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LOREDANA CASOReceived 24 November 2004; Accepted 28 September 2005 Some estimates for solutions of the Dirichlet problem for second-order elliptic equations are obtained in this paper..

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LOREDANA CASO

Received 24 November 2004; Accepted 28 September 2005

Some estimates for solutions of the Dirichlet problem for second-order elliptic equations are obtained in this paper Here the leading coefficients are locally VMO functions, while the hypotheses on the other coefficients and the boundary conditions involve a suitable weight function

Copyright © 2006 Loredana Caso This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited

1 Introduction

LetΩ be a bounded open subset ofRn,n ≥3, and let

L =

n



i, j =1

a i j(x) ∂

2

∂x i ∂x j +

n



i =1

a i(x) ∂

be a uniformly elliptic operator with measurable coefficients in Ω Several bounds for the solutions of the problem

Lu ≥ f , f ∈ L p(Ω),

u ∈ W2,p(Ω)∩ C o( ¯Ω),

u | ∂Ω0,

(D)

(p ∈] n/2, + ∞[) have been given, and the application of such estimates allows to obtain

certain uniqueness results for (D)

For instance, ifp ≥ n, a i,a ∈ L p(Ω) (with a0), a classical result of Pucci [4] shows that any solutionu of the problem ( D) verifies the bound

sup

whereK ∈ R+depends onΩ, n, p,  a i  L p(Ω)and on the ellipticity constant

Hindawi Publishing Corporation

Journal of Inequalities and Applications

Volume 2006, Article ID 76215, Pages 1 14

DOI 10.1155/JIA/2006/76215

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The casep < n, where additional hypotheses on the leading coefficients are necessary, has been studied by several authors Recently, a uniqueness result has been obtained in [3] under the assumption that thea i j’s are of class VMO,a i = a =0 andp ∈]1, +∞[ This

theorem has been extended to the casea i =0,a =0 in [7]

IfΩ is an arbitrary open subset ofRnandp ∈] n/2, + ∞[, a bound of type (1.2) and a consequent uniqueness result can be found in [1] In fact, it has been proved there that

if the coefficients a i j are bounded and locally VMO, the coefficients a i,a satisfy suitable

summability conditions and ess supΩa < 0, then for any solution u of the problem

Lu ≥ f , f ∈ Llocp (Ω),

u ∈ Wloc2,p(Ω)∩ C o( ¯Ω),

u | ∂Ω0, lim sup

| x |→+∞ u(x) ≤0 ifΩ is unbounded,

(D)

there exist a ballB ⊂⊂ Ω and a constant c ∈ R+such that

sup

Ω u ≤ c



B

f −p

dx

 1/ p

where f −is the negative part of f ,



B

f −p

dx = 1

| B |



andc depends on n, p, on the ellipticity constant, and on the regularity of the coefficients

ofL.

The aim of this paper is to study a problem similar to that considered in [1], but with boundary conditions depending on an appropriate weight function More precisely, fix a weight functionσ ∈Ꮽ(Ω)∩ C ∞(Ω) (seeSection 2for the definition ofᏭ(Ω)) and s ∈ R,

we consider a solutionu of the problem

Lu ≥ f , f ∈ Llocp (Ω),

u ∈ Wloc2,p(Ω), lim sup

x → x o

σ s(x)u(x) ≤0 ∀ x o ∈ ∂Ω, lim sup

| x |→+

σ s(x)u(x) ≤0 ifΩ is unbounded.

(1.5)

If the coefficients ai j are bounded and locally VMO, the functions σa i and σ2a are

bounded and ess supΩσ2a < 0, we will prove that there exist a ball B ⊂⊂Ω and a constant

c o ∈ R+such that

sup

Ω σ s u ≤ c o



B

σ s+2 f −p

dx

 1/ p

wherec o depends onn, p, s, σ, on the ellipticity constant, and on the regularity of the

coefficients of L As a consequence, some uniqueness results are also obtained

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2 Notation and function spaces

LetΩ be an open subset ofRnand letΣ(Ω) be the collection of all Lebesgue measurable subsets ofΩ For each E ∈Σ(Ω), we denote by| E |the Lebesgue measure ofE and put

E(x, r) = E ∩ B(x, r) ∀ x ∈ R n,∀ r ∈ R+, (2.1) whereB(x, r) is the open ball inRnof radiusr centered at x.

