Tài liệu thiết kế biện pháp kỹ thuật thi công lắp ghép nhà công nghiệp 1 tầng

CHON CAN TRUC Sau khi x6c dinh duoc c6c th6ng sd yOu cdu ta tien hdnh chon cdn truc lhm c6n g t*c 16p gh6p vh phuc vu.. - Cdn rruc c6 gi6 chi phf thap nhdt tfc td cdn truc c6 th6ng sd s6

Lor Nor oAu

Corrg nghe -ruy tlryltg tlteo phrftng phtip lrip ,qltep ld ntot trortg nhltng cOng

rilrt) t'6ng rtghiep ntot tirrg N6 tuo di|'u ki€rt cho r'6ttg nghiep h6u hi€n dui h6a

rte()nh sdn nui't.vuy tl4nrg,diiy rthunlr tieit cl6 thi t'6rtg, ttitts nting suA't luo cl6ng

vti ,qitim luo d)rtg t,ti't t,ti cho cotrg nltun

De gifip t'lro t'tirt bO kt thuit t'tiy tl4ntg tf rth totirt c'hfnh rtit' r'tit' thong s6'ltu

t'ltort plrto'trg drt khti tlti,ltqp ly, cltilng tdi bi€n soun cuo'rt "Thi07 kA'bierr phtip

kl tlruut thi t'ong lup gtrep rrlrt) t'ortg nghi€p nfit tdrrg" ltlnt ttii tiett htortg din

ttltlnrg didm co btirt nhu't nu) ngtdi k! thuAt phdi t'dn

!tb'i dot' t'6 fid sft dryrtg cld tlri€t ke'nrbt d6 dn ttdng tt.t Stit'h citrtg tltitrg cle' ltint

'.,'

lieu hoc tup cho sirrh vi|rt t'tit'ttgdr*,rdy dtng t'6rtg tt'inlt t,d nhlffig ui qtrurt

' ,,,t cl€it t'orrg t,i€t' ruy tlmrg

Tltunr giu bi€rr soun tdi li€u rfiy gdm r'6: TS Nguy[n Dinh Thtim t'hti tt'i t,d

- ' Plrtirr I , K S T u T h u n h B i r t h t, i A 7 P h c i n I L

Do t'6n lt kinh nghiAnt vt) ldn diiu ra nrcit hun doc'nAn t'htit't'6n rt?'t nhi6n

.',/ r'//i ldng bd cluu vt) g6p i dd ltin trii htin phut'rtr! bun dot'dtdc t6't hon

P H A N 1 - L Y T H U Y E T

THIfT K6 PHUONG Ax THI COXC LAP GHEP

NHA COXC NGHIEP 1 TANG

: PHAN ricu DAc ordu cOxc rnixn

De c6 thd chon phuong 6n hop ly, ngudi thidt kd phii hidu sAu sdc d[c didm cOng::.rii Khi tim hidu c6ng trinh, cdn di sAu vho c6c chi tidt sau:

- Kfch thudc mat bang bidu hiOn bang sd nhip, so budc, k(ch thudc cia cdc nhip L,

- -.i btrdc cot B (ndu L< 15m lh nhd loai nh6, cdn L > 15m lh nhd khdu do lon) vd ndnr.:" \eu hay ch6c, dd tU d6 dinh hucrng chon loai cdn truc bdnh xfch hay b6nh hoi

- Giai ph6p rnf,t b6ng, so khe bien d?ng, ciich bd tri nhip d?ng song song hay vudng : tao thhnh hinh chfr L hay chfr T lhm co s& chon phin doan thi cdng

- Chi0u cao cfia cOng trinh lay til cot 0.00 (m4t ndn) ddn ddu cdt, vai c6t, dinh gihn,

j : n6c dd dinh hu6ng chon cdn truc Loai cao tr0n 10m, thap du6i 10m

- D4c didm cdu kiOn ld be rong cot th6p hay th6p Chi tidt liOn kdt mdi ndi bu l6ng:.: hay moi ndi udt (yeu to quyet dinh ddn cdng nghe thi c6ng) C6c th6ng sd vd cdu

