Abstract. We show that if M and Hi I,J (M) are weakly Laskerian for all i < d, then AssR(Hom(RI, Hd I,J (M))) is finite. If Hi I,J (M) is (I, J)weakly cofinite for all i 6= d, then Hd I,J (M)) is also (I, J)weakly cofinite. We also study some properties of Hi I,J (M) concerning Serre subcategory.
Trang 1MODULES WITH RESPECT TO A PAIR OF IDEALS
TRAN TUAN NAM AND NGUYEN MINH TRI
Abstract We show that if M and H I,Ji (M ) are weakly
Laske-rian for all i < d, then Ass R (Hom(R/I, HI,Jd (M ))) is finite If
H i
I,J (M ) is (I, J )-weakly cofinite for all i 6= d, then H d
I,J (M ))
is also (I, J )-weakly cofinite We also study some properties of
HI,Ji (M ) concerning Serre subcategory.
Key words: local cohomology, weakly Laskerian, weakly cofinite
2000 Mathematics subject classification: 13D45 Local cohomology
1 Introduction Throughout this paper, R is a commutative Noetherian ring and
I, J are two ideals of R In [7] Takahashi, Yoshino and Yoshizawa in-troduced the definition of local cohomology modules with respect to a pair of ideals (I, J ) which is a generalization of the definition of local cohomology modules with respect to an ideal I of Grothendieck Let
M be an R-module, the (I, J )-torsion submodule ΓI,J(M ) of M is the subset consisting of all elements x of M such that Inx ⊆ J x for some
n ∈ N For an integer i, the local cohomology functor Hi
I,J with respect
to a pair of ideals (I, J ) is the i-th right derived functor of ΓI,J Note that if J = 0, then HI,Ji coincides with the ordinary local cohomology functor Hi
I of Grothendieck
In [5] Grothendieck gave a conjecture that: For any ideal I of R and any finitely generated R-module M, the module HomR(R/I, Hi
I(M ))
is finitely generated, for all i One year later, Hartshorne provided a counterexample to Grothendieck’s conjecture He defined an R-module
M to be I-cofinite if Supp(M ) ⊆ V (I) and ExtiR(R/I, M ) is finitely generated for all i and asked: For which rings R and ideals I are the modules HIi(M ) I-cofinite for all i and all finitely generated modules
M ?
The organization of the paper is as follows In next section, we will be concerned with Grothendieck’s conjecture Theorem 2.2 shows that if M and Hi
I,J(M ) are weakly Laskerian R−modules for all i < d,
1
Trang 2then the set AssR(Hom(R/I, HI,Jd (M ))) is finite Let denote W (I, J ) = {p ∈ Spec(R) | In ⊆ p + J for some positive integer n} An R-module
M is said to be (I, J )-weakly cofinite if Supp(M ) ⊆ W (I, J ) and ExtiR(R/I, M ) is weakly Laskerian for all i ≥ 0 We prove in Theo-rem 2.6 that if HI,Ji (M ) is (I, J )-weakly cofinite for all i ≤ d, then ExtiR(R/I, M ) is weakly Laskerian for all i ≤ d On the other hand, if
Hi
I,J(M ) is (I, J )-weakly cofinite for all i 6= d, then Hd
I,J(M )) is also (I, J )-weakly cofinite (Theorem 2.7)
The last section is devoted to study some properties of Hi
I,J(M ) concerning Serre subcategory Theorem 3.1 says that if HI,Ji (M ) ∈ S for all i < d, then ExtiR(R/I, M )) ∈ S for all i < d In case (R, m)
is a local ring and M is a finitely generated R−module we see that if
Hi
I,J(M ) ∈ S for all i < d, then HomR(R/m, Hd
I,J(M )) ∈ S (Theorem 3.2)
2 Weakly Laskerian modules and cofinite modules
We begin by recalling the definition of weakly Laskerian modules ([3, 2.1]) An R-module M is said to be weakly Laskerian if the set of associated primes of any quotient module of M is finite
Lemma 2.1 ([3, 2.3])
i) Let 0 −→ L −→ M −→ N −→ 0 be an exact sequence of R−modules Then M is weakly Laskerian if and only if L and N are both weakly Laskerian Thus any subquotient of a weakly Laskerian module as well as any finite direct sum of weakly Laskerian mod-ules is weakly Laskerian
ii) Let M and N be two R−modules If M is weakly Laskerian and
N is finitely generated, then ExtiR(N, M ) and TorRi (N, M ) are weakly Laskerian for all i ≥ 0
The following theorem answers the question concerning Grothendieck’s conjecture: When is the set AssR(Hom(R/I; HI,Jd (M ))) finite?
