In order to do that, equations of motion and continuity conditions on the interface are first written in matrix form.. Then, by an appro-priate asymptotic expansion of the solution and us
Trang 1Homogenized equations of the linear elasticity in two-dimensional domains
with very rough interfaces
Faculty of Mathematics, Mechanics and Informatics, Hanoi University of Science, 334, Nguyen Trai Str., Thanh Xuan, Hanoi, Viet Nam
a r t i c l e i n f o
Article history:
Received 19 November 2009
Received in revised form 8 February 2010
Available online 20 February 2010
Keywords:
Homogenization
Homogenized equations
Very rough interfaces
a b s t r a c t
The main purpose of the present paper is to find homogenized equations in explicit form of the linear elasticity theory in a two-dimensional domain with a very rough interface In order to do that, equations
of motion and continuity conditions on the interface are first written in matrix form Then, by an appro-priate asymptotic expansion of the solution and using standard techniques of the homogenization method, we have derived explicit homogenized equations and associate continuity conditions Since these equations are in explicit form, they are significant in practical applications
Ó 2010 Elsevier Ltd All rights reserved
1 Introduction
Boundary-value problems in domains with rough boundaries or
interfaces appear in many fields of natural sciences and technology
such as: scattering of waves on rough boundaries (Zaki and
Neu-reuther, 1971; Waterman, 1975; Belyaev et al., 1992; Abboud
and Ammari, 1996; Bao and Bonnetier, 2001), transmission and
reflection of waves on rough interfaces (Talbot et al., 1990; Singh
and Tomar, 2007, 2008), mechanical problems concerning the
plates with densely spaced stiffeners (Cheng and Olhoff, 1981),
the flows over rough walls (Achdou et al., 1998), the vibrations
of strongly inhomogeneous elastic bodies (Belyaev et al., 1998)
and so on When the amplitude (height) of the roughness is much
small comparison with its period, the problems are usually
ana-lyzed by perturbation methods When the amplitude is much large
than its period, i.e the boundaries and interfaces are very rough,
the homogenization method is required (see for instance,Kohler
et al., 1981; Kohn and Vogelius, 1984; Brizzi, 1994; Nevard and
Keller, 1997; Chechkin et al., 1999; Amirat et al., 2004, 2007,
2008; Blanchard et al., 2007; Madureira and Valentin, 2007;
Mel’nik et al., 2009)
InNevard and Keller (1997), the authors applied the
homogeni-zation method to the equations of the theory of linear anisotropic
elasticity, in a three-dimensional domain with a very rough
inter-face The authors have derived homogenized equations However,
these equations are still in the implicit form, in particular, their
coefficients are determined by functions which are the solution
of a boundary-value problem on the periodic cell (called ‘‘cell
problem”), that includes 27 partial differential equations This problem can in general only be solved numerically However, when the interface is in two-dimensions, the cell problem consists of eight ordinary differential equations, rather than partial differen-tial equations, so that, hopefully, it can be solved analytically, and as a consequence, the homogenized equations in the explicit form will then be obtained
Actually, in the present paper we have derived the explicit homogenized equations of the theory of linear elasticity in a two-dimensional domain with a very rough interface, for the case
of isotropic material We first write equations of motion and con-tinuity conditions on the interface in matrix form Then, by an appropriate asymptotic expansion of the solution, and using the homogenization method (see for example, Bensoussan et al., 1978; Sanchez-Palencia, 1980; Bakhvalov and Panasenko, 1989), the explicit homogenized equation in matrix form and associate continuity conditions have been derived From these we obtain ex-plicit homogenized equations and associate continuity conditions
in components
Since there is a large class of practical problems leading to boundary-value problems in two-dimensional domains with very rough interfaces, deriving their explicit homogenized equations is significant, and is of theoretical and practical interest as well
It is noted that, the mentioned above eight ordinary differential equations which come from (9.10) inNevard and Keller (1997)can
be solved analytically, and the explicit homogenized equations will
be then derived calculating their coefficients However, these two procedures are not as simple as those based on the matrix formu-lation (to be used in this paper), for the isotropic case and the anisotropic case as well Further, if starting from the component formulation (corresponding to Nevard and Keller’s approach), 0093-6413/$ - see front matter Ó 2010 Elsevier Ltd All rights reserved.
* Corresponding author Tel.: +84 4 35532164; fax: +84 4 38588817.
E-mail address: pcvinh@vnu.edu.vn (P.C Vinh).
