CHAPTER C5 BUCKLING STRENGTH OF FLAT SHEET IN COMPRESSION, SHEAR, BENDING AND UNDER COMBINED STRESS SYSTEMS C5.1 Introduction.. Chapter A1l8, Part 2, introduced the student to the theo
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STRENGTH & DESIGN OF ROUND, STREAMLINE, OVAL AND SQUARE TUBING C4 28 IN TENSION, COMPRESSION, BENDING,
no restrictions on type of truss or
arrangement of members, however, the goal
is the lightest truss Omit consideration
of weight of any gusset plates at truss
Same as problem (6), but instead of a
cantilever truss use a simply supported truss with supports at points (A) and (B)
Fig 5 shows a front beam and front lift
strut in an externally braced monoplane
The wing beam and lift strut are in the Same vertical plane The ultimate design
loads on the beam for the critical
conditions are w = 50 ib./in and w =
ibs per inch
down
(a)
-30
Minus means load is acting
Design a streamline tube to act as
the lift strut Material {ts 2024-T5
aluminum alloy
Same as (a) but made from alloy steel Fry = 75000 Compare the weights of the two designs
(9) Pig, 6 illustrates the strut and wire
bracing for attaching float to fuselage of
a seaplane Determine the necessary sizes for the streamline struts AC and BD for the following load conditions
Condition 1 ¥V = -32000 lbs.,
H = - 8000 lbs
Condition 2, V = ~ 8000 lbs.,
H = ~28000 lbs
Material 2024-T3 aluminum alloy
Tube size 2 - 065 round L = 44 in.,
C's 1.5 Material alloy steel Fry =
95000, welded at ends Design ultimate loads equal 22000 1b compression and
28000 lbs tension Find margin of safety
(11) Same as Problem 10 but heat treated to
Fey = 150000 after welding
compression L=30 in Use C=l
Design the lightest round tube from the following materials and compare their weights
{a) Aluminum alloy 2024-T3
(b) Alloy steel Fty = 180,000 (c) Magnesium alloy Fey = 10,000 Same design load as in problem (10) but design the lightest streamline tube from 2024-T3 aluminum alloy material
A round tube is to carry an ultimate pure bending moment of 14000 in lbs Select the lightest tube size from the following materials and compare their weights
(a) Alloy steel Fry = 240,000, (b) 2024-73
aluminum alloy, (c) Magnesium alloy
Fey = 30000, (4) Titanium 6AL¬4V
alloy
A round tube 20 inches long is to carry
an ultimate torsional moment of 15000 in
Ib Select the lightest tube size from the following materials and compare their weights
(4) Alioy steel Fey = 180,000, (b) Aluminum alloy 2024-T3, (c) Mag- nesium alloy Fry = 36000
Determine the lightest 2024-TS aluminun alloy round tube 10 inches long to carry
a combined bending and torsional design load of 4500 and 3000 in.lbs respectively Same as Problem 16, but change material
to alloy steel Fry = 95000
A 1-1/2 - 065 2024-T3 round tube 50 inches
long is used as a beam-column The distributed load on beam is 12 lb per inch and the axial load is 700 lbs What
is the M.S under these loads
If the tude in problem (19) was also subjected to a torsional moment of 1400 in.1b., what would be the M.S
Trang 2CHAPTER C5
BUCKLING STRENGTH OF FLAT SHEET IN COMPRESSION, SHEAR,
BENDING AND UNDER COMBINED STRESS SYSTEMS
C5.1 Introduction
Chapter A1l8, Part 2, introduced the
student to the theoretical approach to the
problem of determining the buckling equation
for flat sheet in compression with various
edge or boundary conditions A similar
theoretical approach has been made for other
load systems, such as shear and bending, thus
the buckling equations for flat sheet have
been available for many years This chapter
will summarize these equations and provide
design charts for practical use in designing
sheet and plate structures Most of the
material in this chapter is taken from (Ref 1),
NACA Technical Note 3781-Part I, "Buckling of
Plat Plates” by Gerard and Becker This report
is a comprehensive study and summary of
practically all important theoretical and
experimental work published before 1957 The
report is especially useful to structural design
engineers
C§.2 Equation for Elastic Buckling Strength of
Flat Sheet in Compression
From Chapter Al8, the equation for the
elastic instability of flat sheet in compression!
