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Handbook of mathematics for engineers and scienteists part 183 potx

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The functionΦ can also be dependent on the second and higher derivatives with respect to t.. The functionΦ can also be dependent on the second and higher derivatives with respect to t...

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1242 SYSTEMS OFORDINARYDIFFERENTIALEQUATIONS

5. x 

tt + a(t)x = x–3f (y/x), y  tt + a(t)y = y–3g(y/x).

Generalized Ermakov system.

1 First integral:

1

2(xy t  – yx  t 2+

 y/x

uf (u) – u–3g (u)

du = C,

where C is an arbitrary constant.

2◦ Suppose ϕ = ϕ(t) is a nontrivial solution of the second-order linear differential equation

ϕ 

Then the transformation

τ =



dt

ϕ2(t), u =

x

ϕ (t), v=

y

leads to the autonomous system of equations

u 

ττ = u–3f (v/u), v ττ  = v–3g (v/u). (3)

3 Particular solution of system (3) is

u = A

C2τ2+ C1τ + C0, v = Ak

C2τ2+ C1τ + C0, A=



f (k)

C0C2– 14C2

1

1 4

,

where C0, C1, and C2are arbitrary constants, and k is a root of the algebraic (transcendental)

equation

k4f (k) = g(k).

6. x 

tt = f (y  t /x  t), y 

tt = g(y  t /x  t).

1 The transformation

leads to a system of the first-order equations

u 

t = f (w/u), w t  = g(w/u). (2)

Eliminating t yields a homogeneous first-order equation, whose solution is given by



f (ξ) dξ

g (ξ) – ξf (ξ) = ln|u|+ C, ξ= w

where C is an arbitrary constant On solving (3) for w, one obtains w = w(u, C) On substituting this expression into the first equation of (2), one can find u = u(t) and then

w = w(t) Finally, one can determine x = x(t) and y = y(t) from (1) by simple integration.

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2◦ The Suslov problem The problem of a point particle sliding down an inclined rough

plane is described by the equations

x 

 t



(x  t2+ (y t  2

, y 

tt= –

ky  t



(x  t 2+ (y  t2

,

which correspond to a special case of the system in question with

f (z) =1– √ k

1+ z2, g (z) = –

kz

1+ z2.

The solution of the corresponding Cauchy problem under the initial conditions

x(0) = y(0) = x  t 0) =0, y 

t 0) =1

leads, for the case k =1, to the following dependences x(t) and y(t) written in parametric

form:

x= –161 + 161 ξ4– 1

4ln ξ, y= 23 – 12ξ– 16ξ3, t= 14 – 14ξ2– 12ln ξ (0 ≤ξ≤ 1)

7. x 

tt = xΦ(x, y, t, x  t , y 

t), y 

tt = yΦ(x, y, t, x  t , y 

t).

1 First integral:

xy 

t – yx  t = C,

where C is an arbitrary constant.

Remark The functionΦ can also be dependent on the second and higher derivatives with respect to t.

2◦ Particular solution: y = C1x , where C1is an arbitrary constant and the function x = x(t)

is determined by the ordinary differential equation

x 

tt = x Φ(x, C1x , t, x  t , C1x 

t).

8. x 

tt + x–3f (y/x) = xΦ(x, y, t, x  t , y 

t), y 

tt + y–3g(y/x) = yΦ(x, y, t, x  t , y 

t).

First integral:

1

2(xy t  – yx  t 2+

 y/x

u–3g (u) – uf (u)

du = C, where C is an arbitrary constant.

Remark The functionΦ can also be dependent on the second and higher derivatives with respect to t.

9. x 

tt = F (t, tx  t – x, ty  t – y), y tt  = G(t, tx  t – x, ty t  – y).

1 The transformation

leads to a system of first-order equations

u 

t = tF (t, u, v), v  t = tG(t, u, v). (2)

2 Suppose a solution of system (2) has been found in the form

u = u(t, C1, C2), v = v(t, C1, C2), (3)

where C1 and C2 are arbitrary constants Then, substituting (3) into (1) and integrating, one obtains a solution of the original system,

x = C3t + t



u (t, C1, C2)

t2 dt, y = C4t + t



v (t, C1, C2)

t2 dt.

3◦ If the functions F and G are independent of t, then, on eliminating t from system (2),

one arrives at a first-order equation

g (u, v)u  v = F (u, v).

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1244 SYSTEMS OFORDINARYDIFFERENTIALEQUATIONS

T6.4 Nonlinear Systems of Three or More Equations

1. ax 

t = (b – c)yz, by  t = (c – a)zx, cz t  = (a – b)xy.