L -: hinh ddng, kich thudc, trong lugng dac biOt chf f ddn cau kiOn kh6 l6p (n4ng,cao,

t

4 :

\loi liOn quan gifra lap gh6p thiet bi c6ng nghg ctra dAy chuydn sin xuat vdi l5p gh6p

FT : r o c0ng trinh Thf tu trudc, sau hay kdt hqp Ndu cdn thi phii c6 h6i nghi bdn

pr -'ng 6n thi c6ng gifra don vi xay dung ve bon l5p m6y dd c6 su phdi hqp nhip nhing

- Fhin tfch didu kiOn thi c6ng gdm dlc didm: mit bang thi cOng c6 gi bi han chd, ldiu,.u- khong gian, ndn dat (ydu hay chSc) duong xe vAn chuydn mdy m6c, cau ki0n

l,: ca su phAn t(ch dac didm c6ng trinh duoc thd hien trOn bin vE so d6 lip gh6pcr.i tdnh (g6- mQt mit bdng vA cdc mit cit) Trong d6 thd hiOn rd c\c k;i hi6u cauh :'- , i trf l6p cua n6 trong c6ng trinh

rtrar cAr sO od lAp cHEp cOrc rnixn

I iu rtpx

Ir THoNc rE cAu rrpx

v i e c t h o n g k0 cau ki€n nhdm tdng hcrp khor ,u.-r:.ons'i€c girip ngud'i thiet Ihinh dung duoc tinh phric t?p cria cdng trinh re nr: j.r:r luorre.Thong ke dua ydo bj

vE so d'd l5p gh6p sO khOng bo s6t nhat ld voi nhieu :au kien giong nhau v€ hinh diirsong c6 nhidu chi tiet kh6c bi€t nhin thay vd khong nh)n rhar

6

Hinh d:ingkich thu6c

Cau ki0n thdng k0 duoc ghi vho bang 1.1 gdm c6 cdc c6t chfnh sau:

Bfrng 1.1

Cot 1: Thri tu cau kiOn nOn ghi theo tr)nh tu l6p gh6p c6c cau kiOn

-Cot 2: Ghi ten cau kiOn thudrrg goi khu theo mA hiOu trong hd so thidt kd (KT, KC,lCr Vi du cot bien C,, c6t biOn g6c C,,,, cQt gilra C,, c6t giira hdng hi0n Crn, c6t gilra: : 3 n h i O t C 2 i , , ) ; x e m h i n h 1 1

Cot 3: VE hinh d6ng ciia cau kiOn dd de nhAn d+ng tr6n

j -' ghi ba kich thudc l.p, b"r, h"r l

- chidu dhi cau ki0n vu6ng g6c tay cdn truc;

r-.i - chidu dhy cau kiOn trong mat phing ddng chrla tay cdn;

:r, - chidu cao cdu ki0n theo phucrng thing doi

D0 phAn biet /, b, h, ta cdn cr,i vho trang th6i cdu ki€n

i , ,S cziu l6p, lay kfch thudc ldn nhat

Cot 4 - Don vi tfnh li c6i, chidc (sd ddm)

,lot 5 - Sd lugng tinh theo so dem cira tirng rnd hiOu cau kiOn

,lot 6 - Trong lugng lay theo Catal6 don vi lh tan, lay chinh x6c sau dau phdy m6t sd.l,rt 7 - Tich cfra c6t 5 vdi c6t 6

l,rt 8 - Ghi chri nhlrng dAc didm ctra cau ki€n nhu: c6 quai cdu hay kh6ng c6 quai?

i :l\i chot cdu? gia cudng cau kiOn khuech dai ?

