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Analysis of transient heat conduction in pyinkado (xylia xylocarpa) using finite element solutions

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This paper describes the one-dimensional, transient heat conduction in a rectangular piece of Pyinkado (Xylia xylocarpa) with cross grain and in an orthotropic wooden cylinder. Computerized solutions of a generalized, nonlinear heat equation are derived by discretizing the time domain using finite element techniques.

Trang 1

ANALYSIS OF TRANSIENT HEAT CONDUCTION IN PYINKADO (Xylia xylocarpa) USING

FINITE-ELEMENT SOLUTIONS

Bui Thi Thien Kim1, Hoang Thi Thanh Huong1, Ho Xuan Cac2

1 Nong Lam University

2 Associate Technology And Science Sylvicultre

Information:

Received: 10/09/2018

Accepted: 11/02/2019

Published: 11/2019

Keywords:

Finite element method,

distribution of temperature on

wood

ABSTRACT

This paper describes the one-dimensional, transient heat conduction in a rectangular piece of Pyinkado (Xylia xylocarpa) with cross grain and in an orthotropic wooden cylinder Computerized solutions of a generalized, nonlinear heat equation are derived by discretizing the time domain using finite element techniques A simplified example of linear heat conduction

in cylindrical coordinates illustrates how to apply the finite element solutions The accuracy of the solutions for this special case is evaluated via comparing them with a well-known exact solution The results could give significant information for fire-resistant solutions in house architecture and design

1 INTRODUCTION

In order to analyze an engineering system, a

mathematical model is developed to describe the

behavior of the system The mathematical

expression usually consists of differential

equations and given conditions These

differential equations are usually very difficult to

solve if handled analytically The alternative

way to solve the differential equation is using

numerical methods The numerical method has

some advantages, not only can it solve

complicated equations but also can it reduce the

cost needed to make experiments Moreover,

numerical methods are able to predict the

physical phenomena so it can be studied and

implemented to make some devices

Considering the advantage of the numerical

method, this paper analyzes physics phenomena

in a heat transfer problem on Pyinkado materials

The knowledge of transient temperature profiles plays an important role in some wood uses, for instance, for simulating heat conditioning of logs

in veneer and plywood mills and temperature response of lumber in dry kilns Since wood is a hygroscopic and porous medium, heat transfer may occur by means of several modes: conduction, convection and radiation However, all transfers can be accounted for by using only Fourier's law of heat conduction associated with

an effective thermal conductivity

The values of these components can be determined by knowing the values of the principal conductivities and of the rotational angles between the geometric and the orthotropic axes The likelihood of obtaining an exact solution to the problem of heat conduction

in wood is negligible Therefore, approximated solutions using numerical methods have been

Trang 2

developed for special cases The purpose of this

work is to develop a more general,

three-dimensional finite difference solution for heat

conduction in wood that is shaped as a

rectangular piece with cross grain or as an

orthotropic cylinder The derivation of a one- or

two-dimensional solution, then, is straight

forward

2 MATERIALS AND METHODS

2.1 Materials

Specimens of green Pyinkado (Xylia Xylocarpa)

(20x40x150mm), which are applied a series of

experimental runs, were taken from Dong Nai,

Vietnam

2.2 Methods

The basic idea in the finite element method is to

find the solution of a complicated problem by

replacing it by a simpler one Since the actual

problem is replaced by a simpler one; the

solution is only an approximation rather than the

exact one In the finite element method the

solution domain is divided into small domain

called elements; these elements connected each

other by nodes, therefore this method is called

finite element This subdivision process is called

discretization In each element, a convenient approximate solution is assumed and the conditions of overall equilibrium of the structure are derived The derivation is using several mathematical analyses, likewise integration by parts, weighted residual Once this analyses done, each element will form matrix equation, which resulting in global matrix equations These global matrix equations solved by MATLAB to get the solution for each node All this processes are the basic procedures for the finite element method Systematically, each of the basic procedures will be discussed separately for conduction and convection problem

We use finite element method to determine the transient distribution of temperature on wood (Pyinkado) We research of a temperature-dependent T coefficient with the thermal conductivity coefficient k as show in Fig 1 , with the t-thickness and z direction (constant), the amount of heat generated in the element is

Q (W/m3) As the amount of heat transferred to the differential volume plus the amount of heat generated must be equal to the amount of heat transferred, we have (Nguyễn Lương Dũng (1993) and Phan Anh Vũ (1994))

1 +

+





 + +

 +

= + +

y x

x sti y

y

q q t dy dx x

q q Q t Qdxdy t

dx q

t

dy

From equation (2.1), to find out: − = 0

 +

Q y

q x

qx y

Eq.(2.2)

