Hay xac dinh kh6i hrong natri nitrat tach ra khoi dung dich khi lam lanh dung dich A d~n 20°C.. Can II.[r]
Trang 1(D~thi co 02 trang)
DE cHiNB TiIUd
DETHI CHQN HQC SINH GIOI cAPTiNH LOP 9 TRUNG HQC CO SO -NAM HQC 2018 - 2019
Mon : HOAHQC Ngay thi: 27/02/2019
Tho; gian : 150 phut (khong k~ phat d~)
SOGIAO DUC vA DAo TAO
Can I (2 di~m)
d100°C, nguoi ta da hoa tan 540 gam natri nitrat vao 300 gam nuoc dt (dung dich A) Bi~t rang d9 tan cua natri nitrat la 88 gam (y20°C Hay xac dinh kh6i hrongnatri nitrat tach ra khoi dung dich khi lam lanh dung dich A d~n 20°C
Can II (2 di~m)
Cho sad6 bien hoa sau:
A caco,~
p +B C +D E~CaCO 3
Hay tim cac ch~t thich hQ'P (rug voi cac chfr cai A, B, C, ,Y, Z Bi~t rang cluing la nhtrng chat khac nhau Vi~t phuong trinh hoa h9C cua sad6 tren,
Can ID (3,5 di~m)
Cho 6,45 gam h6n hQ'Phai kim loai hoa tri (II) A va B tac dung voi dung dich H2S04 loang du, sau khi pharr irng xay ra xong thu duoc 1,12 lit khi (dktc) va 3,2 gam chgt r~n Luong chgt r~n nay tac dung vira du voi 200 ml dung dich AgN03 0,5M thu duoc dung dich D va kim loai E L9C 19y E r6i co can dung dich D thu duoc muoi khan F
a) Xac dinh cac kim loai A, B Bi~t rang A dirng tnroc B trong "Day heat d9ng hoa h9C cua kim lo~i"
b) Dem luqng mu6i F nung (ynhi~t d9 cao m9t thai gian thu duqc 6,16 gam chgt r~n va
V lit h6n hQ'Pkhi Tinh th€ tich V, bi~t khi nhi~t phan mu6i F t~o thrum oxit kim lo~i, N02 va 02
Can IV (3 di~m)
M9t nguyen t6 A co t6ng s6 h~t trong nguyen tU b~ng 52 Trong do, s6 h~t mang di~n duang it han s6 h~t khong mang di~n la 1 h~t
a) Xac dinh vi tri cua nguyen t6 A trong bang h~ th6ng tuin hofm
b) Vi~t phuang trinh di~u ch~ A2trong phong thi nghi~m va trong cong nghi~p
Trang 2Cau V (3,5 di~m)
Cho h6n hop X g6m Mg vaFe vao dungdich CUS04,pharr (rug xong thu duoc chMr~n
Bva dungdich C Cho NaOH du vao dung dich C thu duoc k~t rna Nung k~t rna trong kh6ng khi d~n kh6i hrong kh6ng d6i thu duoc ch&tr~ D.
a) Vi~t phuong trinh h6a hoc cuacac pharr irng c6 th~ xay ra.
b) N~u kh6i hrongh6nhop X, ch&tr~n BvaD lk hrot la 1,36 gam; 1,84gam; 1,2 gam thi trong h6n hop X c6 kim 10~inao phan (rug voi dung dich CUS04? Giai thich?
Cau VI (4 di~m)
Cho V lit khi CO (dktc) di qua 6ng su chua 3,48 gam oxit kim loai nung n6ng d~n phan (rughoan toan thu duoc m gam kim 10~iva h6nhop khi c6 ti kh6i so voihidro bang 20 D~ntoan bo hrong khi nayvao binh chua 500ml dungdich Ba(OH)2 0,08M, sauphan (rug thuduoc 3,94 gam k~t rnava dungdich A Loc tach k~t rna r6i cho dungdich nuoc v6i trong du vao dung dich A ta thu duoc p gam k~t rna Cho toan b9 hrong kim Io~i thu duqc a tren vao binh chua dung dich HCI du, pharr ung k~t thuc thu duqc 1,008 lit H2 (dktc).
a) Vi~t phuong trinh h6a hoc cua cac phan (rug xay ra.
b) Tinh V, m, p va xac dinh c6ng thuc cua oxit kim Io~itren.
