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Handbook of mathematics for engineers and scienteists part 104 ppsx

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At the second stage, we successively substitute the ΦiX and ΨjY of 15.5.1.4into all solutions 15.5.4.1 to obtain systems of ordinary differential equations* for the unknown functions ϕp

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2 At the second stage, we successively substitute the Φi(X) and Ψj(Y ) of (15.5.1.4)

into all solutions (15.5.4.1) to obtain systems of ordinary differential equations* for the

unknown functions ϕp(x) and ψq(y) Solving these systems, we get generalized separable

solutions of the form (15.5.1.1).

Remark 1 It is important that, for fixed k, the bilinear functional equation (15.5.1.3) used in the splitting

method is the same for different classes of original nonlinear mathematical physics equations

Remark 2 For fixed m, solution (15.5.4.1) contains m(k – m) arbitrary constants C i,j Given k, the

solutions having the maximum number of arbitrary constants are defined by

Solution number Number of arbitrary constants Conditions on k

m= 12(k 1) 1

4(k2–1) if k is odd.

It is these solutions of the bilinear functional equation that most frequently result in nontrivial generalized separable solution in nonlinear partial differential equations

Remark 3 The bilinear functional equation (15.5.1.3) and its solutions (15.5.4.1) play an important role

in the method of functional separation of variables

For visualization, the main stages of constructing generalized separable solutions by the splitting method are displayed in Fig 15.2.

15.5.4-2 Solutions of simple functional equations and their application.

Below we give solutions to two simple bilinear functional equations of the form (15.5.1.3) that will be used subsequently for solving specific nonlinear partial differential equations.

1 The functional equation

Φ1Ψ1 + Φ2Ψ2 + Φ3Ψ3 = 0 , (15 5 4 2 ) where Φiare all functions of the same argument and Ψiare all functions of another argument,

has two solutions:

Φ1 = A1Φ3, Φ2 = A2Φ3, Ψ3 = –A1Ψ1– A2Ψ2;

Ψ1 = A1Ψ3, Ψ2 = A2Ψ3, Φ3 = –A1Φ1– A2Φ2 (15. 5 4 3 )

The arbitrary constants are renamed as follows: A1= C1,1and A2= C2,1in the first solution,

and A1= – 1/C1,2and A2= C1,1/C1,2in the second solution The functions on the right-hand

sides of the formulas in (15.5.4.3) are assumed to be arbitrary.

2 The functional equation

Φ1Ψ1 + Φ2Ψ2 + Φ3Ψ3 + Φ4Ψ4 = 0 , (15 5 4 4 ) where Φiare all functions of the same argument and Ψiare all functions of another argument, has a solution

Φ1 = A1Φ3+ A2Φ4, Φ2 = A3Φ3+ A4Φ4,

Ψ3 = –A1Ψ1– A3Ψ2, Ψ4 = –A2Ψ1– A4Ψ2 (15. 5 . 4 . 5 )

dependent on four arbitrary constants A1, , A4; see solution (15.5.4.1) with k = 4 , m = 2 ,

C1,1= A1, C1,2= A2, C2,1= A3, and C2,2 = A4 The functions on the right-hand sides of

the solutions in (15.5.4.3) are assumed to be arbitrary.

* Such systems are usually overdetermined

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Write out the functional differential equation

Obtain: (i) functional equation, (ii) determining system of ODEs

Solve the determining system of ordinary differential equations

Write out generalized separable solution of original equation

Search for generalized separable solutions

Substitute into original equation

Apply splitting procedure

Treat functional equation (i)

Figure 15.2 General scheme for constructing generalized separable solutions by the splitting method

Abbre-viation: ODE stands for ordinary differential equation

Equation (15.5.4.4) also has two other solutions:

Φ1 = A1Φ4, Φ2 = A2Φ4, Φ3 = A3Φ4, Ψ4 = –A1Ψ1– A2Ψ2– A3Ψ3;

Ψ1 = A1Ψ4, Ψ2 = A2Ψ4, Ψ3 = A3Ψ4, Φ4 = –A1Φ1– A2Φ2– A3Φ3 (15. 5 . 4 . 6 )

involving three arbitrary constants In the first solution, A1= C1,1, A2= C2,1, and A3= C3,1,

and in the second solution, A1 = – 1/C1,3, A2= C1,1/C1,3, and A3= C1,2/C1,3.

Solutions (15.5.4.6) will sometimes be called degenerate, to emphasize the fact that

they contain fewer arbitrary constants than solution (15.5.4.5).

