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The lowest-order interpolation model consistent with two integration constants is linear, in the form 9.2 We seek to identify Φm1 in terms of the nodal values of u... 122 Finite Element

Trang 1

Element Fields in Linear Problems

This chapter presents interpolation models in physical coordinates for the most part, for the sake of simplicity and brevity However, in finite-element codes, the physical coordinates are replaced by natural coordinates using relations similar to interpola-tion models Natural coordinates allow use of Gaussian quadrature for integrainterpola-tion and, to some extent, reduce the sensitivity of the elements to geometric details in the physical mesh Several examples of the use of natural coordinates are given

9.1 INTERPOLATION MODELS 9.1.1 O NE -D IMENSIONAL M EMBERS 9.1.1.1 Rods

The governing equation for the displacements in rods (also bars, tendons, and shafts) is

(9.1)

in which u(x, t) denotes the radial displacement, E, Α and ρ are constants, x is the spatial coordinate, and t denotes time Since the displacement is governed by a second-order differential equation, in the spatial domain, it requires two (time-dependent) constants of integration Applied to an element, the two constants can

be supplied implicitly using two nodal displacements as functions of time We now approximate u(x, t) using its values at x e and x e+1, as shown in Figure 9.1

The lowest-order interpolation model consistent with two integration constants

is linear, in the form

(9.2)

We seek to identify Φm1 in terms of the nodal values of u Letting u e=u(x e) and

u e+1=u(x e+1), furnishes

(9.3)

9

EA u

u t

2 2

2 2

u t

m T

e e

m T

( )

+

ϕϕ 1 ΦΦ γγ1 1 γγ 1 ϕϕ

1

,

u t e( )=(1 x e)ΦΦ γγm1 m1( ),t u e+1( )t =(1 x e+1)ΦΦ γγm1 m1( ).t

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122 Finite Element Analysis: Thermomechanics of Solids

However, from the meaning of γγγγm1(t), we conclude that

(9.4)

9.1.1.2 Beams

The equation for a beam, following Euler-Bernoulli theory, is:

(9.5)

in which w(x, t) denotes the transverse displacement of the beam’s neutral axis, and

I is a constant In the spatial domain, there are four constants of integration In an element, they can be supplied implicitly by the values of w and w′=∂w/∂x at each

of the two element nodes Referring to Figure 9.2, we introduce the interpolation model for w(x, t):

(9.6)

FIGURE 9.1 Rod element.

FIGURE 9.2 Beam element.

ue

ue+1

x

wet

we

wet +1

we+1

x

Φm

e

x

1

1

1

1

1

1 1

1

=

 =

+

+

+

,

EI w

u t

4 4

2

2 0

w w w w

e e e e

− ′





+ +

2 3

1

1 1

1

0749_Frame_C09 Page 122 Wednesday, February 19, 2003 5:09 PM

Trang 3

Element Fields in Linear Problems 123

Enforcing this model at x e and at x e+1 furnishes

(9.7)

9.1.1.3 Beam Columns

Beam columns are of interest, among other reasons, in predicting buckling according

to the Euler criterion The z–displacement w of the neutral axis is assumed to depend

only on x and the x–displacement Also, u is modeled as

(9.8)

in which u0(x) represents the stretching of the neutral axis It is necessary to know

u0(x), w(x) and at x e and x e+1 The interpolation model is now

(9.9)

and

9.1.1.4 Temperature Model: One Dimension

The temperature variable to be determined is T − T0, in which T0 is a reference

temperature assumed to be independent of x The governing equation for a

one-dimensional conductor is

(9.10)

Φb1

2

2

1 3

2

1

1

1

u x z u x z w x

x

( , )= ( )− ∂ ( ),

0

w x x

( )

u x z t( , , )=(1 x) m1 m1−z(1 x x2 x3) b b,

1 1

Φ

e e

b

e e e e

u t

u t

w w w w

l= l ,

− ′





+

( ) ( ) ,

1

Φm1 1 Φb1

2

2

1 3

2

1

1

1

1

+

l

e

kA

x Ac e t

2 2

Trang 4

124 Finite Element Analysis: Thermomechanics of Solids

This equation is formally the same as for a rod equation (see Equation 9.1),

furnishing the interpolation model for the element as

(9.11)

9.1.2 I NTERPOLATION M ODELS : T WO D IMENSIONS

9.1.2.1 Membrane Plate

Now suppose that the displacements u(x, y, t) and v(x, y, t) are modeled on the

triangular plate element in Figure 9.3, using the values u e(t), v e(t), u e+1(t), v e+1(t), u e+2(t),

and v e+2(t) This element arises in plane stress and plane strain, and is called a

membrane plate element A linear model suffices for each quantity because it provides

three coefficients to match three nodal values The interpolation model now is

(9.12)

