Quá trình truyền dẫn viba số trong truyền dẫn quang part10 ppt

KEÂT LUAÔN  Qua 9 tuaăn laøm luaôn aùn, ñađy laø thôøi gia töông ñoâi ngaĩn nhöng nhoùm thöïc hieôn ñaõ heât söùc coâ gaĩng ñeơ coù theơ thu thaôp nhöõng thođng tin vaø caùc vaân ñeă l

void free_space_lose()//ton that tuyen cua khong gian tu do

{

Ao = 92.5 + 20*log10(f) + 20*log10(d);

printf("Ton that duong truyen cua khong gian tu

do la: %.3lf dB", Ao);

}

void feeder_lose() //ton that feeder

{

double lf1,lf2,feeder_type;

printf("Cho biet loai feeder su dung: \n");

printf("1 RG-59/U\n");

printf("2 RG-11/U\n");

printf("3 RG-24/U\n");

printf("4 RG-58/U\n");

switch(getch())

{

case '1' : feeder_type = 3.4; break;

case '2' : feeder_type = 2.5; break;

case '3' : feeder_type = 2; break;

case '4' : feeder_type = 7.8; break;

default : feeder_type =3.4;

}

printf("\nCho biet do cao anten tai tram A (m):

"); scanf("%lf",&h1);

printf("Cho biet do cao anten tai tram B (m):

"); scanf("%lf",&h2);

lf1 = 1.5*h1;

lf2 = 1.5*h2;

loseA = lf1*3.28*feeder_type/100;

loseB = lf2*3.28*feeder_type/100;

feeder = loseA + loseB;

printf("Ton that feeder tai tram A: %.3lf dB\n", loseA);

printf("Ton that feeder tai tram B: %.3lf dB\n", loseB);

printf("Ton that feeder: %.3lf dB\n", feeder); }

void vatchan() //ton hao cua bo suy hao hoac cac vat chanx

{

double d1[100],d2[100], hc[100],V[100],c,tmp; int i, vc;

printf("Co bao nhieu vat chan: ");

scanf("%d",&vc);

for(i=0; i<vc; i++)

{

printf("Cho biet khoang cach tu tram A den vat chan thu %d: ",i+1);

scanf("%lf", &tmp); d1[i] =tmp;

printf("Cho biet khoang cach tu tram B den vat chan thu %d: ",i+1);

scanf("%lf",&tmp); d2[i]=tmp;

printf("Cho biet do cao vat chan %d:",i+1); scanf("%lf",&tmp); hc[i] =tmp;

}

c = 3*pow(10,8);

lamda = c/(f*pow(10,9));

for(i=0;i<vc;i++)

printf("hc = %lf\n",hc[i]);

printf("Lamda = %0.3lf c= %0.3lf\n",lamda,c); for(i=0;i<vc;i++)

{

V[i] = hc[i] * sqrt( (2/lamda) * (1/d1[i]) * (1/d2[i]));

printf("\n V[%d] = %lf\n",i+1,V[i]);

}

for(Lv=0,i=0;i<vc;i++)

Lv += 6.4 + 20*log10(sqrt(V[i]+1)) + V[i];

printf("Ton hao cua bo suy hao hoac cac vat

chan: %.3lf dB", Lv);

}

void khiquyen() //ton hao khi quyen

{

double Tkq;

printf("Cho biet ton hao dac trung cua khi quyen : "); scanf("%lf",&Tkq);

Aa=Tkq*d;

printf("Ton hao khi quyen: %.3lf dB ",Aa);

}

void total()//tong ton hao

{

double renhanh,bodaunoi;

printf("Cho biet ton hao re nhanh ( 2dB-8dB ):

"); scanf("%lf",&renhanh);

printf("Cho biet ton hao cac bo dau noi( 0.5dB-1dB) : "); scanf("%lf",&bodaunoi);

A = Ao + Aa + feeder + renhanh + bodaunoi + Lv; printf("Tong ton hao la: %.3lf dB", A);

}

void line_lose() //ton hao tuyen truyen

{

while(1)

{

clrscr();

printf("Ton that tuyen:\n");

printf("1 Ton that duong truyen cua khong gian

tu do\n");

printf("2 Ton that feeder\n");

printf("3 Ton hao cua bo suy hao hoac cac vat chan\n");

printf("4 Ton hao khi quyen \n");

printf("5 Tong ton hao \n");

printf("s Exit\n");

printf("Select: \n");

switch( getch())

{

case '1' : free_space_lose(); break;

case '2' : feeder_lose(); break;

case '3' : vatchan(); break;

case '4' : khiquyen();break;

case '5' : total();break;

