Khám phá kỹ thuật giải quyết nhanh gọn đề thi Đại học môn Hóa học: Phần 2

Nối tiếp nội dung phần 1 tài liệu Kỹ thuật giải quyết nhanh gọn đề thi Đại học môn Hóa học, phần 2 giới thiệu một số đề thi Đại học - Cao đẳng tham khảo các năm 2012 và 2013. Mời các bạn cùng tham khảo nội dung chi tiết.

O C Hl/

dN

G V

I

CfiC DE

1

DE T

HI TU YE

N S IN

H D

AI HO

C NA

M 201

3

Mon thi : HOA, kho

H = 1; C = 12

; N = 14

; O = 16

; N

a = 23; M

g = 24;

Al = 27; S = 32

; C

I =

35,5;

P = 31; C

a = 40; C

r =

52, F

e 56; C

-u ^ 64; Z

n = 65; B

r = 80; Ag=108

; B

a =

137

I PH AN C HU NG C HO T AT C

A T

HI SIN

H

(40 cdu,

tic

cdu 1 den cdu 40)

Ca

u 1 : Ho

n hcf

p X gom 3,92 ga

m Fe, 1

6 ga

m Fe20

3 v

a m gam A

i pha

n ban

g nhau Pha

u diicf

c a mol kh

i H2 Biet ca

,51 C 7,0

2 D 4,0

5

Ca

u 2 : Tron

g die

u kie

n thic

h hop, xa

+ CO, + 2H2O

(b) H2SO

4 + Fe(0H)2

^ FeS0

4 + 2H2O

(c) 4H0SO

4 + 2Fe

O ^ Feo(SO.,)

a + SO2 + 4H2O

(d) 6H2SO

4 + 2Fe ^ Fe2

(S04)3

+ 3SO

2 + 6H2O

Trong ca

c pha

n ufn

g tren, pha

B (c) C (b

) D (d

)

Ca

u 3 : Tron

g mo

t bin

h kin chufa 0,3

e X vao li/gn

n hg

p k

hi Y phan ufn

0 mol C 0,2

5 mol D 0,1

5 mo

l

Ca

u 4 : O

(a) 2

C +

Ca CaC2

(b) C + 2H

2 CH

4

(c) C + CO

2 -> 2C

0 (d) 3

C + 4A1 -

> AI4C

3

128

Trong cac phan iJng tren, tinh khuf cua cacbon the hien d phan ufng

A (c) B (b) C (a) D (d)

Cau 5: Len men m gam glucozo de tao thanh ancol etyhc (hieu suat phan ufng bang 90%) Hap thu hoan toan liiong k h i CO2 sinh ra vao dung dich Ca(0H)2 dif, thu duoc 15 gam ket tiia Gia t r i ciia m la

A 15,0 B 18,5 C 45,0 D 7,5

Cau 6: H 6 n hop X gom Ba va A l Cho m gam X vao nvidc dii, sau k h i cac phan

ijfng xay ra hoan toan, thu ducfc 8,96 Ht k h i H2 (dktc) Mat khac, hoa tan hoan toan m gam X bang dung dich NaOH, thu duoc 15,68 l i t k h i H2 (dktc) Gia t r i cua m la

A 29,9 B 24,5 C 19,1 D 16,4

Cau 7: Khol Itfcmg Ag thu dugfc k h i cho 0,1 mol C H 3 C H O phan ufng hoan toan vdi li/ong dtf dung dich AgNOa trong NH3, dun nong la

A 10,8 gam B 43,2 gam C 16,2 gam ' D 21,6 gam

Cau 8: Cho hot Fe vao dung dich gom AgNOs va Cu(N03)2 Sau k h i cac phan

ufng xay ra hoan toan, thu duoc dung dich X gom hai muo'i va chat ran Y gom hai k i m loai Hai muo'i trong X va hai k i m loai trong Y Ian iLfgt la:

A Cu(N03)2; Fe(N03)2 va Cu; Fe B Cu(N03)2; Fe(N03)2 va Ag; Cu

C Fe(N03)2; Fe(N03)3 va Cu; Ag D Cu{N03)2; AgNOg va Cu; Ag

Cau 9: Cho 100 m l dung dich amino axit X nong do 0,4M tac dung viTa dij vdi

80 ml dung dich NaOH 0,5M, thu ducfc dung dich chufa 5 gam muoi Cong thufc cua X la

A NH2C3H6COOH B NH2C3H5(COOH)2

C (NH2)2C4H7COOH D NH2C2H4COOH

Cau 10: Cho 1,37 gam Ba vao 1 l i t dung dich CUSO4 0,01 M Sau k h i cac phan

ufng xay ra hoan toan, khoi liicfng ket tua thu di/oc la

A 3,31 gam B 2,33 gam C 1,71 gam D 0,98 gam

Cau 11: K h i di/cfc chieu sang, hidrocacbon nao sau day tham gia phan ufng the

vdi clo theo t i le mol 1 : 1 , thu diioc ba dan xuat monoclo la dong phan cau tao cua nhau?

A isopentan B pentan C neopentan D butan

Cau 12: Oxi hoa hoan toan 3,1 gam photpho trong k h i oxi duf Cho toan bo san

pham vao 200 ml dung dich NaOH I M den k h i phan ufng xay ra hoan to^n, thu di/gc dung dich X Khoi liiong muo'i trong X la

A 14,2 gam B 11,1 gam C 16,4 gam D 12,0 gam

Cau 13: Cho X la hexapeptit Ala-Ala-Val-Val va Y la tetrapeptit

Gly-Ala-Gly-Glu Thijy phan hoan toan m gam h 6 n hop gom X va Y thu difoc 4 amino axit, trong do c6 30 gam glyxin va 28,48 gam alanin Gia t r i cua m la

A 77,6 B 83,2 C 87,4 D 73,4

u 14 :

O trang tha

i cc

f ban, ca

u hin

) l

a

A Is22s22p'^3s -

B Is22s22p''3s '

n ha

p X chufa b

a ax

it cacboxyli

c de

u do

n chufc, mac

h hd

i ax

it khon

g n

o de

u c

6 mo

t lie

n k

et do

i (C=C) Ch

du vori 15

0

ml dun

g dic

h NaOH 2

M, th

t cha

y hoa

n toan

m ga

m X, ha

p th

u toa

n b

o sa n

h NaOH duf, kho'

i liJgn

g dun

g dic

h tan

g the

i axit cacboxylic

khon

g n

o tron

g m gam

6 ga

m C 18,9

6 ga

m D 12,0

6 ga

m

Ca

u 16 :

Dun

g dic

h axit axetic

phan ufng diig

l, Cu

O B N

a, CuO, HC

l

C NaOH, N

a, CaCO

g D N

aO

H, Cu, NaC

l

Ca

u 17 :

Ten tha

y t

he (the

o lUPAC) cu

a (CH3)3C-CH2-CH(CH3)2 l

a

A 2,2,4-trimxetylpenta

n B 2,2,4,4-tetrametylbuta

n

C 2,4,4,4-tetrametylbuta

n D

2,4,4-trimetylpenta

n

Ca

u 18 :

To nilon-6,

6 l

a sa

n pham tru

ng ngUn g

cua

A etyle

n glico

l v

a hexametylendiamin

B ax

it adipi

c v

a glixero

l

C ax

it adipi

c v

a etyle

n glicol D a

xit adipic v

a hexametyle

: HQ

n ho

p X gom N

a, Ba, Na2

0 v

a BaO Ho

a ta

diigc

1,12 li

t k

hi H

2 (dktc) v

a dun

g dic

h Y, trong

t k

hi CO

2 (dktc) va

o Y, thu

di/g c

6 C 21,9

Hgp chat X c6 than

h phan gom

C,

H, O chufa von

g benzen Ch

NaO

H 0,

5 M

(diT

20%

n toan, th

u difg c dung dic h

Y C

o ca

n Y t

hu

dugc m

gam chat ra

n khan Ma

t khac, do

t O

2 (dktc), t

hu

dirge

15,4 ga

m CO2 Bie

t X c6 con

g thuf

c pha

n nha

t Gi

a t

ri cii

a m

la

A 13,

2 B 12,

3 C 11,

1 D 11,

4

Ca

u 21 :

Bie

t X la axit cacboxylic do

n chufc, Y la ancol no, c

so nguye

n ti

r cacbon Do

t cha

y hoa

n toan 0,4 mo

do s

o mo

l cu

a X Idm hon so' mo

l cu

a Y) ca

u dirg

e 26,8

8 li

t th

e tic

n tie

u chuan Kho'

i liTgn g

Y trong 0,4 mo

l h6

n hg

p tre

n l

a

A 17,

7 ga

m B 9,

0 ga

m C 11,

4 ga

m D 19,

0 ga

m

130

Cau 22: Tien hanh ca!c t h i nghiem sau

(b) Cho hcfi ancol etylic di qua hot CuO nung nong

(c) Sue k h i etilen vao dung dich Br2 trong CCI4

(d) Cho dung dich glucozo vao dung dich AgNOa, trong N H 3 di/, dun nong

(e) Cho FeoOs vao dung dich H2SO4 dac, nong

Trong cac thi nghiem tren, so' thi nghiem c6 xay ra phan ufng oxi hoa - khijf la

Trong so do tren, X va Z Ian liicft la

A HCOOCH-CHa va HCHO B CH3COOC2H5 va C H 3 C H O

C C H 3 C O O C H - C H 2 va C H 3 C H O D CH3COOCH=CH2 va H C H O

cau tao cua nhau?