9.1.2.2 Plate with Bending Stresses

In a plate element experiencing bending only, the in-plane displacements, u and v,

are expressed by

(9.13)

FIGURE 9.3 Triangular plate element.

z

Y

middle surface

Xe+1,Ye+1

Xe+2,Ye+2

( )

t t

e e

+

0

ϕϕT ΦΦ θθ θθ

u x y t

v x y t

t t

m m m m u v

( , , ) ( , , )

( ) ( )

  =

ϕϕ ϕϕ

Φ Φ

γγ γγ

ΤΤ ΤΤ

ΤΤ ΤΤ 2

2 2 2

0 0

0 0

T T

T T

( ) ( ) ( )

( ) ( ) ( )

t

u t

u t

u t

t

v t

v t

v t

x y

e e e

e e e

=





+ +

+ +

1 2

1 2

1

1

x e+ y e+

u x y z t z w

x v x y z t z

w y

( , , , )= − ∂ , ( , , , ) ,

0749_Frame_C09 Page 124 Wednesday, February 19, 2003 5:09 PM

Trang 5

in which z = 0 at the middle plane The out-of-plane displacement, w, is assumed

to be a function of x and y only.

An example of an interpolation model is introduced as follows to express w(x, y)

throughout the element in terms of the nodal values of :

(9.14)

It follows that

(9.15)

9.1.2.3 Plate with Stretching and Bending

Finally, for a plate experiencing both stretching and bending, the displacements are assumed to satisfy

(9.16)

w, ∂w x and w y

w x y t( , , )= ϕϕb2( , )x yΦΦ γγb2 b2( )t

T

ϕϕb2 x y 1 x y x2 xy y2 x3 1 x y2 y x2 y3

2

T

w x

w y

w x

w

T

( )

Φb

x y x x y y x x y x y y

x y x x y y

x x x x y y

x y x x

2

1

1

=

+

y y x x y x y y

x y x x y y

+

1

1 1

1 1

1

1 2

3 1

y y

x y x x y y x x y x y y

x y x x y y

− +

)

x e y e ( x e x e y e ) y e

u(x, y, z, t) v(x, y, z, t) w(x, y, z, t)

z

b

b

b

b b

x y

=





ϕϕ ϕϕ

ΤΤ

ΤΤ

ΤΤ

ϕϕ

ΦΦ γγ

2

2

2

2 2( )

u x y z t u x y z t z w

x v x y z t v x y z t z

w y

( , , , )= ( , , , )− ∂ , ( , , , ) ( , , , )

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126 Finite Element Analysis: Thermomechanics of Solids

and w is a function only of x, y, and t(not z) Here, z = 0 at the middle surface, while

u0 and v0 represent the in-plane displacements Using the nodal values of u0, v0, and

w0, a combined interpolation model is obtained as

(9.17)

9.1.2.4 Temperature Field in Two Dimensions

In the two-dimensional, triangular element illustrated in Figure 9.3, the linear inter-polation model for the temperature is

(9.18)

9.1.2.5 Axisymmetric Elements

An axisymmetric element is displayed in Figure 9.4 It is applicable to bodies that are axisymmetric and are submitted to axisymmetric loads, such as all-around

pressure The radial displacement is denoted by u, and the axial displacement is denoted by w The tangential displacement v vanishes, while radial and axial

dis-placements are independent of θ Now u and w depend on r, z, and t.

There are two distinct situations that require distinct interpolation models In

the first case, none of the nodes are on the axis of revolution (r = 0), while in the second case, one or two nodes are, in fact, on the axis In the first case, the linear

FIGURE 9.4 Axisymmetric element.

u x y z t

v x y z t

w x y z t

u x y t

v x y t

w x y t

z z

b b

b

x y

( , , , )

( , , , )

( , , , )

( , , ) ( , , ) ( , , )

=





+



0

0

0

2

2

2

ϕϕ ϕϕ

ΤΤ

ΤΤ

ΤΤ

ϕϕ





=

ΦΦ γγ

ϕϕ ϕϕ

ϕϕ

Φ Φ Φ

γγ γγ γγ

ΤΤ

ϕϕ ϕϕ

b b

m

b

m

b

b

m m b

u v w

t

z z

t t t

x y

2 2

2

2

2

2

2

2

( )

( ) ( ) ( )

