Numerical Methods in Soil Mechanics A.PDF Numerical Methods in Geotechnical Engineering contains the proceedings of the 8th European Conference on Numerical Methods in Geotechnical Engineering (NUMGE 2014, Delft, The Netherlands, 18-20 June 2014). It is the eighth in a series of conferences organised by the European Regional Technical Committee ERTC7 under the auspices of the International Society for Soil Mechanics and Geotechnical Engineering (ISSMGE). The first conference was held in 1986 in Stuttgart, Germany and the series has continued every four years (Santander, Spain 1990; Manchester, United Kingdom 1994; Udine, Italy 1998; Paris, France 2002; Graz, Austria 2006; Trondheim, Norway 2010). Numerical Methods in Geotechnical Engineering presents the latest developments relating to the use of numerical methods in geotechnical engineering, including scientific achievements, innovations and engineering applications related to, or employing, numerical methods. Topics include: constitutive modelling, parameter determination in field and laboratory tests, finite element related numerical methods, other numerical methods, probabilistic methods and neural networks, ground improvement and reinforcement, dams, embankments and slopes, shallow and deep foundations, excavations and retaining walls, tunnels, infrastructure, groundwater flow, thermal and coupled analysis, dynamic applications, offshore applications and cyclic loading models. The book is aimed at academics, researchers and practitioners in geotechnical engineering and geomechanics.
Trang 1Anderson, Loren Runar et al "CASTIGLIANO’S EQUATION"
Structural Mechanics of Buried Pipes
Boca Raton: CRC Press LLC,2000
Trang 2Figure A-1 Virtual load q on a bridge useful for calculating the deflection of the bridge at the location
of q, in the direction of q, due to the truck load Q
Figure A-2 Free-body-diagrams for writing moment M for the Q-load (left) and moment m for the virtual
q-load (right) for a ring
Trang 3APPENDIX A CASTIGLIANO'S EQUATION
A powerful method for calculating deflection is the
method of virtual work Consider the beam
(bridge) of Figure A-1 We would like to know
the deflection of the beam at midspan due to a
truck load Q located as shown I locate myself at
midspan before the truck reaches the bridge I am
the virtual load, q Comes now the truck As it
reaches the location shown, I feel myself being
lowered by the deflection of the bridge at midspan
due to the truck load Q I do virtual work because
of deflection, D, of the bridge by the truck My
virtual work is qD But this virtual work acts on
the bridge which stores my virtual work as
(potential) virtual energy The stored virtual
energy is mdq, where m is the moment at any
point on the bridge due to the virtual load, and dq
is the change in curvature of the bridge at that
point due to the truck load But dq = Mdx/EI So
the virtual stored energy is mMdx/EI Equating
virtual work to virtual stored energy,
qD =fo mMdx/EI
where
q = virtual load, (Let q = 1.)
