Numerical Methods in Soil Mechanics 10.PDF Numerical Methods in Geotechnical Engineering contains the proceedings of the 8th European Conference on Numerical Methods in Geotechnical Engineering (NUMGE 2014, Delft, The Netherlands, 18-20 June 2014). It is the eighth in a series of conferences organised by the European Regional Technical Committee ERTC7 under the auspices of the International Society for Soil Mechanics and Geotechnical Engineering (ISSMGE). The first conference was held in 1986 in Stuttgart, Germany and the series has continued every four years (Santander, Spain 1990; Manchester, United Kingdom 1994; Udine, Italy 1998; Paris, France 2002; Graz, Austria 2006; Trondheim, Norway 2010). Numerical Methods in Geotechnical Engineering presents the latest developments relating to the use of numerical methods in geotechnical engineering, including scientific achievements, innovations and engineering applications related to, or employing, numerical methods. Topics include: constitutive modelling, parameter determination in field and laboratory tests, finite element related numerical methods, other numerical methods, probabilistic methods and neural networks, ground improvement and reinforcement, dams, embankments and slopes, shallow and deep foundations, excavations and retaining walls, tunnels, infrastructure, groundwater flow, thermal and coupled analysis, dynamic applications, offshore applications and cyclic loading models. The book is aimed at academics, researchers and practitioners in geotechnical engineering and geomechanics.
Trang 1Anderson, Loren Runar et al "RING STABILITY"
Structural Mechanics of Buried Pipes
Boca Raton: CRC Press LLC,2000
Trang 2Figure 10-1 Top — Elliptical ring with uniform radial pressure P acting on it.
Bottom — Free-body-diagram of half of the elliptical ring showing approximate ring compression thrust in the walls due to pressure P
Trang 3CHAPTER 10 RING STABILITY
The performance limit of ring stability is instability
Ring instability is a spontaneous deformation that
progresses toward inversion (reversal of curvature)
At worst, instability is ring collapse Buried pipes
can invert only if the ring deflects and the soil slips
at the same time Instability of buried pipes is
analyzed as a soil-structure interaction The
stiffness of the ring resists inversion Soil supports
the ring by holding it in a stable (near circular)
shape Soil resists inversion of the ring
Two basic modes of ring instability are: 1 ring
compression, i.e., wall crushing or buckling at yield
stress; and 2 ring deformation See Figure 10-1
Each is analyzed separately Instabilities of buried
and unburied rings are also analyzed separately
UNBURIED RING COLLAPSE
From Chapters 2 and 5, external pressure at collapse
of an unburied thin-walled, circular, elastic ring is
found from the equations:
Pr3/EI = 3 R I N G D E F O R M A T I O N
COLLAPSE
where
P = external pressure at collapse,
A = wall area per unit length,
t = wall thickness of plain pipe,
m = r/t = ring flexibility,
do = initial ring deflection (ellipse),
area of the wall per unit length,
Pcr = critical pressure on the circular ring
The ring compression collapse equation is a function
of ring flexibility and yield strength
Performance limit is wall crushing The ring deformation collapse equation is a function of ring stiffness, EI/r3 Performance limit is inversion Ring stiffness is related to pipe stiffness; i.e., F /∆ = 53.77EI/D3 Pipe stiffness can be measured by a parallel plate test or three-edge-bearing test The ring deformation collapse equation is based on assumptions that the ring is elastic, and that the pipe
is restrained longitudinally Longitudinal restraint results in a plane stress analysis The Poisson ratio
is not included
In a plane strain analysis, longitudinal stress is zero, the Poisson ratio is included, and the pressure at collapse is,
Pcr = 3EI/r3(1-ν2), where
Pcr = critical pressure, i.e., P at collapse,
ν = Poisson ratio = 0.27 for steel, EI/r3 = ring stiffness
The difference in fluid pressures between top and bottom of the pipe is usually ignored, but may be significant For plane stress analysis of critical pressure at collapse of circular, unburied pipes,
For plain pipes (not coated, lined, rib stiffened, or corrugated), critical pressure at collapse is,
Moment of Inertia, I
In order to evaluate ring stiffness, EI/r3, the moment
of inertia, I, must be known For plain pipes, I =
t3/12 For corrugated pipes, tables of values for I are found in the manuals provided by manufacturers For steel pipes with lining and coating, consider
Trang 4Figure 10-2 Transformed section of a unit slice of mortar-lined and coated steel pipe wall, transformed into its equivalent section in mortar, for evaluating moment of inertia Shown on the right is the elastic stress distribution
Figure 10-3 Effective T-section , comprising stiffener ring and an effective width of pipe wall — often assumed to be 50t in steel pipes
Trang 5a unit slice of the wall See Figure 10-2.