Cau VII (2 di~m)
C6 3 hoc sinh ti~n hanh di6u ch~ oxi b~ng phan ung nhi~t phan thu6c tim trong 6ng nghi~m, cac 6ng nghi~m duqc I~p l~n Iuqt nhu hinh (1), (2), (3):
a) Vi~t phuong trinh nhi~t phan thu6c tim?
b) Hay cho bi~t cach I~p 6ng nghi~m nhu hinh ve nao la dUngnh&t?Giai thich.
Cho K=39, Na=23, Mg=24, Ca=40, Fe=56, Cu=64, Zn=65, Ag=108, Ba=137, H=1,
C=12, N=14, 0=16, S=32, Cl=35,5.
Hpc sinh i/U'f!Cphep sir dfolngbang h? thang tulin hoan cac nguyen ta hoa hpc.
- H::ET
Trang 3-soGIAO DUC vA DAoTAO
WONG DANCHAM THI CHQN HQC SINH GI(~)1cAPTINH LOP 9 TRUNG HQC CO SO - NAM HQC 2018 - 2019
Mon:HOAHQC Ngay.tbi: 27/02/2019
clni
I -0 lOoDe, 300 gam mroc hoa tan 540 gam natri nitrat-e- dd
(~,O A
diem) -020 D e , vi d(>tan cua natri nitrat la 88 gam nen:
300 gam mroc hoa tan 264 gam natri nitrat l,Od
~ Kh6i IUQ11gnatri nitrat tach ra khoi dung dich khi lam lanh
dd A dSn 20 D e la: 540 - 264 = 276 gam l,Od
(2,0
(A) (P) diem)
(B) (C) 3) Ca(OH)2 +2HCI ~ CaCl2+2H2O 0,25d
(D) (E) 4) CaCl2 + K2C03~ CaC03 + 2KCI 0,25d
(F)
5)CO2+ NaOH ~ NaHC03 0,25d
(X) (Q) 6) 2NaHC03 + 2KOH ~ Na2C03+K2C03+2H2O 0,25d
7) Na2C03 +Ca(N03)2 ~ CaC03 +2NaN03 0,25d
(Z)
III a) Xac dinh kim Ioai A, B
(3,5
Theo dS,A dung tnroc B, khi cho A va B tac dungvoi
diem)
H2S04 loang du thu duoc khi va ch~t r~n
~ B khong phan (rug voi H2SO4
A+H2S04 IDling~ AS04 +H2t 0,25d
nA=nH = 1,12=0,05mol 0,25d
2 22,4
m., = 6,45-3,2 = 3,25g 0,25d
M A =3,25 =65 ~A Ia kern(Zn) 0,5d
0,05
Trang 4B + 2AgN0 ~B(N03)2 + 2Ag 0,25d
nAgN0= 03 ,5.0,2 = 0,1mol 0,25d
~ nB = 0,05 mol
~ M ,=12_ = 64 ~ B la d6ng (Cu) 0,5d
0,05
b) Mu6i F Iii CU(N03)2, nung anhiet dQ cao:
2Cu(N0 )2 ~2CuO +4N02 t+0 t 0,25d
1
nc(N0 h= "2nAgN0= 0,05 mol
~ mC u(N0 h=0,05.l88=9,4g 0,25d Theo d~, sau khinung thu diroc 6,16g ch~t r~n
~mhhkhf = 9,4 - 6,16 = 3,24g
GQi x la s6 mol cua CU(N03)2~ nNO,=2 x vel no, = ~x
0,25d
Ta co: 46 2 x + 32 .! x =3 ,2 4~ x =0 , 03
2
V=(2.0, 03+.! O,03).22,4 = 1,68lit 0,25d
2
IV a) Xac djnh vi tri A trong bang tuAn hoan
(3 di~m)
A ' { e+p+n = 52 {2P+n = 52 0,5d
n-p=I -p+n =1
~{p = 17