Denote byᏭ(Ω) the class of measurable functions ρ : Ω → R+such that

β −1ρ(y) ≤ ρ(x) ≤ βρ(y) ∀ y ∈Ω,∀ x ∈Ωy, ρ(y)

whereβ ∈ R+is independent ofx and y For ρ ∈Ꮽ(Ω), we put

S ρ = z ∈ ∂Ω : limx → z ρ(x) =0 . (2.3)

It is known that

ρ ∈ L ∞loc( ¯Ω), ρ −1∈ L ∞loc¯

Ω\ S ρ



and, ifS ρ = ∅,

ρ(x) ≤dist

x, S ρ



(see [2,6]) Having fixedρ ∈ Ꮽ(Ω) such that S ρ = ∂Ω, it is possible to find a function

σ ∈Ꮽ(Ω)∩ C ∞(Ω)∩ C0,1( ¯Ω) which is equivalent to ρ and such that

σ ∈ L ∞loc( ¯Ω), σ −1∈ L ∞loc(Ω), (2.6)

∂ α σ(x)  ≤ c α σ1−| α |(x) ∀ x ∈Ω,∀ α ∈ N n

γ −1σ(y) ≤ σ(x) ≤ γσ(y) ∀ y ∈Ω, ∀ x ∈Ωy, σ(y)

wherec α,γ ∈ R+are independent ofx and y (see [6]) For more properties of functions

ofᏭ(Ω) we refer to [2,6]

IfΩ has the property

Ω(x,r)  ≥ Ar n ∀ x ∈Ω, ∀ r ∈]0, 1], (2.10) whereA is a positive constant independent of x and r, it is possible to consider the space

BMO(Ω,t), t∈ R+, of functionsg ∈ L1loc( ¯Ω) such that

[g]BMO(Ω,t)= sup

x ∈Ω

r ∈]0,t]



Ω(x,r)

g −



Ω(x,r)

− g

d y < + ∞, (2.11)

where

Ω(x,r)

− gd y =1/ |Ω(x,r)| Ω(x,r) gd y If g ∈BMO(Ω)=BMO(Ω,t A), where

t A =sup

t ∈ R+: sup

x ∈Ω

r ∈]0,t]

r n

Ω(x,r)  ≤ A1

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we will say thatg ∈VMO(Ω) if [g]BMO(Ω,t) →0 fort →0+ A functionη[g] :R +→ R+is

called a modulus of continuity of g in VMO(Ω) if

BMO(Ω,t) ≤ η[g](t) ∀ t ∈ R+, lim

We say thatg ∈VMOloc(Ω) if (ζg)o ∈VMO(Rn) for anyζ ∈ C o ∞(Ω), where (ζg)odenotes the zero extension ofζg outside ofΩ A more detailed account of properties of the above defined spaces BMO(Ω) and VMO(Ω) can be found in [5]

3 An a priori bound

Fix p ∈] n/2, + ∞[ Let B be an open ball ofRn,n ≥3, of radiusδ We consider in B the

differential operator

L B =

n



i, j =1

α i j(x) ∂

2

∂x i ∂x j+

n



i =1

α i(x) ∂

with the following condition on the coefficients:

α i j = α ji ∈ L ∞(B) ∩VMO(B), i, j =1, , n,

∃ μ ∈ R+:

n



i, j =1

α i j ζ i ζ j ≥ μ | ζ |2 a.e inB, ∀ ζ ∈ R n,

α i ∈ L ∞(B), i =1, , n, α ∈ L ∞(B), α ≤0 a.e inB.