Theorem 2.2 Let M be a weakly Laskerian R−module and d a non-negative integer If Hi
I,J(M ) is a weakly Laskerian R−module for all
i < d, then AssR(Hom(R/I; HI,Jd (M ))) is a finite set
Proof Let us consider functors F = HomR(R/I, −) and G = ΓI,J(−) Then F G = Hom(R/I, −) We have a Grothendieck spectral sequence
Trang 3by [6, 11.38]
E2p,q = ExtpR(R/I, HI,Jq (M )) ⇒
p Extp+qR (R/I, M )
We consider homomorphisms of the spectral
Ek−k,d+k−1d−k,d+k−1−→ Ek0,d−→Ed0,d kk,d+1−k Since Ek−k,d+k−1 = 0 for all k ≥ 2, Ker d0,dk = Ek+10,d It follows an exact sequence
0 −→ Ek+10,d −→ Ek0,d−→Ed0,d kk,d+1−k Hence
Ass(Ek0,d) ⊆ Ass(Ek+10,d ) ∪ Ass(Ekk,d+1−k)
By iterating this for all k = 2, , d + 1, we get
Ass(E20,d) ⊆ (
d+1
[
k=2
Ass(Ekk,d+1−k))[Ass(Ed+20,d )
It is clear that
Ed+20,d = Ed+30,d = = E∞0,d Therefore
Ass(E20,d) ⊆ (
d+1
[
k=2
Ass(Ekk,d+1−k))[Ass(E∞0,d)
For all k = 2, , d + 1 as HI,Jd+1−k(M ) a weakly Laskerian R−module,
so is E2k,d+1−k = ExtkR(R/I, HI,Jd+1−k(M )) by 2.1 (ii) As Ekk,d+1−k is a subquotient of E2k,d+1−k, it follows from 2.1 (i) that Ekk,d+1−kis a weakly Laskerian R−module Thus
d+1
S
k=2
Ass(Ekk,d+1−k) is a finite set
The proof is completed by showing that the set Ass(E∞0,d) is finite Indeed, there is a filtration Φ of Hp+q = Extp+qR (R/I, M ) with
0 = Φp+q+1Hp+q ⊆ Φp+qHp+q ⊆ ⊆ Φ1Hp+q⊆ Φ0Hp+q = Extp+qR (R/I, M )
and
E∞k,p+q−k = ΦkHp+q/Φk+1Hp+q, 0 ≤ k ≤ p + q
It follows that Ep,q
∞ is a weakly Laskerian R−module, so Ass(Ep,q
∞) is finite for all p, q In particular, Ass(E0,d
Note that finitely generated modules or modules that have finite support are weakly Laskerian modules So we have an immediate con-sequence
Trang 4Corollary 2.3 Let M be a finitely generated R−module and d a non-negative integer If Hi
I,J(M ) is finitely generated or Supp(Hi
I,J(M )) is
a finite set for all i < d, then AssR(HomR(R/I, HI,Jd (M ))) is finite
An R-module M is said (I, J )-cofinite if Supp(M ) ⊆ W (I, J ) and ExtiR(R/I, M ) is finitely generated for all i ≥ 0 ([8]) The following definition is an extension of the definitions of (I, J )-cofinite modules and I−weakly cofinite modules ([4])
Definition 2.4 An R-module M is said (I, J )-weakly cofinite if Supp(M ) ⊆ W (I, J ) and ExtiR(R/I, M ) is weakly Laskerian for all
i ≥ 0
From the definition of (I, J )-weakly cofinite modules we have the following immediate consequence
Corollary 2.5 i) Every (I, J )-cofinite module is a (I, J )-weakly
cofinite module
ii) If Supp(M ) ⊆ W (I, J ) and M is weakly Laskerian, then M is (I, J )-weakly cofinite
