TRAC NGHIpM 2,0 tli6m Ghi vdo bdi tdm chi mQt cttib ctii A, B, C hofic D tlwdc yhuong tin trd ldi drtng.. MOt ca nd xudi ddng tr6n mOt t... PHONG GD&ET \IINH YENI.. TRic NGHIEM qz,o aiam
Trang 1\ Prr oNG-c D &Dr-l{INu YtN oE xrru rRA HQC rci' u NAU Hqc 2017 - 2a18
nt0N: roAN g
Thdi gian ldnt bhi 90 phtit, khhng kA thdi gian giao di'
I TRAC NGHIpM (2,0 tli6m)
Ghi vdo bdi tdm chi mQt cttib ctii A, B, C hofic D tlwdc yhuong tin trd ldi drtng.
cAu 1 Phuong trinh nio sau t16y li phucrng trinh bac ntr6t rrai ry *,y?
Ciu Z.Cho parabo-l (f) ,y =+vi dudng thang(d) :! =Zx-3cit nhau tai hai di6m A vi B' Khi d6, diQn tfch tam giitc OAB b{ng:
A.6 (dvdt) 8.7 (dvdt) c s (dvd| ' D.9 (dvdt)
cAu 3 Cho rtudmg trdn (o;n) c6 AB =JZn DO dai cung nh6 AB bing:
c"ry
BE CHINH THUC
A nR
c6u 4 Cho mQt hinh cAu c6 thc tich bang 50:o ,rr' Di€n tich mflt ciu d6 1i:
3
5002 a
["
-
gnlz
3
u PrrAN Tu LU4.N'(8,0 cli6m)
(mx-v=l - 1
ciu 5 (1,5 tri6m) cho hQ phuong trinh:
IT^;;, : z (*,v ln 6n; lrr li tham sd)
a) Gi6i hQ Phuong trinh vdi m = -3;
b) Tim m d0 hQ cl nghiQm duy nhat (r;y) sao cho x vit y deu nh4n gi6 tri UY*n
Ciu 6 (1,5 tliam)Cho phuong trinh: x' -Zna+4m-4= 0 (1), (x li dn; mli tham sO)
a) Tim m d6 phuong trinh (1) c6 hai nghiQm ph6n biQt;
b) Tim m d6 hai nghiQm x,;x, cria phucrng trinh (1) th6a rndn:
( n-2)(*'-2)=x" +x" -8' CAu 7 (1,5 rli6m) MOt ca nd xudi ddng tr6n mOt t<tric sing
1) biin A d6n b6n B dai 80 km, sau d6 lai ngogr ddng rtiin dia di€m C c6ch btin B 721<rrL f-trij Si-an ?u i9 xu6i ddng ft hon thdi
;i"r rdnr aOng Ia tS pftit Tinh v6n t5c ri6ng cria ca nO bi6t vfn t6c ddng nudc le 4 km/h
cAu 8
tam gi6c ABC cht nhau tPi I{.
a) Chrmg minh rAng tr: gi6c BDHF vd BCEF n6i tiiSp dudmg trtn;
b) Chring rninh rlngFH li tiaphfln gi6c cria g6c DFE;
c) Gqi MldtrungdiErn cua aC Cfrung rninh rang tu gi6c DMEFnQi ti6p dudrng trdn;
d) Gqi K h gial di6m cria dudrng thAng EF vitBC Chung minh rang H Id tr.uc tdm cria tam gihc AMK
CAu 9 (0,5 di6m)
Cho ba sii ducrng a,b,c th6a mdn a + b +
" = JM Tim gi6 tri l6n nh6t cria bi6u thric
-
Jo' +2018 r/b' +2018 Jc2 +2018
- - - - H e t - - ' Gido vihn coi kidm ta khdng gidi thich gi thAm.
B.ZrR
nR D.-4
D tA}r cm2
Trang 2PHONG GD&ET \IINH YEN
I TRic NGHIEM qz,o aiaml: ME
II Tr/ LUaN 18,0 diOm1.
HDC KIEM TRA Hgg rci, rr xAm Hgc zafi - 2018
MON: roAx q
em
oB cnixH THUc
: M6i c6u drine 0.5 di
5 (1,5
cli6m).
a) Vdi ln : -3 thi he phucrng trinh tro thinh
Ir l-l*- ! =7- l'= -t I
12*-3y=2 1 _ 8
l.' 11
NghiQrn cria hQ phuong trinh li (x,y' ( t 8 \
)=[-11;-n)
0r75
fntx-y=1 fy=ntx-L fy=mx-L
l.2x+ nry-2 [2x+ nt(ntx-1)=2 '-
[(m'+Z)x=m+2
I nt+2 I m+2
l V = tn._;_ _l l X = _-
l" m'+2 I mz +2
l1r -I tn'+2 [' m2+2
b)
0,25
ddu duong
lm+2>0 lnt> -z
<>< <i{
l2nt-2>0 "
l*rl
V6i rnoi gi6 tr! cria ra hQ
khi:
I m+2
trro._.J*= r;*1>tt
lyro- I 2nt-2
\r' lY=: :-:>Q
t- ln'+Z
pt c6 nghiQrn duy nhdt Ta c6 x vit y
e m>1
0r75
0r5
6 (1,5
eli6m).
a) A = (nt-2)2
Phucrng trinh ( 1) c6 hai nghiQrr phAn biQr x, ;x,
khi: A' > 0 e(m-2)' r0e m*2.
b) Vdi moi m thi phucrng trinh (1) lu6n c6 hai
nghiern-Theo h6 thric vi - dt, ta c6: {x, + x, = 2nt
|.', '', =4nt-4
(x, -2)(x, -Z)=x,'+xr' -8e xtxz-2(n*xr)+4=(x, + *r)'-2xrxr-g
o (r, **r)' -3x,xr+2(xr+xr)=12
0,25
(2m)' - 3.(4nt - 4) + 2.2m = t2 e 4m(nt - 2) = 0 fm=O
^I
lnt-) L"'
:0 hodc m:2.
Ta co: