ĐỀ THI ĐÁP ÁN MÔN HỌC TRONG KỸ THUẬT MEIF

Cfiu 8: (0.25 diem) Trong ciia so command cua Matlab, chung ta thirc hien lenh sau: >> a=[1 2 3]; >> b = a'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''' , >> a.*b Két qud in ra la: a.10 c. Cñu lenh bao lot Cñu 9: (0.25 diem) b.14 d. Tat ca deu sai. Trong ciia so Command cua Matlab, cho biét gia tr| cua x khi chung ta thee hien lenh sau: >> x = 0:2.5:8 a. 0 2.5 5.0 7.5 c. Cau lenh bao lot Cfiu 10: (0.25 diém) b. 0 2 4 8 d. Tat câ deu sai. Trong cira so command ciia Matlab, cho biét gia tri cua y khi chung ta there hien lenh sau: >> x = 0:2:6 >> y = 2*sin(x) a.Vecto 1 hing 3 cut c. Vecto 1 hang 1 cot Ciiu 11: (0.25 diem) b.Vecot I hung 4 cot d. Can lenh bao lot. Cho 2 vector x = [1 2 3) va y = [1 0 0], cau lenh nao sau day la SAI: a. pie(x)b. pie(x,y) c. pie(y,x)d. Khong ciu lenh mo SAI. Can 12: (0.25 diem) Cho vecto x cé gia tr| nhu sau: >> x = [l:5] De ve do th| sin2(x), cau lenh nao sau day la DQG: a.plot(sin(x)^2) c. fplot( ''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''sin(x)^2'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''' ) Cau 13: (0.25 diém) b.plot( ''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''sin(x)^2'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''' ) d. Tat ca déu sai. Trong cac cau lenh Matlab sau, can lenh nao la DQG: a. >> y — sym(x)b. >> y = syms(x) c. >> y = sym( ''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''x'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''' )d. >> y = syms( ''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''x'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''' )

TRU'dNG BH SU' PHAM KY THUAT TPHCM

KHOA CO KHI CHE TAO MAY

BO MON CODIENTU'

DE THI CUOI KY HOC KY I NAM HOC 2019-2020 Mon: TIN HOC TRONG KY THUAT

M3 mnn hnc MF.TF1,14529 Chu’ ky giam thi 1 Chu ky giam thi 2 Be so/Ma dl: 01 Be thi co 08 trang.

Thai gian: 70 phut

Dirac phep su dung tai lieu (KHONG su dung laptop).

CB cham thi thu nhat CB cham thi thu hai

So cau dung: So cau dung:

Diem va chir ky Dilm va ch& ky

Ho va ten:

M as6SV :

So TT: Phong thi:

PHIEU TRA LOfI

Hiro'ng dSn tra 161 cau hoi:

Chon cau tra lai dung: Bo chon: Chon lai:

PHANI-M ATLAB (15 cau)

Lenh close all trong Matlab co chuc nang:

a Dong toan bo cua so lam viec

c Dong toan bo cua so do hoa (Figure)

a Vecto 1 hang 3 cot

c Vecto 1 hang 1 cot

b Vecot 1 hang 4 cot

d Cau lenh bao 16i

d Khong cau lenh nao SAI

B6 ve d6 thi sin2(x), cau lenh nao sau day la BUNG:

a plot(sin(x)A2) b plot( 'sin(x)A2 ')

c fplot( 'sin(x)A2 ') d Tat ca d6u sai

b Net li€n, mau den

d Net dut, mau den

Khi chay chuang trinh, ducmg d6 thj co dang:

a Net lien, mau xanh

c Net dut, mau xanh

Cau 15: (0.25 di£m)

Cho cau lenh sau:

» x = [1:5]

» pIot(x,xA2)

Khi chay chuong trinh, ket qua se la:

a Duong d6 thi co mau xanh

c Cau lenh bao loi

P H A N II - C (2 5 cau)

Can 16: (0.25 diem)

d Net dut, mau den

b Duong do thi c6 mau do

d Tat ca deu sai.