A 3 B 5 C 4 D 2

difgc dung dich X va 1,12 l i t k h i NO Them tiep dung dich H2SO4 dif vao binh thu dtfctc 0,448 l i t k h i NO va dung dich Y Biet trong ca hai tri/cfng hop

NO la san phan khijf duy nhat, do d dieu kien tieu chuan Dung dich Y hoa tan vifa het 2,08 gam Cu (khong tao thanh san pham khiif ciia N*^) Biet cac

phan uTng deu xay ra hoan toan Gia t r i cua m la

A 2,40 B 4,20 C 4,06 D 3,92

A cong hoa t r i khong cifc B ion

C cong hoa t r i c6 cifc D hidro

(a) Cho dung dich HCl vao dung dich Fe(N03)2

(b) Cho FeS vao dung dich HCl

(c) Cho Si vao dung dich NaOH dac

(d) Cho dung dich AgN03 vao dung dich NaF

(e) Cho Si vao binh chijfa k h i F2

Trong ca

c t

hi nghie

m tren , s

3

Ca

u 28 : Hoa ta

n hoa

n toa

n m gam A

u di/o

c

5,376 lit (dktc) ho

n ho

p kh

i X gom N2, N2

4 C 18,9

0 D 21

,60

Ca

u 29 : Cho h6

n ho

p X gom 0,0

1 mo

l A

l v

a a mol F

hi pha

n ufn

g hoa

n toan , th u

k im loai Ch

o Z phan

6 khon

g k hi, thu di/oc 1,9

7 ga

m ke

t tu

a T Nun

g T trong khon

,24 C 6,4

8 D 9,7

2

Ca

u 30 : Chat na

4 C KB

r D HNO

3

Ca

u 31 : Phenol pha

KOH C NaHCOg

D HCl

Ca

u 32 : Cho ca

(a) H

2 (k) + h (k) <

> 2

HI (k).

(b) 2NO

2 (k) < >

N2O4

(k)

(c) 3H

2 (k) + N

2 (k) < >

2NH3 (k).

id) 2SO

2 r

^;+02 (k) < >

B (c) C (b)

D (d)

Ca

u 33 : K

B HNO

3 dac , nong , di/

C MgSOn _

D H2SO

4 dac , nong

, dii

Ca

u 34 : Hoa ta

g

dung dic

h HC

l, th

u diio

c 1,06

4 lit k

hi H2 Ma

t khac , ho

Kim loai X

la

A Al B.Cr C

Mg D Zn

Ca

u 35 : Cac cha

dii,

dun nong?

A vinylaxetilen , glucozo

, andehi

t axetic

132

B glucozcf, d i m e t y l a x e t i l e n , a n d e h i t axetic

C v i n y l a x e t i l e n , glucozcf, d i m e t y l a x e t i l e n

D v i n y l a x e t i l e n , glucozo, a x i t propionic

Cau 36: Tien h a n h dien phan dung dich chijfa m gam hon hap CUSO4 va N a C l

(hieu suat 100%, dien ciic trcf, mang ngan xop), den k h i nifcfc b^t dau h i dien phan 0 ca hai dien ciic t h i ngCtog dien phan, t h u dJcfc dung dich X va 6,72 l i t

khi (dktc) a anot Dung dich X hoa t a n toi da 20,4 gam AI2O3 Gia t r i cua m la

Cau 40: Day cac chat deu tac dung difoc vdri dung dich Ba(HC03)2 l a :

A HNO3, Ca(0H)2 va Na2S04 B HNO3, Ca(0H)2 va KNO3

C HNO3, N a C l va Na2S04 D N a C l , NagSO^ va Ca(OH)2

II P H A N R I E N G (10 c a u )

Thi sink chi diic/c lam mot trong hai phan (Phan A hoac Phan B)

Cau 41: Cho X va Y l a h a i a x i t cacboxylic m a c h ho, c6 cCing so' nguyen tii

cacbon, t r o n g do X don chufc, Y h a i chufc C h i a h 5 n hop X va Y t h a n h h a i

phan bang nhau P h a n m o t tac dung h e t vdri N a , t h u di/gc 4,48 l i t k h i H2 (dktc) Dot chay hoan t o a n p h a n h a i , t h u diigc 13,44 l i t k h i CO2 (dktc) P h a n

t r a m kho'i lufcfng cua Y t r o n g hSn hap la

A 28,57% B 57,14% C 8 5 , 7 1 % D 42,86%

Cau 42: Dot chay hoan t o a n h o n hap X gom 0,07 m o l m o t ancol da chufc va

0,03 mol m o t ancol k h o n g no, c6 m o t l i e n k e t doi, m a c h h d , t h u di/gc 0,23

mol k h i CO2 va m g a m H2O G i a t r i ciia m l a

A 5,40 B 2,34 C 8,40 D 2,70

Cau 43: Day cac chat deu c6 M f e n a n g t h a m gia p h a n ufng t h i j y p h a n t r o n g dung dich H2SO4 dun n o n g la:

A fructoza, saccarozo va t i n h hot B saccaroza, t i n h bot va xenluloza

C glucoza, saccaroza v a fructoza D glucoza, t i n h hot va xenluloza

u 44 : Ch

; Fe^^/Fe,

Sn^VSn; Cu^VCu Tie

A (b) v

a (c) B (a

) v

a (c) C (a

) v

a (b) D (b

) v

a (d)

Ca

u 45 : Ch

o ca

c pha

t bie

u sau:

m thuo

c ch

u k

i 4, nho

(c) Tron

g ca

c ho

p chat, so' ox

p cha

t crom(III) ch

Trong ca

c pha

t bie

u tren, nhuTn

g pha

t bie

u diin

g la:

A (a), (b) v

a (e) B (a), (c) v

a (e) C (b), (d) v

a (e) D (b), (c) v

a (e

)

Ca

u 46 : T

hi nghie

m vdi

dung dic

h HNO3 thi/dng sin

h r

a k

hi do

c NO2 De ha

n

che kh

i NO

2 thoat r

a ti/ on

g nghiem, ngifcf

(a) bon

g kho (b) bon

g c

6 tar

n nifdrc

g c

6 ta

m gia

m an

Trong 4 bien pha

p tren, bie

) C.(a) D

(b)

Ca

u 47 : H6

n ho

p X gom H2, C2H

la 9,25 Ch

o

22,4 lit

X (dktc) va

o bin

h kin c6 sS

5 mo

l C 0,07

5 mo

l D 0,05

0 mo

l

Cau 48: Tron

g ca

p dun

g dic

h CH3-CH2-NH2, H2N-CH2

-COOH, HzN-CHz-CHCNHg)-

COOH, HOOC-CH2-CH2

-CH(NH2)-COOH, s

l C 2

D.3

Cau 49: Ch

la

A 1 : 3

B 2 : 3

C 2 : 5

D 1 : 4

Ca

u 50 : Ch

va AI2O 3

tan hoan toa

n tron

g dun

g

dich H2SO 4

trong X

la

A 40

% B 60

% C 20

% D 80

%

134

B Theo chitofng trinh Nang cao (20 cdu, ti£ cdu 51 den cdu 60)

Cau 51: Cho phtfcfng t r i n h phan ufng:

aFeS04 + bKzCraOv + CH2SO4 > dFe2(S04)3 +6X2804 + {Cr2(S04)3 + gHgO

Ty le a:b la

A.3:2 B 2:3

Cau 52: Cho cac phat bieu sau:

(a) De xuf ly thiiy ngan rai vai, ngifcfi ta c6 the dung bot liAi huynh

(b) Khi thoat vao k h i quyen , freon pha huy tan ozon

(c) Trong k h i quyen, n6ng do CO2 vifot qua tieu chuan cho phep gay ra hieu ufng nha kinh

(d) Trong k h i quyen , nong do NO2 va SO2 viiOt qud tieu chuan cho phep gay

ra hien ti/gng miTa axit

Trong cac phat bieu tren , so phdt bieu dung la:

A.2 B 3 C 4 D 1

Cau 53: Cho cac phat bieu sau:

(a) Glucozo CO kha nang tham gia phan uTng tr^ng bac

(b) Sir chuyen hoa tinh bot trong co the ngifdi c6 sinh ra mantozO

(c) Mantorazo c6 kha nang tham gia phan ufng trang bac

(d) Saccarozo difgc cau tao iii hai go'c p-glucozo va a-fructozcf

Trong cac phat bieu tren , so phat bieu dung la:

Cau 55: Peptit X bi thiiy phan theo phiiomg trinh phan ilng X + 2H2O -> 2Y + Z

(trong do Y va Z la cac amino axit) Thuy phan hoan toan 4,06 gam X thu diicfc

m gam Z Dot chay hoan toan m gam Z can vi/a dii 1,68 l i t k h i O2 (dktc), thu difcfc 2,64 gam CO2; 1,26 gam H2O va 224 ml khi N2 (dktc) Biet Z c6 cong thufc phan tijf trung vdi cong thufc don gian nhat Ten goi ciia Y la

A glyxin B lysin C axit glutamic D alanin

Cau 58: Trifdng hop nao sau day khong xay ra phan ufng?

(a) CH, = C H - C H 2 - C 1 + H , 0 ^ ^

(b) C H ^ - C H ^ - C H ^ - C l + H p >

135

(c) C^H,-C

! + NaO

H (dac)-

i cao.

p ca

o

^ vdi (CeHs- la go'c pheny

l)

(d) C^

Hj-C

l + NaOH^

^

A (a)

B (c) C (d

)

D (b )

Ca

u 57 : Trtfcfn

g ho

p na

o sa

u day, ki

m loa

i

bi an

6n die

n ho

a hoc

?

A Do

t da

y s&

t trong k

hi ox

i kh

o

B Thep cacbon

de trong khong k

hi am

C Ki

m lo

ai ke

m tron

g dung dic

h HC

l

D Ki

m loa

i sS

t tron

g dung dich

HNO3

loan

g

Ca

u 58 : C

ho 12 gam hgp

im ciia bac vao dun

g dich

HNO3

loan

g (dii)

, du

n

nong den pha

n ufn

g hoa

n toan, th

u di/o

c dun

g dic

h c

6 8,

5 gam AgNOa Pha

n

tram khoi

iLfgrng

cua bac tron

g ma

u ho

p ki

m l

a

A 65%

B 30

% C 55

Cr(0

H)3

D Na[C

H6n hop

X gom ancol

metylic, anco

l etyli

c va glixerol

m gam

X, thu

dLfgc

15,68 l

it kh

i CO2 (dktc) v

a 1

8 gam H2O

Ma

t khac

,

80 gam

X hoa tan

duac to'

i d

a 29,

4 ga

m Cu(0H)2

Phan tra

m kh

oi lifgn

g cu

a

ancol etyli

c tron

3D 4A

5A 6B

YD 8B

9A lOA

II

B 12A 13B

14D 15D

16C 17A

18D 19B

20B

21C 22D

23C 24C

25C 26C

27B 28D

29A 30D

31B 32A

33A 34A

35A 36C

37B 38B

39D 40A

41D 42A

43B 44B

45B 46B

47C 48C

49D 50C

5

ID 52C

53A 54C

55A 56D

57B 58D

59D 60C

BA

I GI

AI CH

I T IE

T

Ca

u 1 : T

ol

Vi phan

2 tac

un

g vdr

i dun

g dic

h NaO

H dii

gia

i phon

t theo pha

n ufng:

2A1 + Fe203

> AI2O3 + 2Fe

n hop sau nhi

et nhom gom A

l d

ii va

(— 1-0,2

) = 0,27 m

ol Fe

56

136

Theo de, Fe d m o i p h a n g i a i phong (4a - a) = 3a m o l H2 n e n

— = 3a o a = 0,045 (mol)

2

Do a = 0,045 (mol) n e n A l d i i a m o i p h a u = ^ ' - 0,03 m o l

Vay m = 27(0,2 + 2.0,03) - 7,02 gam Vay chon C

Cau 2: Loai A , C, D v i H2SO4 loang k h o n g t h e o x i h o a F e ( I I ) t h a n h F e ( I I I ) Vay chon C

26.0,3.^ + 2.0,65 Cau 3: T a c6 nx = 1 m o l v a ny = = 0,65 m o l

Do do so' m o l H2 da p h a n ufng = 1 - 0,65 = 0,35 m o l

Chu y r a n g do C2H2 con d i i 0,1 m o l n e n x e m n h i / chi c6 (0,35 - 0,10) = 0,25

mol C2H2 tac dung vdi H2

Vi 0,25 m o l C2H2 c6 k h a n a n g tac dung to'i da vdri 0,5 m o l H2 n e n h o n h o p Y

con CO k h a n a n g tac dung t o i da v(5i (0,5 - 0,35) = 0,15 m o l H2, tufc cung 0,15

mol Br2 V a y chon D

Cau 4: T r o n g p h a n ijfng C + CO2 > 2 C 0 t h i C c6 so' oxi h o a t a n g sau p h a n

iJng nen C dong v a i t r o chat khijf Vay chon A

Cau 5: TCf phuong t r i n h CeHizOe > 2C2H5OH + 2CO2

Ta tha'y cuf 180 g a m glucoza se tao 200 g a m ke't t u a , do do

15.180.100

200.90

dich N a O H d i i t h i X t a n het, n h i i n g a t h i n g h i e m vdri nifdrc dii, c h i c6 B a t a n

het con A l t a n m o t p h a n , t a c6 he:

Vay m - 137a + 27b = 24,5 V a y chon B

Cau 8: C h u y r k n g vofi dang b a i t a p n a y , k i m loai t h u Axioc l a cac k i m loai c6

tlnh khtf m a n h n h a t , con muo'i t h u diioc l a muo'i cua nhufng k i m loai c6 t i n h khijf ye'u n h a t V a y dung dich X g o m Cu(N03)2 va Fe(N03)2, con r S n Y g o m

Cu va Ag V a y chon B

Ta pha

i c6

n,nu6i

- n^aon = 0,0

4 m

ol ne

n M

n

0,04

= 125

Vay M

x = 125

- 2

2 =

103, tuf

c X l

a NHaCgHsCOOH

o d

e t

a c6:

n , =0,01mo

l

n^^^

=0,02m

ol

n -0,01m

ol

n^^.,

=0,0

1 m

ol

Vay nikettua =

m,, ^„^

+mcu,ou,, = 233.0,01

+ 98.0,0

1 = 3,31 (gam) Va

y cho

n A

Ca

u 11 : P

enta

n CH3CH2CH2CH2CH3 ta

o difcr

c 3 dfin xuat monocl

o la:

CH3CH2CH2CH2CH2CI; CH3CH2CH2CHCICH

3 va CH3CH2CHCICH2CH3

So m

ol NaOH = 0,

u ducf

c du

y nha

i

Vay chon

A

Ca

u 13 : G

oi

x, y Ian lifcft la so m

ol

X, Y

Ta

CO h e:

2x + 2

y

=

^ = 0,4

2x.y

=

^.0,3

x = 0,12

y = 0,0

8

Va

y m = m

x + m

y = 472.0,12

+ 332.0,0

8 = 83,2 (gam)

J trang tha

i c

o ban, ca

u hin

D

Ca

u 15 : G

oi con

g thijf

c ax

h 2 a

xit

chUa n

o

laC

„H2„

, 2O2

Go

i a l

a s

o m

ol ax

it no

; b l

a s

o m

ol 2 axit chi/a no

a = 0,15

b = 0,15

an + b

m = 0,69

a+

b=

a3

Taco he:

ia(14n + 54) + b(14m + 52) = 25,56 « <

44(n

a +

m) + 18(an

+ b

m b) = 40,0

-8

Rut ra

n +

m = 4,6

Ch

u y ran

g t

a pha

i c

6 m ^ 3 nen c

hi c

6 n = 1

; m = 3,6ga

m la

= b(14m + 30) = 0,15(14.3,6

+ 30) = 12,06

gam

Va

y chon

D

138

Cau 16: Dung dich CH3COOH tac dung diidc vdri N a O H ; N a va CaCOa

Vay chon C

Cau 17: Ten thay the (theo l U P A C ) cua (CH3)3C-CH2-CH(CH3)2 la

2 , 2 , 4 - t r i m e t y l p e n t a n Vay chon A

Cau 18: To nilon-6,6 la san p h a m t r u n g ngtfng cua axit adipic

va h e x a m e t y l e n d i a m i n Vay chon D

Cau 19: Goi a, b, c, d Ian lifot la so' m o l ciia N a ; Na20; Ba va BaO

<:<>: ' CO-, o i l C O , ' ' '

Ma n = 0,12 mol nen n„ = 0,08 mol, tufc mtettua = 197.0,08 = 15,76 gam Vay chon B

Lilu y

+ Khi dung cong thiic n^,^^, = n^^^^ " " c o

nen sd dung dieu kien kiem chiing Id n^^^, ^ n^^,

U day dieu kien nay thoa ui n^^, = 0,3 mol,

con n , = n - n „ , , = 0,08 mol, tiic n , < n„,,

COV OH C^": C O i l ^ " :

n

+ Hoac chl dung cong thiic n^^^, = n^^^^ - n^^.^^ khi 1 < < 2

'

n 0

38 — " = " vi nay thoa dieu kien O day

— = 1,26

CO ,

0,3

Ca

u 20 : Go

a c

6 pha

n ufn

g chay:

a(12x +

y + 16z) = 6,9

< =>

ax = 0,35

ax = 0.35

ay = 0,3

a/ = 0,i5

Rut ra

X

: y : z = 7 : 6 : 3 Va

y X c6 con

g thufc C7H6O3

So mo

l X = 6,9

138

= 0,0

5 mol

a c

6 b + 0,2

b = 0,18

X pha

i c

6 ca

u tao

HCOOC6H4OH

Phan ufn

g xa

y ra:

HCOOC6H4OH + 3 Na OH

> HCOONa +

C6H4(ONa )2 + 2H2O

0,1.18 = 12,3 (gam)

x+

-) = l,35 4 2

^-0,4x = l,2

0,4

^ = 0,55 2

x =

3

y = 5,5

z =

2

Do s

o O trung bin

h =

2 m

a X c6 20 nen

Y cun

g c

6 20

h = 5,5 m

a Y c6 8

la s

o mo

l X, Y trong 0,

4 mo

l ho

n hop

140

Neu chon Y la C3H2O2, ta c6 he:

a + b = 0,4 2a + 8b

a =

b =

30 7_

30

Vay Y la C3H4O2 va ta c6 he

(loai vi naxit < Hancol)

a + b = 0,4 4a + 8b _ g ^ « <

0,4

a = 0,25

b = 0,15

Do do m = 76.0,15 = ll,4gam Vay chon C

Cau 22: Cac t h i nghiem c6 xay ra phan ufng oxi hoa - khuf la: —

- Sue khi etilen vao dung dich KMn04 loang

- Cho hoi ancol etylic di qua hot CuO nung nong

- Sue khi etilen vao dung dich Br2 trong CCI4

- Cho dung dich glucoza vao dung dich AgN03, trong NH3 duT, dun nong

Cau 25: De y rang Fe cuoi bai da bi oxi hoa toan bo thanh Fe^*

Tong so mol NO = 0,05 + 0,02 = 0,07; So mol Cu = 0,0325

0,0325mol 0,065mol

Vay 2a + 0,065 = 0,21 mol <» a = 0,0725 mol

Do do m = 56.0,0725 = 4,06 (gam)

Vay chon C

u 26 : Lie

Ca

u 27 : Ca

Vay cho

n C

Ca

u 28 : T

a c

6 s

o mol N2 = s

o mol N2O = 0,1

2 mol

8-<=> m = 21,

o de, dun

g dic

h Z gom 0,01 mo

l Al''^

;

Ran Y chi l

a Ag

De y rang 1,9

va y mol Fe(0H

a c

6 he:

90x + 107y =

1,97 f

x = 0,01

x +

y = 2.0,01 =

0,02 [

y = 0,01

NhLf va

y ho

n ho

p X ban dau d

a ch

o (0,01

3 + 2x + 3y) = 0.08 mo

o d

o m = 108.0,0

8 = 8,64

Vay cho

n A

Ca

u 30 : Dun

va KBr Va

y cho

n D

Ca

u 31 : Pheno

y cho

n B

Ca

u 32 : Ca

n ban

g ho

a ho

c H2

(k) +

h (k) < >

2HI (k) c6 ton

y cho

n A

Ca

u 33 : F

a c

6 he

:

'56a + bX = 1,80

5

2a +

bn =2

^

^ = 0,095 «

22,4

Rut r

a X = 9

n (Al) Va

y cho

n A

a = 0,025

bX = 0,40

5

bn = 0,045

142

Cau 35: Cac chat trong day vinylaxetilen, glucozcf, andehit axetic deu tao ket tua

khi cho tac dung vcfi dung dich AgNOs trong NH3 dif, dun nong, trong do vinylaxetilen tao ket tua AgC = C - CH = C H ^ , hai chat con lai tao ket tua Ag Vay chon A

Vi dung dich sau dien phan hoa tan diicfc toi da 0,2 mol Al20;j nen dung dich nay chi'/a 1,2 mol hoac 0,4 mol OH

+ Neu dung dich dung dich sau dien phan chiifa 1.2 mol H^

a 2a

l,2mol 0,3mol Loai vi anot thoat ra 22,4(0,5b + 0,3) > 6,72 ht

+ Neu dung dich dung dich sau dien phan chifa 0.4 mol OH"

Vay m = 160a + 58,5b = 51,lgam Vay chon C

Cau 40: Cac phan ufng:

Ba(HC03)2 + HNO3 > Ba(N03)2 + 2CO2 + 2H2O

Ba(HC03)2 + Ca(OH)2

Ba(HC03)2 + Na2S04

2H2O

-» BaS0

4 + 2NaHC

03

Ca

u 41 : G

pi n la so' C m

oi ax

it v

a a, b Ia

n liicf

t l

a s

o mo

l 2 axit tre

na + n

b = 0,6

De y ran

g ~ +

<a + b

<a + 2

b nen 0,2 < a + b < 0,

4

0,6 0,6 0,6

va

Y la HOOC-CO

OH

Thay

n =

2 va

o h

e tren gia

i difp

c a = 0,2mol

; b = O,lmol

Do

do

%HOOC-COOH = = 42,86(%) 1 + 90.0, 60.0,2

i

n, m Ia

n lii

gt la so' C cua anco

l d

a chuf

c anco

l khon

t do

i, mach ho da cho

Theo

de ta c6 0,07

n + 0,03m

= 0,23

Ch

u y ran

g t

a pha

i c

6 n > 2 va

m >

3 nen c

hi c

6 n = 2 va

n hop gom 0,07 mol C2H6O2 v

a 0,0

3 mo

a nang tha

m gi

a phan uTng thuy p

ha

n tron

g

dung dich

H2SO4

dun non

g la: saccarozcr, t

in

h bo

t v

a xenlulozcf Va

c phan ijfng xa

y ra la:

CUSO4 >

SnS

g ph

at bie

u dun

g la:

m thup

c ch

u k

i 4, n

ho

m VIB

- Trong cac hp

p chat, so' ox

i ho

a ca

o nh

at cu

a cro

m la

+6

- K

hi phan ufng vdr

i khi

CI2 dii,

crom tao r

a ho

p cha

t cromdH)

o NO2 la oxit axit nen ngiicfi

ta dun

g bon

g c

6 ta

i NO2 khon

g ch

o thoa

t r

a ngoai Va

y cho

n B

1 44

Cau 47: Ta c6 nxMx = nyMy nen ny = " ^ ^ ^ _ 1.0,925.2 ^ Q,925mol

Do do so mol Hg da phan ufng = 1 - 0,925 = 0,075mol Vay chon C

Cau 48: Cac dung dich lam xanh quy t i m la

CH3-CH2-NH2, H2N-CH2-CH(NH2)-COOH Vay chon C

Cau 49:

Vay chon D

160a + 342b = 57,9 l b = 0,05

Do do %Al203 ^>02.0,05.100 ^ 20(%) Vay chon C

25,5 Cau 51: Ta c6 phan ufng:

Vay a : b = 6 : 1 Vay chon D

Cau 52: Cac phat bieu diing la:

- Khi thoat vao khi quyen , freon pha huy tan ozon

- Trong khi quyen , nong do NO2 va SO2 vi/cft qua tieu chuan cho phep gay

ra hien tifcfng mifa axit

Vay chon C

Cau 53: Cac phat bieu dung la:

- Glucozcf CO kha nang tham gia phan ufng trang bac

- Sif chuyen hoa tinh bot trong ca the ngufcJi c6 sinh ra mantozcf

- Mantorazo c6 kha nang tham gia phan ufng trang bac

Vay chon A

Cau 54: V i 0,6 mol Ag* phan ufng nhtfng chi tao 0,4 mol Ag chufng to day 1^

andehit dcfn chufc c6 noi ba dau mach

Theo de 13,6 gam tufc 0,2 mol C H s C - C H ^ - CHOda phan ufng viia du vdi dung dich chufa 0,6 mol AgNOa trong NH3 theo phufomg trinh:

CH = C - C H , - CHO + SAgNOa + 4NH3 + H2O

> CAg = C - C H , - COONH4 + 3NH4NO3 + 2Ag Vay chon C

u 55 : Dat

con

g thuf

c Z la

CxHyO^Nt

Ta

CO

nc 0,06 m

-ol ;

n n

- 0,1

4 mol;

nN = 0,0

2 mo

l v

a n

o (0,06.2

+ 0,07) - 2.0,075

- 0,0

4 mo

l

Do

do X

: y : z : t = 0,0

6 : 0,14 : 0,0

4 : 0,02 = 3:

n tuf

C3H7NO2 vd?

i so' m

ol = 0,02 m

ol

Phan ijrng xa

y ra:

X +

2H2O

>

2Y + Z

2

Rut ra

M

Y =

— = 75

Va

y X

la glyxin Vay chon

Ca

u 56 : C

ho

n D

Ca

u 57 : T

he

p cacbo

n d

e tron

g khong k

hi am b

i an mon die

n ho

a Fe-C , trong

do F

e la ciJc am va

C l

a cif

c diiong Va

y cho

n B

Ca

u 58 : V

i dung dic

h c

6 chuT

a 0,0

5 mo

l,

^M'-I'N

""

"-

^-^ ) Na[

Cr(OH) J

Va

y chon' D

Ca

u 60 : Go

i a, b, c Ia

n lifa

t la so' mo

l 3 ancol

tren trong

m ga

Va

y

%A

g = 108.0,05.100

- 45(7r) Va

y cho

a + 2b + 3

c = 0,7

2a + 3b4 4c =

l

32ka + 46k

b + 92k

c = 80 <=

^

a = 0,05

b = 0,10

0,

c-15

k = 4,0

Vay %C2H50H

- = 46b 10

(40 cau, tic cau 1 den cau 4G)

Cau 1: H 6 n hop X gom ancol metyhc, etylen gUcol Cho m gam X - p h a n liiig hoan

loan vdi N a dii, t h u dtfcfc 2,24 lit k h i H2 (dktc) Dot chay hoan toan m gam X,

thu di/oc a gam CO2 G i ^ t r i cua a la

A 8,8 B 6,6 C 2,2 D 4,4

Cau 2: Cho 0,76 g a m h 6 n hop X gom h a i a m i n dcfn chijfc, c6 so' m o l b ^ n g n h a u ,

lifcrng cua a m i n c6 p h a n tijf k h o i nho h o n t r o n g 0,76 g a m X l a

A 0,45 gam B 0,38 gam C 0,58 gam D 0,31 gam

Cau 3: H o n hop X gom FeO, FezOg va Fe304 Cho k h i CO qua m gam X n u n g

nong, sau m o t thori g i a n t h u dtfoc h o n hop chat r a n Y v a h o n hcfp k h i Z Cho

toan bo Z vao dung dich Ca(0H)2 dil, den p h a n urng hoan t o a n , t h u dtfcfc 4

gam ket tiia M a t khac, hoa t a n hoan t o a n Y t r o n g dung dich H2SO4 dac, nong (dif), t h u dufcfc 1,008 l i t k h i SO2 (dktc, san p h a m khijf duy n h a t ) va dung dich chufa 18 gam muoi Gia t r i ciia m la

A 7,12 B 6,80 C 5,68 D 13,52

Cau 4: Hoa t a n hoan t o a n 1,28 gam Cu vao 12,6 gam dung dich HNO3 6 0 % t h u diroc dung dich X ( k h o n g c6 i o n N H ^ ) Cho X tac d u n g h o a n t o a n vdfi 105

ml dung dich K O H I M , sau do loc bo ke't tua diicfc dung d i c h Y Co can Y

di/gc chat rSn Z N u n g Z den k h o i lirgng k h o n g doi, t h u duac 8,78 g a m chat

ran N o n g do p h a n t r a m cua Cu(N03)2 t r o n g X la

A 28,66% B 30,08% C 27,09% D 29,89%

Cau 5: Cho gia t r i do a m d i e n ciia cac nguy.en to: F (3,98); O (3,44); C (2,55); H

(2,20); N a (0,93) H o p chat nao sau day la hop chat ion?