(h B)

Letμ0,μ1,μ2∈ R+such that

n



i, j =1

α i j

L ∞(B) ≤ μ0, δ

n



1=1

α i

L ∞(B) ≤ μ1, δ2 α  L ∞(B) ≤ μ2. (3.2)

Note that under the assumption (h B), the operator L B from W2,p(B) into L p(B) is

bounded and the estimate

L B u

L p(B) ≤ c1 u  W2,p(B) ∀ u ∈ W2,p(B) (3.3) holds, wherec1∈ R+depends onn, p, μ0,μ1,μ2

Lemma 3.1 Suppose that condition ( h B ) is verified, and let u be a solution of the problem

u ∈ W2,p(B),

L B u ≥ φ, φ ∈ L p(B),

u | ∂B ≤0.

(3.4)

Then there exists c ∈ R+such that

sup

B

u ≤ cδ2− n/ pφ −

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where c depends on n, p, μ, μ0,μ1,μ2, [p(α i j)]BMO(R n,·), and where p(α i j ) is an extension

of α i j toRn in L ∞(Rn)VMO(Rn ).

Proof Put B = B(y, δ), where y is the centre of B, and B ∗ = B(y, 1).

Consider the functionT : B → B ∗defined by the position

T(x) = y + x − y

and for each functiong defined on B, put g ∗ = g ◦ T −1

We observe that

L ∗ B u ∗ = δ2 

L B u

where

L ∗ B =

n



i, j =1

α ∗ i j(z) ∂

2

∂z i ∂z j +δ

n



i =1

α ∗ i (z) ∂

∂z i+δ2α ∗(z). (3.8) Denote byp(α i j) an extension ofα i jtoRnsuch that

p

α i j

∈ L ∞

Rn

VMO

Rn

(3.9) (for the existence of such function see [5, Theorem 5.1]) Since

p

α i j



∈ L ∞

Rn

VMO

Rn

, p

α i j



| B ∗ = α ∗ i j, (3.10)

it follows that

α ∗ i j ∈ L ∞(B ∗)VMO(B ∗). (3.11) Moreover, the condition (h B) yields that

α ∗ i j = α ∗ ji, i, j =1, , n,

n



i, j =1

α ∗ i j ζ i ζ j ≥ μ | ζ |2 a.e inB ∗,∀ ζ ∈ R n,

α ∗ i ∈ L ∞(B ∗), i =1, , n, α ∗ ∈ L ∞(B ∗), α ∗ ≤0 a.e inB ∗

(3.12)

We observe that the condition (3.12) implies that forr, s ∈]1, +∞[ the modulus of

con-tinuity ofδα ∗ i in L r(B ∗) and that ofδ2α ∗in L s(B ∗) depend only on δα ∗ i  L ∞(B ∗) and

 δ2α ∗  L ∞(B ∗), respectively

Thus, applying (3.10), (3.12), and [7, Theorem 2.1], it follows that the problem

L ∗ B v = ψ ∈ L p(B ∗),

v ∈W2,p(B ∗)∩ W o1,p(B ∗) (3.13)

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has a unique solutionv satisfying the estimate

 v  W2,p(B ∗)≤ K  ψ  L p(B ∗), (3.14)

whereK depends on n, p, μ, μ0,μ1,μ2, [p(α i j)]BMO(R n,·)

The estimate (3.5) follows now from (3.14) using the same arguments of the proof of Lemma 3.2 [1] in order to obtain there (e B) from [1, (3.23)] 

4 Hypotheses and preliminary results

LetΩ be an open subset ofRn,n ≥3 Fixρ ∈Ꮽ(Ω)∩ L ∞(Ω) such that Sρ = ∂Ω

Consider a functiong ∈ C ∞ o( ¯R +) satisfying the condition

0≤ g ≤1, g(t) =1 ift ≥1, g(t) =0 ift ≤1

For anyk ∈ N, we put

η k(x) =1

k ζ k(x) +



1− ζ k(x)

whereζ k(x) = g(kσ(x)), x ∈ Ω Clearly, η k ∈ C ∞(Ω) for any k∈ Nand

η k(x) =

1

k ifx ∈Ω¯k,

where

Ωk =



x ∈ Ω : σ(x) >1

k



In the following we will use the notation

f x =

n

i =1

f2

x i

 1/2

, f xx =

 n

i, j =1

f2

x i x j

 1/2

It is easy to show that for eachk ∈ N,

σ(x) ≤ η k(x) ≤2σ(x), x ∈Ω\Ω¯k, (4.6)

c k σ(x) ≤ η k(x) ≤ σ(x), x ∈Ωk, (4.7)