_ HON THIET BI TREO BUOC

e Treo buOc cOt

vh dung cu sdn c6 ta chon ciic thidt bi treo bu6c thfchchon dudng kinh dAy c6p, kich thudc thidt bi, chidu

l-.:t bi treo bu6c cOt c6 thd chon c6c loai sau:

+ DAy cdu k6p buOc theo cdch br"roc trbng (hinh l.2a) ndu c6t nho Q < 500kg Kh6ng

c6 vai hay 16 chi chdt thi c6ng;

+ DAy cdu hai nh6nh c6 vdnh khuyOn dDng v6i c6t c6 16 cdi chot thi c6ng c6 thO dilng

chot kho6 b6n tu dQng (hinh l.2b);

+ Dai kep ma sdt khi c6t c6 vai (hinh l.2c)

Luc cing trong dAy c6p tinh theo c6ng thfrc:

S _ m.KQ.r.

n cos 0"

Trong d6:

K: h0 sd an tohn, lay k = 5 + 6

m: h€ sd kd den sfc cdng day khOng ddng ddu Ldy:

m - 1,0 dAy chd tao tai nhh mdy chuy6n dirng;

m = 1,2 ddy chd tao tai xu&ng gia c6ng

n: so nhdnh diy treo vAt (n - 2);

0': g6c gifra soi cdp vh dAy doi (ct = 0);

Til S tra bing (xem phu luc 1) chon D day cdp

U

T

f -ir

b) Treo buOc ddm cdu chay

Yi kh0n g c6 quai cdu, nOn ddm cdu

r.:od bdn tu dQng & hai ddu c6ch ddu

jng lOn, nhdnh cdp cira dAy cdu phii

rdnh luc doc phdt sinh lon (hinh 1.3)

ch?y thudng duoc treo bdng hai dAr cau kJp ;.'mrit khoing 0,1L, sau d6 dirng cdu hai moc detao v6i duong n6m ngang mQt g6c a > J5' de

Hinh 1.3: Treo bubc' cliim t'du trryt'

1 Th6p dQm; 2.Day cdu; 3 Kh6a; 4 dng ludn cr{p

Luc cdng day c6p tinh theo c6ng thrfc

'\ KQ

t - ffi = chon dAy c6p theo bAng 1 (phU lgc).

Luc cf,ng trong dAy crip tfnh theo c6ng thric:

2 s i n o 4 sin s

G6c cr phAi chon sao cho h,o cira dbn treo khdng lcrn qu6 lirm tang chidu ddi tay cdn,

nhung cfrng khong nh6 qud l)m luc n6n phdt sinh gAy mat dn dinh cira cau kiOn cfrng

nhu xh ddn Til cdch treo budc ta quydt dinh phuong 6n gia cuhng cau ki0n (xem s6ch

K! thuAt xay dqng tqp2 - COng t6clap gh6p vh xAy gach ddt

d) Treo buOc Panel sin, m6i

Khi treo bu6c panen shn, m6i thi tu! theo kich thudc cua cau ki€n ta c6 thd chon

chilm dAy cdu 4,6 hodc 8 m6c (hinh 1.5)

H i n h l 5 T r e o b u d c p a n e n m d i

Chidu dhi cira dAy c6p chon sao cho g6c nghiOng o so v6i m6t bang ldn hon 45"

(cr ) 45') Dd luc cdng trong cdc ddy c6p b[ng nhau thi chim dAy cdu phii c6 co cdu tu

cAn bdng theo nguyOn t6c ttng ddi mOt LUc cing duoc tfnh theo cOng thric:

e) Treo bu0c tdm tudng cfra sd

Cau kien tudng thudng c6 2 quai cdu (rat hidm khi gap c5 sd quai cdu nhidu hon) n6n:-r thudng ding dAy cdu hai m6c tuctng frng vdi sd quai cdu cria cau ki6n L\rc cang dAy-in tfnh theo cdns thric:

KQ

S

-O day chon cr = 400 + 50o

Neu dAy cdu c6 sa-n ta dtrng c6ng thfic:

ffi, k, Q nhu dd trinh bhy

L - khoAng cdch gifra hai/ - c h i O u d d i

Hinh 1.6: Treo bu6c tdnt tudng

Sau khi chon cdc thi€t bi treo budc ta c6 thd bidt duoc rrong lugng crta cdc th^dt