m = moment in the beam due to load q,
M = moment in the beam due to load Q,
E = modulus of elasticity of material,
I = moment of inertia of the cross section of
the beam about its horizontal neutral
surface,
L = length of the beam
Because the virtual load was set equal to unity, the
resulting equation for deflection of the bridge at
midspan due to the truck is,
D=f o mMdx/EI
integrated over the length of the beam M is the
equation of the moment as a function of x to be
integrated over the length of the beam x is
distance from an assumed origin of axes The
dummy moment, m, is the equation of moment as
a function of q throughout the length of the beam
in terms of x measured from the same origin of
axes Clearly, the two moment equations require analyses of two separate free-body-diagrams of the beam
Deflection by virtual work is not limited to a straight beam It can be a curved beam or a ring for which equations for moments M and m are written in terms of radius and angle, q Deflections can also be found for shear ing loads and thrust as well as moments In fact, because energy is scalar, the deflection due to moments, thrust and shear can be found by adding the energies of all of the load elements
Castigliano observed that it is us ually easier to apply the virtual work equation by use of the Leibnitz rule which allows differentiation under the integral sign as follows:
D=f o (M/EI)( M/ q)ds CASTIGLIANO EQUATION where
D = deflection of the beam at the location of
the virtual load q in the direction of q q is
a differential that approaches zero at the location where the deflection is to be calculated (q can also be a differential moment for calculating the angle of rotation of the beam at the location of q.),
M = equation of the moment at any point due
to both q and Q,
EI = stiffness of the beam,
ds = differential distance along the beam (dx
for the beam)
The advantage of Castigliano over virtual work is
a reduction of analysis Only one free-body-diagram is required with both the virtual load and the applied load in place For small deflections, Castigliano's equation is well adapted to rings because M can be written for the applied loads and pressures plus the virtual load in terms of stiffness EI, angle q, and ds EI is constant, and
ds = rdq where r is the radius of the ring See
Figure A-2
©2000 CRC Press LLC
Trang 4Figure A-3 F-load on a ring showing a quadrant of the ring as a free-body-diagram for evaluation of the moment at A by Castigliano's equation
Figure A-4 Free-body-diagram of a quadrant of a ring subjected to an F-load, showing the notation for evaluation of the vertical deflection of A with respect to B
Trang 5Because of symmetry, it is convenient to consider
half of the ring
Example 1
What is the moment at A due to an F-load on a
ring? The free-body-diagram is a quadrant shown
in Figure A-3 Let Q = F/2 for convenience
Moment MA is an unknown in addition to the three
reactions at B The quadrant is statically
indeterminate to the first degree Therefore, an
equation of deflection is required in addition to the
three equations of static equilibrium In this case,
it is possible to find MA by means of a single
equation of deflection Note that the relative
rotation of A with respect to B is zero, i.e., yA/B =
0 Applying m at A in the direction of rotation of
yA/B, from Castigliano,
yA/B = (M/EI)( M/ m)rdq = 0
M = Qsinq - MA - m, where m 0
M/ m = -1
Substituting into Castigliano's equation,
0 = (Qrsinq-MA)dq = [Qrcosq+MAq],
from the limits 0 < q < p/2
Substituting the limits, MA = 2Q/p
Example 2
Knowing MA, what is ring deflection, d, of
Example 1 due to the F-load? For a
free-body-diagram, use the quadrant redrawn in Figure A-4
d = D/D = (yA/B)/r; where yA/B is vertical
displacement of A with respect to B due to the
half load, Q = F/2 From Castigliano, yA/B =
(M/EI)( M/ q)rdq
M = (F/2 + q)rsinq - 2Q/p; where q 0
M/ q = r sinq
Substituting into Castigliano's equation,
yA/B = (Qr3/EI) (sin2q - (2sinq)/p)dq
yA/B = Qr3/EI[q/2 - (sin2q)/4+2cosq)/p], from the limits 0 < q < p/2
Substituting limits, yA/B = (Qr3/EI)(p/4 - 2/p) But d = (yA/B)/r, so d = 0.0186Fr2/EI This is one of the solutions in Table A-1, a summary of moments, thrusts, and ring deflections for rings subjected to typical loads
Example 3
A ring from a profile rib HDPE pipe is cut and loaded as shown in the sketch below The objective is to find any possibility for long term wall buckling at B due to constant load, F What
is the gap, 2x, as a function of load, F? The right half of ring AB is analyzed by Castigliano's equation,
x = (M/EI)( M/ p)rdq
M = (F+p)r(1-cosq); where p 0
M/ p) = r(1-cosq)
x = (Fr3/EI) (1-2cosq+cos2q)dq
Integrating,
x = (Fr3/EI)[q-2sinq+q/2+(sin2q)/4]
Substituting limits, 0 < q < p,
x = (Fr3/EI)(3p/2)
©2000 CRC Press LLC
Trang 6Table A-1 Mechanical Analyses of Thin-wall Rings With Symmetrical Loads
Trang 7©2000 CRC Press LLC
Trang 8Table A-2 Circular Arcs (Partial Circular Rings)