A N a F B CH4 C H2O D CO2

Cau 6: Cho m gam m o t o x i t sSt p h a n uTng viia du vdfi 0,75 mol H2SO4, t h u difoc

dung dich chi chufa mot m u o i duy n h a t va 1,68 l i t k h i SO2 (dktc, san p h a m khijf duy n h a t cua S"^) Gia t r i cua m la

A 24,0 B 34,8 C 10,8 D 46,4

u 7 :

H6n ha

p X gom hidro, propen

, axi

t acryUc, anco

l anlylic

u di/g

c 30,2

4 lit khi CO2 (dktc) Du

C 0,3

D 0,4

Ca

u 8 : Thu

C 10,6

D 14,6

Ca

u 9 : Ch

o pha

n ufng: Fe

O + HNO3 Fe(N03

)3

+ N

O + H2O

Trong phuon

g trin

h cii

a pha

n ufn

g tren, k

C 8

D 4

Ca

u 10 : S

3 v

a 14 C 1

2 v

a 14 D 1

o axi

t X c6 pha

n tu

f kho

i bkn

g 75 Te

n cu

a X

la

A lysin B

alanin C

glyxin D

valin

Ca

u 12 : Ch

o 3,3

6 lit k

hi hidrocacbo

n X (dktc) pha

C2H2- C

C4Hg D

C3H4

Ca

u 13 : Te

c l

a

A 2-metylbut-2-en B

2-metylbut-l-en

C 3-metylbut-l-en D

3-metylbut-2-en

Ca

u 14 : Tron

g ca

c chat: stiren, axi

t acrylic, axi

t axetic, vinylaxetile

C 2

D 4

Ca

u 15 : Ch

o s

o d

o pha

n ufng: C2H2 ^

o sa

u day

?

A CH3C00Na B

CaH.OH C

HCOOCH3 D CH3CHO

Ca

u 16 : Ho

a ta

n hoa

n toa

n x mol F

va z 1^

A

X

= y

- 2z B 2

x =

y +

z C 2

x =

y + 2z D y

= 2x

148

Cau 17: Cho cac phat bieu sau:

(a) Cac chat CH3NH2, C2H5OH, NaHCOg deu c6 kha nang phan ting vcfi HCOOH

(b) Phan (tag the brom vao vong benzen cua phenol (CeHsOH) de hcfn cua benzen

andehit axetic

(d) Phenol (CsHgOH) tan i t trong etanol

Trong cac phat bieu tren, so' phat bieu dung la

A 4 B 3 C 2 D 1

Cau 18: So dong phan amin bac mot, chufa vong benzen, c6 cung cong thufc

phan ttf C7H9N la

A 3 B 5 C 2 D 4.~"

Cau 19 : Cho cac phat bieu sau:

(a) Trong cac phan ufng hoa hoc, flo chi the hien tinh oxi hoa

(b) Axit flohidric la axit yeu

(c) Dung dich NaF loang diicJc dung lam thuoc chong sau rang

(d) Trong hgp chat, cac halogen (F, CI, Br, I) deu c6 so oxi hoa:

- 1 , +1, +3, +5 va +7

(e) Tinh khi^f cua cac ion halogenua tang dan theo thuf tif: F , CF, Br", 1

Trong cac phat bieu tren, so' phat bieu dung la

A 2 B 4 C 3 D 5

Cau 20: Phat bieu nao sau day khong dung?

A Chat beo la trieste ciia etylen glicol vcfi cac axit beo

B Cac chat beo thucfng khong tan trong niidc va nhe hcfn nifcfc

C Triolein c6 kha nang tham gia phan ufng cong hidro k h i dun nong c6 xuc tac N i

D Chat beo hi thuy phan khi dun nong trong dung dich kiem

Cau 21: Chat nao sau day trong phan tuf chi c6 lien ket dan?

A Axit axetic B Metyl fomat C Andehit axetic D Ancol etylic

Cau 22: Hon hop X gom hai axit cacboxylic dan chufc, mach hcf, ke tiep nhau

trong cung day dong ding Dot chay hoan toan 4,02 gam X, thu dtfcfc 2,34

gam H2O Mat khac 10,05 gam X phan ufng viia du vdi dung dich NaOH, thu

difcfc 12.8 gam muoi Cong thiJc cua hai axit la

A CgHsCOOH va C4H7COOH B C2H3COOH va C3H5COOH

C C2H5COOH va C3H7COOH D CH3COOH va C2H5COOH

Cau 23: Cho phifang trinh hoa hoc cua phan ufng: X + 2Y —> Z + T O thcfi diem

ban dau, nong do ciia chat X la 0,01 mol/1 Sau 20 giay, nong do cua chat X

la 0,008 moLl Toe do trung binh ciia phan ufng tinh theo chat X trong khoang thM gian tren la

A 4,0.10

" mol/(l.s)

B 7

,5.10" mol/d.s)

C 1,0.10

" mol/d.s) D

5,0.10

" mol/(l.s)

Ca

u 24 :

Tripeptit

X va tetrapept

it Y deu mac

h hd Kh

i thuy pha

Y ch

i ta

o ra m

ot amin

o ax

it du

y nh

l Y trong oxi dif, th

m CO2, H2O Do

t cha

y 0,0

1 mo

l X trong oxi dii, ch

o sa

n

pham chay va

o dung dic

h Ba(0H)

2 dtf, th

u dtfg

c m gam ke't tua

Bie

t ca

c

phan ufng de

u xa

y ra hoa

n toan Gi

a tr

i cu

a m

la

A 29,55 B

17,73

C 23,64

D 11,82

Ca

u 25 : C

acbohidra

ai disaccarit

?

A Xenluloz

o B Glucoz

o C Saccaroz

o D

Amilo

zo

Ca

u 26 : Th

e tic

h dung dic

h NaOI

u du

'cfc lifcfn

g k

et tu

a 16

n nha

t

la

A 210 m

l B

90 m

i C

180 m

l D

60 m

l

Ca

u 27 : P

A Than

h phan chin

t do

n ch

i c

6 Ca(H2P04)2

C

Ur

e

C O cong thufc l

a (NH2)2C

O

D Phan Ia

g

Ca

u 28 : D

ie

n phan nong chay AI2O

n chi, t

hu

difcfc m

kilogra

n ho

p kli

i X

a anot

Ti kh

X (dktc) pha

t tua Bie'

a tr

i cii

a m

la

A 115,2 B

82,8

C.

144,0 D

104,4

Ca

u 29 : H

ai cha

t huT

u cc

f X va

Y, than

h phan nguyen

to' de

u go

m C ,

t tron

g

oxi du' de

u th

u dLfg

c so' m

ol H2

O bSn

g so' m

ol CO2 Ch

o 0,

1 mo

n ufn

g hoan toa

n vd

i liTcrn

g dii dun

g dic

h AgNO

s tron

Ag

Phan tra

m kho

i liion

g cu

a X trong hon hdp b

%

C 39,66

% D 21,84%

Ca

u 30 : K

hi ho

a ta

n hoan toan

m ga

m m5

i ki

m loa

i va

o niidc

dii

u d\Jac

th

e tic

h kli

i H

2 (cun

g die

u kien nhie

A Na

B C

a C K

D

Li

Ca

u 31 : Ch

o 20

0

ml dung dic

h Ba(0H)

h NaHCO

a

0,1M, thu

dLfcfc

dun

g dich X va k

et tii

a Y Ch

o ti

i sin

h ra t

hi he

t V m

l

Bie

t ca

c ph

an

ufng de

u

xay ra hoa

n toan Gia t

0 D

40

150

Cau 32: H o n hcfp X gom h a i k i m loai k i e m va m o t k i m l o a i k i e m t h o H 6 a t a n hoan t o a n 1,788 g a m X vao nifdrc, t h u difofc dung d i c h Y v a 537,6 m l k h i H2 (dktc) D u n g dich Z gom H2SO4 va H C l , t r o n g do so' m o l cua H C l gap h a i I a n so' mol cua H2SO4 T r u n g hoa dung dich Y b k n g dung dich Z tao r a m gam hon hop muoi G i a t r i cua m l a

A 4,656 B 4,460 C 2,790 D 3,792

dung dich X T r o n g cac chat: N a O H , Cu, Fe{N03)2, K M n 0 4 , BaCla, Ch va A l ,

so' chat CO k h a n a n g p h a n ijfng difoc v d i dung dich X l a

A 7 B 4 C 6 D 5

Cau 34: D u n g dich X chufa 0,12 m o l N a ^ x m o l SO;'; 0,12 m o l - G T v a 0,05 m o l

N M ; Cho 300 m l dung dich Ba(0H)2 0 , 1 M vao X den k h i cac p h a n ufng xay

ra hoan toan, loc bo ke't tua, t h u dijgc dung dich Y Co can Y , t h u dxiac m

gam chat rSn k h a n G i a t r i cua m la

A 7,190 B 7,020 C 7,875 D 7,705

Cau 35: T r o n g cac polime: to t a m , scfi bong, t o visco, t o n i l o n - 6 , t o n i t r o n , nhCfng polime c6 nguon go'c t i f xenlulozor l a

A to t a m , sai bong v ^ tcf n i t r o n B to visco va t o n i l o n - 6

C sgi bong, t o visco va t o n i l o n - 6 D soi bong va to visco

Cau 36: Hoa t a n hoan t o a n hon hop "gom 2,8 gam Fe v a 1,6 gam Cu t r o n g 500

ml dung dich h 6 n hop HNO3 0,1M va H C l 0 , 4 M , t h u difoc k h i N O ( k h i duy nhat) va dung dich X Cho X vao dung dich AgNOs dtf, t h u diioc m g a m chat

rin, Bie't cac p h a n utng deu xay r a hoan t o a n , N O l a san p h a m khuf duy n h a t

cua N*^ t r o n g cac p h a n u'ng Gia t r i cua m la

A 29,24 B 30,05 C 28,70 D 34,10

Ba(0H)2 0,2M, t h u dugc m gam ke't tua Gia t r i cua m la

A 29,55 B 9,85 C 19,70 D 39,40

Cau 38: A x i t cacboxylic X h a i chijfc (c6 p h a n t r a m k h o i lOOng ciia oxi nho hon