:_ r Ndu kh6ng bidt chinh xdc tac6 thd udc lugnrg g,u S 0,1 e"o

bi d6

l 1

rv xAc Dr-NH cAC rsONc sd cAu r-AP

Dd c6 co s& chon cdn truc mQt c6chchinh x6c tacdn x6c dinh c6c thong sd tdi thidu

cdn truc phai d6p tmg, R.in, Q.in, H.in, L*,n hay ta cdn goi ld th6ng sd yOu cdu R'"' Qv"'

Hu., Ly

Trong d6:

Qr = Q.r * g,u lh stlc nang toi thidu cdn truc phii nang duoc;

Hr = Hn, * h.6p = H' + a + h'k * htn * h'un(xem hinh hinh l'7);

H,_- chidu cao vi trf l6p cau kiOn tinh til mdt ibang mdy dfngt

a - chidu cao nAng b6ng cdu kiOn trOn vi trf l6p a = 0,5 + lm;

h.* - chidu cao cfia cdu kiOn;

h,n - chidu cao thidt bi treo bu6c;

h.6n - chidu ,Cdi dAy cdp cdn truc tinh til

R ,-;- -

I

I - i;inr vdi ngan nhat cdn truc c6 thd tidp cAn vi tri l6p Rr phu thu6c vdo mat bang-* -r.-p rvAt cdn khong cho cdn truc ddn gdn vi tri l6p nhu dong ddt, c6ng trinh, ao hd.r-.,r \.\' vd g6c nAng cdn tdi da (cr*o* -75\ hodc vi trf tdi uu ctra tay cAn

- \:u khong phu thu6c vAt can (khong didm ch4m) thi Ry x6c dinh nhu sau (hinh 1.7):

xuat hi0n didm cham (xem s6ch K! thuAt xAy dUne - T4p 2) thi

e - khoing c6ch an tohn cho cdn lay e = 0,5 + 1;

b - khoing cdch n6m ngang tir m6c cdu ddn didm cham;

H.r, - chidu cao didm cham tay cdn, tfnh til didm cham ddn khcrp tay cdn theophuong dring;

o,," - g6c tay cdn tdi uu rfng vdi tay cdn ngan nhdt c6 thd l6p cau kiOn;

\eu khi l6p tay cdn

: I theo cOng thrlc sau:

Tinh theo c6ng thric: 0,* = arctg

0t* = arctg

(dilng m6 chfnh);

I H ^ ut/;-* (dtrng m6 phu);

Trong d6:

b - nhu tren;

/p = 3 + 5m chidu ddi cdn phu, tuj' thu6c loai cdn truc

Tat ca c6c thong sd Rr., Qr", Hr", L-in, cria cdc cau kiOn duoc xdc dinh vd ghi vdo

bang chon cdn truc 1.2, cdt tir I ddn 7

Th6ng so cdn truc

Ghichu

Qr Rr. Hr. L*i,', Q", R.t H.t L-in

V CHON CAN TRUC

Sau khi x6c dinh duoc c6c th6ng sd yOu cdu ta tien hdnh chon cdn truc lhm c6n g t*c

16p gh6p vh phuc vu Chon cdn truc dua trOn nhlrng nguyOn t6c sau:

- Cdcthong so yOu cdu phii nh6 horn thdng so cria cdn truc

- Nhfrng cdn truc du-o c chon c6 khi ndng tiep nhAn dO ding (noi cdp, hinh thirc tidp

nhAn, thdi gian van chuydn ) vd hoat dQng duoc trOn mit bang thi c6ng

- Cdn rruc c6 gi6 chi phf thap nhdt tfc td cdn truc c6 th6ng sd s6t vdi tiiong so yOu

cdu nhat (cdc rfnh nf,ng ctra cdn truc duoc thd hien qua bidu d6 tfnh ndng vd cdc thdng

so cdn thidt (catal6)

Nghia l):