18,
nk, E
oy = ——— @* - (05.1)
12 (1-Uạ) Ô
Where kg = buckling coefficient which depends
on edge boundary conditions and
sheet aspect ratio (a/b)
E = modulus of elasticity
Vg = elastic Poisson’s ratio
bd = short dimension of plate or loaded
edge
t = sheet thickness
CS5.3 Buckling Coefficient ke
Fig C5.1 shows the change in buckled
shape as the boundary conditions are changed
on the unloaded edges from free to restrained
In Fig (a) the sides are free, thus sheet
acts as a column In Fig (bd) one side is
restrained and the other side free, and such a
restrained sheet is referred to as a flange
In Fig (c) both sides are restrained and this
restrained element ts referred to as a plate
supports are added along unlaaded edges Note changes in
buckle configurations
Fig C5.2 gives curves for finding the puckling coefficient kK, for various boundary
or edge conditions and a/b ratio of the sheet
The letter C on edge means clamped or
fixed against rotation The letter F means a
free edge and SS means simply supported or hinged Fig C5.3 shows curves for k, for
various degrees of restraint (e) along the
sides of the sheet panel, where ¢ is the ratio
of rotational rigidity of the plate edge stiffener to the rotational rigidity of the plate
Fig C5.4 shows curves for k, fora
flange that has one edge free and the other
with various degrees of edge restraint Fig
CS.5 illustrates where the compressive stress varies linearly over the length of the sheet,
a typical case being the sheet panels on the upper side of a cantilever wing under normal flight condition
Fig CS.6 gives the ky factor for a long
sheet panel with two extremes of edge stiff-
ener, namely a zee stiffener which is a torsitonally weak stiffener and a hat section
je
Trang 3Fig CS.4 (Ref 1) Compressive-buckling-stress coefficient
of flanges as a function of a/b for various amounts of edge
Fig C5.3 (Ret 1) Compressive-buckling-stress coefficient
of plates as a function of a/b for varicus amounts of edge rotational restraint
with linearly varying axiai load ke p17 E 2
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which 1s a closed section and, therefore, a Substituting in Eq C5.1,
relatively torsionally strong stiffener File
c5.6a gives the compression buckling Jan = mn? x 4.0% 10,700,000 (204? = 2480 pst
coefficients ky for isosceles triangular cr 12 (1 - 3*) 5 x psi
range, then E and YV are not the same as for
elastic buckling, thus a plasticity correction factor is required and equation C5.1 is
written,
NV ke BO
STIEFEWER 7 H T 12(1 - 1⁄2?)
Fig C5 8 (Ref 1} Compressive-buckling coefficient for long
rectangular stiffened panels as a function of b/t and stiffener
Fig, C5 6a (Ref 1) Uniform Compression
Illustrative Problem Find the compressive
buckling stress for a sheet panel with (a) = 10
and b = 3 inches, thickness t = 04 and all
edges are simply supported Material is
Thus
using curve (c) for a/b = 2, we read ky = 4.0
The values of k, and Uy are always the
elastic values since the coefficient 7 contains
all changes in those terms resulting from
inelastic behavior
A tremendous amount of theoretical and “ experimental work has been done relative to
the value of the so-called plasticity cor-
rection factor Possibly the first values
used by design engineers were n = E,/E or <
N= Esec/E- Whatever the expression for ] it
must involve a measure of the stiffness of the
material in the inelastic stress range and
since the stress-strain relation In the plastic range is non-linear, a restrt must be made to
the stress-strain curve to obtain a plasticity correction factor This complication is
greatly simplified by using the Ramberg and Osgood equations for the stress-strain curve which involves 3 simple parameters (The
reader should refer to Chapter Bl for information on the Ramberg-Osgood equations.)