Theorem 2.6 Let M be an R-module and d a non-negative inte-ger such that Hi
I,J(M ) is (I, J )-weakly cofinite for all i ≤ d Then ExtiR(R/I, M ) is weakly Laskerian for all i ≤ d
Proof We now proceed by induction on d When d = 0, the short exact sequence
0 → ΓI,J(M ) → M → M/ΓI,J(M ) → 0 induces an exact sequence
0 → HomR(R/I, ΓI,J(M )) → HomR(R/I, M ) → HomR(R/I, M/ΓI,J(M ))
Since M/ΓI,J(M ) is (I, J )-torsion free, it is also I-torsion free and then HomR(R/I, M/ΓI,J(M )) = 0 It follows
HomR(R/I, M ) ∼= HomR(R/I, ΓI,J(M ))
Hence HomR(R/I, M ) is a weakly Laskerian R-module
Let d > 0 Note that HI,Ji (M ) ∼= HI,Ji (M/ΓI,J(M )) for all i > 0 Let
M = M/ΓI,J(M ) and E(M ) denote the injective hull of M From the short exact sequence
0 → M → E(M ) → E(M )/M → 0
we get
ExtiR(R/I, E(M )/M ) ∼= Exti+1R (R/I, M ) and
HI,Ji (E(M )/M ) ∼= HI,Ji+1(M )
Trang 5for all i ≥ 0 It follows from the hypothesis that Hi
I,J(E(M )/M ) is (I, J )-weakly cofinite for all i ≤ d − 1 By the inductive hypothesis ExtiR(R/I, E(M )/M ) is weakly Laskerian for all i ≤ d − 1 and then ExtiR(R/I, M ) is also weakly Laskerian for all i ≤ d Now the short exact sequence
0 → ΓI,J(M ) → M → M → 0 gives rise to a long exact sequence
· · · → Exti
R(R/I, ΓI,J(M )) → ExtiR(R/I, M ) → ExtiR(R/I, M ) → · · · Since ΓI,J(M ) is (I, J )-weakly cofinite, ExtiR(R/I, ΓI,J(M )) is weakly Laskerian for all i ≥ 0 Finally, it follows from the long exact sequence that ExtiR(R/I, M ) is also weakly Laskerian for all i ≤ d Theorem 2.7 Let M be R-module such that ExtiR(R/I, M ) is weakly Laskerian for all i and d a non-negative integer If HI,Ji (M ) is (I, J )-weakly cofinite for all i 6= d, then Hd
I,J(M )) is also (I, J )-weakly cofi-nite
Proof We use induction on d When d = 0, set M = M/ΓI,J(M ), then the short exact sequence
0 → ΓI,J(M ) → M → M → 0 gives rise a long exact sequence
· · · → ExtiR(R/I, ΓI,J(M )) → ExtiR(R/I, M ) → ExtiR(R/I, M ) → · · ·
We have Hi
I,J(M ) ∼= HI,Ji (M ) for all i > 0 and H0
I,J(M ) = 0 From the hypothesis, Hi
I,J(M ) is (I, J )-weakly cofinite for all i ≥ 0 It follows from 2.6 that ExtiR(R/I, M ) is weakly Laskerian for all i ≥ 0 There-fore, combining the long exact sequence and the hypothesis gives that ExtiR(R/I, ΓI,J(M )) is weakly Laskerian This implies that H0
I,J(M ) is (I, J )-weakly cofinite
Let d > 0 The short exact sequence
0 → M → E(M ) → E(M )/M → 0 yields
ExtiR(R/I, E(M )/M ) ∼= Exti+1R (R/I, M ) and
HI,Ji (E(M )/M ) ∼= HI,Ji+1(M ) for all i ≥ 0 Then HI,Ji (E(M )/M ) is (I, J )-weakly cofinite for all
