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On solving these equations for the derivatives, we obtain linear separable equations, which are easy to integrate.. Lopez, G., Partial Differential Equations of First Order and Their App

Trang 1

T7.3 N ONLINEAR E QUATIONS 1263

10. F1



x, ∂w

∂x



= F2



y, ∂w

∂y



.

A separable equation Complete integral:

w = ϕ(x) + ψ(y) + C1,

where the functions ϕ = ϕ(x) and ψ = ψ(y) are determined from the ordinary differential

equations

F1 x , ϕ  x

= C2, F2 y , ψ  y

= C2

11. F1



x, ∂w

∂x



+ F2



y, ∂w

∂y



+ aw = 0.

A separable equation Complete integral:

w = ϕ(x) + ψ(y),

where the functions ϕ = ϕ(x) and ψ = ψ(y) are determined from the ordinary differential

equations

F1 x , ϕ  x

+ aϕ = C1, F2 y , ψ y 

+ aψ = –C1,

where C1is an arbitrary constant If a≠ 0, one can set C1 =0in these equations

12. F1



x, 1

w

∂w

∂x



+ w k F2



y, 1

w

∂w

∂y



= 0.

A separable equation Complete integral:

w (x, y) = ϕ(x)ψ(y).

The functions ϕ = ϕ(x) and ψ = ψ(y) are determined by solving the ordinary differential

equations

ϕk F

1 x , ϕ  x /ϕ

= C, ψ k F

2 y , ψ y  /ψ

= –C, where C is an arbitrary constant.

13. F1



x, ∂w

∂x



+ e λw F2



y, ∂w

∂y



= 0.

A separable equation Complete integral:

w (x, y) = ϕ(x) + ψ(y).

The functions ϕ = ϕ(x) and ψ = ψ(y) are determined by solving the ordinary differential

equations

eλϕ F1 x , ϕ 

x

= C, e λψ F2 y , ψ 

y

= –C, where C is an arbitrary constant.

Trang 2

1264 FIRST-ORDERPARTIALDIFFERENTIALEQUATIONS

14. F1



x, 1

w

∂w

∂x



+ F2



y, 1

w

∂w

∂y



= k ln w.

A separable equation Complete integral:

w (x, y) = ϕ(x)ψ(y).

The functions ϕ = ϕ(x) and ψ = ψ(y) are determined by solving the ordinary differential

equations

F1 x , ϕ  x /ϕ

– k ln ϕ = C, F2 y , ψ y  /ψ

– k ln ψ = –C, where C is an arbitrary constant.

15. ∂w

∂x + yF1



x, ∂w

∂y



+ F2



x, ∂w

∂y



= 0.

Complete integral:

w = ϕ(x)y –



F2 x , ϕ(x)

dx + C1,

where the function ϕ(x) is determined by solving the ordinary differential equation ϕ  x+

F1(x, ϕ) =0

16. F



∂w

∂x + ay, ∂w

∂y + ax



= 0.

Complete integral: w = –axy + C1x + C2y + C3, where F (C1, C2) =0

17.



∂w

∂x

2

+



∂w

∂y

2

= F



x2+ y2, y ∂w

∂x – x ∂w

∂y



.

Complete integral: w = –C1arctan y

x+1 2

 

ξF (ξ, C1) – C12

ξ +C2, where ξ = x2+y2

18. F



x, ∂w

∂x, ∂w

∂y



= 0.

Complete integral: w = C1y +ϕ(x, C1)+C2, where the function ϕ = ϕ(x, C1) is determined

from the ordinary differential equation F x , ϕ  x , C1

=0

19. F



ax + by, ∂w

∂x, ∂w

∂y



= 0.

For b =0, see equation T7.3.3.18 Complete integral for b≠ 0:

w = C1x + ϕ(z, C1) + C2, z = ax + by, where the function ϕ = ϕ(z) is determined from the nonlinear ordinary differential equation

F z , aϕ  z + C1, bϕ  z

=0

20. F



∂x, ∂w

∂y



= 0.

Complete integral:

w = w(z), z = C1x + C2y,

where C1and C2 are arbitrary constants and w = w(z) is determined by the autonomous ordinary differential equation F w , C1w 

z , C2w 

z

=0

Trang 3

R EFERENCES FOR C HAPTER T7 1265

21. F



ax + by + cw, ∂w

∂y



= 0.