Thus using the Ramber-Osgood parameters (Ref.1)
presents Figs C5.7 and CS.8 for finding the compressive buckling stress for flat sheet panels with various boundary conditions for both elastic and inelastic buckling or in-
~ The sketch shows a 3x9 Ess
inch sheet panel The sides ss 4 ga are simply supported The
material is aluminum alloy SA TTT
2024-73 The thickness is van 094" = 10,700,000, H1 :
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Fig C$.7% Chart of Nondimensional Compressive Buckling Stress for Long
Hinged Flanges 7] = (Eg/E)(1 - Ve*)/(1 - VU)
Trang 6ANALYSIS AND DESIGN OF FLIGHT VEHICLE STRUCTURES
Ve = 0.3 Pind the buckling stress oor
Solution: We use Fig C5.8 since it covers
the boundary conditions.of our problem The
parameter for bottom scale is,
The use of Fig C5.8 involves the use of
o,,, and n the Ramberg-Osgood parameters
Referring to Table Bl.1 of Chapter Bl, we find
for 2024-T3 aluminum alloy that o,., = 39000
and the shape factor n = 11.5 —
Tei phoosy
Substituting in (A):-
4,0 1° x 10,700,000 (2084) so)" #985
12 a - 3°) 39, 000 ~
From Fig C5.8 using 98 on bottom scale
and n = 11.5 curve, we read on left hand scale
that Gor/o,,, = 84.-
NN Then doy’ = 39000 x 84 = 32800 pst ~
If we neglected any plasticity effect, then!
we would use equation C5.2 with ne =1,0, oy
n? x4 0x10,700, 000 cán"
12 - 3°)
Whereas the actual buckling stress was 32800,
or in this case the plasticity correction
factor is 328/384 = 954
The sheet thickness used in this example
of 094 is relatively large If we change the
sheet thickness to 051 inches the results
would be practically no correction within the
accuracy of reading the curves, and the buckling|
Stress Ogr would calculate to be 11200 psi,
which is below the proportional limit stress
and thus no plasticity correction
C5.6 Cladding Reduction Factors
Aluminum alloy sheet is available with a
thin covering of practically pure aluminum and
is widely used in aireraft structures Such
material is referred to as alclad or clad
aluminum alloy, The mechanical strength
properties of this clac material is consider-
ably lower than the core material Since the
clad is located at the extreme fibers of the
alclad sheet, it is located where the strains
attain their highest value when buckling takes
place Fig C5.9 shows make up of an aliclad
Sheet and Fig C5.10 shows the stress-strain
curves for cladding, core and alclad combina-
tions
C5.5
Thus a further correction must be made for
alclad sheets because of the lower strength
clad covering material Thus the buckling stress for alclad sheets can be written:
by use of equation C5.3, using values of
and Alclad Combinations Ø/Œ„are = Ì - Ý +01; 0 *ƠglØcore:
Tabie C5 1 (Ref 1) Summary of Simplifted Cladding
Reduction Factors
Trang 7BUCKLING UNDER SHEAR LOADS
C5.7 Buckling of Flat Rectangular Plates
Under Shear Loads
The critical elastic shear buckling stress for flat plates with various boundary
conditions is given by the following equation:
Where (b) is always the shorter dimension of
the plate as all edges carry shear k, is the
shear buckling coefficient and is plotted as a
function of the plate aspect ratio a/b in Fig
CS.11 for simply supported edges and clamped
Test results compare favorably with the
results of equation (5.5 if 7], * Gg/G where G
18 the shear modulus and Gg the shear secant
modulus as obtained from a shear stress-strain
diagram for the material
A long rectangular plate subjected to ' pure shear produces internal compressive
stresses on planes at 45 degrees with the
plate edges and thus these compressive stresses
cause the long panel to buckle in patterns at
an angle to the plate edges as illustrated in
Fig C5.12, and the buckle patterns have a half
wave length of 1.25b
fae 1 25b —o
Fig C5 12 (Ref 7) Fig C5.13 is a chart of non-dimensional shear buckling stress for panels with various
This chart fs
Similar to the chart in Figs C5.7 and C5.8 in