}

if(getche() == '6') break ;

}

}

void gain() //do loi

{

double D,n;

clrscr();

printf("\t\tTinh Toan Do Loi\n");

printf("Cho biet cong suat may phat(dBm): "); scanf("%lf",&pt);

printf("Cho biet duong kinh anten (m): ");

scanf("%lf",&D);

printf("Cho biet goc mo hieu dung: ");

scanf("%lf",&n);

printf("Cho biet nguong thu ung voi BER = 10^-3 (dB): "); scanf("%lf",&RXa);

printf("Cho biet nguong thu ung voi BER = 10^-6 (dB): "); scanf("%lf",&RXb);

G = 20 * log10(D) - 20*log10(lamda) + 10 *

log10(n) + 9.943;

G1 = pt; Gt = 2*G + G1 ;

A1 = A - Gt; pr = pt -A1;

FMa = pr -RXa;

FMb = pr - RXb;

clrscr();

printf("\n");

printf("Do loi cua anten: %.3lf dB\n",G);

printf("Do loi may phat: %.3lf dB\n",G1);

printf("Tong do loi: %.3lf dB\n", Gt);

printf("Tong ton hao: %.3lf dB\n", A1);

printf("Muc dau vao cua may thu: %.3lf dBm\n", pr);

printf("Do du tru fading phang FMa: %.3lf dB,voi BER = 10^-3\n", FMa);

printf("Do du tru fading phang FMb: %.3lf dB,voi BER = 10^-6\n", FMb);

getch();

}

void fading() //gom xac suat fading nhiue tia, xs tai cac nguong, thoi gian fading

{

double a,c, alpha,beta,c2;

double gamma,M,nuy,K,t;

clrscr();

printf("Cho biet he so cai tien dac trung cho dia hinh a (0.25 - 4): ");

scanf("%lf",&a);

printf("Cho biet he so dia hinh C: \n");

printf(" 1 1 cho dia hinh trung binh co khi hau

on doi\n");

printf(" 2 4 cho dia hinh tren mat nuoc bo bien hay khi hau am uot\n");

printf(" 3 0.25 cho dia hinh mien nui va khi hau kho\n");

switch (getch())

{

case '1' : c = 1;printf("C=1"); break;

case '2' : c = 4;printf("C=4"); break;

case '3' : c = 0.25;printf("C=0.25"); break; default : c=1;

}

printf("\nCho biet alpha2: ");

scanf("%lf",&alpha);

printf("Cho biet beta2: "); scanf("%lf",&beta); printf("Cho biet c2: "); scanf("%lf",&c2);

printf("Cho biet toc do bit cuc dai gama b

(MBit/s): ");scanf("%lf",&gamma);

printf("Cho biet so muc trong so do dieu che M :

"); scanf("%lf",&M);

printf("Cho biet dang dieu che :\n");

printf("1 QAM 64\n"); printf("2 QAM 16\n"); printf("3 PSK 8\n"); printf("4 PSK 4\n");

switch( getch())

{

case '1' : printf("Ban chon QAM 64\n"); K = 15.4; break;

case '2' : printf("Ban chon QAM 16\n");K = 5.5; break;

case '3' : printf("Ban chon PSK 8\n");K = 7; break;

case '4' : printf("Ban chon PSK 4\n");K = 1; break;

default : printf("Ban chon khong dung!\nMac nhieu la QAM 64!");K = 15.4;

}

clrscr();

po=0.3*a*c*(f/4)*pow( (d/50),3);

pa = pow(10,(-FMa/10));

pb = pow(10,(-FMb/10));

Ta = c2*pow(10,( (-alpha)* FMa)/10)*pow(f,beta);

Tb = c2*pow(10,( (-alpha)* FMb)/10)*pow(f,beta);

Za = 0.548*log(10/Ta); Zb = 0.548*log(10/Tb);

Za = arround(Za); Zb = arround(Zb);

if(Za>mem || Zb>mem) { printf("So lieu ngoai bang tra!"); delay(500); exit(1);}

p10 = 0.5*erfc_fun(Za); p60 = 0.5*erfc_fun(Zb); if(po>10) nuy =1;

if(0.1<po && po<2) nuy =0.182*pow(po,0.1);

if(po<0.01) nuy =1.44*po;

t= pow( 2 * pow(d,1.5) * (gamma / (

log10(M)/log10(2) )) * pow(10,-6),2);

giandoan = 200*nuy*K*t;

tong_giandoan = giandoan + po*pa;

printf("Xac suat fading nhieu tia la: %.8lf\n", po);

printf("Xac suat dat cac nguong RXa:

%.8lf\n",pa);

printf("Xac suat dat cac nguong RXb:

%.8lf\n",pb);

printf("Khoang thoi gian fading voi BER > 10^-3:

%.8lf\n",Ta);

printf("Khoang thoi gian fading voi BER > 10^-6:

%.8lf\n",Tb);

printf("\nXac suat fading dai hon 10s:

%.8lf",p10);

printf("\nXac suat fading dai hon 60s:

%.8lf",p60);

printf("\n Xac suat BER vuot 10^-3: %.8lf",

pa*po);

printf("\n Xac suat BER vuot 10^-6: %.8lf",

pb*po);

printf("\nDo kha dung cua tuyen: %.8lf %",(1-po*pa*p10)*100);

printf("\n Xac suat BER vuot 10^-6 trong khoang 60s: %.8lf", pa*p10);

printf("\nXac suat mach tro nen khong su dung duoc: %.8lf",po*pa*p10);

printf("\nXac suat BER > 10^-6 trong khoang 60s:

%.8lf",po*p60);

printf("\nThoi gian gian doan thong tin do

fading: %.8lf %",giandoan);

printf("\nTong gian doan thong tin trong BER > 10^-3: %.8lf %",tong_giandoan);

printf("\nXac suat BER > 10^-6 do fading lua chon: %.8lf",9.82*giandoan);

printf("\nTong BER > 10^-6: %.8lf",

9.828*giandoan + po*pb);

getch();

}

void khadung()

{

double MTTR,MTBF,tong;

printf("Cho biet MTTR: "); scanf("%lf",&MTTR); printf("Cho biet MTBF: "); scanf("%lf",&MTBF); khongkhadung =100*(MTTR/(MTBF+MTTR));

tong = 100* po*pa*p10 + 100*p10*giandoan

+khongkhadung;

printf("Do khong kha dung la: %.3lf

%\n",khongkhadung);

printf("Do khong su dung duoc do fading phang nhieu tia: %.3lf %\n",100*po*pa*p10);

printf("Do khong su dung duoc do fading nhieu tia lua chon: %.3lf %\n",100*p10*giandoan);

printf("Tong do khong su dung duoc la:

%.3lf%",tong);

getch();

}

int menu()

{

clrscr();

printf("\n\nTINH CAC THONG SO TON HAO DUONG TRUYEN\n");

printf("1 Ton that tuyen \n");

printf("2 Do loi\n");

printf("3 Cac hieu ung fading phang\n");

printf("4 tinh toan kha nang su dung\n"); printf("5 Exit\n");

printf("Select:\n");

switch(getch())

{

case '1' : line_lose(); return 1;

case '2' : gain(); return 1;

case '3' : fading(); return 1;

case '4' : khadung(); return 1;

case '5' : return 0;

default : return 1;

}

}

void main()

{

int k;

textcolor(BLUE);

textbackground(WHITE);

clrscr();

printf("\t\tCHUONG TRINH TINH TOAN CAC THONG SO DUONG TRUYEN");

nhap_bien();

while(1)

{

k= menu();

if(k==0) break;

}

}

VIBA.H

#include <stdio.h>

#include <conio.h>

#include <math.h>

double

erfd[260]={0.000,0.005,0.010,0.015,0.020,0.025 ,0.030,0.035,0.040,0.045,0.050,0.055,0.060,0.065,0 070,0.075,0.080,0.085,0.090,0.095,0.100,0.105,0.1 10,0.115,0.120,0.125,0.130,0.135,0.140,0.145,0.150 ,0.155,0.160,0.165,0.170,0.175,0.180,0.185,0.190,0 195,0.200,0.205,0.210,0.215,0.220,0.225,0.230,0.2 35,0.240,0.245,0.250,0.255,0.260,0.265,0.270,0.275 ,0.280,0.285,0.290,0.295,0.300,0.305,0.310,0.315,0 320,0.325,0.330,0.335,0.340,0.345,0.350,0.355,0.3 60,0.365,0.370,0.375,0.380,0.385,0.390,0.395,0.400 ,0.405,0.410,0.415,0.420,0.425,0.430,0.435,0.440,0 445,0.450,0.455,0.460,0.465,0.470,0.475,0.480,0.4 85,0.490,0.495,0.500,0.505,0.510,0.515,0.520,0.525 ,0.530,0.535,0.540,0.545,0.550,0.555,0.560,0.565,0 570,0.575,0.580,0.585,0.590,0.595,0.600,0.605,0.6 10,0.615,0.620,0.625,0.630,0.635,0.640,0.645,0.650 ,0.655,0.660,0.665,0.670,0.675,0.680,0.685,0.690,0 695,0.700,0.705,0.710,0.715,0.720,0.725,0.730,0.7 35,0.740,0.745,0.750,0.755,0.760,0.765,0.770,0.775 ,0.780,0.785,0.790,0.795,0.800,0.805,0.810,0.815,0 820,0.825,0.830,0.835,0.840,0.845,0.850,0.855,0.8 60,0.865,0.870,0.875,0.880,0.885,0.890,0.895,0.900 ,0.905,0.910,0.915,0.920,0.925,0.930,0.935,0.940,0 945,0.950,0.955,0.960,0.965,0.970,0.975,0.980,0.9 85,0.990,0.995,1.000,1.050,1.100,1.150,1.200,1.250 ,1.300,1.350,1.400,1.450,1.500,1.550,1.600,1.650,1 700,1.750,1.800,1.850,1.900,1.950,2.000,2.050,2.1 00,2.150,2.200,2.250,2.300,2.350,2.400,2.450,2.500 ,2.550,2.600,2.650,2.700,2.750,2.800,2.850,2.900,2 950,3.000,3.050,3.100,3.150,3.200,3.250,3.300,3.3 50,3.400,3.450,3.500,3.550,3.600,3.650,3.700,3.750 ,3.800,3.850,3.900,3.950,};