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j o u r n a l h o m e p a g e : w w w e l s e v i e r c o m / l o c a t e / m e c h r e s c o m
Trang 2these procedures will become complicated for the interfaces
oscil-lating between two parallel curves such as two concentric circles
or ellipses, much complicated for the systems including more than
two unknowns In the mean time, the matrix approach will keep
almost the same simple for these cases With the mentioned
rea-sons, and in order to introduce the matrix approach to the
prob-lems more complicated than the one considered byNevard and
Keller (1997)we do not start from the cell problem (9.10)–(9.11)
in their paper
2 Equations of motion and continuity conditions in matrix
form
Consider a linear elastic body that occupies two-dimensional
domainsXþ;Xof the plane x1x3 The interface ofXþandXis
de-noted by L, and it is expressed by the equation x3¼ hðyÞ; y ¼ x1=e,
where hðyÞ is a periodic function of period 1, as described inFigs 1,
and 2 The minimum value of h is A ðA > 0Þ, and its maximum
va-lue is zero We also assume that, in the domain 0 < x1<e, i.e
0 < y < 1, any straight line x3¼ x0¼ const ðA < x0<0Þ has
ex-actly two intersections with the curve L (seeFig 2) Suppose that
0 <e 1, then the curve L is called very rough interface (or highly
oscillating interface) ofXþandX Let two partsXþ;Xof the body
be perfectly welded to each other Suppose that the body is made
of isotropic material, and it is characterized by Lame’s constants:
k;land the mass densityqdefined as follows:
k;l;q¼ kþ;lþ;qþfor x3>hðx1=eÞ
k;l;qfor x3<hðx1=eÞ
ð1Þ
where kþ;lþ;qþ;k;l;q are constant We consider the plane
strain for which the displacement components u1;u2;u3are of the
form:
ui¼ uiðx1;x3;tÞ; i ¼ 1; 3; u2 0 ð2Þ
The components of the stress tensorrij;i; j ¼ 1; 3 are related to
the displacement gradients by the following equations (Love,
1944):
r11¼ ðk þ 2lÞu1;1þ ku3;3;r33¼ ku1;1þ ðk þ 2lÞu3;3;
where commas indicate differentiation with respect to the spatial
variables xi Equations of motion are of the form (Love, 1944):
r11;1þr13;3þ f1¼q€u1; r13;1þr33;3þ f3¼q€u3 ð4Þ
in which f1; f3are the components of the body force, and a super-posed dot signifies differentiation with respect to the time t Substi-tuting(3)into(4)yields a system of equations for the displacement components whose matrix form is:
ðAhku;kÞ;hþ F ¼qu€ ð5Þ
where u ¼ ½u1u3T; F ¼ ½f1f3T, the symbol T indicates the trans-pose of matrices, the indices h, k take the values 1, 3, and:
A11¼ kþ 2l 0
0 l
A13¼ 0 k
A31¼ 0 l
k 0
A33¼ l 0
0 k þ 2l
ð6Þ
Note that, since k þ 2l>0; l>0 (seeTing, 1996), the matrix
A11is invertible SinceXþ; Xare perfectly welded to each other along L, the continuity for the displacement vector and the traction vector must be satisfied Thus we have:
½uL¼ 0; ½ðA11u;1þ A13u;3Þn1þ ðA31u;1þ A33u;3Þn3L¼ 0 ð7Þ
where nkis xk-component of the unit normal to the curve L, by the symbol ½uLwe denote the jump ofuthrough L Expressing nkin terms of h, the continuity condition(7)can be written as:
½uL¼ 0;e1½h0ðyÞðA11u;1þ A13u;3ÞL ½A31u;1þ A33u;3L¼ 0 ð8Þ
3 Explicit homogenized equations Following Bensoussan et al (1978), Sanchez-Palencia (1980), Bakhvalov and Panasenko (1989), Kohler et al (1981)we suppose that: uðx1;x3;t;eÞ ¼ Uðx1;y; x3;t;eÞ, and we express U as follows:
U ¼ V þeðN1V þ N11V;1þ N13V;3Þ þe2ðN2V þ N21V;1þ N23V;3
þ N211V;11þ N213V;13þ N233V;33Þ þ Oðe3
where V ¼ Vðx1;x3;tÞ (being independent of y), N1, N11, N13, N2, N21,
N23, N211, N213, N233are 2 2-matrix valued functions of y and x3 (not depending on x1, t), and they are y-periodic with period 1, E
is the identity 2 2-matrix In what follows, byu;ywe denote the derivative ofuwith respect to the variable y The matrix valued functions N1, , N233are determined so that the Eq.(5)and the continuity conditions(8)are satisfied Since y ¼ x1=e, we have:
Fig 1 Two-dimensional domains Xþ and X have a very rough interface L
expressed by equation x 3 ¼ hðx 1 =eÞ ¼ hðyÞ, where hðyÞ is a periodic function with
Fig 2 The curve L in the space 0yx 3 ; y 1 ; y 2 ð0 < y 1 < y 2 < 1Þ are two roots in the interval (0, 1) of equation x 3 hðyÞ ¼ 0 for y; A < x 3 ¼ const < 0; y 1 ¼
y 1 ðx 3 Þ; y 2 ¼ y 2 ðx 3 Þ.