L., ) L*,n

Qr S Q.,, Ry" < R(Qr.)cdn rruc Hy" < H- i omin ( 0., ( 0-u* =7 5"

Sau khi chon duoc cdn truc ta ghi c6c sd liOu cua cdn truc bd sung vho Bin g 1.2: c6t"

8 ghi t6n m6y; cqt 9 - srlc nang cfra cdn truc; l0 - tdm vdi cria cdn truc; 11 - chidu cao

nAng m6c; 12 - chidu dii tay cdn; 13 - nhfrng ghi chri cdn thidt

Ta lu6n nhd cdc dai luong Q.,; R",i H cira cdn truc lu6n phu thudc 16n nhau qua

bidu dd t(nh n6ng, vi vAy ddu tien ta chon ho cdn truc sau d6 chon chidu ddi tay cdn

dd bidt duoc bidu dd tinh ndng (xem phu luc) Ba dai luong Q", , Rct, H sE lay mdt

d+i

\ y c

l\

t l

I

s

S O C

mfrlap

d 6 ((

t a qr'6icautruc

\/I

(

Jo chon cdn truc cho tlng nh6m.

C6ch lhm tr0n cho ph6p ta ddn su du thila khi nang ctra cdn truc vdo nhfrng th6ng sd:r quan tAm dd tAn dung hdt khA n[ng cfia cdn truc Vi du ddn khi ning thila vho tdm.di dd c6 thd d.nrg mQt ch6 l6p nhidu cau ki6n, hodc ddn vho H." dd khi l6p didu chinh.-iu kiOn mdm hcrn, cdn ddn khi n[ng thira vho Q chi dd tlng dn dinh chdng lAt cho cdniruc (rdt ft ding)

\-I CHON VI TRi DTNG VA DUONG DI CUA CAN TRUC

R.in - cho ta khoin g cdch cdn truc kh6ng duoc dturg gdn hon.

R*o* {hay R", (Q.*) } - cho ta khoin g cdch cdn truc kh6ng thd dung xa hon vi trf lip.R., (Q/2) - cho ta khoAn g c6ch didm m6c cau kiOn khOng thd c6ch xa vi tri dfrng ciracdn truc Khi cdn truc nAng mQt ddu cau kiOn vdi cdu kiOn cdn truc l6p theo phuongph6p quay Lfc ddu cdn rruc nAng mQt ddu cdu kiOn lOn sau d6 nAng bdng vdo vi tri l6p(l6p cot)

Til d6 ta x6c dinh vi tri cria cdn truc nhu sau (hinh 1.8): Til vi tri l6p v6 duhng trbnb6n k(nh Rn,in vd R-.* {hay R., (Q.o) } hinh vdnh xuydn gifra hai duhng trbn ld c6 thdcho cdn truc dfrng dugc

- Ndu hinh vhnh xuydn khong c6t nhau cdn truc dung mQt vi trf chi l6p duoc mOt caukiOn (hinh 1.8a)

- Ndu hai vdnh xuydn cdchnhau cdn truc drnrg trong khu vuc giao nhau sO l6p duochai cau kiOn (hinhl.8b, d)

- Ndu 4 vdnh xuydn c6t nhau ta c6 vi trf cdn truc dung (vDng giao nhau) l6p 4 cdukien (hinh 1.8c)

Tuong ru ta tim vi tri dtrng mh cdn truc c6 thd l6p duoc nhidu cau kiOn nhat

Ndi c6c didm dung li€n tiep cria cdn truc ta duoc dulng di cria cdn truc (hinh 1.9 v)

Hinh 1.10: sort6 b6',tt.i ttiir kien cli t'huydn crfu ldp tldn mdi,punen

4tr-13ryg, dd c6 th€j thuc hien lap theo p ,.@

chAn cau kiOn nam trong bdn kinh R didm treo trong bdn kfnh R(Qr"/2).