η k(x)

x ≤ c1



σ(x)



η k(x)

xx ≤ c2



σ(x) 2

x+σ(x)

σ(x)

xx

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wherec k ∈ R+depends onk and σ, and c1,c2∈ R+depend only onn Moreover, for any

s ∈ R, we have



η s k(x)

x

η s

k(x) ≤ c3



η k(x)

x



η s k(x)

xx

η s k(x) ≤ c3



η k(x) 2

x+η k(x)

η k(x)

xx

wherec3∈ R+depends ons and n.

We consider inΩ the differential operator

L =

n



i, j =1

a i j(x) ∂

2

∂x i ∂x j+

n



i =1

a i(x) ∂

and put

L o =

n



i, j =1

a i j(x) ∂

2

We will make the following assumption on the coefficients of L:

a i j = a ji ∈ L ∞(Ω)VMOloc(Ω), i, j=1, , n,

∃ ν,ν0∈ R+:

n



i, j =1

a i j

L ∞(Ω)≤ ν0,

n



i, j =1

a i j ζ i ζ j ≥ ν | ζ |2 a.e inΩ,∀ ζ ∈ R n,

∃ ν1,ν2∈ R+: ess sup

Ω



σ(x)

n



i =1

a i(x)≤ ν1, ess sup

Ω



σ2(x) | a(x) |≤ ν2,

∃ a o ∈ R+: ess sup

Ω



σ2(x)a(x)

= − a o

(h1)

Fixeds ∈ R, let u be a solution of the problem

Lu ≥ f , f ∈ Llocp (Ω), u∈ Wloc2,p(Ω), lim sup

x → x o

σ s(x)u(x) ≤0 ∀ x o ∈ ∂Ω, lim sup

| x |→+∞ σ s(x)u(x) ≤0 ifΩ is unbounded.

(P)

For anyk ∈ N, we put

w k(x) = η s

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Lemma 4.1 Suppose that condition ( h1) holds Then, for any k ∈ N there exist functions

b i k(i =1, , n), b k,g k and positive constants β1and β2such that

ess sup

Ω



σ(x)

n



i =1

b k

i(x)≤ β1, (4.15)

ess sup

Ω



where β1 depends on s, n, ν0, ν1 and β2 depends on s, n, ν0, ν2 Moreover, the function

w k,k ∈ N , satisfies the following conditions:

w k ∈ Wloc2,p(Ω), limsup

x → x o

w k(x) ≤0 ∀ x o ∈ ∂Ω, lim sup

| x |→+∞ w k(x) ≤0 if Ω is unbounded, (4.18)

L o w k+

n



i =1

b k i

w k

x i+b k w k ≥ g k in Ω. (4.19)

Proof Fix k ∈ N From (4.6)–(4.11) and from (2.6), (2.8), it easily follows that the func-tionw k, defined by (4.14), verifies (4.18)

Moreover, observe that

L o w k − uL o η s k −2

n



i, j =1

a i j

η k s

x j u x i+

n



i =1

a i

η s k u

x i

− u

n



i =1

a i

η s k

x i+aη s k u = η s k Lu, x ∈ Ω.

(4.20)

Since



η s k

x j u x i =η s k u

x i



η s k

x j

η s k −



η s k

x i(η s k)x j



η s k 2



η s k u

from (4.20), (4.19) follows, where we have put

b k i = a i −2

n



j =1

a i j



η k s

x j

η k s , i =1, , n,

b k = a + 2

n



i, j =1

a i j



η s k



x i



η s k



x j



η s k

n



i, j =1

a i j



η s k



x i x j

η s k

,

g k = η k s f +

n



i =1

a i



η s k

x i

η s k w k .