i 6= d − 1 Note that ExtiR(R/I, ΓI,J(M )) is weakly Laskerian and then
Trang 6ExtiR(R/I, E(M )/M ) is weakly Laskerian for all i ≥ 0 By the induc-tive hypothesis HI,Jd−1(E(M )/M ) is (I, J )-weakly cofinite Therefore
Combining 2.1(ii) with 2.7 we obtain the following consequence Corollary 2.8 Let M be a weakly Laskerian R-module and d a non-negative integer If HI,Ji (M ) is (I, J )-weakly cofinite for all i 6= d, then
HI,Jd (M )) is also (I, J )-weakly cofinite
Corollary 2.9 Let I be a principal ideal of R and M a weakly Laske-rian module Then Hi
I,J(M ) is (I, J )-weakly cofinite for all i ≥ 0 Proof It follows from [7, 4.11] that HI,Ji (M ) = 0 for all i > 1 More-over, H0
I,J(M ) is a weakly Laskerian R−module, since H0
I,J(M ) is a submodule of M That means Hi
I,J(M ) is (I, J )-weakly cofinite for all
i 6= 1 Now the conclusion follows from 2.7
3 On Serre subcategory Recall that the class S of R-modules is a Serre subcategory of the category of R-modules if it is closed under taking submodules, quotients and extensions
Theorem 3.1 Let M be an R−module and d a non-negative integer
If HI,Ji (M ) ∈ S for all i < d, then ExtiR(R/I, M )) ∈ S for all i < d Proof We begin by considering functors F = HomR(R/I, −) and G =
ΓI,J(−) It is clear that F G = Hom(R/I, −) By [6, 11.38] we have a Grothendieck spectral sequence
E2p,q = ExtpR(R/I, HI,Jq (M )) ⇒
p Extp+qR (R/I, M )
Since Hi
I,J(M ) ∈ S for all i < d, E2p,q ∈ S for all p ≥ 0, 0 ≤ q < d
We consider homomorphisms of the spectral for all p ≥ 0, 0 ≤ t < d and i ≥ 2
Eip−i,t+i−1 d
p−i,t+i−1 i
−→ Eip,t d
p,t i
−→ Eip+i,t−i+1 Note that Eip,t = Ker dp,ti−1/ Im dp−i+1,t+i−2i−1 and Eip,j = 0 for all j < 0 This implies Ker dp,t−pt+2 ∼= Ep,t−p
t+2 ∼= ∼= Ep,t−p
∞ for all 0 ≤ p ≤ t We now have a filtration Φ of Ht = ExttR(R/I, M ) such that
0 = Φt+1Ht⊆ ΦtHt⊆ ⊂ Φ1Ht⊆ Φ0Ht = ExttR(R/I, M ) and
ΦiHt/Φi+1Ht= E∞i,t−i
Trang 7for all 0 ≤ i ≤ t Then there is a short exact sequence
0 → Φi+1Ht→ ΦiHt→ Ei,t−i
From the proof above we have Ei,t−i
∞ ∼= Ei,t−i
t+2 ∼= Ker di,t−i
t+2 a subquotient
of E2i,t−i and E2i,t−i ∈ S for all 0 ≤ i ≤ t It follows that Ei,t−i
∞ ∈ S for all 0 ≤ i ≤ t By induction on i we get ΦiHt ∈ S for all 0 ≤ i ≤ t Finally ExttR(R/I, M ) ∈ S for all t < d Theorem 3.2 Let M be a finitely generated module over a local ring (R, m) and d a non-negative integer If Hi
I,J(M ) ∈ S for all i < d, then HomR(R/m, HI,Jd (M )) ∈ S