To change qx = − kTx ; qy = − kTy , Qsti=Qsti+1 because steady state so we have heat conduction equation:

0

= +





 +

Q y

T k y x

T

k

For the two-dimensional case as shown in Figure 1, heat move along the x y axis Under constant pressure condition, Luikov (1966) equations

Trang 3

Differential equation described two dimensional conductive process (2.3) was special case of general equation for Helmholtz’s conductive process (O.C Zienkiewicz (2000);Kwon, Y.W and Bang, H (2000);Zienkiewicz, O C and Taylor, R.L.(1989)

where T is temperature, t time, K thermal conductivity coefficients, respectively

Boundary conditions

Equation (2.3) must be solved with certain boundary conditions We have T = T0 on wallside S T; We will be used triangular elements to solve conductive problem (Figure 1)

We expressed heating field in element through:

T = T1 N1 + T2 N2 + T3 N3 Eq (2.4) [3,4,5]

or: T = NT e

Figure 1 first clas triangular elements in this problem

where:

 −  −    

= 1

T T T

T = 1 2 3 was temperature at dots which was finding unknown with triangular elements, we have

x

1

2

3

1

2

3

 = 1

 = 1

y

T(x,y)

T1

T3

T2

Reference element

A

(b) (a)

A

A-A

y

x

Q

q y

q x

d x

d y

Trang 4

x = N1 x1 + N2 x2+ N3 x3

To find out

 +

=

y

T x x

T

T

 +

=

y

T x x

T T

Or





 

=





 

y T x

T J T

T

J was Jacobian matrix which was defined :

=

31 31

21 21

y x

y x

J

Where: x ij = x i - x j ; y ij = y i - y j và det J = 2 Ae , here A e is the area of the triangle element inverse (1.7), to get:

e

T x

x

y y

J T

T J y

T

x

T

=





=





 

1 0 1

0 1 1 det

1

21 31

21 31

1

Eq (2.8)[5,8]

Or :

e

TT B y T x

T

=





 

Where :

=

=

21 13 32

12 31 23

21 31 21 31

21 31 31 21

det

1 det

1

x x x

y y y J x

x x x

y y y y

J

Trang 5

Results:

e T T T

T e

T B B T y T x T

y

T x

T y

T

x

T

=





 

=





+

Set up functions

As reported, we need to solve equation (2.3) with boundary conditions (i) T = T0 on ST We solve this equation similar minimum this function :

tdA QT y

T k x

T

k

A





 +

=

2

So that T = T0 on S T

To change equation (2.11) in two first term in first integral of , we will be had :

e T T e e

e T T e e

e T T T e T

e

e T T T T e A

T K T T

k T T

B B ktA

T

tdA T B B kT

tdA y

T k x

T k

2

1 2

1 2

1

2

1

2

=

=

=

=





 +

=

 



Where conductive matrix of element was defined by:

T T T e

And conductive matrix of system:

=

e T

When Q =Q e was contans in element; thick of element t = const

e

e

T Q e

e A

T r T

NtdA Q

=

NidA Ae

3

1

=

 , so that calory vector :

Trang 6

 T e

e Q

tA Q

3

Final, we have this function (2.12) in the form:

T R KT

TTT

=

 2

1

Where :

( )

=

e Q

r

To minimum functions  must perform so that satisfy with conditions T = T0 on all the note on

S T From there, to build problem apply the finite element method to define heating elements on wood following the footsteps such as:

• Elemental meshing

• Numbering each elements

• Establish the coordinate system and determine the coordinates of the nodes in each element

• Calculate the thermal conductivity of each element

+ Compute the Jacobi matrix of the element + Calculates the matrix B of the element + Calculate thermal conductance ke

• Calculate the thermal conductivity of the coefficient K

• Solve the equation for determining the temperature vector at the Te node in the systemKTe= R

3 RESULTS AND DISCUSSION

The objective of this paper is finding the temperature distribution in wood as shown in figure 4 The wood considered natural material, inside the wood consist a solid substance The initial temperature inside the wood is considered

to 30 the wood heated on the top sidewall while the bottom side is keeps at 30 temperature, meanwhile the left and right of the wood is remain insulated Wood board with a thermal conductivity k = 0.17W / m.K have the boundary conditions The two opposite sides kept at a temperature of 1000C = 373 K and below kept at

300C = 303K; Left side must be insulated Determine the temperature distribution on the wood section The face of wood which was surveyed to divide 8 elements with 10 dots is illustrated as Figure 4

vector at Te dots for system

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Following the diagram with element divided, we conducted to join many elements

Table 1: Diagram with element divided

Freedom level Elements

Following the equation we have:

=

21 13 32

12 31 23 det

1

x x x

y y y J

BT

We calculated:

=

100 100 0

0 50 50 1

=

0 100 100

50 0 50 2

=

0 100 100

50 50 0

3

B

=

100 100 0

50 0

50 4

=

100 100 0

0 50 50 5

=

0 100 100

50 0 50 6

B

=

0 100 100

50 50 0

7

=

100 100 0

50 0

50 8

B

k=0,17W/m.

K

2

3

1

5

2

0,02m 0,04m

T=1000

Figure 4 Conductive problem model

T=300

4

5

T=1000

1

7

6

6

10

8

9

Trang 8

Apply the equation k =T kAeBT TBT (t=1 unit), we calculated heating matrix of element

=

17 , 0 17 , 0 0

17 , 0 2125 , 0 0425 , 0

0 0425 , 0 0425 , 0 1

T

k

=

0425 , 0 0 0425 , 0

0 17

, 0 17 , 0

0425 , 0 17 , 0 2125 , 0 2

T

k

=

0425 , 0 0425 , 0 0

0425 , 0 2125 , 0 17 , 0

0 17

, 0 17

, 0 3

T

k

=

2125 , 0 17 , 0 0425 , 0

17 , 0 17

, 0 0

0425 , 0 0

0425 , 0 4

T

k

=

17 , 0 17 , 0 0

17 , 0 2125 , 0 0425 , 0

0 0425 , 0 0425 , 0 5

T

=

0425 , 0 0 0425 , 0

0 17

, 0 17 , 0

0425 , 0 17 , 0 2125 , 0 6

T

k

=

0425 , 0 0425 , 0 0

0425 , 0 2125 , 0 17 , 0

0 17

, 0 17

, 0 7

T

=

2125 , 0 17 , 0 0425 , 0

17 , 0 17

, 0 0

0425 , 0 0

0425 , 0 8

T

k

Conductive matrix of system (dimensions 10x10) will be constructed based on join table of this

element Boundary condition T = 1000C at dot 9 and 10, T = 300C at dot 1 and 2 we have matrix

Table 2 Matrix KT=R

We use Matlab programs to solve matrix (KT = R) with results:

T1 = 300C = 303K; T2 = 300C = 303K; T3 = 47,450C = 320,45K ; T4= 47,450C = 320,45K; T5= 64,970C

= 337,97K; T6 = 64,970C = 337,97K; T7 = 82,480C = 355,48K; T8 = 82,480C = 355,48K; T9 = 1000C

= 373K; T10 = 1000C = 373K

Trang 9

Figure 5 Conductive problem model

4 CONCLUSIONS

This paper presents the study and

implementation of finite element method to find

the temperature distribution inside wood

material (Pyinkado) The temperature

distribution were analyzed by the help of the

contour chart It was shown that the temperature

parameter governs the conduction on the heated

sidewall As the temperature increase, the

temperature in the sidewall becomes increase

too The results of the heated sidewall

conduction yield to the boundary condition for

the convection diffusion inside the wood It was

shown in contour map for each layer inside of

wood The temperature distribution inside the

wood was dominated by the temperature

conditions on the heated sidewall The study will

contribute to predicting the heat transfer process

in the logs, which will be useful for the drying

and thermal processing of wood in the wood

processing industry

5 ACKNOWLEDGEMENTS

I would like to express my endless thanks and

gratefulness to my supervisors and my students

REFERENCES Nguyen Luong Dung, (1993) Finite element

method in mechanics Ho Chi Minh City University of Technology, Vietnam

Phan Anh Vu (1994), Finite element method in

structural calculations, Ho Chi Minh City

University of Technology Ho Chi Minh,

Youth Publishing House

Dehghan, M (2004) On Numerical Solution of

the One-Dimensional Convection-Diffusion Equation Mathematical Problems in Engineering 2005

O.C Zienkiewicz (2000), The finite element

method, McGraw - Hill Kwon, Y.W and Bang, H (2000), The Finite

(2nded.)Florida: CRC Press LLC

Rannacher, R (1999) Finite Element Method for the Incompressible Navier-Stokes Equations Heidelberg: Institute of Applied Mathematics University of Heidelberg Rao, S (2005) The Finite Element Method in Engineering (4thed.).Oxford: Elsevier Inc Zienkiewicz, O C and Taylor, R.L.(1989), The Finite Element Method, Vol1 Basic Formulation and Linier Problems, 4thEd., McGraw Hill, London

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