(4.22)

On the other hand, using the hypothesis (h1), (4.6)–(4.11), and (2.8) it is easy to show that there existβ1∈ R+depending ons, n, ν0,ν1andβ2∈ R+depending ons, n, ν0,ν2,

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Now we suppose that the following hypothesis onρ holds:

lim

k →+



sup

Ω\Ωk



σ(x)

x+σ(x)

σ(x)

xx



An example of functionρ such that σ satisfies ( h2) is provided in [2]

Lemma 4.2 Suppose that conditions ( h1) and ( h2) hold Then there exists k o ∈ N such that

ess sup

Ω



σ(x)

n



i =1

b k o

i (x)≤ ν1+a o

2, ess sup

Ω



σ2(x)b k o(x)

≤ − a o

2,

g k o(x) ≥ η s k o(x) f (x) − a o

8σ

2(x)w k

o(x), x ∈ Ω.

(4.23)

Proof From (4.10), (4.11), and hypothesis (h1), we deduce that

σ







n



i, j =1

a i j



η s k

x j

η s k





 ≤ c4



η k

x,

σ2







n



i, j =1

a i j



η k s

x i



η s k

x j



η s k

 2





+σ2







n



i, j =1

a i j



η s k

x i x j

η s k





 ≤ c5



η k

 2

x+η k



η k



xx



,

σ2







n



i =1

a i



η s k

x i

η s k





 ≤ c6



η k



x,

(4.24)

wherec4,c5∈ R+ depend ons, n, ν0 andc6∈ R+ depends on s, n, ν1 Observing that (η k)x =(η k)xx =0 in ¯Ωk, the statement follows now from (4.8), (4.9), (h1), (h2), and

5 Main results

It is well know that there exists a function ˜α ∈ C ∞(Ω)∩ C0,1( ¯Ω) which is equivalent to dist(·,Ω) (see, e.g., [8]) For every positive integerm, we define the function

ψ m:x ∈Ω¯ −→ g

m˜ α(x)

1− g

| x |

2m



whereg ∈ C ∞( ¯R +) verifies (4.1) It is easy to show thatψ m belongs toC o ∞(Ω) for every

m ∈ Nand

0≤ ψ m ≤1, suppψ m ⊆ E2m, ψ m |¯

where

E m =



x ∈Ω :| x | < m, ˜ α(x) > 1

m



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Remark 5.1 It follows from hypothesis ( h1) and from [5, Lemma 4.2] that for anym ∈ N

the functions (ψ m a i j)o(obtained as extensions ofψ m a i jtoRnwith zero values out ofΩ) belong to VMO(Rn) and



ψ m a i j

o

 BMO(R n,t) ≤ψ m a i j

fort small enough.

In the following we denote byw, b i,b, and g the functions defined by (4.14), (4.22), respectively, corresponding tok = k o, wherek ois the positive integer ofLemma 4.2

We can now prove the main result of the paper

Theorem 5.2 Suppose that conditions ( h1) and ( h2) hold, and let u be a solution of the problem ( P ) Then there exist an open ball B ⊂⊂ Ω and a constant c o ∈ R+such that

sup

Ω σ s(x)u(x) ≤ c o



B

σ s+2 f −p

dx

 1/ p

where c o depends only on n, p, s, γ, ν, ν0, ν1, ν2, a o , η[ψ m a i j] (m ∈ N).

Proof It can be assumed that supΩσ s(x) u(x) > 0 Thus it follows from (4.14) and (4.18) that there exists y ∈Ω such that supΩw(x) = w(y); moreover, there exists R o ∈]0,

dist(y, ∂ Ω)[ such that w(x) > 0 for all x ∈ B(y, R o)

Letλ, α, α o ∈ R+, withα o > 1 (that will be chosen late), such that

λα ≤min{R o,σ(y) }, α = α o σ(y). (5.6)

In the following we denote byB the open ball B(y, αλ).