Cho a,b la bien s6 nguyen (int) va a = 5, b = 2, c = 2 Hay cho biet gia tri cua bieu thuc: a/b/c

d Tat ca deu sai.

Cho a,b la bien so nguyen (int) va a = 4, b = 3 Hay cho bi6t gia tri cua biSu thuc: (a++*++a)%b:

c 2.

Cau 19: (0.25 diem)

d Tat ca deu sai.

Cho a,b,c la cac bi6n s6 nguyen va a = 4, b = 2, c = 3 Hay cho biet gia tri cua bieu thuc:

char S I[10] = "12345", S2[10] = "abcde";

for (int i = 3; i>=0; i—)

{

if ( i%2 == 0) Sl[i] = S2[i+1];

else S2[i] = Sl[i+1];

for (int i = 0;i<3;i++)

{ for (int j = 0y<3J++)

{ if (i = j) x = x + M[i][j];

}}

Ghi chu:Can bo coi thi khong duoc giai thick de thi.

Cliuan dau ra cua hoc phan (ve kien thuc) Noi dung kiem tra

[CBR 1.1]: Giai thich duoc, mo ta duoc hoat dong cua mot

chuong trinh lap trinh may tinh

Cau 1,2,3,4,5,6,7,8,9,10,11,12 31,32,33,34,35,36,37,38,39,40[CBR 1.2]: HiSu va giai thich duoc cac luu do giai thuat Cau 13,14,15,16

[CBR 2.2]: Trinh bay duoc cac bai toan dieu khien duoi

dang thuat toan va giai thuat

Cau 17,18,19,20,21

[CBR 4.1]: Bi6t su dung cac phuong phap lap trinh de xay

dung chuong trinh

Cau 22,23,24,25,26,27 28,29,30

Ngay 15 thang 12 nam 2019

^T ruong bo mon

TRU'CSNG BH SU' PHAM KY THUAT TPHCM

KHOA CO KHI CHE TAO MAY

D £ THI CUOl KY HOC KY I NAM HOC 2019-2020 Mon: TIN HOC TRONG KY THUAT

M3 mnn hnr,- ME,TF1 ^4^7.9 Chu ky giam thi 1

n/y

Chu ky giam thi 2 B6 so/Ma de: 02 Be thi co 08 trang.

Then gian: 70 phut

Dirffc phep sir dung tai lieu (KHONG su dung laptop).

CB cham thi thu nhat CB chtim thi thu hai

S6 cau dung: So cau dung:

Diem va ch& ky Diem va chu ky

Ho va ten:

M asoS V : S6 TT: Phong thi:

PHIEU TRA LOT

Hiring dan tra 161 cau hoi:

Chon cau tra lcri dung: N<T Bo chon: ]^ T Chon lai:

PHANI-M ATLAB (15 cau)

Khi chay chuong trinh, duong do thj co dang:

a Net lien, mau xanh

c Net dut, mau xanh

b Net li6n, mau den

d Net dut, mau den Cau 4: (0.25 diem)

Trong cua so Command cua Matlab, cho biet gia tri cua x khi chung ta thuc hien lenh sau:

Khi chay chuong trinh, ket qua se la:

a Duong do thj co mau xanh

c Cau lenh bao loi

b Duong do thi co mau do

d Tat ca deu sai.

Cau 6: (0.25 diem)

Trong cua so command cua Matlab, cho biet gia tri cua y khi chung ta thuc hien lenh sau:

» x = 0:2:6

» y = 2*sin(x)

a Vecto 1 hang 3 cot

c Yecto 1 hang 1 cot

b Vecot 1 hang 4 cot

d Cau lenh bao loi

Lenh close all trong Matlab co chuc nang:

d Tat ca deu dung

a Dong toan bo cua so lam viec

c Dong toan bo cua so d6 hoa (Figure)

Cho doan chuong trinh nhu sau:

char S[20] = "KIEM TRA";

for (int i = 0;i<2;i++)

{ for (int j = 0y<2y++)

if ( i%2 = 0) S 1 [i] = S2[i+1];

else S2[i] = Sl[i+1];

for (int i = 0;i<3;i++)

{ for (intj = OJOJ-H-)

{ if (i == j) x = x + M[i][j];

}}

Ghi chit:Can bo coi thi khong duac giai thick de thi.

