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Tuần 14 giao an tieng anh hpt10 2016

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Lớp 10T Tiết 28 LESSION PLAN THE SYSTEM OF EQUATION 1.. Knowledge: Students use knowledge: the system of equation and solution system of equation b.. Skills: Know how to solution, and

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Tuần 14 Ngày 4 / 12 / 2015 Lớp 10T Tiết 28

LESSION PLAN THE SYSTEM OF EQUATION

1 Aim of The Lesson:

a Knowledge:

Students use knowledge: the system of equation and solution system of equation

b Skills:

Know how to solution, and applications solution system of equation

c Attitude:

• Careful, accuracy in calculations and reasoning

• Positive sense of learning, creative thinking

• Understand and apply solution system of equation

2 Subject Matter

- Reference: Algebra - Analysis for High-school Textbook

- Materials: Sheets of paper, Puzzles

3 Procedure

Exercise 1: Solve the system of equation

7 1(1)

10 1(2)

Solution Reviews:

1

y= : system of equation satisfactory

1

y≠ , (1) x 7y 1

y

⇔ =

We substitute into (2), we obtain:

39y +34y −8y −2y+ =1 0

2 (y 1)(3y 1)(13y 6y 1) 0

1 1 3

y y

= −

 =

Thus, the solution set is (8; 1 ; 10;) 1

3

Exercise 2: Solve the system of equation

2

(2 )( ) (2 1) 7 2

(4 1) 7 3

Solution From (2)⇔ =7 4x2+ +x 3y

We substitute into (1), we obtain:

(2x +y x y)( + +) x x(2 + =1) 4x + +x y

Trang 2

2 (x y 1)(2x y) 0

2

1 2

= −

Substitute y= −1 x into equation (2), we obtian

2

1 17 4

1 17 4

x

x

=

− − = ⇔

=



Substitute 2

2

y= − x into equation (2), we obtian 2

2x − + =x 7 0 ( no real roots) Thus, the solution set is

1 17 3 17 1 17 3 17

Exercise 3: Solve the system of equation

1

x y

+ = −

 − = −

Solution Hint:

(1): y= − −1 x

Thus, the solution set is (1; 2 ;) 1 1; , 2;1( )

2 2

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