Vi6c bd trf sao cho cdn cdu nAng l6p cdu kiOn thuAn loi nhat dtnrg 15pkh6ng bivudng, bdn kinh quay cdn nh6, sfrc nAng cdn truc kh6e-

Trong trudng hqp cau kiOn duoc l6p til xe vAn chuydn th) phii dua xe vDro trong tdmhoar dQng cira cdn truc Cau kiOn duoc nAng lOn sao cho d€ d)ng phD h-o p vh an tohn cho

re vOn chuydn, cau ki6n kh6ng dua qua n6c budng l6i xe

VII CHON PHI-IONG AN T-AP GHEP

TrOn co so nhlrng giAi ph6p ky thuAt khA thi ta c6 thd chon c6c phucrng 6n thi c6ngiap gh6p

Mqt phucrng 6n thi cong bao gdm nhidu giii phdp ky thuAt vd td chrlc khA thi m5i:not su thay ddi c6c giii ph6p ld c6 c6c phuong 6n khdc nhau

V0 mlt k! thuAt c6 thd ld cdch chon loai cdn truc, so cdn truc, su kdt hqp c6ch bo tri:au ki6n v.v vd m1 td chfc c6 thd ld thfi tu l6p, sd phAn doan, dulng di ctra cdn truc,.u ket hqp cdn truc v.v

t 7

vrrl t-Ap rmx oO rHt cOxc IAP GHEP

Dtra vdo chung loai cau kien, trong lugng cau kion

mirc (xem phu luc) tim chi phi nhan c6ng vd ca m6y

brlng thong so tien d0 - bing 1.3

G i dc0ng

G i dm6y

Cam6y

NhAncdng

- rhd hi6n tidn d6 l6p gh6p c6r vh ddrn cdu truc Lap cdt ding cdu CKG -25, c6t truc Al6p ttr I ddn n; rruc B l6p tir n vd 1; truc C l6p til I den n (cdn truc di lon) L6p ddm cdutruc ding cdu E 12028 di gifra IEry 2 truc A vh B tt 1 ddn n; ddm cdu truc dor: truc c dibiOn l6p tt} n vd I

vd loai cdn cdu ta tra bAng dinhcho tDng cau kiOn kdt qui ta c6

Hinh I.Ila: So d6 phdn docln thi cdng kip ghep

l 9

1 Chon cdn truc boc xeP

So cdn cdu cdn phqc vu bdc xdp tfnh theo cong thfc:

r , f r Q rM _ f f i K [ m 6 y l

Trong d6:

IQ.* - tfing trong lugng cau kiOn lap gh6p ltAn;;

T - thdi gian thuc hion cong t6cl6p gh6p (lay theo tien d0) (ngay):

Z - s6 gid lhm viOc trong m6t ca;

P - Nang suat bdc xep trung binh ctra cdn truc (t6nlgid);

K - Hg sd su lhm viec khong ddu ctra van chuydn K = 1 boc tai nhi m6y,K = 1,1bdc tai bdi cau kiOn'

2 So s6nh phuong 6n l6P gh6P

Dd chon duoc phuong dn phir hgp ta c6 thd chon theo c6c tieu chi sau:

( 1) Thdi gian thuc hi6n l6p gh6p - T.

(2) Gi6 thdnh thuO mdy C = I Cn,,iy.Vh gir{ thhnh l6p gh6p tren 1 ran cau ki€n

n, sd cau kiOn loai i

Sau dAy li mdt bhi vi du vd phuong phdp thidt ke bi0n phr{p k! thuar rhi c6ng l5pgh6p nhh c6ng nghiOp 1 tdng, n6 sE gidp ban doc hinh dung de dhng hon cdc phdn lfthuydr rrinh bdy rr6n day

w - I K r n i

' \ s d -

) f l ,I

- 1

21

pHAru lt - THi ou

Tr6n h)nh 2.la,,b lh so do lap gh6p cdng trinh ta cdn lAp biOn ph6p thi cdng COng

trinh ld loai nhir c6ng nghiep mOt tdng 3 nhip, 19 budc cdt; thi c6ng bang phudng phdp

i6p gh6p c6c cau kien ket cau khdc nhau: cdu truc, cQt, ddm cdr,r chay, ddn vi kdo vd cira

trdi bang BTCT Cdc cau kion niy duoc sin xuat trong nhd m6y vd vAn chuydn bang

c6c phucmg tien vAn chuydn chuyOn dung den cdng trudng d0 tien hdnh l6p gh6p

Day ld c6ng rrinh lon 3 nhip, 19 bu6c c6t x 6m = l-lzlm Vi vAv phii b6 trf khe lfn