70%), Y va Z l a h a i ancol dong dSng ke t i e p (My < Mz) Do't chay h o a n t o a n 0,2 m o l h o n hop gom X, Y , Z can vCra du 8,96 l i t k h i O2 (dktc), t h u dtfoc 7,84

l i t k h i CO2 (dktc^ va 8,1 gam H2O P h a n t r a m k h d i lifgng cua Y t r o n g h o n hop t r e n la

u 40 :

Cho sa

do pha

n uTng

: A UC SO Jj

^ X ^ Y ->

A l

Trong sc

f d

o tren, mo

c chS'

t X, Y Ian

g v

a A1(0H

)3

11 PH AN R IE NG (10 cau )

Thi sink chi diiac

Idm mot trong hai

phan (Phan

A hoac Phan B)

A Th eo chu'orng

tr in

h C hu an

(10 cau, tii cau

41 den cau 50)

Ca

u 41 :

2 v

a S O2 difg

C

2 D 3

Ca

u 42 :

Cho ca

c pha

t bie

u sau:

(b) O dieu

kien thiTdng, glucozc

(c) Xenlulozc

f trinitr

(d) Amilopecti

n tron

g tin

D 5

Ca

u 43 :

Este na

o sa

u da

y kh

CHgCOOCgH

s (pheny

l axetat)

C

C H3 CO O -[

CH 2]

OO CC H2 CH 3.

D CH3OOC-COOCH3

Ca

u 44 :

Tien ha»h len men giam

a

A 2,47% B

7,99%

C 2,51%

D 3,76%>

Ca

u 4 5

: Amin

o axi

t X c6 con

g thuf

c H.NC^

H

Y CC OO H)

h H2 SO

^0,5

o Y phan

va KO

H 3M, th

% C 10,526%

D 11,966

%

152

Cau 46 : Hoa t a n hoan toan 24 gam h6n hcJp X gom M O , M(OH)^ va M C O ,

(M la k i m loai c6 hoa t r i k h o n g doi) t r o n g 100 gam dung dich H^SO^ 39,2% thu di/cfc 1,12 l i t k h i (dktc) va dung dich Y chi chufa m o t chat t a n duy n h a t

CO nong do 39,41% K i m loai M la

A M g B Cu D Z n D Ca

Cau 47: T r o n g so cac dung dich c6 cung nong do 0,1M dvtdi day, dung dich chat

nao CO gia t r i p H nho nhat?

A Ba(OH)2 B H^SO^ C H C l D N a O H

Cau 48: Thifc h i e n cac t h i nghiem sau:

(a) Cho A l vao dung dich H C l

(b) Cho A l vao dung dich A g N O ,

(c) Cho N a vao H , 0

(d) Cho A g vao dung dich H^SO^ loang

Trong cac t h i n g h i e m t r e n , so' t h i nghiem xay ra p h a n ufng la

A 3 B 4 C 1 D.2

Cau 49 : Cho phifong t r i n h hoa hoc ciia phan ufng :

2Cr + 3Sn'* > 2 C r ' ^ + 3 S n

Nhan xet nao sau day ve phan ufng t r e n la dung?

A Cr'* la chat khur, Sn'* la chat oxi hoa

B Sn'na chat khijf, C r ' ^ a chat oxi hoa

C Cr la chat oxi hoa, Sn^" la chat khiJf

D Cr la chat khtf, Sn^' la chat oxi hoa

Cau 50 : Hidrocacbon nao sau day k h i p h a n ijfng vdfi dung dich b r o m t h u dxiac

1,2-dibrombutan?

A But-l-en B Butan C B u t - l - i n D Buta-l,3-dien

B T h e o chifcfng t r i n h N a n g cao (10 cau, tii cau 51 den cau 60)

Cau 5 1 : N h i i n g mot t h a n h sSt vao dung dich h6n hcrp chufa 0,02 m o l A g N O ,

va 0,05 mol C u ( N O , ) , Sau k h i cac phan ufng xay ra hoan toan, k h o i liicfng

thanh sat t a n g m gam (coi toan bo k i m loai sinh ra b a m vao t h a n h sat) Gia

tri ciia m la

A 5,36 B 3,60 C 2,00 D 1,44

Cau 52 : T r o n g mot b i n h k i n c6 can bSng hoa hoc sau :

2 N O , ( k ) < = z ^ N ^ O ^ ( k )

i tron

g bin

h s

o ver

t

H, d nhiet d

o T, bSn

g 34,5 Bie

ve ca n

bkng tren

l

a

dung?

A Phan ufng thua

n l

a pha

n u'n

g to

a nhie

t

B Kh

i tan

g nhie

t do, a

m

C Kh

i gia

m nhie

t do, a

g

D Phan ufng nghic

h la pha

n uTn

g to

a nhie

t

Ca

u 5 3

: Hon hop

X go

m mo

t ax

it cacboxyli

c no, do

n chuTc ,

mac

h her

a 18,

9 ga

m H,

0 Thiic hie

n phan u'ng est

u dtfcf

c m gam este Gi

4 C 10,8

0 D

9,18

Ca

u 54 :

Cha

t na

o dxidi

day k

NH^dU

,

dun

nong, kh on g

xay r

a pha

n uTn

g trang bac?

A Mantoz

o B GIucoz

o C Fructozc

f D

Saccarozo

Ca

u 55 :

Cho da

y cha

t sau

- isopren,

anili

n, andehit axetic, toluen

o cha

t tron

g da

y phan ijfng di

Hoa tan m

ot kh

i X vao niJdc,

d\J vao

dung dic

h ZnSO_,, ba

n da

u thay c6 ke

t tii

a tr

l B

NO C SO

^ D

N

H,

Ca

u 57 :

Dun soi dun

g dic

h go

m cha

t X va KOH

d ac

trong C

n

Cong thufc cii

a X

la

A CH

^CH^

Cl B

CH,COO

H

C CH,CHC

lj D

CH,COOCH = C

H,

Ca

u 58 :

xay ra pha

n iJng

?

A Ag + O, ^

B S

n + HNO, loan

g >

C Au + HNQ, da

c >

D

Ag + HNO, da

c >

Ca

u 5 9

: T

o nitro

n (olon) l

a sa

n pham trung hop cua monom

=C(CH,)-COOC

H, B

CH,COO-C

H = C

H,

C CH,

=CH-CN

D

CH,

=CH-CH = C

H,

Ca

u 60 :

Hoa tan h6n hop

dich

H,SO^

loan

g (dif), thu

du'O c

dung dic

h Y Ch

o dun

g dic

h NaOH da

vao Y

thu

difgc ke

t tu

a Z Nung

Z tron

g khong k

hi de

n kh

oi lifcfn

g khong doi,

n

Bie

t ca

c phan ufng de

u xa

y ra hoan toan Gi

0 C 3

6 D 1

8

154

DAP AN

BAI GIAI CHI T I E T

Cau 1 : Goi a, b Ian lu'cft la so' mol ancol metylic, etylen glicol, ta c6 — + b = 0,1

Vay so mol CO2 = a + 2b - 0,2 tii'c a = 8,8 Vay chon A

1,49-0,76 Cau 2: Goi a la so mol moi amin, ta c6 2a = = 0,02 <=> a = 0,01(mol)

Vay phan tuf luang trung binh 2 amin =

36,5

2a 0,02 phan tuf khoi nho hcfn trong h5n hop la CH3NH2 ( M = 31)

Cau 3: Ap dung cong thufc giai nhanh m^.^ ^ = (mj^j^ + 16n^Q )

Ta CO 18 = ^ ^ ( m ^ + 16^^^^) « • = 6,48gam

160 ^ 22,4 ^ Mat khac h6n hop Z co 0,04 mol CO2, chufng to X da bi mat 0,04 mol O theo

phan ijfng:

Vay mx = my + mo = 6,48 + 16.0,04 = 7,12 gam Vay chon A

Cau 4: Ta c6 so mol Cu = 0,02; so mol HNO3 = 0,12; so mol KOH = 0,105

Chu y rang dung dich Y chuTa KNO3 va c6 the c6 KOH (du), do do 8,78 gam

ran gom KNO2 (a molj va KOH dii (b mol)

85a -t-56b = 8,78

a = 0,1

b = 0,005 Gia suf phan uTng cua Cu vdi HNO3 da tao x mol NO va y mol NO2

'x + y + 0,l = 0,12 Bao toan N va bao toan electron cho ta he: <

• [3x + y = 2.0,02

x = 0,01 y=.0,01

u 5 : Ta c

8 0,93 = 3,05 >

y cho

n A

Li^u y

That ra khong can

cdc gid tri do

dm dien tren ta

vdn ket ludn dugc

NaF la hap chat

ion vi

Na la kim loai

dien hinh, con F

Id phi kim dien

hinh

Ca

u 6 : Ta c

6 n^,, , = 0,075 mo

l ne

n ba

o toa

n S cho

0,7 5- 0,0

ni+m„^so, =m,,^,so,,.+mso ,

<^m =

400.0,225 + 0,075.6

4 + 0,75.18-0,75.98

= 34,

8 gam

Vay cho

n B

Cau 7:

t acrylic , anco

H 2

va b mol

C sH yO

t

a +

b = 0,75

b = 0,45

Mat kha

c nxM

x = nyMy «

> = "'^^'^

= =

0,6mol

^ MY

da pha

n ufn

g = 0,75 - 0,6 :