double erfdr[260]=

{1.000000,0.994358,0.988717,0.983076,0.977435, 0.971976,0.961590,0.960523,0.954889,0.949257,

0.943628,0.938002,0.932378,0.926759,0.921142,

0.915530,0.909922,0.904318,0.898719,0.893126,

0.887537,0.881954,0.876377,0.870806,0.965242,

0.859684,0.854133,0.848589,0.843053,0.837524,

0.832004,0.826492,0.820988,0.815493,0.810008,

0.804531,0.799064,0.793607,0.788160,0.782723,

0.777297,0.771882,0.766478,0.761085,0.755704,

0.750335,0.744977,0.739632,0.734300,0.728980,

0.723674,0.718380,0.713100,0.707834,0.702582,

0.697344,0.692120,0.686911,0.681717,0.676537,

0.671730,0.666225,0.661092,0.655975,0.650874,

0.645789,0.640721,0.635670,0.630635,0.625618,

0.615635,0.610607,0.605723,0.600794,0.595883,

0.590990,0.586117,0.581261,0.576425,0.571608,

0.566810,0.562031,0.557272,0.552532,0.547813,

0.543113,0.538434,0.533773,0.529136,0.524518,

0.519921,.510789,0.506255,0.501742,0.479250,

0.492780,0.488332,0.483905,0.479500,0.475117,

0.470756,0.466418,0.462101,0.475807,0.453536,

0.449287,0.445061,0.440857,0.436677,0.432519,

0.428384,0.424273,0.420184,0.411619,0.412077,

0.408059,0.404063,0.400092,0.396144,0.392220,

0.388319,0.384442,0.380589,0.376759,0.372954,

0.369172,0.635414,0.361680,0.357971,0.354285,

0.350623,0.346986,0.343372,0.339783,0.336248,

0.332677,0.329600,0.325667,0.332199,0.318755,

0.315334,0.311939,0.308567,0.305219,0.315896,

0.298597,0.295322,0.292071,0.288844,0.285642,

0.282463,0.279309,0.276178,0.273072,0.269990,

0.266931,0.263897,0.260886,0.257899,0.254936,

0.251996,0.249081,0.246189,0.243321,0.240476,

0.237655,0.234857,0.232083,0.229332,0.226604,

0.223900,0.221218,0.218560,0.215925,0.213313,

0.210723,0.208157,0.205613,0.203092,0.200593,

0.198117,0.195664,0.193232,0.190823,0.188436,

0.186072,0.183729,0.181408,0.179109,0.176832,

0.174576,0.172342,0.179130,0.167938,0.165768,

0.163620,0.161492,0.159385,0.157299,0.137564,

0.119795,0.103876,0.089686,0.077100,0.065992,

0.56238,0.047715,0.040305,0.033895,0.028377,

0.023652,0.019624,0.016210,0.013328,0.010901,

0.0088889,0.0072096,0.0058207,0.0046778,0.0037419, 0.0029795,0.0023614,0.0018629,0.0014627,

0.0011432,0.00088929,0.00068853,0.00053060,0.00040 697,0.00031068,0.00023605,0.00017850,0.00013434,0 00010062,0.000075017,0.000055658,0.000041100,0.000 030205,0.000022092,0.000016081,0.00000011649,0.000 0083987,0.0000060247,0.0000043040,0.0000030593,0.0 000021637,0.0000015200,0.0000010673,0.0000007437,0 0000005163,0.0000003563,0.0000002433,0.0000001683 ,0.0000001137,0.000000076,0.0000000527,0.000000035 3,0.0000000227};

