‘day to day’ operation of process for monitoring operating efficiency Making calculations for design and development of a process i.e. quantities required, sizing equipment, number of items of equipment
Trang 1Module 9001 Mass Balance
Trang 2The accounting of all mass in a
chemical/pharmaceutical process is referred
to as a mass (or material) balance
Trang 3• ‘day to day’ operation of process for
monitoring operating efficiency
• Making calculations for design and
development of a process i.e quantities
required, sizing equipment, number of items
of equipment
Trang 4Simple example – batch mixing
Trang 5Total initial mass = total final mass = 300 kgInitial methanol mass = final methanol mass
80 + 70 = final methanol mass = 150 kg
Therefore final composition of batch is
(150/300) x 100 = 50 % by wt
Trang 61000 kg of 8% by wt sodium hydroxide
(NaOH) solution is required 20% sodium hydroxide solution in water and pure water are available How much of each is
required?
Trang 7Integral balances are carried out on batch
processes where balances are carried out on
the initial and final states of the system.
Trang 9Simple batch reaction cycle
3 steps
Add reactants etc reaction Empty reactor
Next cycle
Trang 10Continuous processes
These processes are continuous in nature and operate in steady state and balances are
carried out over a fixed period of time
Materials enter and leave process
continuously
Trang 11Law of conservation of mass
When there is no net accumulation or
depletion of mass in a system (steady state) then:
Total mass entering system = total mass
leaving system
Trang 12General mass balance equation
Input + generation – output – consumption =
accumulation
Notes: 1 generation and consumption terms refer only to generation of
products and consumption of reactants as a result of chemical reaction
If there is no chemical reaction then these terms are zero.
2 Apply to a system
3 Apply to total mass and component mass
Trang 13• System – arbritary part or whole of a system
• Steady state/non-steady state
• Accumulation/depletion of mass in system
• Basis for calculation of mass balance (unit
of time, batch etc)
• Component or substance
Trang 141000 kg of a 10 % by wt sodium chloride
solution is concentrated to 50 % in a batch evaporator Calculate the product mass and the mass of water evaporated from the
evaporator
Trang 15Mixing of streams
F1
F2
F4
Trang 16Calculate E and x
Fresh feed 1000kg, 15%
by wt sodium hydrogen carbonate
Recycle stream 300 kg, 10% satd soln
evaporator feed E, composition x%
Trang 17• Streams
• Operations/equipment sequence
• Standard symbols
Trang 18• Process flow diagram
• PID
Trang 19Typical simple flowsheet
Trang 21Exercise – batch distillation
1000 kg of a 20% by wt mixture of acetone in water is separated by multistage batch
distillation The top product (distillate)
contains 95% by wt acetone and the still
contains 2% acetone Calculate the amount
of distillate
Trang 22Use of molar quantities
It is often useful to calculate a mass balance using molar quantities of materials and to express composition as mole fractions or mole %
Distillation is an example, where equilibrium data is often expressed in mole fractions
Trang 23• To convert from moles of a substance to grams
multiply by the molecular weight
• To convert from grams to moles divide by the
molecular weight.
• Mole fraction is moles divided by total moles
Trang 25Exercise – batch distillation
1000 kmol of an equimolar mixture of
benzene and toluene is distilled in a
multistage batch distillation unit 90 % of
the benzene is in the top product (distillate) The top product has a benzene mole fraction
of 0.95 Calculate the quantities of top and bottom products and the composition of the
Trang 26Mass balance - crystalliser
A crystalliser contains 1000 kg of a saturated solution of potassium
chloride at 80 deg cent It is required to crystallise 100 kg KCl from this solution To what temperature must the solution be cooled?
Trang 27T deg cent Solubility
Trang 28At 80 deg cent satd soln contains (51.1/151.1)x100
% KCl i.e 33.8% by wt
So in 1000 kg there is 338 kg KCl & 662 kg water Crystallising 100 kg out of soln leaves a satd soln containing 238 kg KCl and 662kg water i.e
238/6.62 g KCl/100g water which is 36 g
KCl/100g So temperature required is approx 27 deg cent from table
Trang 29Mass balance filtration/centrifuge
feed suspension
wash water/solvent
solid
Trang 31Mass balance - drier
water/evaporated solvent
Trang 32Mass balance – extraction/phase
Trang 33Example (single stage extraction;
Trang 34F = 195 kg; xf = 0.11 kg API/kgwater
S = 596 kg chloroform
y = 1.72x, where y is kgAPI/kg chloroform in extract and x is kg
API/kg water in raffinate.
Trang 35Mass balance – absorption unit
feed gas stream
feed solvent exit gas stream
Trang 36Mass balances – multiple units
• Overall balance
• Unit balances
• Component balances
Trang 38Mass balance procedures
• Process description
• Flowsheet
• Label
• Assign algebraic symbols to unknowns
(compositions, concentrations, quantities)
• Select basis
• Write mass balance equations (overall, total, component, unit)
Trang 39A mass balance and tracking of usage of a solvent
used in an API production process is required for a Pollution Emission Register (PER)
Discuss and outline in general terms how you would
do this.
Trang 41• Refers to quantities of reactants and
products in a balanced chemical reaction
Trang 42Reactor mass balances
Trang 43Example – aspirin synthesis
reaction
Trang 44Limiting reactant/excess reactant
• In practice a reactant may be used in excess
of the stoichiometric quantity for various
reasons In this case the other reactant is
limiting i.e it will limit the yield of
product(s)
Trang 45A reactant is in excess if it is present in a
quantity greater than its stoichiometric
proportion
% excess = [(moles supplied – stoichiometric moles)/stoichiometric moles] x 100
Trang 46Example – aspirin synthesis
Trang 47• Fractional conversion = amount reactant
consumed/amount reactant supplied
• % conversion = fractional conversion x 100
Note: conversion may apply to single pass reactor
Trang 48Yield = (moles product/moles limiting
reactant supplied) x s.f x 100
Where s.f is the stoichiometric factor =
stoichiometric moles reactant required per mole product
Trang 49Example – aspirin synthesis
Trang 51Extent of reaction = (moles of component leaving reactor – moles of component entering
reactor)/stoichiometric coefficient of component
Note: the stoichiometric coefficient of a component
in a chemical reaction is the no of moles in the
balanced chemical equation ( -ve for reactants and
Trang 52i.e stoichiometric coefficients a = 1; b = 1
100 kmol fresh feed A; 90 % single pass
conversion in reactor; unreacted A is
separated and recycled and therefore overall process conversion is 100%
F
R
Trang 53Discussion - Synthesis of 3,3
dimethylindoline
Trang 54Discussion - Aspirin synthesis
Trang 55• Elementary Principles of Chemical
Processes, R M Felder and R W
Rousseau, 3rd edition, John Wiley, 2000