We put

ϕ(x) =1 +λ2− | x − α2y |2, x ∈ B,¯ (5.7) and observe that

1≤ ϕ(x) ≤1 +λ22, x ∈ B,¯ (5.8)

ϕ x i ≤2

α, ϕ x i ϕ x j ≤4 2

α2 , i, j =1, , n, (5.9)

ϕ x i x j =0 ifi = j, ϕ x i x j = −2

Consider now the functionv defined by

Obviously,

v | = w | − w(y) ≤0, v(y) = λ2w(y). (5.12)

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It is easy to show that

L o(ϕw) − wL o ϕ −2

n



i, j =1

a i j ϕ x j w x i+

n



i =1

b i(ϕw) x i

n



i =1

b i ϕ x i w + bϕw = ϕ



L o w +

n



i =1

b i w x i+bw



≥ ϕg inB.

(5.13)

Thus

L o(ϕw) +

n



i =1

d i(ϕw) x i+dϕw ≥ ϕg +

n



i =1

b i ϕ x i w inB, (5.14)

where

d i = b i −2

n



j =1

a i j ϕ x j

d = b + 2

n



i, j =1

a i j ϕ x i ϕ x j

ϕ2

n



i, j =1

a i j ϕ x i x j

Therefore we obtain from (5.14) that

L o v +

n



i =1

where

h = ϕg + w

n



i =1

Clearly, (2.9), (5.6), and (5.9) yield that

ϕ x

i  ≤2 σ

α2

and hence it follows fromLemma 4.2that

h ≥ ϕη s k o f − a o

8σ

2ϕw(y) −2γw(y)



ν1+a o 2



1

α2

o

σ −2(y) − dw(y)

≥ ϕη s k o f +



− d −

a

o

4γ

2+ 2γν1

α2

o

+γa o

α2

o



σ −2(y)



w(y).

(5.20)

The constantα ocan be chosen in such a way thatd < − d o σ −2(y) in B, where

d o = a o

4γ

2+ 2γν1

α2

o

+γa o

α2

o

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In fact, byLemma 4.2, (5.9) and (5.10), we have

d + d o σ −2(y) = b + 2

n



i, j =1

a i j

ϕ x i ϕ x j

ϕ2

n



i, j =1

a i j

ϕ x i x j

ϕ +d o σ

2(y)

≤ − a o

2σ

2+ 8ν o λ2

α2+ 2ν o 1

α2+d o σ −2(y)



− γ2a o

4 +



10ν o+ 2γ ν1+γa o1

α2

o



σ −2(y),

(5.22)

and hence, fixedα osuch that

1

α2

o

≤ γ2a o

4

10ν o+ 2γ ν1+γa o, (5.23)

it follows that

By (5.11), (5.12), and (5.15)–(5.17), we deduce that the problem

v ∈ W2,p(B),

L o v +

n



i =1

d i v x i+dv ≥ ϕη s

k o f , f ∈ L p(B),

v | ∂B ≤0

(5.25)

satisfies the hypotheses ofLemma 3.1 Therefore, it follows from (5.6), (4.15), and (4.16) that there exists a constantc1∈ R+, depending onn, p, s, γ, ν, ν0,ν1,ν2, [p(a i j | B)]BMO(R n,·), such that

v(x) ≤ c1(λα)2− n/ p

ϕη s

k o f

L p(B) ∀ x ∈ B. (5.26)

So it follows from (5.8) and from (5.26) withx = y that

λ2w(y) ≤ c1(λα)2− n/ p

ϕη s

k o f

L p(B) ≤2c1(λα)2− n/ pη s

k o f −

L p(B) (5.27) Thus by (5.6) and (5.27) we have

w(y) ≤ c2(λα) − n/ p α2

o σ2(y)η s

k o f −

L p(B) ≤ c3(λα) − n/ p α2

oσ2η s

k o f −

L p(B), (5.28) wherec2,c3∈ R+depend on the same parameters asc1 Finally from (4.6), (4.7), (4.14), and (5.28) we obtain

sup

Ω σ s u ≤ c4(λα) − n/ p



B

σ2+s f −p

dx

 1/ p

≤ c5



B

σ s+2 f −dx1/ p

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