For c =0, see equation T7.3.3.19 If c≠ 0, then the substitution cu = ax + by + cw leads to

an equation of the form T7.3.3.20: F

cu, ∂u

∂xa

c, ∂u

∂yb

c



=0

22. F



x, ∂w

∂x, ∂w

∂y , w – y ∂w

∂y



= 0.

Complete integral: w = C1y + ϕ(x), where the function ϕ(x) is determined from the ordinary differential equation F x , ϕ  x , C1, ϕ

=0

23. F



∂y , x ∂w

∂x + y ∂w

∂y



= 0.

Complete integral:

w = ϕ(ξ), ξ = C1x + C2y,

where the function ϕ(ξ) is determined by solving the nonlinear ordinary differential equation

F ϕ , C1ϕ 

ξ , C2ϕ  ξ , ξϕ  ξ

=0

24. F



ax + by, ∂w

∂y , w – x ∂w

∂x – y ∂w

∂y



= 0.

Complete integral:

w = C1x + C2y + ϕ(ξ), ξ = ax + by, where the function ϕ(ξ) is determined by solving the nonlinear ordinary differential equation

F ξ , aϕ  ξ + C1, bϕ  ξ + C2, ϕ – ξϕ  ξ

=0

25. F



x, ∂w

∂x , G



y, ∂w

∂y



= 0.

Complete integral:

w = ϕ(x, C1) + ψ(y, C1) + C2,

where the functions ϕ and ψ are determined by the ordinary differential equations

F (x, ϕ  x , C1) =0, G (y, ψ  y ) = C1

On solving these equations for the derivatives, we obtain linear separable equations, which are easy to integrate

References for Chapter T7

Kamke, E., Differentialgleichungen: L¨osungsmethoden und L ¨osungen, II, Partielle Differentialgleichungen

Erster Ordnung f¨ur eine gesuchte Funktion, Akad Verlagsgesellschaft Geest & Portig, Leipzig, 1965.

Lopez, G., Partial Differential Equations of First Order and Their Applications to Physics, World Scientific

Publishing Co., Singapore, 2000.

Polyanin, A D., Zaitsev, V F., and Moussiaux, A., Handbook of First Order Partial Differential Equations,

Taylor & Francis, London, 2002.

Rhee, H., Aris, R., and Amundson, N R., First Order Partial Differential Equations, Vols 1 and 2, Prentice

Hall, Englewood Cliffs, New Jersey, 1986 and 1989.

Tran, D V., Tsuji, M., and Nguyen, D T S., The Characteristic Method and Its Generalizations for First-Order

Nonlinear Partial Differential Equations, Chapman & Hall, London, 1999.

Trang 5

Chapter T8

Linear Equations and Problems

of Mathematical Physics

T8.1 Parabolic Equations

2w

∂x2

T8.1.1-1 Particular solutions

w (x) = Ax + B,

w (x, t) = A(x2+ 2at ) + B,

w (x, t) = A(x3+ 6atx ) + B,

w (x, t) = A(x4+ 12atx2 + 12a2t2) + B,

w (x, t) = x2n+

n



k=1

( 2n)( 2n– 1) (2n– 2k+ 1 )

k x2n–2k,

w (x, t) = x2n+1+

n



k=1

( 2n+ 1 )( 2n ) (2n– 2k+ 2 )

k x2n–2k+1 ,

w (x, t) = A exp(aμ2t μx ) + B,

w (x, t) = A √1

texp



x

2

4at



+ B,

w (x, t) = A x

t3/2 exp



x

2

4at



+ B,

w (x, t) = A exp(–aμ2t ) cos(μx + B) + C,

w (x, t) = A exp(–μx) cos(μx –22t + B) + C,

w (x, t) = A erf



x

2√ at



+ B,

where A, B, C, and μ are arbitrary constants, n is a positive integer, and erf z ≡ 2

π

 z

0 exp(–ξ

2) dξ is the error function (probability integral).