0,5d
n = 18
A thuoc 0 17, chu ki 3,nhom VIlA 0,5d b) Vi~t phuong trinh di~u ch~ A2: (A2la Cla)
- trong phong thi nghiem:
Mn02 +4HCl d~c ~ MnCl2+Cl2 +2H2O 0,5d
- trong cong nghiep:
2NaCI +2H2O dp dd )2NaOH + CI + H
V a)Vi~t phuong trinh phan frng
(3,5
Mg + CuS04 ~ MgS04 + Cu 0,25d
Fe+CuS04 ~ FeS04 + Cu (2) 0,25d MgSO4+2NaOH ~ Mg(OH)2-!.-+ Na2SO4 (3) 0,25d
FeS04 +2NaOH~Fe(OH)2 -!.-+Na2S04 (4) 0,25d
Mg(OH)2~ MgO+ H2O (5) 0,5d
Trang 5(6) 0,5d
b) Khi IUQ'Ilgchit dn D thu dUQ'chi 1,2 gam
*NSu ca Mgva Fe d6u phan irng hSt:
GQix, y l~n hrot las6 mol cua Mg v a Fe
ta c6 h~pt:
{
2 X + 56 y = 1,36
40 x +- y l60 =1,2'
2
~ Mg va Fe khong phan irng hSt
*NSu chi c6 Mg phan img (chi c6 phan irng 1 , 3 , 5):
n = 1,84-1,36 =°012mol
~ nMgO= 0,012mol
~ ffiD= mMgO = 0,012.40 =0,48g:;t: 1 , 2g (v o li )
~ Mg phan irn gh~t,Fe tham gia phan irng mot phan
0,5d
0,25d
0,5d
0,25d
VI a) Vi~t phuong trinh phan ung
(4di~m) GQi cong thirc oxit la R x O y
yCO +RxOy~ R +yC02 (1)
~ hh khi thu duoc : CO va C02
Khi cho hh khi tac dung voi Ba(OH)2 thu diroc ket rna va dd
A, khi cho mroc v i trong v an dd A lai thu diroc kSt rna
~ dd A c6 chua Ca(HC03)2
Ba(HC03)2 +Ca(OH)2~ BaC03 ,! +CaC03 ,! +H2 (4)
2
b) Tinh V, m , p va xac djnh cong thire oxit kim lo~i
n Ba(OH)2 = 0,08.0,5 = 0,04 mol
n.,! (3)= 3,94 =0,02 mol
197
~ nB a(Heo3 h(2) = 0,02 mol
neo2(1)=neo2(2) +neo2(3)=0,04+0,02=0,06 mol
0,25d
0,25d
0,25d
0,25d
0,25d
0,25d
0,25d
0,25d
Trang 6GOi avab lin hrotla s6 mol cua CO du va C02, ta c6:Ta c6:
Mu =20.2=40
0,250
0,250
nco =nco,(1)+neodu= 0,06+0,02=0,08 mol
Ap dung dinh lu~t BTKL a(1): 0,06.28+3,48 = m+0,06.44
nH = =0,045mol
~nR =0,9/n ~ MR =28n
Ta c6: _x_ = x_ => _:_= ~
VII
(2 di~m)
V~ycong thirc oxit kim loai la Fe304
a) Vi~t phuong trinh phan ung nhi~t phan thu8c tim
0,250
1,00
b)
Hinh (3) dung nh~t vi khi oxi nang han khong khi nen 6ng
nghiem dnphai Hipnghieng xuong d€ khi d~ thoat ra va
cling dS phong hoi mroc trong qua trinh dun roi xuong day
lam va 6ng nghiem,
1,0d
• Liru y:HQc sinh co th~ ghli theo cac each khac, n~u dung vin cho du di~m