Trang 3Substituting(9)into(5) and (8), and taking into account(10)
yield equations which we call Eqs ðe1Þ and ðe2Þ, respectively In
or-der to make the coefficients ofe1 of Eqs ðe1Þ and ðe2Þ zero, the
functions N1, N11, N13are chosen as follows:
½A11N1;y;y¼ 0; 0 < y < 1; y – y1;y2;
½A11N1
;yL¼ 0; ½N1L¼ 0 at y1;y2; N1
ð0Þ ¼ N1ð1Þ ð11Þ
½A11E þ N11;y
;y¼ 0; 0 < y < 1; y – y1; y2;
½A11 E þ N11
;y
L¼ 0; ½N11L¼ 0 at y1; y2; N11
ð0Þ ¼ N11ð1Þ ð12Þ
A11N13;y þ A13
;y¼ 0; 0 < y < 1; y – y1; y2;
A11N13;y þ A13
L¼ 0; ½N13L¼ 0; at y1; y2;
N13
where y1;y2ð0 < y1<y2<1Þ are two roots in the interval (0, 1) of
the equation hðyÞ ¼ x3 for y, in which x3 belongs to the interval
ðA 0Þ The functions y1ðx3Þ; y2ðx3Þ are two inverse branches of
the function x3¼ hðyÞ It is easy to see from(11)that N1
;y¼ 0
Equating to zero the coefficiente0of Eq.ðe1Þ provides:
A11N2
;yþ A13N1
;3
;yV þ A11 N1
þ N21;y
þ A13N11
;3
;yV;1
þ A11N23;y þ A13 N1þ N13;3
;yV;3
þ A11 N11þ N211;y
;yþ A11 E þ N11;y
V;11
þ A11N13þ N213;y
þ A13N11
;yþ A13þ A11N13;y
V;13 þ½A11N233;y þ A13N13;yV;33þ ðA33V;3Þ;3
þ½A31 E þ N11
;y
V;1þ A31N13
;yV;3;3þ F qV ¼ 0€
ð14Þ
Making the coefficiente0of Eq ðe2Þ zero gives:
A11N2
;yþ A13N1
;3
Lh0V
þ A11 N1
þ N21;y
þ A13N11
;3
Lh0 A31 E þ N11
;y
L
V;1
þ A11N23
;y þ A13 N1
þ N13;3
Lh0 ½A33þ A31N13
;y
L
V;3 þ½A11 N11
þ N211;y
Lh0V;11þ ½A11 N13
þ N213;y
þ A13N11
Lh0V;13 þ½A11N233
;y þ A13N13
Lh0V;33¼ 0
ð15Þ
In order to make(15)satisfied we take:
½A11N2
;yþ A13N1
;3L¼ 0 at y1; y2 ð16Þ
½A11N1þ N21;y
þ A13N11;3L¼ Ah 31E þ N11;yi
L=h0 at y1; y2 ð17Þ
A11N23;y þ A13N1þ N13;3
L¼ Ah 33þ A31N13;yi
L=h0 at y1; y2 ð18Þ
A11N11þ N211;y
L¼ 0 at y1; y2 ð19Þ
A11N13þ N213;y
þ A13N11
L¼ 0 at y1; y2 ð20Þ
A11N233;y þ A13N13
L¼ 0 at y1; y2 ð21Þ
By integrating Eq (14) along the line x3¼ const; A < x3<0
from y ¼ 0 to y ¼ 1 (seeFig 2), and taking into account(16)–(21)
we have:
A11E þ N11;y
V;11þ A11N13;y þ A13
V;13
þ A31 E þ N11
;y
V;1þ A31N13
;y
V;3
;3
þ ½hA33iV;3;3þ F hqi €V ¼ 0 ð22Þ
here:
hui ¼
Z1 0
udy ¼ ðy2 y1Þuþþ ð1 y2þ y1Þu ð23Þ
Note that if mijare elements of matrix M, then hMi ¼ ðhmijiÞ It is clear that in order to make Eq.(22)explicit we have to calculate the quantities:
q1¼ A11 E þ N11
;y
; q2¼ A11N13
;y þ A13
;
q3¼ AD 31E þ N11;yE
; q4¼ AD 31N13;yE ð24Þ
