1. Trang chủ
  2. » Luận Văn - Báo Cáo

Báo cáo hóa học: " Research Article Liouville Theorems for a Class of Linear Second-Order Operators with Nonnegative Characteristic Form" potx

16 241 0
Tài liệu đã được kiểm tra trùng lặp

Đang tải... (xem toàn văn)

Tài liệu hạn chế xem trước, để xem đầy đủ mời bạn chọn Tải xuống

THÔNG TIN TÀI LIỆU

Thông tin cơ bản

Định dạng
Số trang 16
Dung lượng 558,33 KB

Các công cụ chuyển đổi và chỉnh sửa cho tài liệu này

Nội dung

Volume 2007, Article ID 48232, 16 pagesdoi:10.1155/2007/48232 Research Article Liouville Theorems for a Class of Linear Second-Order Operators with Nonnegative Characteristic Form Alessi

Trang 1

Volume 2007, Article ID 48232, 16 pages

doi:10.1155/2007/48232

Research Article

Liouville Theorems for a Class of Linear Second-Order Operators with Nonnegative Characteristic Form

Alessia Elisabetta Kogoj and Ermanno Lanconelli

Received 1 August 2006; Revised 28 November 2006; Accepted 29 November 2006 Recommended by Vincenzo Vespri

We report on some Liouville-type theorems for a class of linear second-order partial dif-ferential equation with nonnegative characteristic form The theorems we show improve our previous results

Copyright © 2007 A E Kogoj and E Lanconelli This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, dis-tribution, and reproduction in any medium, provided the original work is properly cited

1 Introduction

In this paper, we survey and improve some Liouville-type theorems for a class of hypoel-liptic second-order operators, appeared in the series of papers [1–4]

The operators considered in these papers can be written as follows:

ᏸ := N

i, j =1

∂ x i



a i j(x)∂ x j



+

N



i =1

b i(x)∂ x i − ∂ t, (1.1)

where the coefficients ai j, b i are t-independent and smooth in RN The matrix A =

(a i j)i, j =1, ,Nis supposed to be symmetric and nonnegative definite at any point ofRN

We will denote byz =(x,t), x ∈ R N,t ∈ R, the point ofRN+1, by Y the first-order

differential operator

Y : =N

i =1

Trang 2

and byᏸ0the stationary counterpart ofᏸ, that is,

ᏸ0:=

N



i, j =1

∂ x i



a i j(x)∂ x j



+

N



i =1

b i(x)∂ x i (1.3)

We always assume the operatorY to be divergence free, that is,N

i =1∂ x i b i(x) =0 at any pointx ∈ R N Moreover, as in [2], we assume the following hypotheses

(H1)ᏸ is homogeneous of degree two with respect to the group of dilations (d λ)λ>0 given by

d λ(x,t) =D λ(x),λ2t

,

D λ(x) = D λ



x1, ,x N



=λ σ1x1, ,λ σ N x N



whereσ =(σ1, ,σ N) is anN-tuple of natural numbers satisfying 1 = σ1≤ σ2

··· ≤ σ N When we say thatᏸ is d λ-homogeneous of degree two, we mean that

ᏸu

d λ(x,t)

= λ2(ᏸu)d λ(x,t)

∀ u ∈ C ∞

RN+1

(H2) For every (x,t),(y,τ) ∈ R N+1,t > τ, there exists an ᏸ-admissible path η : [0,T] →

RN+1such thatη(0) =(x,t), η(T) =(y,τ).

Anᏸ-admissible path is any continuous path η which is the sum of a finite number of

diffusion and drift trajectories

A di ffusion trajectory is a curve η satisfying, at any points of its domain, the inequality



η (s),ξ 2

 A

η(s)

ξ,ξ

Here,· denotes the inner product inRN+1 andA(z) =  A(x,t) =  A(x) stands for the

(N + 1) ×(N + 1) matrix



A =

A 0

A drift trajectory is a positively oriented integral curve of Y.