0 0

T T







T−T0=ϕϕ ΦΤΤ 2Φ θθ2 2 θθ2 ΤΤ= T −T0 T+1−T0 T+2−T0

r

e+2

e e+1

θ

Trang 7

interpolation model is given by

(9.19)

Now suppose that there are nodes on the axis, and note that the radial displace-ments are constrained to vanish on the axis For reasons shown later, it is necessary

to enforce the symmetry constraints a priori in the formulation of the displacement model In particular, suppose that node e is on the axis, with nodes e + 1 and e + 2

defined counterclockwise at the other vertices The linear interpolation model is now

(9.20)

A similar formulation can be used if two nodes are on the axis of symmetry so

that the u displacement in the element is modeled using only one nodal displacement,

with a coefficient vanishing at each of the nodes on the axis of revolution

9.1.3 I NTERPOLATION M ODELS : T HREE D IMENSIONS

We next consider the tetrahedron illustrated in Figure 9.5

A linear interpolation model for the temperature can be expressed as

(9.21)

u r z t

w r z t

t t

a a a a ua wa

( , , ) ( , , )

( ) ( ) .

 =

ϕϕ ϕϕ

Φ Φ

γγ γγ

1 1 1 1 1 1

T T

T T

T T

0 0

0 0

ua e e e

wa

e e e

r z

u u u

w w w

1

2

2

1

1 1 1

T

=







+ +

+ +

u r z t

w r z t

t t

a a a a ua wa

( , , ) ( , , )

( ) ( )

 =

00 ϕϕ

γγ γγ

2 2 2 2 2 2

T T

T T

r z z

1

T

T−T0=ϕϕ Φ3TΦ θθ3T 3

T

ϕϕ

Φ

3

3

1

1 1 1 1 1

T

T

T T

T =

=

θ

Trang 8

128 Finite Element Analysis: Thermomechanics of Solids

For elasticity with displacements u, v, and w, the corresponding interpolation

model is

(9.22)

9.2 STRAIN-DISPLACEMENT RELATIONS

AND THERMAL ANALOGS

9.2.1 S TRAIN -D ISPLACEMENT R ELATIONS : O NE D IMENSION

For the rod, the strain is given by An estimate for ε implied by the interpolation model in Equation 9.3 has the form

(9.23)

FIGURE 9.5 Tetrahedral element.

e+2

e+3

y e

z

0

u x y z t

v x y z t

w x y z t

t t t

u v w

( , , , ) ( , , , ) ( , , , )

( ) ( ) ( )

=

γγ γγ γγ

3 3 3

3 3 3



e e e e

v

e e e e

w

e

e

t

u t

u t

u t

u t

t

v t

v t

v t

v t

t

w t

w t

( )

( ) ( ) ( ) ( )

( ) ( ) ( ) ( )

( ) (

=





=





=

+ + +

+ + +

+ 1

2 3

1 2 3

1

)) ( ) ( )

w t

e e

+ +





2 3

ε = = ∂

E11 u x

ε( , )x t = ββmT1( )xΦΦ γγm1 m1( ),t

Trang 9

For the beam, the corresponding relation is

(9.24)

from which the consistent approximation is obtained:

(9.25)

For the beam column, the strain is given by

(9.26)

9.2.2 S TRAIN -D ISPLACEMENT R ELATIONS : T WO D IMENSIONS

In two dimensions, the (linear) strain tensor is given by

(9.27)

We will see later the two important cases of plane stress and plane strain In the

latter case, E zz vanishes and s zz is not needed to achieve a solution In the former

case, s zz vanishes and E zz is not needed for solution

In traditional finite-element notation, we obtain [cf (Zienkiewicz and Taylor, 1989)]

(9.28)

ββm ϕϕ

m

d dx

T T

ε( , , )x z t z w,

x

= − ∂

ε( , , )x z t = − ββz b1( )xΦΦ γγb1 b1( ),

T

t

ββb ϕϕ

b

d

2

T T

ε( , , )x z t = − ββz mTb1( )x ΦΦ γγmb1 mb1( ),t

γγ γγ

m mb m b

z

t t

1 1 1 1

 ( ) ( )

xx xy

xy yy

u

x u y x v u

y v x v y

, =

1 2 1

2

′ =

γγ

E E E

xx yy xy

m T m u v

2 2

2 2

ˆ

Trang 10

130 Finite Element Analysis: Thermomechanics of Solids

The prime in e′ is introduced temporarily to call attention to the fact that it does

not equal VEC(EL) Hereafter, the prime will not be displayed

For a plate with bending stresses only,

(9.29)

from which

For a plate experiencing both membrane and bending stresses, the relations can

be combined to furnish

(9.31)