T8.1.1-2 Formulas allowing the construction of particular solutions

Suppose w = w(x, t) is a solution of the heat equation Then the functions

w1 = Aw( λx + C1, λ2t + C2) + B,

w2 = A exp(λx + aλ2t )w(x +2aλt + C1, t + C2),

w3 = | A

δ + βt| exp

 – βx

2

4a (δ + βt)



w



x

δ + βt,

γ + λt

δ + βt

 , λδ – βγ =1,

1267

Trang 6

1268 LINEAREQUATIONS ANDPROBLEMS OFMATHEMATICALPHYSICS

where A, B, C1, C2, β, δ, and λ are arbitrary constants, are also solutions of this equation The last formula with β =1, γ = –1, δ = λ =0was obtained with the Appell transformation

T8.1.1-3 Cauchy problem and boundary value problems

For solutions of the Cauchy problem and various boundary value problems, see Subsec-tion T8.1.2 withΦ(x, t)≡ 0

2w

∂x2 +Φ(x, t)

T8.1.2-1 Domain: –∞ < x < ∞ Cauchy problem.

An initial condition is prescribed:

w = f (x) at t =0 Solution:

w (x, t) =

 ∞ f (ξ)G(x, ξ, t) dξ +

 t 0

 ∞ Φ(ξ, τ)G(x, ξ, t – τ) dξ dτ,

where

G (x, ξ, t) = 1

2√ πat exp

 –(x – ξ)

2

4at



T8.1.2-2 Solutions of boundary value problems in terms of the Green’s function

We consider boundary value problems on an interval 0 ≤ xl with the general initial condition

w = f (x) at t =0

and various homogeneous boundary conditions The solution can be represented in terms

of the Green’s function as

w (x, t) =

 l

0 f (ξ)G(x, ξ, t) dξ +

 t 0

 l

0 Φ(ξ, τ)G(x, ξ, t – τ) dξ dτ.

Here, the upper limit l can be finite or infinite; if l = ∞, there is no boundary condition

corresponding to it

Paragraphs T8.1.2-3 through T8.1.2-8 present the Green’s functions for various types

of homogeneous boundary conditions

Remark Formulas from Section 14.7 should be used to obtain solutions to corresponding nonhomoge-neous boundary value problems.

T8.1.2-3 Domain: 0 ≤x<∞ First boundary value problem.

A boundary condition is prescribed:

w=0 at x=0 Green’s function:

G (x, ξ, t) = 1

2√ πat

 exp

 –(x – ξ)

2

4at

 – exp

 –(x + ξ)

2

4at



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T8.1 P ARABOLIC E QUATIONS 1269

T8.1.2-4 Domain: 0 ≤x<∞ Second boundary value problem.

A boundary condition is prescribed:

∂ x w=0 at x=0 Green’s function:

G (x, ξ, t) = 1

2√ πat

 exp

 –(x – ξ)

2

4at

 + exp

 –(x + ξ)

2

4at



T8.1.2-5 Domain: 0 ≤x<∞ Third boundary value problem.

A boundary condition is prescribed:

∂ x w – kw =0 at x=0 Green’s function:

G (x, ξ, t) = 1

2√ πat



exp



(x – ξ)

2

4at



+ exp



(x + ξ)

2

4at



– 2k



0 exp



(x + ξ + η)

2

4at – kη





.

T8.1.2-6 Domain: 0 ≤xl First boundary value problem

Boundary conditions are prescribed:

Two forms of representation of the Green’s function:

G (x, ξ, t) = 2

l



n=1 sin



nπx l

 sin



nπξ l

 exp

 –an2π2t

l2



= 1

2√ πat



n=–∞

 exp

 –(x – ξ +2nl)2

4at

 – exp

 –(x + ξ +2nl)2

4at



The first series converges rapidly at large t and the second series at small t.

T8.1.2-7 Domain: 0 ≤xl Second boundary value problem

Boundary conditions are prescribed:

∂ x w=0 at x=0, ∂ x w=0 at x = l.

Two forms of representation of the Green’s function:

G (x, ξ, t) = 1

l + 2

l



n=1 cos



nπx l

 cos



nπξ l

 exp

 –an2π2t

l2



= 1

2√ πat



n=–∞

 exp

 –(x – ξ +2nl)2

4at

 + exp

 –(x + ξ +2nl)2

4at



The first series converges rapidly at large t and the second series at small t.

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