Chuan dau ra cua hoc phan (ve kien thuc) Noi dung kiem tra

[CBR 1.1]: Giai thich duoc, mo ta dugc hoat dong cua mot

chuong trinh lap trinh may tinh

Cau 1,2,3,4,5,6,7,8,9,10,11,12 31,32,33,34,35,36,37,38,39,40[CBR 1.2]: Hilu va giai thich duoc cac luu do giai thuat Cau 13,14,15,16

[CBR 2.2]: Trinh bay duoc cac bai toan dieu khien duoi

dang thuat toan va giai thuat

Cau 17,18,19,20,21

[CBR 4.1]: Biet su dung cac phuong phap lap trinh de xay

dung chuong trinh

Cau 22,23,24,25,26,27 28,29,30

Ngay 15 thang 12 nam 2019

P. Truong bo mon

TRCONG BH SC PHAM KY THUAT TP.HCM

KHOACO KHI CHE TAO MAY

BO MON CO BIENTC

DE THI CUOI KY HOC KY II NAM HQC 2019-2020 Mon: TIN HQC TRONG KY THUAT

Ma mon hoc: MEIF134529

Chu ky giam thi 1

P Chii ky giam thi 2

c B6 s6/Ma d6: 01 B6 thi co 08trang

Thai gian: 60phut

Bugc phep sir dung tai lieu (KHONG dung laptop)

SV lam bai tru e tiep tren de thi va nop lai deDiem va chir ky

CB cham thi thu nhat CB cham thi thu hai

Ho va ten :

M a s 6 S V :

So T T : Phong t h i :

PHIEU TRA LOT

Hirtmg d in tra 151 cau hoi:

Chon cau tra ldi dung: Bo chon: Chon lai: j^ T

Ham ceil(x) trong Matlab duqc hilu la:

a.Lam tron len

c.Lam tron xuong

Cau4: (0.25 diem)

b.Tinh |x|

d.Tat ca dlu sai

Trong cira so Command cua Matlab, chung ta thuc hien lenh sau, hay cho bilt k it qua:

» 3 A3/3\3A3

a.l

c.Cau lenh bao loi

b.3d.Tat ca deu sai

Khi chay chuong trinh, k it qua se la:

a.Budng do thi co mau xanh

c.Cau lenh bao 16i

b.plot(x)d.stem(x)

b.Buong d6 thi co mau do d.Tat ca dlu sai

Trong cac cau lenh sau, cau lenh nao la BUNG:

a.char A[] = “ 123”; b.char A[3] = 123;

c.char A[3] = “ 123”; d Tat ca dlu dung

D o a n chicffng tr in h s au d u n g c h o c a u 2 2 ,2 3 :

int tong = 0, max = 0;

for(int i = 0; i<5; i++)

if(i%2==0) tong = tong + i;

D o a n c h ita n g tr in h sau d u n g cho cau 27,28:

for (int i = 0;i<strlen(S);i++)

{ for (int j = 0y<strlen(S)y++)

Cau31: (0.25 diem)

Cho biSt k it qua in ra man hinh sau khi chay doan chucmg trinh tren:

D oan c h u ffn g t r in h sau d u n g cho cau 32,33,34:

int M[2][3] = {1,2,3,4,5,6};

for (int i = 0;i<2;i++)

{ for (intj = 0;j<3y++)

{ if(M[i][j]<M[i][i]) M[i][j] = M[i][i];

else M[i][j] = 0;

printf("%d",M[i][j]);

}}

D o an chieang tr in h sau d u n g cho cau 35,36,37:

D o a n chieorng tr in h sau d u n g cho cau 38,39,40:

Ghi chu:Can bo coi thi khong duac giai thick de thi.

Chuan dau ra cua hoc phan (ve kiln thuc) Noi dung kiem tra

[CDR 1.1]: Giai thich duac, mo ta dugc hoat dong

cua mot chuang trinh lap trinh may tinh.