Proof The proof is by induction on d When d = 0, since M is finitely generated, so is HI,J0 (M ) Hence HomR(R/m, HI,J0 (M ))) has finite length and then HomR(R/m, H0
I,J(M ))) ∈ S by [1, 2.11]
Let d > 0 It follows from [7, 1.13 (4)] that Hi
I,J(M ) ∼= HI,Ji (M/ΓI,J(M )) for all i > 0 Thus we can assume, by replacing M with M/ΓI,J(M ), that M is (I, J )-torsion-free Since ΓI(M ) ⊆ ΓI,J(M ) = 0, it follows that M is also I-torsion-free Hence, there exists an element x ∈ I which is non-zerodivisor on M Set M = M/xM, the short exact se-quence
0 → M → M → M → 0.x gives rise to a long exact sequence
· · · → Hd−1
I,J (M )→ H.x d−1
I,J (M )→ Hf d−1
I,J (M )→ Hg d
I,J(M )→ H.x d
I,J(M ) → · · ·
As Hi
I,J(M ) ∈ S for all i < d, Hi
I,J(M ) ∈ S for all i < d − 1 Then HomR(R/m, HI,Jd−1(M )) ∈ S by the inductive hypothesis Applying the functor HomR(R/m, −) to the short exact sequence
0 → Im f → HI,Jd−1(M ) → Im g → 0
we get a long exact sequence
0 → HomR(R/m, Im f ) → HomR(R/m, HI,Jd−1(M )) →
→ HomR(R/m, Im g) → Ext1R(R/m, Im f ) → · · · Note that Ext1R(R/m, Im f ) ∈ S, so HomR(R/m, Im g)) ∈ S Now from the exact sequence
0 → Im g → HI,Jd (M )→ H.x d
I,J(M )
we obtain an exact sequence
0 → HomR(R/m, Im g) → HomR(R/m, HI,Jd (M ))→ Hom.x R(R/m, HI,Jd (M ))
Trang 8It is clear that Im(HomR(R/m, HI,Jd (M ))→ Hom.x R(R/m, HI,Jd (M ))) =
0 Hence HomR(R/m, Im g) ∼= HomR(R/m, Hd
I,J(M )) and then HomR(R/m, Hd
I,J(M )) ∈ S The proof is complete
It should be mentioned that if M is a finitely generated module over
a local ring (R, m) with Supp(M ) ⊆ {m}, then M is artinian From 3.2 we obtain the following consequence
Corollary 3.3 Let M be a finitely generated module over a local ring (R, m) and d a non-negative integer If HI,Ji (M ) is finitely generated for all i < d, then HomR(R/m, Hd
I,J(M )) has finite length
Proof It follows from 3.2 that HomR(R/m, HI,Jd (M )) is finitely gener-ated Moreover Supp(HomR(R/m, Hd
I,J(M ))) ⊆ {m} Therefore HomR(R/m, Hd
I,J(M )) is an artinian R-module and then it has finite
Acknowledgments We would like to express our gratitude to Pro-fessor Nguyen Tu Cuong for his support and advice The first author
is partially supported by the Vietnam Institute for Advanced Study in Mathematics (VIASM), Hanoi, Vietnam
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Trang 9Department of Mathematics-Informatics, Ho Chi Minh University
of Pedagogy, Ho Chi Minh city, Viet Nam.
E-mail address: namtuantran@gmail.com
Department of Natural Science Education, Dong Nai University, Dong Nai, Viet Nam.
E-mail address: triminhng@gmail.com