BÀI TẬP TẾT LỚP 8A, 8B
BÀI 1: GIẢI CÁC PT SAU (Hạn nộp: ngày 5/ Ỉ (tết))
2x+3 | 6
xt+l x
3)3(2x44)-5(x+3)=2(x+1)
1) =2
5) = 2 _i_ x’ +2
-l1 x 2x -2x
q) xi! - | 42 =5- 2x
x -9 x- 3
- 2
11 M5 {+2 5x —2)=2 (Sx — 2) = 22 *
a ‘5 x — x-1 + 1
8x 4x°- 8x 2x(x-2) 8x- 16
13) 43-273
x- 2 2- x
15) x+5_2x-3_6x-] 2x-1
x+2 x-2 4
x-2 x+2 x-4
x+1 x-2 (x +1)(x- 2)
22) x11 _ 4 _ x-]
x- 1 x? - 1 x+l
x-5xy 2x +l10x 2x ˆ- 50
96) 1 _7_ = 1
x-1 x-2 (x- l\(2- x)
X_ 2- x
6
31) x- 1 x =/*" 3
x+3 x-3 9-x
33)1+2#-3=3-*
4 35) 2x- 1 _x+4
2
37) 2(x+l)=5x—7
38) 4x? - 12x+5=0
2) 3 2 8 +6x
1- 4x
xe]
6) 3x — 2)(
8) 2x -
Xx
x-l
2x+5 x+3
2x+6 _
4x
+3 x+3
“T+4x 16x-1
4) 3x- 1
4x -
5 +2
7
x_ 3x- 2 10)
12)
14) x+] x†+2 _ Á
x+2 x- 2 4-
3
x- 1
16)
19 x+4
1
5 ]
21 ) x +]
25
12
x- 1 27) 30)
10 3
5
10x+3 _15- 8x
9
3
x?-4 2-x
2x+l x-2 3- 2x
15
x+3_
3
6 32)
34) 232
x+l
36) ——=
) “5
30) x2
4
2x+3- 3 2x- 3- 4x- 6
4 16x+l
7
x-2
3
-3x+2=0
(Lép 8B lam ta cau 1 dén cau 20)
3
=2Z
5
x+3 x?+2x-3 3x-2 6x+1
x+f# 2x-3 3x4+2 x-
X
)=0
x-2 (x+1)(2- x)
23) 2*4_ 4 5=
5
x- 2
2