= 0,1

5 mol

Vi 0,4

5 mo l

C sH yO t

0,1

= 0,

5 lit Va

y cho

n B

Li/u y

Propen, axit acrylic vd

ancol anlylic deu c6

3C va deu c6

kha nang

tdc dung uai H2

hoac vai Br2 theo ti

le mol

1 :

1 nen c6 the

dung cong thiic

CsHyOi dai dien cho chung

ancol CO

,

0,3

"H

,o -n co , 0,4 -0 ,3

= 3

156

Vi ancol Y khong hoa tan Cu(OH)2, nhiftig sii thuy phan e s t e X lai tao 2

muoi n e n Y phai la ancol hai chufc, cong thufc C3H6(OH)2

Phan ufng xay r a :

RCOOCgHeOOCR' + 2NaOH > RCOONa + R'COONa + C3H6(OH)2

0,1 mol O,lmol O,lmol 0,1 mol

Vay 0,1(R + 67) + 0,1(R'.+ 67) = 15 R + R' = 16

Chi C O R = 1; R' = 15 la p h u hop

Do do este X l a HCOOCgHgOOCCHg, tufc m i = 0,1.146 = 14,6 gam Vay chon D

Cau 10: Nguyen tuf 13 A l c6 13 proton va 14 ncftron Vay chon B

Cau 11: Glyxin N H 2 C H 2 C O O H c6 M = 75 Vay chon C

NH3 se tao 0,15 mol AgC s CAg tufc 0,15.240 = 36 gam ket tiia Vay chon B

nhomlOH lay di I H of C ke can c6 bac cao hon Vay san pham chinh phai la

(CH3)2C=CHCH3 (2-metylbut-2-en) Vay chon A

Cau 14: So' chat c6 kha nang tham gia phan ufng cong hidro (xuc tac N i , d u n

nong) la: stiren, axit acrylic, va vinylaxetilen Vay chon A

Cau 15: Ta c6 so do phan ufng: C2H2 ^ CH3CHO -> CH3COOH Vay chon D

Cau 16: Chat tan duy nhat cf day la FeCl2=

C H O N H A N

Fe >Fe'" + 2e Fe^^ + l e > Fe^^

x mol 2x mol y mol y mol

z mol z mol Vay ta phai c6 2x = y + z Vay chon B

Cau 17: Cac phat bieu dung la

- Phan ufng the brom vao vong benzen ciia phenol (CeHsOH) de hem ciia benzen

andehit axetic Vay chon B

Cau 18: Co 4 dong phan amin bac mot, chufa vong benzen, c6 cimg cong thufc

phan tuf C7H9N la:

CH3C6H4NH2 ( 0 ; m; p) va CeHgCHaNHa

Vay chon D

u 19 : Cac pha

t bie

u dun

g la :

e hie

n tin

h ox

i hoa

Ca

u 20 : Phat bie

u klion g

Ca

u 21 : Ancol etyli

6 s

o mo

l 2 axit tron

g 10,0

5 gam ho

n hcf

p = = 0,12

(loai ca

p CH3COO

H v

a C2H5COOH)

Mat kha

c s

o mo

l 2 axit tron

—

-=

=5,2 nen loai ca

y 2 axit d

Vay cho

n B

Ca

u 23 : Toe d

g thd

i

gian tren la:

y cho

n C

Ca

u 24 : Theo

d _e tripepti

t X

va tetrapepti

t Y c6 con

va

2N4O5

Vay 44.0,05

m + 18.0,025(2m

- 2 ) - 36,3 m

- 12

Suy r

a X , Y deu ta

o bcf

i alanin

Do d

o tripepti

t X c6 con

g thiir c C9H17N3O4

Dot 0,0

1 mo

l X thu di/ac 0,0

a cacbohidra

t thuo

c loa

i disaccarit Va

y cho

n C

Ca

u 26 : Ta c

6 s

o mo

l Al'''

* = 2.0,015.0,5 =

0,045 tijf

c V = 18

0 ml Va

y cho

n C

Ca

u 27 : Ure c

6 con

g thuf

c l a (NH2)2CO

Vay cho

n C

158

Cau 28: V i 1,12 l i t X (dktc) phan ling v6i dung dich Ca(0H)2 du, t h u diioc 1,5 gam

ket tua nen X chtfa 30% CO2 theo the tich

Nhif vay 4 k m o l X gom: •

CO^ ;1,2 k m o l

C O : a k m o l O2 :b k m o l

Cau 29: V i moi chat chay deu t h u diigc so m o l H2O b a n g so m o l CO2 nen m o i

chat deu chi chijfa I T :

n

Vi UAg = 0,26 m o l nen 2 < < 4 , suy r a c6 m o t chat la H C H O

Theo de X la H C H O ; Y la RCHO NhiAig X, Y c6 cung so C nen Y phai la H C O O H Goi a, b 1^ so m o l H C H O va H C O O H

dung dic

h HC

l va

o X den kh

l ne

n V = 0,02

0,25

= 0,0

8 lit Va

y cho

n A

Cau 32:

Vi so ' mo

va HC

l d

a dung , t

a c6 :

2a + 2a - 0,048 <t:>

a = 0,012

Vay mmuo

i = nikimioai

+

m ^^

^ + m

^ ^

= 1,78

8 + 96.0,012 +

35,5.2.0,012 3,792 gam

- Va

y cho

n D

Cau 33:

Vi dun

g dic

h X chufa FeS04

, Fe

(N03

)2, KMn04, BaCl2

, CI

2 va Al Va

y cho

n A

Cau 34:

35,5.0,12 + 17.0,01 =

Trong ca

c polim

e tren , nhOn

y cho

n D

Fe + 4H^

+ NO

: >

Fe

^ ^ + NO + 2H2

Theo d

e t a

col

Cu

0,025mol 2Fe

n ufn

g c

6 chufa : 0,0

160

3Fe^" + 4 H ^ + N O ; > 3Fe^^ + N O + 2H2O

+ Can cii vao vi tri cdc cap oxi hoa khi2 trong day dien hoa, thiJc tU cdc phdn

ling oxi hoa khxi xdy ra khi cho X vao dung dich AgNOs du phdi Id:

3Fe^* + 4W + N O , > 3Fe^* + NO + 2H2O

Fe^* + A g " > Fe^* + Ag

+ Cach giai khac (dung d i n h luat bao t o a n electron)

Chu y r S n g Fe v a Cu b a n dau da cho electron de t h a n h Fe*^ v a Cu*^ cf cuol

thi nghiem; tiicfng t\i N*^ v a A g " ban dau da n h a n electron de t h a n h N"^ va A g

ct cuoi t h i n g h i e m , t a c6 cac qua t r i n h cho, n h a n electron:

C H O N H A N

Fe > Fe"^ + 3e N O ; + 4 H " + 3e > N O + 2H2O (*)

0,05mol 0,15mol 0,05mol 0,0375mol

Cu > Cu"^ + 2e A g " + e > Ag

0,025mol 0,05mol 0,0125mol 0,0125mol

Nhif vay B a ( 0 H ) 2 da d u n g dtf, sau p h a n ufng t h u diicfc 0,1 m o l k e t t u a tuTc

nikettiia = 19,7 gam V a y chon C

Suy r

a s

o mo

l axit

X = 0,05;

tong

so mo

l 2 ancol Y

; Z = 0,15

Goi n

la so' C

cua a

xit v

a m

la so' C trung bin

h cu

a 2 ancol

Ta C

O 0,05

n + 0,15m = 0,3

5

Nh Lf ng

m >

1 nen 0,05n < 0,3

5 0,15 = 0,2

c CH2

(COOH)2

Theo

de ax

it X

c6 %0

(theo kho

i liidng) <

70%

nen (C00H

)2

kho

Va

y X la CH2

(COOH)2

Goi a, b la

so mo

l CH3OH

va C2H5OH, ta

c6 he:

'0,05.3 + a + 2

b = 0,35 |

a = 0,l

a +

b = 0,15 [b

LT CT C cufng kh

i du

n so

i th

i ma

t tinh

cufng

pha

n Ca(HC03

)2, Mg(HC03)2

Ca

u 41 :

Cac kh

i CO2, NO2,

va SO

2 la ca

c ox

it axit

n en

tac dung

Vay chon D

Ca

u 42 :

Trong cac ph

at bie

u tre

n, ca

c ph

n thiicfng, glucozc

g nLfcfc

dac

- Trong cong nghiep

d it oc

pha

m, saccarozo

diJOc

diing

d e

Ca

u 43 :

ban

g dun

g dic

h Na

v

a muo

i NaOOC-COONa Va

So

ml C2H5O H

= = 36,8 ;

So

ml nifdr

c =

460 36,8 =

423,3

Va

y kh

oi Itfcfn

g dun

g dic

h anco

l ba

n da

u ^ 36,8.0,8

+ 423,2

1 = 452,64

gam

s

n

K " ' = ' dau an b H l C2H5O mo So = 0,6

4 mo

30

Vi H = 30

%

n en

chi c

6 0,64 =0,19

2 mo

l C9H5O H

C2H5OH + Oa

0,192mol 0,192mol

0,192mol 60.0,192.100

2,51(%) Vay chon C

Do do nong do % axit axetic =

452,64 + 0,192.32

Cau 45: V i hon hop 0,1 mol X va 0,2 l i t dung dich H^SO^ 0,5M c6 chufa 0,4 mol

H"^ nen dung dich bazo da dung phai chufa 0,4 m o l O H " , tufc dung dich bazcf chufa 0,1 mol N a O H va 0,3 mol K O H

Theo de t h i 36,7 gam rSn gom:

O O C H ^ N R C O O :0,1 SO^" :0,1 m o l

moL-N a " :0,1 m o l :0,3 m o l

Do do 0,1(104 + R) + 96.0,1 + 23.0,1 + 39.0,3 = 36,7 <=> R = 27 (C2H3)

Suy ra aminoaxit da cho la HOOCCH(NH2)CH2COOH, c6

% N = l i i l l ^ = io,526(%) Vay chon C

Li^u y: Khong can dung d& kien so gam hon hap Id 24 gam

Cau 47: Trong so cac dung dich t r e n , dung dich H2SO4 c6 nong do \6n n h a t

nen c6 p H thap nhat Vay chon B

Cau 48: Cac phan ufng xay ra la

- Cho A l vao dung dich H C l

- Cho A l vao dung dich A g N O ,

- Cho N a vao H^O Vay chon A

Cau 49: Trong phiiong t r i n h phan ufng2Cr+ 3Sn^'^

chat khuf, Sn^* la chat oxi hoa Vay chon D

- > 2 C r ' ^ + 3 S n t h i Cr la

u 50 : But-l-e

n kh

CH

O

Fe > Fe^^ +

-a

= (108.0,0

2 + 64.0,05) -

56.0,06 =

2 gam

Vay cho

n C '

Ca

u 52 : T

g 34,

5 (T

i >

T2) chufng t

i s

o mo

l CO2

a CniH2r

a + 2O

(b mol

)

a = 0,2

b = 0,15

an + bm = 0,

9

a(14n + 32) + b(14m + 18) = 21,7

Ta

CO

he: i an + b

m =0,

9 <^ i

an + b(m + l) = l,05

Do d

o 0,2

n + 0,15m

= 0,1

8 O 4n + 3

la ph

u hop

= 9,1

8 gam Va

y cho

n D

Ca

u 54 : Saccarozc

y cho

n D

Ca

u 55 : Ca

,

andehit axetic, axi

t metacryli

c v

a stiren Va

y cho

n C

Ca

u 56 : Ho

a ta

n NH

3 vao nxldc, thu

)4](OH

)2

Vay cho

n D

164

Cau 57: Phan ufng xay ra: CH^CH^Cl + K O H ^'^^ > C2H4 + KCl + H2O

Vay chon A

Cau 58: Phan ijfng khong xay ra la Au + H N O , dac > Vay chon C

Cau 59: Tcf nitron (olon) la san pham trung hop ciia CH^ = C H - CN

Vay chon C

Cau 60: So mol Fe = 0,2; So mol Mg = 0,1

D E SO 3

D E T H I D A I H O C T H A M K H A O

D E T H I T U Y E N S I N H D A I H O C , C A O D A N G N A M 2012

Mon thi : HOA, khoi A - Ma de : 384

Cho biet nguyen tuf kho'i ciia cac nguyen to':

H 1; C = 12; N = 14; O = 16; Na - 23; Mg - 24; Al = 27; S = 32; F = 9; I - 127;

K = 39; Ca = 40; Cr = 52, Fe - 56; Cu = 64; Zn = 65; Br = 80; Ag=108; Ba = 137

I P H A N C H U N G C H O T A T C A T H I S I N H

{40 cdu, tie cau 1 den cau 40)

Cau 1 : Nguyen tijf R tao di/gc cation R* Cau hinh electron d phan Idp ngoai

nguyen tijf R la

A 11 B 10 C 22 D 23

Cau 2: Dien phan 150 ml dung dich AgNOa I M vdri dien cifc trcf trong t gicf,

cUcfng do dong dien khong doi 2,68A (hieu suat qua t r i n h dien phan la

100%), thu dugc chat ran X, dung dich Y va k h i Z Cho 12,6 gam Fe vao Y,

sau k h i cac phan ufng ket thuc thu diicfc 14,5 gam h6n hap k i m loai va k h i

NO (san pham khijf duy nhat cua N*^) Gia t r i cua t la

A 0.8 B 0,3 C 1,0 D 1,2

Cau 3: Cho cac phat bieu sau:

(a) Chat beo difcfc goi chung la triglixerit hay triaxylglixerol

(b) Chat beo nhe hon nUdc, khong tan trong n\idc nhitog tan nhieu trong

dung moi hiJu co

(c) Phan ling thiiy phan chat beo trong moi trutfng axit la phan tftig thuan nghich (d) Tristearin, triolein c6 cong thufc Ian luot la:

(CnHaaCOOaCsHs, (CnHsgCOOaCgHs So' phat bieu dung la

A 3 B 2 C 4 D 1

u 4: Ch

o da

y ca

c chat: stiren, anco

l benzyUc, aniHn

, toluen, pheno

C 5

D 2

Ca

u 5 :

(b) NaaSaO

a + dung dic

h H2SO

4 (loang)

(^)Si0

2 + M

g >

(d) AI2O

3 + dung dic

h NaO

H ^

(e) A

g + O

3 ^ (g) Si0

2 + dung dic

C 6

D 3

Ca

u 6 :

Y

(b) Y + AgNO

g + NH3 + H2

O ^ amoni glucona

t +

Ag + NH4NO3

(c) Y

—

^ E + Z

•

^d) Z + H2O

p^;^ >

X +

G

X, Y, Z Ian lifgt la:

A Tin

h bot, glucozo, etanol

B Tin

h hot, glucozo, cacbo

n dioxit

C Xenlulozo, saccarozcf

, cacbo

n dioxit

D Xenlulozo, fructozo

, cacbo

n dioxit

Ca

u 7 :

it sat B Hemati

t do C Manhetit

D Xiderit

Ca

u 8 :

H5n hop X c6 kho

4 lit O2 (dktc), cha

n b

o Y tac dun

h K2CO

3 I

M

thu dtrgc dun

g dic

h Z Li/gn

g KC

l tron

g Z nhieu

gap 5 Ian Iticfng KC

12,67%

C 18,10%

D 29,77%

Ca

u 9 :

H6n hop M gom

n chufc, mac

t Y

la

A etylmetylamin B

butylamin

C etylamin D

propylamin

166

Cau 10: Day chat nao sau day deu t h e h i e n t i n h oxi hoa k h i p h a n uTng v6i SO2?

A H2S, O2, niidrc b r o m

B O2, riLfdc b r o m , d u n g d i c h K M n 0 4

C Dung d i c h N a O H , O2, d u n g d i c h K M n 0 4

D D u n g d i c h BaCl2, CaO, nuTcJc b r o m

Cau 11: T r o n g ancol X, oxi chiem 26,667% ve k h o i luang D u n n o n g X v d i

H2SO4 dac t h u difcJc a n k e n Y P h a n tuf kho'i cua Y l a

A 56 B 70 C 28 D 42

Cau 12: Cho 2,8 gam bot sat vao 200 m l dung d i c h gorn AgNOs 0 , 1 M va

Cu(N03)2 0 , 5 M ; k h i cac p h a n ufng xay r a h o a n t o a n t h u dLfgc m g a m c h a t r a n

X Gia t r i ciia m l a

A 4,72 B 4,08 C 4,48 D 3,20

Cau 13: H i d r a t hoa 5,2 gam axetilen v<5i xuc tac H g S 0 4 t r o n g m o i trUcfng a x i t ,

dun nong Cho t o a n bo cac chat huTu ccf sau p h a n uTng vao m o t lucfng dtf dung dich AgNOs t r o n g NH3 t h u di/gc 44,16 g a m k e t t u a H i e u suat p h a n ufng

h i d r a t hoa a x e t i l e n l a

A 80% B 70% C 9 2 % D 6 0 %

Cau 14: H 6 n hop X gom 2 a m i n o a x i t no (chi c6 n h o m chijfc - C O O H va - N H 2

trong p h a n tuf), t r o n g do t i le mo : mN = 80 : 2 1 De tac d u n g vtfa du vdri 3,83 gam h o n hop X can 30 m l d u n g d i c h H C l I M M a t khac, dot chay h o a n t o a n 3,83 gam h o n hop X can 3,192 l i t O2 (dktc) D i n t o a n bo san p h a m chay

(CO2, H2O va N2) vao nirdrc v o i t r o n g diT t h i k h o l liTcfng k e t t u a t h u dxiac la

A 20 gam B 13 gam C 10 gam D 15 g a m

Cau 15: Cho cac cap oxi hoa - khijf diigc sSp xep theo chieu t a n g d a n t i n h oxi

hoa cua d a n g oxi hoa n h i i sau: Fe 2*/Fe, Cu^VCu, Fe^"/Fe^^ P h a t bieu nao sau day la dung?

A Cu^' oxi hoa difgc Fe^^ t h a n h Fe^^

B Fe^* oxi hoa duac Cu t h a n h Cu^"^

C Cu khijf duac Fe^^ t h a n h Fe

D Fe^"^ oxi hoa dtfac Cu t h a n h Cu^^

Cau 16: Dot chay hoan toan 7,6 gam hon hcrp gom mot a x i t cacboxylic no, dcfn

chijfc, mach h d va mot ancol dcfn chijfc (c6 so nguyen tii cacbon t r o n g p h a n t\i

khac nhau) t h u dtfcfc 0,3 m o i CO2 va 0,4 m o i H2O Thiic h i e n p h a n ijfng este hoa 7,6 gam h o n hop t r e n vcfi hieu suat 8 0 % t h u diicfc m gam este Gia t r i cvja m l a

A 4,08 B 6,12 C 8,16 D 2,04

C a u 17: P h a n t r a m k h d i liicmg cua nguyen to R t r o n g h o p chat k h i vdi h i d r o

(R CO so oxi hoa t h a p n h a t ) va t r o n g o x i t cao n h a t ttfcfng ufng l a a% va b % , vdi a : b = 11 : 4 P h a t bieu nao sau day l a dung?