vitit phucrng trinh dudng thing I ciit ao ttri c tei hai dii5m p, e sao cho tti gi6c MNPQ la hinh binh hdnh.. iiott ttr-c ii.h r,iu nroi .itop's.. i,ecn vd khoang cricf, tL Aiem t ei5n m
Trang 1so crAo DUC vA DAo rAo HA rlxn
TNUOxG THPT I{GT]yEn TRUNG THTEx DE Trrr THUDAI rrQC LAt{ rr xAru 2014
Mdn: TOAxt Kh6i A, B, Al (Thoi gian: 180 phft, khdng hO ttroi gian phft aC;
r pnAN cHUNG cHo rAr cA rni srNH 12,0 ai6m)
p.ha l1Z,O Ai6m; Cho hdm s6 y = x3 +3x2 - 4 (l)
\/ a,Khho s6t sg bi6n thi6n vd vE OO ttri (C) cria ham sO (t)
y,(
"no z ai6m ,(!,r),*(:r) vitit phucrng trinh dudng thing I ciit ao ttri (c) tei hai dii5m p, e sao
cho tti gi6c MNPQ la hinh binh hdnh.
Ciu2 (1,0 tli6m) Giai phucrng trinh: =2-4cos2x
/ ""['-;j
^ V" ^ f*t +l2yz +x+2=8y3 +8/
Cf,u 3 (1,0 tli6m) Giai hQ phucmg e trinh: I
:-LJtt * 8y1 +2y =5*
nfO"
4 (l,|Ai6m; Tinh tfch ph6n: t ="[ffia.
u/ c6u 5 (1, 0 tli6m) Cho hinh ch6p s.ABCD.c6 d6y ABCD la hinh thoi canh bang a (a>0), AC : a.
Tam gi6c QAB cQn t4i S vd nim trong m4t phing vudng g6c v6i mlt ddy; g6c eitra SC v6i *at pttittg (AB!D) bing 600 Ggi I ld trung ai6- cfla AB iiott ttr-c ii.h r,iu nroi itop's i,ecn vd khoang cricf,
tL Aiem t ei5n m{t phEng (SBC) theo a.
Ciu 6 1f,O AiOm; Cho c6c s6 thgc duong X, y, zthbamdn:
*' * y' + z2 + xy + yz + zx -2 Chimgminh ring: r' *!,u * r" *!,, * r'* !!r r-3
\x + y)' (y + z)" (z + x)"
rf, PHAN nftNC 1f,O AiOml Thf sinh chi tlugc lim mQt trong hai phAn (A hoic B)
t ,{, fheo chrong trinh Chudn
Wq Ta (1,0 tli6m) Trong m4t phing tga dQ Oxy Cho tam gi6c ABC vudng t4i A Phucrng trinh ducmg 1.hi"g BC ld 4x -3y - 4 = 0; c6c di6n A, B thuQc tryc hodnh vd diQn tich tam gi6c ABC biig 6 fim tgi
i,/dOtrgng tdm G cta tam gi6c ABC.
V Ceu 8a (1, 0 tli6m)
.Trong kh6ng gian vdi hQ tga dQ Oxyz, cho hai rli6m A(1;1;t) vd B (0; 2;2).Viet
ghucrng trinh m{t phing (P) di qua A, B il6ng thdi (P)
"6t o*, oy lAn luqr taitrai Aicm ph6n ti-ci vt, N
fM, N khdng trung vdi O) sao cho OM:2ON.
t / \U/cau 9a (1,0 tti6m) -.r Tim t " , / ly
h9 s5 cria sti h4ng chfa x5trong khai triiSn Niutcrn t;-i| , uitit raog
['i
+Clu+zc: = 4, neZ*
B Theo chwong trinh Nfrng coo
Cdu 7b (1, 0 tli6m) Trong mat phang vdi hQ tqa d0 Oxy, cho hai ducmg trdn (q) :x2 +(y+t)z =4 u6
(cr):(x-l)'+ f2 =2 vii5t phucrng trinh dulng thdng A, bii5t A titip xric v6i (Cr) vd A^ cgt (Cz tai hai tli€m phdn biet AB sao cho AB :2.
Ciu 8b (1, 0 tli6m) Trong kh6ng gian v6i hQ tga dQ Oxyz, cho hai duOrng thAng: A, ,; =
+ =
T uU
x-I v-(
A ' r- -J t-=' Timili6mAt6nA1,Bt6nA2saochodudrngthAngABdiquadi€mM(1;9;0).
ll^.-'t.-2-l
Ciu 9b (1,0 tli6m) Tirc6c,cht sO 1,2,?,4,5,6.Vi6t ngSu nhi€n mQt st5 Lu nhiOn g6m 4 cht s6 it6i mQt
khric nhau Tfnh x6c suSt dc vir5t du-ry c so qr ntricn sa9 cho trong mdi si5 d6 ph6i .o -At cht s6 I vd2.
.HET-Hp vd tAn thf sinh