First integrals:

ax2+ by2+ cz2= C

1,

a2x2+ b2y2+ c2z2= C

2,

where C1and C2 are arbitrary constants On solving the first integrals for y and z and on

substituting the resulting expressions into the first equation of the system, one arrives at a separable first-order equation

2. ax 

t = (b – c)yzF (x, y, z, t),

by 

t = (c – a)zxF (x, y, z, t), cz t  = (a – b)xyF (x, y, z, t).

First integrals:

ax2+ by2+ cz2= C

1,

a2x2+ b2y2+ c2z2= C

2,

where C1and C2 are arbitrary constants On solving the first integrals for y and z and on

substituting the resulting expressions into the first equation of the system, one arrives at a

separable first-order equation; if F is independent of t, this equation will be separable.

3. x 

t = cF2– bF3 , y 

t = aF3– cF1 , z 

t = bF1– aF2 , where F n = F n (x, y, z).

First integral:

ax + by + cz = C1,

where C1 is an arbitrary constant On eliminating t and z from the first two equations of

the system (using the above first integral), one arrives at the first-order equation

dy

dx = aF3(x, y, z) – cF1(x, y, z)

cF2(x, y, z) – bF3(x, y, z), where z=

1

c (C1– ax – by).

4. x 

t = czF2– byF3 , y 

t = axF3– czF1 , z 

t = byF1– axF2

Here, F n = F n (x, y, z) are arbitrary functions (n =1, 2, 3)

First integral:

ax2+ by2+ cz2= C

1,

where C1 is an arbitrary constant On eliminating t and z from the first two equations of

the system (using the above first integral), one arrives at the first-order equation

dy

dx = axF3(x, y, z) – czF1(x, y, z)

czF2(x, y, z) – byF3(x, y, z), where z=

1

c (C1– ax2– by2)

5. x 

t = x(cF2– bF3 ), y 

t = y(aF3– cF1 ), z 

t = z(bF1– aF2 ).

Here, F n = F n (x, y, z) are arbitrary functions (n =1, 2, 3)

First integral:

|x|a|y|b|z|c = C1,

where C1 is an arbitrary constant On eliminating t and z from the first two equations of

the system (using the above first integral), one may obtain a first-order equation

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6. x 

t = h(z)F2– g(y)F3 , y 

t = f (x)F3– h(z)F1 , z 

t = g(y)F1– f (x)F2

Here, F n = F n (x, y, z) are arbitrary functions (n =1, 2, 3)

First integral: 

f (x) dx +



g (y) dy +



h (z) dz = C1,

where C1 is an arbitrary constant On eliminating t and z from the first two equations of

the system (using the above first integral), one may obtain a first-order equation

7. x 

tt=

∂F

∂x, y 

tt=

∂F

∂y, z 

tt=

∂F

∂z , where F = F (r), r =



x2+ y2+ z2

Equations of motion of a point particle under gravity.

The system can be rewritten as a single vector equation:

rtt = grad F or rtt = F  (r)

r r,

where r = (x, y, z).

1 First integrals:

(r t 2 =2F(r) + C1 (law of conservation of energy),

[r×r t] = C (law of conservation of areas),

(rC) =0 (all trajectories are plane curves)

2 Solution:

r = a r cos ϕ + b r sin ϕ.

Here, the constant vectors a and b must satisfy the conditions

|a|=|b|=1, (ab) =0,

and the functions r = r(t) and ϕ = ϕ(t) are given by

t=



r dr

2r2F (r) + C

1r2– C2 3

+ C2, ϕ = C3



dr

r 2r2F (r) + C

1r2– C2 3 , C3 =|C|

8. x 

tt = xF , y tt  = yF , z tt  = zF , where F = F (x, y, z, t, x  t , y  t , z t ).

First integrals (laws of conservation of areas):

zy 

t – yz  t = C1,

xz 

t – zx  t = C2,

yx 

t – xy  t = C3,

where C1, C2, and C3are arbitrary constants

Corollary of the conservation laws:

C1x + C2y + C3z=0 This implies that all integral curves are plane ones

Remark The functionΦ can also be dependent on the second and higher derivatives with respect to t.

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1246 SYSTEMS OFORDINARYDIFFERENTIALEQUATIONS

9. x 

tt = F1 , y 

tt = F2 , z 

tt = F3 , where F n = F n (t, tx  t – x, ty  t – y, tz t  – z).