3 Solutions of the functional equation

Φ1Ψ1 + Φ2Ψ2 + Φ3Ψ3 + Φ4Ψ4 + Φ5Ψ5 = 0 (15 5 4 7 )

can be found by formulas (15.5.4.1) with k = 5 Below is a simple technique for finding solutions, which is quite useful in practice, based on equation (15.5.4.7) itself Let us assume that Φ1 , Φ2 , and Φ3 are linear combinations of Φ4 and Φ5 :

Φ1 = A1Φ4+ B1Φ5, Φ2 = A2Φ4+ B2Φ5, Φ3 = A3Φ4+ B3Φ5, (15 5 4 8 )

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where An, Bnare arbitrary constants Let us substitute (15.5.4.8) into (15.5.4.7) and collect the terms proportional to Φ4 and Φ5 to obtain

(A1Ψ1+ A2Ψ2+ A3Ψ3+ Ψ4 ) Φ4 + (B1Ψ1+ B2Ψ2+ B3Ψ3+ Ψ5 ) Φ5 = 0

Equating the expressions in parentheses to zero, we have

Ψ4 = –A1Ψ1– A2Ψ2– A3Ψ3,

Ψ5 = –B1Ψ1– B2Ψ2– B3Ψ3 (15. 5 4 9 ) Formulas (15.5.4.8) and (15.5.4.9) give solutions to equation (15.5.4.7) Other solutions are found likewise.

Example 1 Consider the nonlinear hyperbolic equation

2w

∂t2 = a ∂

∂x



w ∂w

∂x



where f (t) and g(t) are arbitrary functions We look for generalized separable solutions of the form

Substituting (15.5.4.11) into (15.5.4.10) and collecting terms yield

2(ϕϕ  x) x + aψχϕ  xx + (f ψ – ψ  tt )ϕ + f χ + g – χ  tt=0

This equation can be represented as a functional equation (15.5.4.4) in which

Φ1 = (ϕϕ  x) x, Φ2= ϕ  xx, Φ3= ϕ, Φ4=1,

Ψ1= aψ2, Ψ2= aψχ, Ψ3= f ψ – ψ tt , Ψ4= f χ + g – χ  tt (15.5.4.12)

On substituting (15.5.4.12) into (15.5.4.5), we obtain the following overdetermined system of ordinary

differ-ential equations for the functions ϕ = ϕ(x), ψ = ψ(t), and χ = χ(t):

(ϕϕ  x) x = A1ϕ + A2, ϕ  xx = A3ϕ + A4,

f ψ – ψ tt  = –A12– A3aψχ , f χ + g – χ  tt = –A22– A4aψχ (15.5.4.13) The first two equations in (15.5.4.13) are compatible only if

A1=6B2, A2 = B2–4B0B2, A3=0, A4=2B2, (15.5.4.14)

where B0, B1, and B2are arbitrary constants, and the solution is given by

ϕ (x) = B2x2+ B1x + B0 (15.5.4.15)

On substituting the expressions (15.5.4.14) into the last two equations in (15.5.4.13), we obtain the following

system of equations for ψ(t) and χ(t):

ψ  tt=6aB2ψ2+ f (t)ψ,

χ  tt= [2aB2ψ + f (t)]χ + a(B2–4B0B22+ g(t). (15.5.4.16) Relations (15.5.4.11), (15.5.4.15) and system (15.5.4.16) determine a generalized separable solution of

equation (15.5.4.10) The first equation in (15.5.4.16) can be solved independently; it is linear if B2=0and is

integrable by quadrature for f (t) = const The second equation in (15.5.4.16) is linear in χ (for ψ known) Equation (15.5.4.10) does not have other solutions with the form (15.5.4.11) if f and g are arbitrary functions and ϕ 0, ψ 0, and χ 0

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Remark It can be shown that equation (15.5.4.10) has a more general solution with the form

w (x, y) = ϕ1(x)ψ1(t) + ϕ2(x)ψ2(t) + ψ3(t), ϕ1(x) = x2, ϕ2(x) = x, (15.5.4.17)

where the functions ψ i = ψ i (t) are determined by the ordinary differential equations

ψ1=62+ f (t)ψ1,

ψ2= [61+ f (t)]ψ2,

ψ3= [21+ f (t)]ψ3+ aψ2+ g(t).

