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Outline  Analog and digital data/signals  Time and frequency domain views of signals  Bandwidth and bit rate  Transmitting digital signals as analog  Theoretical data rate  Signal

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Physical Layer:

Data and Signals

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Outline

 Analog and digital data/signals

 Time and frequency domain views of

signals

 Bandwidth and bit rate

 Transmitting digital signals as analog

 Theoretical data rate

 Signal impairment

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Analog vs Digital Data

 Data take on continuous values

 E.g., human voice, temperature reading

 Data take on discrete values

 E.g., text, integers

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Periodic Signals

A signal x(t) is periodic if and only if

x(t) = x(t+T) -  < t < 

value

time

period

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 General form: x(t) = A×sin(2 ft +  )

period

T = 1/f

peak amplitude

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0 0.5 1 1.5 2 2.5 3

A = 1, f = 1,  = /4

Varying Sine Waves

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0 0.5 1 1.5 2 2.5 3 -1.5

-1 -0.5 0 0.5 1 1.5

0 0.5 1 1.5 2 2.5 3

Demo: sine.py

) 3 2

sin(

3

1 )

2 sin(

)

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signal strength

frequency

Time Domain Representation

 plots amplitude as a function

of time

Frequency Domain Representation

 plots each sine wave’s peak amplitude against its frequency

Demo: Equalizer

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Fourier Analysis

 Any periodic signal can be represented

as a sum of sinusoids

 known as a Fourier Series

 E.g., a square wave:

=

Joseph Fourier (1768-1830)

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rd harmonic 5 th harmonic

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0 cos( 2 ) sin( 2 ) )

c t

j

n e c t

x( ) 2  0

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The time and frequency domains of a nonperiodic signal

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Frequency Spectrum

signal

0 0 f0 3f0 5f0 7f0 9f0 11f0

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Bandwidth

 A property of a medium

 Indicates the difference between the highest

and the lowest frequencies allowed to pass

<highest freq allowed> – <lowest freq

allowed>

 Also a property of a single spectrum

Cutoff frequency (half of power is lost)

Cutoff frequency (half of power is lost)

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Example

4000 to 7000 Hz Can the above

signal pass through?

) 6000

sin(

3

1 )

2000 sin(

2 )

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Digital Signals

Bit rate – number of bits per second

Bit interval – duration of 1 bit

time amplitude

bit interval

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Two digital signals: one with two signal levels and the other

with four signal levels

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The time and frequency domains of periodic and nonperiodic

digital signals

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Baseband transmission

 Sending a digital signal over a channel

without changing it to an analog signal

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A digital signal is a composite analog

signal with an infinite bandwidth.

Note

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Baseband transmission using a dedicated medium

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f = 0 Analog

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Digital vs Analog

 Adding 3rd harmonic to improve quality

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32

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Modulation of a digital signal for transmission on a bandpass channel

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Signal Attenuation

 Signal strength falls off with distance

of frequency

Transmission medium

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Sometimes the decibel is used to measure signal power

in milliwatts In this case, it is referred to as dBm and is calculated as dB m = 10 log10 P m , where P m is the power

in milliwatts Calculate the power of a signal with dBm =

−30.

Solution

We can calculate the power in the signal as

Example

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The loss in a cable is usually defined in decibels per kilometer (dB/km) If the signal at the beginning of a cable with −0.3 dB/km has a power of 2 mW, what is the power of the signal at 5 km?

Solution

The loss in the cable in decibels is 5 × (−0.3) = −1.5 dB

We can calculate the power as

Example

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Signal Distortion

 Distortion  Change in signal shape

 Only happens in guided media

 Propagation velocity varies with frequency

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Noise

between the transmitter and the

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Bit Rate = 2 × Bandwidth × log2L

Bit Rate = 2 × Bandwidth × log2L

Harry Nyquist (1889-1976)

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We need to send 265 kbps over a noiseless channel with

a bandwidth of 20 kHz How many signal levels do we need?

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A telephone line normally has a bandwidth of 3000 The

signal-to-noise ratio is usually 3162 Calculate the

theoretical highest bit rate of a regular telephone line.

Example

This means that the highest bit rate for a telephone line

is 34.860 kbps If we want to send data faster than this,

we can either increase the bandwidth of the line or improve the signal-to-noise ratio.

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We have a channel with a 1-MHz bandwidth The SNR for this channel is 63 What are the appropriate bit rate and signal level?

Solution

First, use the Shannon capacity

followed by the Nyquist formula

Example

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The Shannon capacity gives us the

upper limit; the Nyquist formula tells us

how many signal levels we need.

Note

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 Time it takes for an entire message to

completely arrive at the destination

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time

propagation

time

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First bit arrives

Last bit arrives

Sender Receiver

Propagation time

Transmission time

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Bandwidth-Delay Product

 Cross section = bandwidth

 Length = delay

number of bits that can fill the link

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Figure Filling the link with bits for case 1

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Summary

be transmitted

signal allows easier analysis

 Fourier analysis

frequencies to pass

distortion, and noise

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