KEÂT LUAÔN

 Qua 9 tuaăn laøm luaôn aùn, ñađy laø thôøi gia töông ñoâi ngaĩn nhöng nhoùm thöïc hieôn ñaõ heât söùc coâ gaĩng ñeơ coù theơ thu thaôp nhöõng thođng tin vaø caùc vaân ñeă lieđn quan ñeân luaôn aùn vaø cuoâi cuøng ñaõ hoaøn thaønh ñuùng thôøi gian quy ñònh

 Cuõng qua luaôn aùn nhoùm thöïc hieôn ñaõ hóc hoûi ñöôïc nhieău kieân thöùc vaø kinh nghieôm quyù baùu veă ngeă nghieôp cụa mình trong töông lai Hieơu roõ nhöõng khoù khaín caăn phại giại quyeât khi baĩt tay vaøo nghieđn cöùu moôt lónh vöïc khoa hóc môùi, caăn phại boâ trí thôøi gian moôt caùch hôïp lyù khoa hóc thì môùi coù theơ hoaøn thaønh

 Noôi dung ñeă taøi chia laøm 3 phaăn chính:

Phaăn I: Lyù thuyeât thieât keâ tuyeân

Goăm 9 böôùc cô bạn Ñađy laø phaăn lyù thuyeât neăn tạng khi thieât keâ moôt tuyeân Viba soâ Noù laø moôt trong nhöõng cô sôû ñeơ xađy döïng moôt heô thoâng theo yeđu caău Tređn cô sôû ñoù ta coù theơ thaây ñöôïc phaơm chaât vaø ñoô tin caôy cụa heô thoâng thieât keâ coù ñát yeđu caău ñaịt ra hay khođng

Phaăn II: Thieât keâ vaø tính toaùn t uyeân truyeăn daên Viba soâ thöïc teâ

AÙp dúng caùc böôùc ôû phaăn II,thieât keâ vạ tính toaùn cho moôt tuyeân cú theơ

Trong quaù trình tính toaùn caùc thođng soâ cụa ñöôøng truyeăn, em coøn gaịp moôt soâ khoù khaín ñoù laø vieôc nghieđn cöùu veă ñòa hình cuõng nhö tính chaât cụa ñaât tái caùc trám … (do ñoù khođng tìm ñöôïc caùc thođng soâ moôt caùch chính xaùc maø chư coù tính töông ñoẫi)

 Qua nghieđn cöùu em nhaôn thaây raỉng cođng vieôc tính toaùn caùc thođng soâ cụa ñöôøng truyeăn khaù phöùc táp vôùi nhöõng cođng thöùc khaù daøi coù lieđn quan vôùi nhau neđn deê bò sai soùt neâu ngöôøi thöïc hieôn khođng quen vaø caơn thaôn Chính vì lí do tređn neđn em söû dúng ngođn ngöõ C ñeê hoê trôï cho vieôc tính toaùn, giuùp ngöôùi thieât keâ coù theơ an tađm nhaôp caùc thođng soâ caăn thieât laøm giạm ñi raât nhieău caùc cođng vieôc tính toaùn

phöùc táp vaø ít sai soâ

 Ñađy laø ñeă taøi khaù môùi mẹ ñoâi vôùi em Do thôøi gian vaø ñieău kieôn coøn hán cheâ vôùi moôt khoâi löôïng cođng vieôc khaù lôùn Vì theâ nhöõng sai soùt laø ñieău khođng theơ traùnh

khoûi

 Trong ñeă taøi naøy tuyeâu thieât keâ chư laø moôt dáng cô bạn cụa heô thoâng Viba

chuyeơn tieâp maø thođi Heô thoâng khođng söû dúng trám laôp chöa mang tính chaât quoâc

teâ Chính vì vaôy ñeă taøi naøy coøn coù theơ ñöôïc phaùt trieơn theđm neâu coù ñieău kieôn

 Raât mong ñöôïc tieâp túc nghieđn cöùu aùp dúng thieât keâ cho nhöõng heô thoâng coù qui mođ lôùn

 Moôt laăn nöõa em chađn thaønh cạm ôn Qủ Thaăy, Cođ vaø söï höôùng daên nhieôt tình

cụa Thaăy NGUYEÊN HUY HUØNG, cuøng taât cạ caùc bán ñaõ giuùp em hoaøn thaønh

luaôn aùn naøy