From(11)–(13), it is not difficult to verify that:
q1¼ A111
D E1
;q2¼ A111
D E1
A1
11A13
;q3¼ A31A1
11
A1 11
D E1
q4¼ A31A1
11
A1 11
D E1
A1
11A13
A31A1
11A13
ð25Þ
On use of(24) and (25)into(22)we have:
A111
D E1
V;11þ A111
D E1
A111A13
V;13
þ DA31A111E
A111
D E1
V;1
;3
þ hA33i þ AD 31A111E
A111
D E1
A111A13
A31A111A13
V;3
;3
Therefore we have the following theorem
Theorem 1 Let uðx1;x3;e;tÞ satisfy(5) and (8)with Ahkare defined
by(6), the curve L: x3¼ hðyÞ; y ¼ x1=e, is a very rough interface which oscillates between two lines x3¼ 0 and x3¼ A ðA > 0Þ and hðyÞ is a differentiable y-periodic function with period 1 In addition, suppose
u ¼ Uðx1;y; x3;e;tÞ and Uðx1;y; x3;e;tÞ has asymptotic form(9) Then, Vðx1;x3;tÞ is a solution of the problem:
A1 11
D E1
V;11þ A1 11
D E1
A1
11A13
V;13þ A31A1
11
A1 11
D E1
V;1
;3
þ hA33i þ A31A1
11
A1 11
D E1
A1
11A13
A31A1
11A13
V;3
;3
ð28Þ
þ hFi hqi €V ¼ 0; A < x3<0
A31A1 11
A1 11
D E1
V;1þ
hA33i þ A31A1
11
A1 11
D E1
A1
11A13
A31A1
11A13
V;3
¼ 0 and ½VL¼ 0; Lis lines x3¼ 0; x3¼ A Note that the continuity condition(30)1is originated from:
½A31u;1þ A33u;3L¼ 0;
Lis either the line x3¼ 0; or the line x3¼ A ð31Þ
Substituting(9)into(31)and taking into account(10)yield an equation denoted by Eq ðe3Þ By equating to zero the coefficient of
e0of Eq ðe3Þ we have:
A31E þ N11;y
V;1þ A 33þ A31N13;y
V;3
Integrating(32)along the line Lfrom y ¼ 0 to y ¼ 1 and using the results obtained above we derive equation(30)
Trang 4On use of(6), we can write(27)–(30)in the component form as:
ðkþþ 2lþÞV1;11þlþV1;33þ ðkþþlþÞV3;13þ f1 þ¼qþV€1;
x3>0
ðkþþlþÞV1;13þlþV3;11þ ðkþþ 2lþÞV3;33þ f3 þ¼qþV€3;
x3>0
8
>
<
>
:
ð33Þ
1
kþ2l
D E1
V1;11þ 1
l
D E1
V1;3
;3
þ 1 l
D E1
V3;1
;3
þ 1
kþ2l
D E1
k þ2l
D E
V3;13þ hf1i ¼ hqi €V1; A < x3<0;
1
l
D E1
V1;13þ k
þ2l
D E
1 kþ2l
D E1
V1;1
;3
þ 1 l
D E1
V3;11
kþ2li1h k
þ2l
þ 4 lðkþlÞ kþ2l
V3;3
;3
þ hf3i ¼ hqi€V3;
A < x3<0
0
B
B
B
B
B
B
B
B
ð34Þ
ðkþ 2lÞV1;11þlV1;33þ ðkþlÞV3;13þ f1 ¼qV€1;
x3<A
ðkþlÞV1;13þlV3;11þ ðkþ 2lÞV3;33þ f3 ¼qV€3;
x3<A
8
>
<
>
:
ð35Þ
V1;V3;r0
13;r0
33 continuous on x3¼ A; x3¼ 0 ð36Þ
where
r0
13¼ h1=li1ðV1;3þ V3;1Þ;
r0
33¼ h1=ðk þ 2lÞi1hk=ðk þ 2lÞiV1;1
þ h1=ðk þ 2lÞi1hk=ðk þ 2lÞi2þ 4 lðk þlÞ
kþ 2l
V3;3 ð37Þ
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