Discounting conservatively the bond between mortar
and steel, moment of inertia, I, is the sum of the
separate moments of inertia of steel, lining, and
coating Because the mortar is the critical material,
steel is transformed into its equivalent width, n, in
mortar n = Es /Em For the layers,
Ic = tc3/12
Is = nts3/12
Il = tl3/12,
and I = Ic + Is + Il
For pipes with stiffener rings welded to the pipe, the
moment of inertia is found from the effective
T-s ection See Figure 10-3 The procedure is
described in texts on mechanics of solids For steel
pipes, the T-section comprises the stiffener ring and
an effective width of pipe wall — in steel usually
assumed to be 50t The pipe wall between effective
T-sections is ignored in calculating I
Elliptical Ring Instability
Instability of non-circular, unburied rings is difficult
to analyze However, analysis is available from
texts on mechanics of solids for one important case
— a ring that is initially elliptical with ring deflection
do Vacuum increases ring deflection Stress is
c ritical at the spring lines, B, where the ring is
subjected to both maximum ring compression stress
and maximum flexural stress See Figure 10-1
Vacuum, P, at collapse is found from:
P2 - [σf /m + (1+6mdo)Pcr] P + σ f Pcr /m = 0
(10.3a)
Equation 10.3a is applied by plotting values of P as
a function of m for given values of do and for a
constant σf For design, a simplification is proposed
by Murphy and Langner (1985),
Example 1
A plain 18-inch high-density polyethylene pipe is out-of-round (elliptical) by five percent It is unburied What is the internal vacuum at collapse?
ID = 16.217 and t = 0.857,
σf = 3.2 ksi = yield strength',
E = 110 ksi = modulus of elasticity,
Pcr = 27.5 psi = E/4m3 from Equation 10.2,
do = 0.05 = initial ring deflection
Substituting into Equation 10.3a, internal vacuum at collapse is, P = 21.5 psi From Equation 10.3b, P = 9.2 psi with ample safety factor included
Example 2
Calculate the vacuum at collapse of a mortar-lined and coated steel pipe, for which:
r = 25.5 inch (D = 51 inch for steel),
Em = 4(106) psi,
Es = 30(106) psi,
n = 7.5 = Es /Em,
σf = 10 ksi for mortar (critical),
I = 0.04893 in3,
d = 0 = ring deflection (negligible)
From Equation 10.1, Pcr = 3Σ(EmI/r3) Assuming the mean radius of the steel is,
rs = 25.5, then rc = 25.9625 and rl = 25.1625 Substituting values, Pcr = 32 psi
Example 3
What does Equation 10.3a reduce to if Pcr = P? It is easily shown that all of the terms cancel except 6mdoP, which must be zero The only way this term can be zero is if initial ring deflection is do = 0 As expected, for a circular ring, P = Pcr
Trang 6BURIED RING COLLAPSE
Stress Analysis of Elliptical Ring
Figure 10-1 is a half ring free-body-diagram At B
the ring compression stress is,
σc = P(OD)(1+d)/2A (10.4)
and the ring deformation stress (flexural stress) is,
σd = Ec(1/r'x - 1/rx) (10.5)
Notation:
P = vertical external pressure,
OD = outside diameter of the circular ring,
do = initial ring deflection,
d = ring deflection after P is applied,
r'x = radius of curvature at B due to initial ring
deflection do,
rx = radius of curvature at B after vacuum P is
applied,
c = distance from the neutral surface of the
wall to the most remote fiber (t/2 for a
plain pipe),
σd = flexural stress caused by ring deformation
Substituting in values of radii of curvature for the
ellipse from Chapter 3, the equation for flexural (ring
deflection) stress becomes:
σd = (Ec/r) 3(d-do) / (1-2d-2do) (10.6)
The maximum stress is the sum of Equations 10.4
and 10.6; i.e., σ = σc + σ f The maximum stress at B
in a buried plain pipe is,
σ = Pm(1+d) + (E/2m)3(d-do) / (1-2d-2d (10.7)o)
where m = r/t = ring flexibility of a plain pipe
Equation 10.7 can be solved to find vacuum P at
yield stress for brittle (rigid) pipes
But yield stress is not failure for plastics or