Cau 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16 31,32,33,34,35,36,37,38,39,40[CDR 2.2]: Trinh bay duac cac bai toan dilu khien

dudi dang thuat toan va giai thuat.

Cau 17,18,19,20,21

[CDR 4.1]: Biet sir dung cac phuong phap lap trinh

de xay dung chuang trinh

Cau 22,23,24,25,26,27 28,29,30

Ngay 21 thang 07 nam2020

TM Trirong bo mon

So hieu: BM3/QT-PDBCL-RDTV Trang: 8/8

TRtfCJNG BH SU- PHAM KY THUAT TP.HCM

KHOACO KHI CHE TAO MAY

Be so/Ma d6: 02 B Sthico 08 trang

Thai gian: 60 phut

Bugc phep su dung tai lieu (KHONG dung laptop)

SV lam bai true tiep tren de thi va nop lai de

Hufrng d in tra lfri cau hoi:

Chon cau tra lai dung: Bo chon: | ] ^ Chon lai

PHAN I - MATLAB (15 cau)

Cau 1: (0.25 diem)

Trong Matlab, de giai phucmg trinh sin(x) = 0, ta sir dung cau lenh nao sau day:

a.solve(‘sind(x)’) b.solve(‘sind(x) = O’)

c.solve(‘sind(x) = O’) d.Ca 3 cau lenh dSu dung

Ham ceil(x) trong Matlab dugc hi6u la:

Cho cau lenh sau:

» x = [1:5]

b » y - x.*eAx

d Khong cau lenh nao dung

» p lo t(x ,x A2)

Khi chay chuong trinh, ket qua se la:

a.Buong d6 thi co mau xanh c.Cau lenh bao loi

Cau 12: (0.25 dilm)

Cho vecto x co gia tri nhu sau:

b.Bubng do thi co mau do d.Tlt ca deu sai

» x = [1:5]

Be ve do thj sin(x)cos(x), ta sir dung cau lenh nao trong cac cau lenh sau:

a.fplot('sin(x*cos(x)') b.fplot(sin(x)*cos(x))c.plot( sin(x).*cos(x))

b.3d.Cau lenh bao loi

Trong cac cau lenh sau, cau lenh nao la DUNG:

a.char AQ = “ 123”; b.char A[3] = 123;

c.char A[3] = “ 123”; d T it ca dlu dung.

D o an chwcfng trin h sau d un g cho cau 24,25,26:

int M[2][3] = {1,2,3,4,5,6};

for (int i = 0;i<2;i++)

{ for (intj = 0y<3y++)

{ if (M[i][j]<M[i][i]) M[i][j] = M[i][i];

printf("%d",M[i][)]);

}}

Cau 26: (0.25 dilm)

Cho biet ket qua in ra man hinh sau khi chay doan chucmg trinh tren:

D o a n c h ittin g tr in h sau d u n g cho ca u 2 7,28:

int tong = 0, max = 0;

for(int i = 0; i<5; i++)

D o a n c h ittin g t r in h sau d un g cho ca u 29,30,31:

D o a n ch u ffn g trin h sau d u n g cho ca u 32,33,34:

D o an ch u ffn g trin h sau d u n g cho cau 35,36,37:

for (int i = 0;i<strlen(S);i++)

{ for (int j = Oy<strlen(S)y++)

Ghi chu:Can bo coi thi khong duoc giai thick de thi.

Chuan dau ra ciia hoc phan (ve kien thuc) Noi dung kiem tra

[CBR 1.1]: Giai thich duoc, mo ta duoc hoat dong

cua mot chuong trinh lap trinh may tinh

Cau 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16 31,32,33,34,35,36,37,38,39,40[CBR 2.2]: Trinh bay duoc cac bai toan diSu khien

dudi dang thuat toan va giai thuat

Cau 17,18,19,20,21

[CBR 4.1]: Biet su dung cac phuong phap lap trinh

d! xay dung chuong trinh

Cau 22,23,24,25,26,27 28,29,30

Ngay 21 thang 07 nam2020

7 M Truong bo mon

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