that the values go, „ and n must be known for
the material before the chart can be used to
find the shear buckling stress
BUCKLING UNDER BENDING LOADS
C5.8 Buckling of Flat Plates Under Bending Loads
The equation for bending instability of flat plates in bending is the same as for
compression and shear except the buckling co- efficient kp is different from k, or kg When
@ plate in bending buckles, it involves relatively short wave length buckles equal to 2/3 0 for long plates with simply supported edges (see Fig C5.14) Thus the smaller buckle patterns cause the buckling coeffictent
Where Kp is the buckling coefficient and
is obtained from Fig C5.15 for various a/b
ratios and edge restraint « against rotation
In the a/b ratio the lodded edge is (b),
The plasticity reduction factor can be obtained from Fig C5.3 using simply supported
edges
BUCKLING OF FLAT SHEETS UNDER COMBINED LOADS
The practical design case involving the
use of thin sheets usually involves a combined
load system, thus the calculation of the buckling strength of flat sheets under com- bined stress systems 1s necessary The approach used involves the use of inter-action equations or curves (see Chapter Cl, Art
C1.15 for explanation of inter-action equations)
C5.9 Combined Bending and Longitudinal Compression
The interaction equation that has been widely used for combined bending and longi-
Trang 8ANALYSIS AND DESIGN OF FLIGHT VEHICLE STRUCTURES C5.7
Fig CS, 13 (Ref 1) Chart of Nondimensional Shear Buckling Stress for Panels With
Edge Rotational Restraint 7) = (Eg/E) (1 - Ve*/(1 - V4
ae Ver he Meas B.#vo
Trang 9this equation is found in many of the
structures manuals of aerospace companies
Fig C5.15 is a plot of eq C5.8 It also shows curves for various margin of safety
values
Lt
Fig C5.15 Combined Bending
& Long Compression
Rpts Real
1.0
0 1 3 3 4 5 6 ,7 8 9 1.0 L1
5.10 Combined Bending & Shear
The interaction equation for this com-
bined leading (Ref, 1 & 2) 1s,
(cS.10)
Fig C5.16 is a plet of equation C5.9
Curves showing various M.S values are also
shown Rg is the stress ratio due to
torsional shear stress and Rgt is the stress
ratio for transverse or flexural shear stress
CS.11 Combined Shear and Longitudinal Direct Stress
Fig.-C5.17 ts a plot of equation CS.11,
If the direct stress is tension, it is included on the figure as negative compression using the compression allowable
CS.12 Combined Compression, Bending & Shear
From Ref 5, the conditions for buckling
are represented by the interaction curves of Fig C5.18 This figure tells whether the sheet will buckle or not but will not give the margin of safety
Rp:- if the value of the Re curve defined by Given the ratios Re, Rg and
the given value of Rp and Rg is greater
mumerically than the given value of Re, then the panel will buckle
1,0
Rp
9
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BUCKLING STRENGTH OF FLAT SHEET IN COMPRESSION, SHEAR, BENDING AND UNDER COMBINED STRESS SYSTEMS C5 10
The margin of safety of elastically
buckled flat panels may be determined from
Pig C5.19 The dashed lines indicate a
typical application where Ry = 161, Rg = 23,
and Rp = 38 Point 1 is first determined for
the specific value of Rg and Rp The dashed
diagonal line from the origin O through point
1, intersecting the related Re/Rg curve at
point 2, yields the allowable shear and bending
stresses for the desired margin of safety
calculations (Note when R, is less than Rg
use the right half of the figure; in other
cases use the left nalf)
C§.13 Mlustrative Problems
In general a structural component com-
posed of stiffened sheet panels will not fail
when buckling of the sheet panels occurs since
the stiffening units can usually continue to
carry more loading before they fail However,
there are many design situations which require
that initial buckling of sheet panels satisfy
certain design specifications For example,
the top skin on a low wing passenger airplane