1 The transformation

u = tx t – x, v = ty t  – y, w = tz t  – z (1) leads to the system of first-order equations

u 

t = tF1(t, u, v, w), v t  = tF2(t, u, v, w), w t  = tF3(t, u, v, w). (2)

2 Suppose a solution of system (2) has been found in the form

u (t) = u(t, C1, C2, C3), v (t) = v(t, C1, C2, C3), w (t) = w(t, C1, C2, C3), (3)

where C1, C2, and C3are arbitrary constants Then, substituting (3) into (1) and integrating, one obtains a solution of the original system:

x = C4t + t



u (t)

t2 dt, y = C5t + t



v (t)

t2 dt, z = C6t + t



w (t)

t2 dt,

where C4, C5, and C6are arbitrary constants

References for Chapter T6

Kamke, E., Differentialgleichungen: L¨osungsmethoden und L ¨osungen, I, Gew¨ohnliche Differentialgleichungen,

B G Teubner, Leipzig, 1977.

Polyanin, A D., Systems of Ordinary Differential Equations, From Website EqWorld—The World of

Mathe-matical Equations, http://eqworld.ipmnet.ru/en/solutions/sysode.htm.

Polyanin, A D and Zaitsev, V F., Handbook of Exact Solutions for Ordinary Differential Equations, 2nd

Edition, Chapman & Hall/CRC Press, Boca Raton, 2003.

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First-Order Partial

Differential Equations

T7.1 Linear Equations

 In equations T7.1.1.1–T7.1.1.11, the general solution is expressed in terms of the prin-cipal integral Ξ as w = Φ(Ξ), where Φ(Ξ) is an arbitrary function.

∂x +

f (x)y + g(x)  ∂w

∂y = 0.

Principal integral: Ξ = eF y–

eF g (x) dx, where F =

f (x) dx.

∂x +

f (x)y + g(x)y k  ∂w

∂y = 0.

Principal integral: Ξ = eF y1 –k– (1– k)



eF g (x) dx, where F = (1– k)



f (x) dx.

∂x +

f (x)e λy + g(x)  ∂w

∂y = 0.

Principal integral: Ξ = eλy E + λ

f (x)E dx, where E = exp



λ



g (x) dx



4. f (x) ∂w

∂x + g(y) ∂w

∂y = 0.

Principal integral: Ξ =



dx

f (x)



dy

g (y).

5. 

f (y) + amx n y m–1  ∂w

∂x 

g(x) + anx n–1 y m  ∂w

∂y = 0.

Principal integral: Ξ =



f (y) dy +



g (x) dx + ax n y m.

6. 

e αx f (y) + cβ  ∂w

∂x 

e βy g(x) + cα  ∂w

∂y = 0.

Principal integral: Ξ =



eβy f (y) dy +

eαx g (x) dx – ceαx–βy.

1247

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1248 FIRST-ORDERPARTIALDIFFERENTIALEQUATIONS

∂x + f (ax + by + c) ∂w

Principal integral: Ξ =



dv

a + bf (v) – x, where v = ax + by + c.

∂x + f



y x



∂w

∂y = 0.

Principal integral: Ξ =



dv

f (v) – v – ln|x|, where v = y

x

9. x ∂w

∂x + yf (x n y m)∂w

∂y = 0.

Principal integral: Ξ =



dv

v

mf (v) + n – ln|x|, where v = x n y m.

10. ∂w

∂x + yf (e αx y m)∂w

∂y = 0.

Principal integral: Ξ =



dv

v

α + mf (v)  – x, where v = e αx y m.

11. x ∂w

∂x + f (x n e αy)∂w

∂y = 0.

Principal integral: Ξ =



dv

v

n + αf (v) – ln|x|, where v = x n e αy.

 In the solutions of equations T7.1.2.1–T7.1.2.12, Φ(z) is an arbitrary composite function whose argument z can depend on both x and y.

1. a ∂w

∂y = f (x).

General solution: w = 1

a



f (x) dx + Φ(bx – ay).

∂y = f (x)y k.

General solution: w =

 x

x0

(y –ax+at) k f (t) dt+ Φ(y–ax), where x0can be taken arbitrarily.

∂y = f (x)e λy.

General solution: w = e λ(y–ax)



f (x)e aλx dx+Φ(y – ax).

... C1and C2 are arbitrary constants On solving the first integrals for y and z and on

substituting the resulting expressions into the first equation of the system,... C1and C2 are arbitrary constants On solving the first integrals for y and z and on

substituting the resulting expressions into the first equation of the system,... http://eqworld.ipmnet.ru/en/solutions/sysode.htm.

Polyanin, A D and Zaitsev, V F., Handbook of Exact Solutions for Ordinary Differential Equations, 2nd

Edition,

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