elasto-plastics (metals), for which wall crushing can occur only after ring compression stress (not flexural stress) reaches yield strength See Chapter 5 Therefore, Equation 10-7 is limited Initial ring deflection, do, depends upon compression of sidefill which requires analysis of pipe-soil interaction
Equations 10.4 to 10.7 are based on elastic theory Under some circumstances, plastic theory is justified For plain pipes and corrugated pipes, the plastic moment (at plastic hinging) is 3/2 times the moment at yield stress by elastic theory
Ring Deformation Collapse of Buried Pipes
For the following analyses, vacuum is negative
pressure, p, inside the pipe plus positive external hydrostatic pressure, u Both affect ring collapse Rigid Pipes
Because ring deflection of rigid pipes is negligible, rigid pipes are analyzed by ring compression except that vertical pressure on the pipe is P+p
Ring compression stress is,
where
σ = ring compression stress in the pipe wall,
P = total soil pressure at the top of the pipe,
including water pressure, u,
OD = outside diameter of the pipe,
A = wall area per unit length of pipe
Area A is a transformed section if the wall is composite such as concrete reinforced with steel bars For design, the ring compression stress, σ , from Equation 10.8 is equated to the strength of the pipe wall, σf, reduced by a safety factor
In the case of a very large diameter pipe, it may be necessary to consider the change in pressure of liquids (both inside and outside) throughout the depth
Trang 7of the pipe For example, if the pipe is empty, but
the water table is above the top of the pipe, it may
be prudent to apply Equation 10.8 to the bottom of
the pipe where total pressure P, acting up on the
bottom, is greater than prismatic soil pressure on top
by the increase in hydrostatic pressure between the
top and bottom Of course, water inside the pipe will
negate any increase in external hydrostatic pressure
It is noteworthy that internal vacuum and external
hydrostatic pressure have little effect on the opening
of cracks in rigid pipes The 0.01-inch crack is not
a suitable performance limit
Flexible Pipes
Collapse of buried flexible pipes is either: 1 wall
crushing (ring compression) or 2 inversion (ring
deformation) Collapse due to longitudinal bending
is not included in this analysis Bending deforms the
pipe cross section into an ellipse with the short
diameter in the plane of the bend Bending strength
is decreased Bending failure is collapse Following
are procedures for evaluating the vacuum at which
a buried flexible ring collapses
If the ring could be held circular, analysis would be
simple ring compression — the same as for a rigid
pipe But flexible ring analysis anticipates ring
deflection, do, before the vacuum is applied Ring
deflection depends upon ring stiffness and stiffness
of the embedment soil It is assumed that pipes are
initially circular and empty, and that coefficient of
friction between the pipe and the backfill is zero
because of the inevitable breakdown of shearing
stresses due to earth tremors and changes in
temperature, moisture, and pressures The
embedment is assumed to be granular The flexible
pipe is often assumed to be thin-walled; i.e., OD =
ID = D = mean diameter of the pipe
Performance limit is collapse which occurs if the
ring either crushes due to ring compression, or
inverts due to sidefill soil slip at B See Figure 10-4
COLLAPSE BY WALL CRUSHING where
σf = ring compression stress at yield stress in
the pipe wall at B,
A = wall area per unit length of pipe,
t = wall thickness = A for plain pipes,
OD = outside diameter,
P = external pressure at top of pipe,
d = ∆D = ring deflection
Area, A, is used for transformed composite sections,
or ribbed, or ring-stiffened or corrugated
At ring deformation collapse the soil must slip in order for the ring to deflect See Figure 10-4 In the left sketch, the vertical pressure includes soil pressure and vacuum; i.e PA = P+p Before it is buried, the ring is circular, but as backfill is placed, the ring deflects into an ellipse