9.2.3 A XISYMMETRIC E LEMENT ON A XIS OF R EVOLUTION

For the toroidal element with a triangular cross section, it is necessary to consider two cases If there are no nodes on the axis of revolution, then

(9.32)

ββ

00

ΤΤ

ϕϕ

ϕϕ

m

m

m

m m m

x

y

2

2

2

2 2 2

1 2

1 2

=

=

∂ ∂





e ( , , , ) x y z t z ,

w x w y w

x y

2 2 2 2 2

∂ ∂





e ( , , , ) x y z t z ( )x ( ),t

x y

x y

b T

b b b

ϕϕ ϕϕ ϕϕ

2 2 2 2 2 2 2

2

e ( , , , ) x y z t ββmb2( , , )x y zΦΦ γγmb2 mb2( )t

T

γγ γγ

m b mb

m b

t t

2 2 2

2 2

( ) ( )

e( , , )

( ) ( )

r z t

t t

u r u r w z u z

w r

a a a ua wa

=

1 2

1 1 1 1 1

ββ Φ

Φ

γγ γγ

0

Trang 11

in which the prime is no longer displayed If element e is now located on the axis

of revolution, we obtain

(9.33)

9.2.4 T HERMAL A NALOG IN T WO D IMENSIONS

The thermal analog of the strain is the temperature gradient satisfying

(9.34)

9.2.5 T HREE -D IMENSIONAL E LEMENTS

Recalling the tetrahedral element in the previous section, the strain relation can be written as

(9.35)

ββa

z r

1

1 2

1

T

=

e( , , ) b

( ) ( )

r z t

t t

a a a ua wa

2 2 1 2 1

0

Φ Φ

γγ γγ

ββa

z ze r

2

T

=

T ββ ΦT Φ θθ ββ

T

2 2 2 2

e=





=

=

∂ +∂∂

∂ +∂∂

E E E E E E

xx yy zz xy yz zx

u x v y w z u y

v x v

z w y w

x u z

1 2 1 2 1 2

3

ββT

Φ Φ Φ

γγ γγ γγ

3 3 3

3 3 3





u v w

Trang 12

132 Finite Element Analysis: Thermomechanics of Solids

9.2.6 T HERMAL A NALOG IN T HREE D IMENSIONS

Again referring to the tetrahedral element, the relation for the temperature gradient is

(9.36)

9.3 STRESS-STRAIN-TEMPERATURE RELATIONS

IN LINEAR THERMOELASTICITY

9.3.1 O VERVIEW

If S is the stress tensor under small deformation, the stress-strain relation for a

linearly elastic, isotropic solid under small strain is given in Lame’s form by

(9.37)

in which I is the identity tensor The Lame’s coefficients are denoted by λ and µ,

and are given in terms of the familiar elastic modulus E and Poisson ratio ν as

(9.38)

Letting s = VEC(S) and e = VEC(E L), the stress-strain relations are written using Kronecker product operators as

(9.39)

and D is the tangent-modulus tensor introduced in the previous chapters.

9.3.2 O NE -D IMENSIONAL M EMBERS

For a beam column, recalling the strain-displacement model,

(9.40)

The cases of a rod and a beam are recovered by setting γγγγm1 or γγγγb1 equal to zero vectors, respectively

T ββ3 3 θθ3 ββ3

S=2µE Ltr( E L) ,I

µ

ν

=

E E

2 1( ), (1 2 )(1 ).

s=De, D=2µI9+λii T,

S11=σ( , , )x z t =Eε= −zEββmbT1( )x ΦΦ γγmb1 mb1( ).t

Trang 13

9.3.3 T WO -D IMENSIONAL E LEMENTS

9.3.3.1 Membrane Response

In two-dimensional elements, several cases can be distinguished We first consider elements in plane stress It is convenient to use Hooke’s Law in the form

(9.41)

Under plane stress, S xz = S yz = S zz = 0 Now, E zz ≠ 0, but we will see that it is not of present interest since it does not influence the solution process Later on, for reasons such as tolerances, we may wish to calculate it, but this is a postprocessing issue Consequently, in plane stress, the stress-strain relations reduce to

(9.42)

In traditional finite-element notation, this can be written as

(9.43)

in which

(9.44)

= +

= +

= +

1

1

1

1

1

1

E

E

E

E

E

E

ν ν ν ν ν ν

= +

1

1

1

E

E

E

ν ν ν

S S S

E E E

xx yy xy m xx yy xy

=

D m21

1

2

1

=

+

=

+

ν ν

ν ν

ν

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