C6ng rrinh dtrcrc thi cOng tren khu dat bang phang khong bi han che rnat bdng, cdc didu

ki6n cho thi c6ng l) thuAn loi, c6c phtrong ti€n phuc vLI thi cong d.i1'dr-r, nh0n c6ng lu6n

h-r6n dArn bao (kh6ng bi gi6i han)

1 So dd cOng trinh

+-12000I

O a

\o

O O

\o

O C)

C) O

(:)

O

!-)

\O O O

\o

O

\o

O a O

\D O a (f

\o

O O

\o

O lr'\

|r)

o

O

v]

-i<-16 J

J

2 Sd li€u tinh to6n

GiA thiet rnat bang thi cOng o cdt - 0,3 m

0,6 m Can ct'r theo so li€u ddu bdi ta cd :

- C Q t g i f r a ( C , ) : H - 1 4 , 6 r n + 0 , 9 m =

(bdng cot rnlt r-n6ng ); cQt nghrn vio m6ng

1 5,,5 m 12,7 m

3 lo,

i

I l

3 Thong k0 cdu kien ldp gh6p

rr TINH ToAN THrgT BI vA cAC pHuoNG AN THI cOxc

1 Chon vi tinh to6n thi6t bi treo bu0c

1.1 Thiei bi treo buoc cot

Su dung c6c dat ma s6t lhm thiet bi treo bu6c ( so dd cau tao xem bAn vO

vdo so dd buoc ciip tinh duoc ducrng k(nh cilp cdn thiet.

u) Cot gilru C, :

P , , = 1 , 1 P = l , l J , 6 = 8 , 3 6 7 Luc cdn g cdp duoc xdc dinh theo :

) Can ctt

_Q.,S

k P , ,

\ - "

f f I n c o s Q

Trong do :

k - h0 so an tohn (kd tdi luc qu6n tfnh k - 6);

m - hg sd kd den sftc cang c6c soi c6p kh6ng ddu;

n - so soi

"6p;

q - g6c nghi€ng cfia cdp so vdi phuong dung (cp - 0)

= chon c6p mdm cau trf c 6 x 3l + 1, dudng kfnh D - 24

o = 1 5 0 k G / m m 2

e r u = T l * i p * g a ^ i m a s i r = 1 , 9 9 x 7 , 2 + 3 0 = 4 1 , 8b) Cdt bien C,, :

P , , = 1 1 P = 1 , 1 6 , 1 = 6 , J I TLuc can g e6p duoc x6c dinh theo :

1.3 Thiet bi treo buoc vi kio vd cira troi

Tien hhnh td hop vi kdo vir cu'a trdi sau d6 cdu l6p ddng thdi Su dung ddn treo vh

d A y tr e o tu c A n b a n g

Hinh vd, 2.3, 2.4

d ) D , v r ) C T 1 :

P , , = 1 , 1 ' P = 1 , 1 ' ( 1 2 , 2 + 2 , 5 ) - 1 6 , 1 7 TLuc cdn g c6Lp duoc x6c dinh theo :

Hinh 2.3: Treo hbt' tlcin nhiP 24

Hinh 2.4: Treo budt: diin nhip 18

1.4 Thidt bi treo buoc panel mdi (hinh 2.5):

Sir dung chim dAy cdu c6 vbng treo tu cAn bang

= chon c6p mdm cdu truc 6 x 3l + l, dudng kinh

) = 13 mm, cudng dO chiu k6o o - 140 kG/mm2 vdi

l : u = 0 , 0 1 T

1.5 Thiet bi treo buoc ta'm ttdng (hinh 2.6):

Su dung m6c cdu c6 2 m6c

P , , = 1 , 1 P = 1 , 1 1 , 4 = 1 , 5 4 7Luc cdn g cdp duoc x6c dinh theo :

