTRICAL & ELECTRONICS ENGINEERING

SUBJECT: ELECTROMAGNETIC TRANSIENT PROCESS MISSION: CALCULATE, SOFTWARE SIMULATION

ADYISED BY: Dr NGUYỄN CÔNG TRÁNG GROUP: 06

BY: NGUYỄN NGỌC HOÀNG vũ, StudentlD code: 41900916

NGUYỄN VĂN THẢNG, StudentlD code: 41900877 NGUYỄN MINH THUẬN, StudentlD code: 41900891 TRANG THANH TUẤN, StudentlD code: 41900912

LÊ MINH THẢNG, StudentlD code: 41900875

HO CHI MINH CITY, 2021

I Introduce tbe problem and calculate

Tbe fígure:

Detailed specifications;

Generator; SrG i 1 117,5 MVA; UrG1 1 10 KY; Cosọ 1 0.85; X^1 0.1593 , E^ 1

6.6 kV

System; c k.sys 1 176.5 MVA;

Transíorthers: SrTi 1 SrT2 1 125 MVA; Uđm 1 10.5/115 KV; UkTi % 1 UkT2 % 1 10.5%;

T3; SrT31 200 MVA; Uđm 1 15.75/242 KV; UkT3% 1 11%;

Lines; 11 1 45 km; 12 1 23km; 161 40km; All 4 lines have X’i 0.4 Y/km, R’ 1 0.3 Y/km, 110kY

Loads; stuck on busbar 22kV, SrL 1 15 MYA, Cosọ 1 0.8; X "L 1 0.4

Calculate sbort circuit:

Choose u bs=10KY

RL3 =R'L *3 *<u^)2=0.1 íi

Trans1, 2:

u % 2 10,5 10 2

X71 1 X72 1 Z T1 1 Z T2 = «b *ŨS= 100 * 125=0.084 a

10 2

* 1£=0.055 Q

200

Loads;

rl s rl w 15

EL = v rl *7 (cos cos + (sí^2 -X"r =22* 7 (0,8)2 + (síO.6 - 0.4)2 -X" r

=17,1KV

Electromotive of system return to base voltage chosen; Esys = u bs=10KV

Trans3;

T3

100 $rT3 100

Generator: X G = X"D =5^=!^ 5=0.14 ữ

Z1 =XG + XT1 =0.14j+0.084j=0.224j

z21XT3 + x sys i0.055j+0.57ji0.625j

Z3=XT3 + x rl i0.084j+5.1+4ji5.3+4.084j

(0.11+0.15 j)*(0.06+0.08j)

ZL12 1

Z LI ZLZ * L ZL-2Z L 3 10.11 + 0.15 j+0.06 + 0.08ĩ+0.1 + 0.13 j 1 0

-025+0.03 j

ZL„ĨT^LV- ‘°-1 i + ': 1 :j)’(0,1+ ’:13jí.,, 10.04+0.0=j

L13 Z

L1 +Z

L2+ Z

Z L23- , Z,L2*Z L ^„ ^(0 0 ^“06+2:^— 1 0.02+0.03j

Z

L1 +ZL2+ Z

Z4 1 ZL13 + Z2=0.04+0.05j+0.625j=0.04+0.675j

Z5 1 ZL23 + Z3=0.02+0.03j+5.3+4.084j=5.32+4.114j

„ „ Y,.„ Z , _ (0.025+0.03í)*(0.04+0.675í)

Z6 = Z4 + X L12 +^ i

ZiZ4

=0.06+0.7j

z7 =z5 + X L12 +ÍA^=5.32+4.114j+0.025+0.03j+

(O

'O25+O'O37')

*(5'32 +4'114;')

=5.7+4.15j

Y1 =1=7=5=4.46

1

Z 1 VO.224 2

1 1

Y7 =Z 7=V5.7 2 +4.15 2=0-14

BG.y1+Ễ'2«r7 6.6*4.46+18.1*0.14 x

Y 1 +Y 7 4.46+O.14

z17=Z1//Z7=5.54*10“3+0.22j

1

0.04+0.675;

Y

7

ỉ"—ỉ k 3* u bs —90 0*—=<> 9CA

ỉ k3-ỉsc eq U considerin ^^ 10-<0.ôkA

Eẹq

jk3 - _

sc - eq ^Z z sc

6.07

20.6kA

II Simulate the problem by software.

Introduction hbout software MELSHORT2.

• The Melshort provided by Mitsubishi is nearly perfect It provides all functions and information about short circuits

• The software can calculate short circuits at all times of breakers

• Help to choose a suitable CB (Circuit Breaker)

• The software is used to design a short circuit diagram easily In addition, the difference between two types of CBs is clearly shown through their routing curve diagram

• Because it is Mitsubishi’s software, the data intồrmation of eacb type of CB is shown very clearly in detail along with other data to make the calculation easier

Simulation

1

F'Jr Fdỉỉ y SìEÍvtiHi Cc-ỊEidJiahỉ:n P»Ịin<1 rtalnyi • ■|*mcEí‘rhi I-Iplp

Ụ ĩ H ‘í r r > -i Ẻ? [Ễ ■ -■

-Click the icons on the toolbar to create the diagram following the problem.

3 Enter the parameters

Sublransienl short-ciíéuit currerô l N kd[kÀ|

ĩíâmĩerìÈ shữltocuit curĩeni í'kd[kÀ]:

AC component ũf shoít-ciícuit current lacno-loâdíkA’

AC compũrtent of shoit-circiiib cunẹnt lac load(kA):

Peat value oí short-cÍTCUÌt currsnt lac[kA):

Cancel

■ 1 ổ J- ; ' ■ J |' li! -■ ' '

Ríísr&rttèNũ.: 1^1

prequen^y

f * Ẹ»Hs c ẸOHí

Cđlciilãtion paint

ỮK

o System

o Transỉồrmers (Tl, T2, T3)

Traristormer

Primâiy ÝũHageiy):

Secũndary vdlageM:

E aíthing Ỳiíỉtem ữn L'V

side:

c apãty|kVA):

Ralẽd ciirrẹnt ọf ẸẸCọndặry

S-ĩmpedanceíX):

X/R:

fieactanee[rtwhms):

Peak value ũFrush cỵrren((K hh

Peak vaíue aí rush currentíAr

Đamping time carstanttíTìíec):

OK

Ị 806667 1.587 2.S67 14 8786 120 Cancel 1'

o Lines

Tick in Calculation point to calculate sbort Circuit at Line 2

Sasic I 3phases I

4 Clỉck Number 2 to auto check the dỉagram

MELSHOR 2 - 'Prọiectl ms2 - Skeleton 7ICA]

Tbe software notiíĩcation

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1 I n □ rd£ r to cal cu fate ĩho rt-cir CUIt cu rrenE, phcaĩ e pu 5 lĩ í ưtton

ori

Click OK tben click Number 3 to calculate automatically and sbow tbe

result.

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III Comment, compare the results

Compare

Actual sbort circuit current

122.427kA Comment

• Manual calculation and software simulation is not too different

2 Rounding by manual calculation

20.6kA