(15.5.4.18)

(The prime denotes a derivative with respect to t.) The second equation in (15.5.4.18) has a particular solution

ψ2= ψ1 Hence, its general solution can be represented as (see Polyanin and Zaitsev, 2003)

ψ2 = C1ψ1 + C2ψ1



dt

ψ2

The solution obtained in Example 1 corresponds to the special case C2=0

Example 2 Consider the nonlinear equation

2w

∂x∂t+



∂w

∂x

2

– w ∂

2w

∂x2 = a ∂

3w

which arises in hydrodynamics (see Polyanin and Zaitsev, 2004)

We look for exact solutions of the form

Substituting (15.5.4.20) into (15.5.4.19) yields

ϕ  t θ x  – ϕψθ xx  + ϕ2

(θ x )2– θθ  xx

– aϕθ  xxx=0

This functional differential equation can be reduced to the functional equation (15.5.4.4) by setting

Φ1= ϕ  t, Φ2= ϕψ, Φ3= ϕ2, Φ4= aϕ,

Ψ1= θ  x, Ψ2= –θ  xx, Ψ3= (θ  x)2– θθ  xx, Ψ4= –θ xxx  (15.5.4.21)

On substituting these expressions into (15.5.4.5), we obtain the system of ordinary differential equations

ϕ  t = A1ϕ2+ A2, ϕψ = A3ϕ2+ A4,

(θ  x)2– θθ  xx = –A1θ  x + A xx , θ xxx  = A x – A4θ  xx (15.5.4.22)

It can be shown that the last two equations in (15.5.4.22) are compatible only if the function θ and its

derivative are linearly dependent,

The six constants B1, B2, A1, A2, A3, and A4must satisfy the three conditions

B1(A1+ B2– A3B1) =0,

B2(A1+ B2– A3B1) =0,

B2+ A4B1– A2=0

(15.5.4.24)

Integrating (15.5.4.23) yields

θ=



B3exp(B1x) – B2

B1 if B1≠ 0,

where B3is an arbitrary constant

The first two equations in (15.5.4.22) lead to the following expressions for ϕ and ψ:

ϕ=

A2a

C exp(–A2at ) – A1 if A2≠ 0,

A1t + C if A2=0, ψ = A3ϕ + A4a, (15.5.4.26)

where C is an arbitrary constant.

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Formulas (15.5.4.25), (15.5.4.26) and relations (15.5.4.24) allow us to find the following solutions of equation (15.5.4.19) with the form (15.5.4.20):

w= x + C1

t + C2 + C3 if A2= B1=0, B2 = –A1;

w= C1e

–λx+1

λt + C2 + aλ if A2=0, B1 = –A4, B2= –A1– A3A4;

w = C1e–λ(x+aβt)+ a(λ + β) if A1= A3= B2=0, A2= B2+ A4B1;

w= aβ + C1e

–λx

1+ C2e–aλβt+ a(λ – β) if A1= A3B1– B2, A2= B2+ A4B1,

where C1, C2, C3, β, and λ are arbitrary constants (these can be expressed in terms of the A k and B k) The analysis of the second solution (15.5.4.6) of the functional equation (15.5.4.4) in view of (15.5.4.21) leads to the following two more general solutions of the differential equation (15.5.4.19):

w= x

t + C1 + ψ(t),

w = ϕ(t)e–λx– ϕ



t (t)

λϕ (t) + aλ, where ϕ(t) and ψ(t) are arbitrary functions, and C1and λ are arbitrary constants.

15.5.5 Titov–Galaktionov Method

15.5.5-1 Method description Linear subspaces invariant under a nonlinear operator Consider the nonlinear evolution equation

∂w

where F [w] is a nonlinear differential operator with respect to x,

F [w]F



x , w, ∂w

∂x , , ∂mw

∂xm



(15 5 5 2 ) Definition A finite-dimensional linear subspace

n= 5

ϕ1(x), , ϕn(x) 6

(15 5 5 3 )

formed by linear combinations of linearly independent functions ϕ1(x), , ϕn(x) is called invariant under the operator F if F [n] n This means that there exist functions

f1, , fnsuch that

F

 n

i=1

Ciϕi(x)



=

n



i=1

fi(C1, , Cni(x) (15 5 5 4 )

for arbitrary constants C1, , Cn.

Let the linear subspace (15.5.5.3) be invariant under the operator F Then equation

(15.5.5.1) possesses generalized separable solutions of the form

w (x, t) =

n



i=1

Here, the functions ψ1(t), , ψn(t) are described by the autonomous system of ordinary

differential equations

ψ

i= fi1, , ψn), i = 1 , , n, (15 5 5 6 )

where the prime denotes a derivative with respect to t.

The following example illustrates the scheme for constructing generalized separable solutions.

