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bài giảng hóa bằng tiếng anh Chemical Kinetics hay

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• kinetics is the study of the factors that affect the speed of a reaction and the mechanism by which a reaction proceeds.. • experimentally it is shown that there are 4 factors that i

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Chemical Kinetics

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• kinetics is the study of the factors that affect the speed of a reaction and the mechanism

by which a reaction proceeds

• experimentally it is shown that there are 4

factors that influence the speed of a

reaction:

nature of the reactants,

temperature,

catalysts,

concentration

Kinetics

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Defining Rate

rate is how much a quantity changes in a given

period of time

• the speed you drive your car is a rate – the distance your car travels (miles) in a given period of time (1 hour)

 so the rate of your car has units of mi/hr

time

distance Speed

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Defining Reaction Rate

• the rate of a chemical reaction is generally measured in terms of how much the concentration of a reactant

decreases in a given period of time

 or product concentration increases

• for reactants, a negative sign is placed in front of the

definition

time

[reactant]

time

[product]

Rate

time

ion

concentrat Rate

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Reaction Rate Changes Over Time

• as time goes on, the rate of a reaction generally

slows down

because the concentration of the reactants decreases

• at some time the reaction stops, either because the reactants run out or because the system has

reached equilibrium

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at t = 0

[A] = 8

[B] = 8

[C] = 0

at t = 0 [X] = 8 [Y] = 8 [Z] = 0

at t = 16

[A] = 4

[B] = 4

[C] = 4

at t = 16 [X] = 7 [Y] = 7 [Z] = 1

       

1 6 0 0.25

0

4 Rate

t t

C C

t

C Rate

1 2

1 2

1 6 0 0.0625

0

1 Rate

t t

Z Z

t

Z Rate

1 2

1 2

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       

1 6 0 0.125

4

6 Rate

t t

C C

t

C Rate

1 2

1 2

1 6 0 0.0625

7

6 Rate

t t

X X

t

X Rate

1 2

1 2

at t = 16

[A] = 4

[B] = 4

[C] = 4

at t = 16 [X] = 7 [Y] = 7 [Z] = 1

at t = 32

[A] = 2

[B] = 2

[C] = 6

at t = 32 [X] = 6 [Y] = 6 [Z] = 2

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       

1 6 0 0.0625

6

5 Rate

t t

X X

t

X Rate

1 2

1 2

       

1 6 0 0.125

2

0 Rate

t t

A A

t

A Rate

1 2

1 2

at t = 32

[A] = 2

[B] = 2

[C] = 6

at t = 32 [X] = 6 [Y] = 6 [Z] = 2

at t = 48

[A] = 0

[B] = 0

[C] = 8

at t = 48 [X] = 5 [Y] = 5 [Z] = 3

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Hypothetical Reaction

Time

(sec)

Number Red

Number Blue

in this reaction, one molecule of Red turns into one molecule of Blue

the number of molecules will always total 100

the rate of the reaction can

be measured as the speed of loss of Red molecules

over time, or the speed of gain of Blue molecules

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Hypothetical Reaction

Red  Blue

Concentration vs Time for Red -> Blue

100

84

71

59

50

42

35

30

25

21

18

0

16

29

41

50

58

65

70

82

0

10

20

30

40

50

60

70

80

90

100

0 5 10 15 20 25 30 35 40 45 50

Number Red Number Blue

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Hypothetical Reaction

Red  Blue

Rate of Reaction Red -> Blue

5, 3.2

10, 2.6

15, 2.4

20, 1.8

25, 1.6

30, 1.4

35, 1 40, 1

45, 0.8

50, 0.6

0

0.5

1

1.5

2

2.5

3

3.5

4

4.5

,

]/

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Reaction Rate and Stoichiometry

• in most reactions, the coefficients of the balanced

equation are not all the same

H2 (g) + I2 (g)  2 HI(g)

• for these reactions, the change in the number of

molecules of one substance is a multiple of the change in the number of molecules of another

 for the above reaction, for every 1 mole of H2 used, 1 mole of I2 will also be used and 2 moles of HI made

 therefore the rate of change will be different

• in order to be consistent, the change in the concentration

of each substance is multiplied by 1/coefficient

t

HI]

[ 2

1 t

] I [ t

] H

[ Rate 2 2

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Average Rate

• the average rate is the change in measured

concentrations in any particular time period

linear approximation of a curve

• the larger the time interval, the more the average rate deviates from the instantaneous rate

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Hypothetical Reaction Red  Blue

Avg Rate Avg Rate Avg Rate

Time

(sec)

Number Red

Number Blue

(5 sec intervals)

(10 sec intervals)

(25 sec intervals)

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H2 I2

HI

Avg Rate, M/s Avg Rate, M/s Time (s) [H2], M [HI], M -[H2]/t 1/2 [HI]/t

0.000 1.000

10.000 0.819

20.000 0.670

30.000 0.549

40.000 0.449

50.000 0.368

60.000 0.301

70.000 0.247

80.000 0.202

90.000 0.165

Avg Rate, M/s Avg Rate, M/s Time (s) [H2], M [HI], M -[H2]/t 1/2 [HI]/t

0.000 1.000 0.000

10.000 0.819 0.362

20.000 0.670 0.660

30.000 0.549 0.902

40.000 0.449 1.102

50.000 0.368 1.264

60.000 0.301 1.398

70.000 0.247 1.506

80.000 0.202 1.596

90.000 0.165 1.670

Avg Rate, M/s Time (s) [H2], M [HI], M -[H2]/t

0.000 1.000 0.000

10.000 0.819 0.362 0.0181

20.000 0.670 0.660 0.0149

30.000 0.549 0.902 0.0121

40.000 0.449 1.102 0.0100

50.000 0.368 1.264 0.0081

60.000 0.301 1.398 0.0067

70.000 0.247 1.506 0.0054

80.000 0.202 1.596 0.0045

90.000 0.165 1.670 0.0037

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Concentration vs Time for H 2 + I 2 > 2HI

0.000

0.200

0.400

0.600

0.800

1.000

1.200

1.400

1.600

1.800

2.000

0.000 10.000 20.000 30.000 40.000 50.000 60.000 70.000 80.000 90.000 100.000

[H2], M [HI], M

average rate in a given

the line connecting the

of the line for [HI]

the average rate for the first 10 s is 0.0181 M/s

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Instantaneous Rate

• the instantaneous rate is the change in

concentration at any one particular time

slope at one point of a curve

• determined by taking the slope of a line tangent

to the curve at that particular point

first derivative of the function

for you calculus fans

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H 2 (g) + I 2 (g)  2 HI (g) Using [H

2], the instantaneous rate at

50 s is:

s

M

0.0070 Rate

s 40

M 28 0 Rate

Using [HI], the instantaneous rate at

50 s is:

s

M

0.0070 Rate

s 40

M 56 0 2

1 Rate

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Ex 13.1 - For the reaction given, the [I] changes from 1.000 M to 0.868 M in the first 10 s Calculate the

average rate in the first 10 s and the  [H+]

H2O2 (aq) + 3 I(aq) + 2 H+(aq)  I3(aq) + 2 H2O(l)

Solve the equation

for the Rate (in

terms of the change

in concentration of

the Given quantity)

Solve the equation

of the Rate (in terms

of the change in the

concentration for the

quantity to Find) for

s

M 3

-10 4.40

Rate

s 10

M 000

1 M 868 0 3

1 t

] I [ 3

1 Rate

] H [

Rate

2 t

] H [

t

] H [ 2

1 Rate

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