If the ring is flexible, and if shearing stresses between pipe and soil are neligible, vertical and horizontal soil pressures are related as follows:
PArA = PBrB = Pr = constant where Pr is the product of pressure and radius of curvature at any point on the circumference of the ring For an ellipse,
rA /rB = (1+d)3/(1-d)3 Therefore,
PB = PA(1+d)3/(1-d)3 = PArr (10.10) where
rA = mean radius of curvature at the top A,
rB = mean radius of curvature at the side B,
PA = pressure on the pipe at A,
PB = pressure on the pipe at B,
d = /D = initial ring deflection,
rr = (1+d)3/(1-d)3 = ratio of radii
Trang 8Figure 10-4 UNSATURATED SOIL — (left) Free-body-diagram of an infinitesimal cube at spring line, B, showing the stresses at incipient soil slip (right) Vertical soil pressure, Po, supported by the pipe due to ring stiffness
Figure 10-5 Free-body-diagrams for finding the vertical deflection of point B by means of the Castigliano theorem
p
Trang 9But for any pipe stiffness, F/∆ (or equivalent ring
stiffness, 53.77 EI/D3), the ring itself is able to
support part of the vertical pressure as it deflects
That part of the vertical pressure supported by ring
stiffness is Po shown in the sketch on the right of
Figure 10-4 For a given ring deflection, Po can be
calculated by the Castigliano theorem from the
free-body-diagram in Figure 10-5 From the sketch on
the left, the moment M at point B can be evaluated
by noting that the slope at B does not change during
deflection θBA = 0 Knowing M, Castigliano can be
applied again using the sketch on the right from
which the vertical deflection, YB, is evaluated for the
virtual load p due to the forces on the ring quadrant
Knowing YB, the ring deflection, d, can be found as
a function of EI and Po, and from this relationship, Po
can be found as a function of d The result is:
Po = 96(EI/D3)d/(1-2d)
For small ring deflections, it is conservative to
disregard 2d in the denominator; whereupon,
Po = Ed/m3 = 96(EI/D3)d
where
that can be supported by ring
stiffness,
Ed/m3 = Po for a plain pipe,
EI/D3 = ring stiffness = 0.0186 F/∆ ,
unit length of pipe = t3/12 for plain
pipe,
Pressure Against Soil at Spring Lines
The horizontal pressure of the pipe against the soil at
B is reduced by Po; i.e.,
PB = (PA+p-Po)rr - p See Figure 10-6 for free- body-diagram and assumptions For a plain pipe, substituting in Po,
PB = (PA+uA+p-Ed/m3)rr - p (10.11) where
PB = horizontal pressure of pipe on soil,
PA = vertical external soil pressure at A,
EI/D3 = ring stiffness, F/ = 53.77(EI/D3) = pipe stiffness,
D = mean diameter of the circular ring,
r = mean radius of the circular ring = D/2,
t = thickness of the plain pipe wall,
m = r/t = ring flexibility,
d = ∆/D = initial ring deflection,
rr = (1+d)3/(1-d)3 = ratio of vertical and
horizontal radii (maximum and minimum radii of the ellipse)
If soil at B does not have adequate strength, the soil slips, and the ring inverts
Strength of Soil at Spring Lines
Because most embedment is granular, the following
is analysis of strength for granular (cohesionless) sidefill See Figure 10-6 The horizontal strength of soil at point B, at soil slip, is soil passive resistance,
σx = Kσ y
where
σx = horizontal effective soil stress at B,
y = vertical effective soil stress at B,
K = ratio of horizontal to vertical effective stresses at soil slip (ring collapse),
K = (1+sinφ)/(1-sinφ),
φ = friction angle of the embedment, for which values can be obtained from tests
σy can be evaluated at the spring lines by methods
of Chapter 4
µA = rwh for floods at level h
σ _ _
_
Trang 10Figure 10-6 SATURATED SOIL — Free-body-diagram of an infinitesimal soil cube at B, showing the stresses acting on it at incipient soil slip, and showing the shear planes at soil slip
Figure 10-7 Pressure diagram for analyzing critical hydrostatic pressure on the bottom of the pipe at inversion
of the ring from the bottom rr = ry /rx