should not buckle under accelerations due to
air gusts which occur in normal every day
flying thus preventing passengers from
observing wing skin buckling in normal flying
conditions Another example would be that no
buckling of fuselage skin panels should occur
while airplane is on ground with full load
aboard in order to prevent public from
observing buckling of fuselage skin In many
airplanes, fuel tanks are built integral with
the wing or fuselage, thus to eliminate the
chances of leakage developing, it is best to
design that no buckling of sheet panels that
bound the fuel tanks occur in flying and
landing conditions In some cases aerodynamic
or rigidity requirements may dictate no
buckling of sheet panels To insure that
buckling will not occur under certain load
requirements, it 1s good practice to be
conservative in selecting or calculating the
boundary restraints of the sheet panels,
Problem 1
Pig CS.20 shows a portion of a cantilever wing composed of sheet, stiffeners and ribs
The problem is to determine whether skin panels
marked (A), (B) and (C) will buckle under the
various given load cases The sheet material
compressive axial load of 2 x 700 = 1400 lb
Since the P, loads are not acting through the
centroid of the cross-section, a bending moment
is produced about the x-x axis equal to 1400 x
3.7 = 5170 in lb = My, where 3.7 15 distance from load P, to x=x axis
Area of Zee Pr Stringer = 18
Area of Corner Member =
0.25 sq in
Fig C5 20
The sheet thicknesses, stiffener areas and
all necessary dimensions are shown on Fig
c5.20 The total cross-sectional area of beam
section including all skin and stringers is
3.73 sq in The moment of inertia about x-x
centroidal axis calculates to be 49.30 in.*
Since the beam section is symmetrical, the top panels A, B and C are subjected to the same stress under the P, load system
Compressive stress due to transferring
loads P, to centroid of beam cross-section is,
t, = 2P,/area = 1400/3.73 = 375 psi Compressive stress due to constant bending moment of 5170 in lbs is,
f, = M,2/T,, = 5170 x 4,.233/49.30 = 444 psi Total T1 3 375 + 444 = 819 pst
The skin panels are subjected to compres- sion as shown in Pig a The boundary edge conditions given by the longitudinal sti?*-rors
Trang 12ANALYSIS AND DESIGN OF FLIGHT VEHICLE STRUCTURES
and the rib flanges will be con- The Re + Rg = 431 + 3097 = 826 Since
servatively assumed as simply Pris? the result is less than 1.0, no buckling
Supported (Fo, is same as dor) 4 SSF occurs
ssc
“>2 TU Ge -
(See Hq 05.1) môn pb a = rẽ 2 1= ,69
From Fig C5.2 far Case Œ, g (a) `
Po, 202 fer 4.0 1057005000 (088)* ¡on nọ; The two loads P, produce bending and
12 (1 - 0.3") 5 P - fleXural shear on the beam,
Since Foor the buckling stress is less than the applied stress fg, the panels will
moment of 500 x 16.5 = 8250 in lb on the
beam structure, which means we have added 4
pure shear stress system to the compressive
stress system of Case 1 loading
The shear stress in the top panels A, B and € 1s,
a/p = 18/5 = 3 Prom Fig C5.11, for
hinged or simply supported edges, we read
Kg = 5.8
TẾ x 6.8 x 10,700,000
ne “Ser” 2 (1 - 3? (SE) = 2760 pst 2035 ,3_
The sheet panels are now loaded in
combined compression and shear so the inter-
action equation must be used From Art C5.12
the interaction equation is Ry + Rễ =1
Rẹ =ứ, đ 3 3 é ‡ b 819/1900 = 431
Rg = s ay œ 3 3 a 854/2760 = 309
The bending moment
produces a different end compressive stress on
the three sheet panels since the bending moment
is not constant over the panel moment To simplify we will take average bending moment on
The two loads P, produce a traverse shear
load V = 200 lb The flexural shear stress must be added to the torsional shear stress ag
found in Case 2 loading
Due to symmetry of beam section and Py, loading the shear flow q at midpoint of sheet panel (B) is zero We will thus start at this
Gs = - 10.94-4.05 x 051 x 3.69% 3.69/2 = -12.34 (See Fig b for plot of shear flow)