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Example 1 Consider the nonlinear second-order parabolic equation

∂w

∂t = a ∂

2w

∂x2 +



∂w

∂x

2

Obviously, the nonlinear differential operator

F [w] = aw xx + (w x)2+ kw2+ bw + c (15.5.5.8)

for k >0has a two-dimensional invariant subspace 2=5

1, cos(x√ k)6

Indeed, for arbitrary C1and C2we have

F

C1+ C2cos(x √

k)

= k(C2+ C2) + bC1+ c + C2(2kC1– ak + b) cos(x √

k)

Therefore, there is a generalized separable solution of the form

w (x, t) = ψ1(t) + ψ2(t) cos(x √

where the functions ψ1(t) and ψ2(t) are determined by the autonomous system of ordinary differential equations

ψ 1= k(ψ2+ ψ2) + bψ1+ c,

Remark 1 Example 3 below shows how one can find all two-dimensional linear subspaces invariant under the nonlinear differential operator (15.5.5.8)

Remark 2 For k > 0, the nonlinear differential operator (15.5.5.8) has a three-dimensional invariant subspace 3=5

1, sin(x√ k ), cos(x √

k)6

; see Example 3

Remark 3 For k < 0, the nonlinear differential operator (15.5.5.8) has a three-dimensional invariant subspace 3=5

1, sinh(x√ –k ), cosh(x √

–k )6

; see Example 3

Remark 4 A more general equation (15.5.5.7), with a = a(t), b = b(t), and c = c(t) being arbitrary functions, and k = const <0, also admits a generalized separable solution of the form (15.5.5.9), where the

functions ψ1(t) and ψ2(t) are determined by the system of ordinary differential equations (15.5.5.10).

15.5.5-2 Some generalizations.

Likewise, one can consider a more general equation of the form

L1[w] = L2[U ], U = F [w], (15 5 5 11 )

where L1[w] and L2[U ] are linear differential operators with respect to t,

L1[w] ≡ s1

i=0

ai(t) ∂

iw

∂ti , L2[U ] ≡ s2

j=0

bj(t) ∂

jU

and F [w] is a nonlinear differential operator with respect to x,

F [w]F



t , x, w, ∂w

∂x , , ∂mw

∂xm



, (15 5 5 13 )

and may depend on t as a parameter.

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Let the linear subspace (15.5.5.3) be invariant under the operator F , i.e., for arbitrary constants C1, , Cnthe following relation holds:

F

 n

i=1

Ciϕi(x)



=

n



i=1

fi(t, C1, , Cni(x). (15. 5 5 14 )

Then equation (15.5.5.11) possesses generalized separable solutions of the form (15.5.5.5),

where the functions ψ1(t), , ψn(t) are described by the system of ordinary differential

equations

L1

ψi(t) 

= L2

fi(t, ψ1, , ψn) 

, i = 1 , , n. (15 5 5 15 )

Example 2 Consider the equation

a2(t) ∂

2w

∂t2 + a1(t) ∂w

∂t =∂w

∂x

2w

which, in the special case of a2(t) = k2and a1(t) = k1/t , is used for describing transonic gas flows (where t

plays the role of a spatial variable)

Equation (15.5.5.16) is a special case of equation (15.5.5.11), where L1[w] = a2(t)w tt +a1(t)w t , L2[U ] = U , and F [w] = w x w xx It can be shown that the nonlinear differential operator F [w] = w x w xxadmits the three-dimensional invariant subspace  3 =5

1, x3/2, x36

Therefore, equation (15.5.5.16) possesses generalized separable solutions of the form

w (x, t) = ψ1(t) + ψ2(t)x3/2+ ψ3(t)x3,

where the functions ψ1(t), ψ2(t), and ψ3(t) are described by the system of ordinary differential equations

a2 (t)ψ1 + a1(t)ψ 1= 98ψ2,

a2(t)ψ2 + a1(t)ψ 2= 454ψ2ψ3,

a2(t)ψ3 + a1(t)ψ 3=18ψ2

Remark The operator F [w] = w x w xxalso has a four-dimensional invariant subspace 4=5

1, x, x2, x36

Therefore, equation (15.5.5.16) has a generalized separable solution of the form

w (x, t) = ψ1(t) + ψ2(t)x + ψ3(t)x2+ ψ4(t)x3

15.5.5-3 How to find linear subspaces invariant under a given nonlinear operator The most difficult part in using the Titov–Galaktionov method for the construction of exact solutions to specific equations is to find linear subspaces invariant under a given nonlinear operator.

In order to determine basis functions ϕi= ϕi(x), let us substitute the linear combination

n



i=1Ciϕi(x) into the differential operator (15.5.5.2) This is assumed to result in an expression

like

F

 n

i=1

Ciϕi(x)



= A1(C) Φ1 (X) + A2(C) Φ2 (X) + · · · + Ak(C) Φk(X) + B1(C)ϕ1(x) + B2(C)ϕ2(x) + · · · + Bn(C)ϕn(x), (15 5 5 17 )

where Aj(C) and Bi(C) depend on C1, , Cn only, and the functionals Φj(X) depend

on x and are independent of C1, , Cn:

Aj(C)Aj(C1, , Cn), j = 1 , , k,

Bi(C)Bi(C1, , Cn), i = 1 , , n,

Φj(X) ≡ Φj x , ϕ1, ϕ1, ϕ1, , ϕn, ϕ n, ϕ n

.

(15 5 5 18 )

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