ViOc lua chon so dd di chuydn cdu trong qu6 trinh l6p gh6p lh budc ddu rdt quanrrong, n6 Anh hucrng ddn vi€c tinh to6n c6c thdng so cdu l6p Trong m6t sd trulng hqp

do bi khdng chd mat bang thi c6ng trOn c6ng trutrng mh cdu kh6ng thd dLrng 6 vi trfthuAn loi nhat dDng toi da sfc truc duoc khi d6 R, sE phai lay theo vi trf thuc td trOnmat b[ng cdu c6 thd dung duoc Song vdi bdi to6n dd ra cria ddu bdi, viOc bd tri so dd dichuydn kh6ng bi khdng chd mdt bAng ve k! su c6ng trudng hoin tohn c6 thd chri d6nglua chon; nhu vAy dd c6 loi nhat ta sE chon theo phtrmg dn su dqng tdi da sfc truc cuacdu Sau dAy tr)nh bdy c6ch tfnh to6n cdc th6ng sd cdu theo quan didrn d6 (ban doc c6thd xem k! hcm o phdn lf thuyet)

Sau khi tfnh todn c6c thong so cdu l6p, chon cdu ta s6 lua chon so dd di chuydn hqp

ly nhat ad dim bAo ton ft thdi gian luu kh6ng cdu (vf du g6c quay cdn chng nh6 cdngloi, cilng mqt vi trf lap cdng nhidu cau kiOn cDrng loi) vh dd hO sd K.o sfc truc l6n nhdt

Dd chon dtroc cdn truc dirng cho qud trinh thi c6ng l6p gh6p ta cdn phii tinh c6cthdng sd cdu l6p yOu cdu bao gdm :

+ Hr - chidu cao puli ddu cdn;

+ Lr - chidu dhi tay cdn;

* Qr - sfc nAng;

+ R r

29

2.1 Ldp ghdp cot

viOc l5p gh6p cot khong c6 trd ngai gi, do d6 ta chon ray cdn rheo

o n , o * = 7 5 " ( s i n 7 5 " x 0 , 9 6 6 ; cos75'x0,,259 ; tg75"x3,732).Dtng phuctng phrip hinh hoc ta c6 so dd dd chon ciic thong so cdn rruc nhu sau

l()-il _c.

1 , 5 m

R r " = S +

H r = H ' + a + h k * h , o + 4 0 , ; 0 + 0 , 5 + 1 5 , 5 + 1 , 5 + 1 , 5 = 1 9 m_ H , , , , - h l g _ 1 , 5 r

S - i: - l8.lm

s i n 7 5 o 0 , 9 6 6

S = L i n c o s 7 5 0 = 1 8 , 1 0 , 2 5 9 = 4 , , J m - R y = 4 , 7 + 1 , 5 = 6 ' , 2 m

Q r ' = 9 * 9tr' = [i'36 + 0'04 = 8'4 T2.2 Ldp Shdp ddm cdu chay

Vi€c lAp gh6p ddm cdu chav khong c6 tro ng?i gi, do d6 ta chon tay cdn theo o-u^ =

H r = H + a + h k + h , o + \ r p 9 , 2 + 0 , 5 + 0 , 8 + 2 , 4 + 1 ' 5 = 1 4 , 4 m

H , - h 1 4 , 4 _ 1,5

S _ r ' " : _ _ 1 3 , 4 msin 75" 0,966

S = L n , i , , c o s 7 5 0 = 1 3 , 4 0 , 2 5 9 = 3 , 5 m - R y = 3 , 5 + 1 , 5 = 5 m

Qr = 9a * 9tn = 3,96 + 0,01 - 3,97 T

3 1

._-".-