Throughout the paper, we will denote byQ the homogeneous dimension ofRN+1with respect to the dilations (1.4), that is,

and assume

Then, theD λ-homogeneous dimension ofRNisQ −23

We explicitly remark that the smoothness of the coefficients of ᏸ and the homo-geneity assumption in (H1) imply that thea i j’s and the b i’s are polynomial functions (see [5, Lemma 2]) Moreover, the “oriented” connectivity condition in (H1) implies the

Trang 3

hypoellipticity ofᏸ and of ᏸ0(see [1, Proposition 10.1]) For anyz =(x,t) ∈ R N+1, we define thed λ-homogeneous norm| z |by

| z | = (x,t) :=

| x |4+t2  1/4

where

| x | = x1, ,x N  = N

j =1



x2jσ/σ j 1/2σ

, σ =

N

j =1

σ j (1.11)

Hypotheses (H1) and (H2) imply the existence of a fundamental solutionΓ(z,ζ) of ᏸ

with the following properties (see [2, page 308]):

(i)Γ is smooth in{(z,ζ) ∈ R N+1 × R N+1 | z = ζ },

(ii)Γ(·,ζ) ∈ L1

loc(RN+1) andᏸΓ(·,ζ) = − δ ζ for everyζ ∈ R N+1, (iii)Γ(z, ·)∈ L1

loc(RN+1) andᏸ∗ Γ(z, ·)= − δ zfor everyz ∈ R N+1, (iv) lim supζ → z Γ(z,ζ) = ∞for everyz ∈ R N+1,

(v)Γ(0,ζ) →0 asζ → ∞,Γ(0,d λ(ζ)) = λ − Q+2 Γ(0,ζ),

(vi)Γ((x,t),(ξ,τ)) ≥0,> 0 if and only if t > τ,

(vii)Γ((x,t),(ξ,τ)) = Γ((x,0),(ξ,τ − t)).

In (iii)ᏸdenotes the formal adjoint ofᏸ

These properties of Γ allow to obtain a mean value formula at z =0 for the entire solutions toᏸu = 0 We then use this formula to prove a scaling invariant Harnack in-equality for the nonnegative solutions ᏸu = f inRN+1 Our first Liouville-type theorems will follow from this Harnack inequality All these results will be showed inSection 2

InSection 3, we show some asymptotic Liouville theorem for nonnegative solution to

ᏸu =0 in the halfspaceRN ×]− ∞, 0[ assuming thatᏸ, together with (H1) and (H2), is left invariant with respect to some Lie groups inRN+1

Finally, inSection 4some examples of operators to which our results apply are showed

2 Polynomial Liouville theorems

Throughout this section, we will assume thatᏸ in (1.1) satisfies hypotheses (H1) and (H2) LetΓ be the fundamental solution of ᏸ with pole at the origin With a standard procedure based on the Green identity forᏸ and by using the properties of Γ recalled in the introduction, one obtains a mean value formula atz =0 for the solution toᏸu =0 Precisely, for every point (0,T) ∈ R N+1andr > 0, define the ᏸ-ball centered at (0,T) and

with radiusr, as follows:

Ωr(0,T) : = ζ ∈ R N+1:Γ(0,T),ζ

>

1

r

Q −2 

Then, ifᏸu =0 inRN+1, one has

u(0,T) =

1

r

Q −2 

Ω (0,T) K(T,ζ)u(ζ)dζ, (2.2)

Trang 4

K(T,ζ) =



A(ξ) ∇ ξΓ,∇ ξΓ

andΓ stands for Γ((0,T),(ξ,τ)) Moreover, ·,· denotes the inner product inRNand∇ ξ

is the gradient operator (∂ ξ1, ,∂ ξ N)

Formula (2.2) is just one of the numerous extensions of the classical Gauss mean value theorem for harmonic functions For a proof of it, we directly refer to [6, Theorem 1.5]

We would like to stress that in this proof one uses our assumption divY =0

The kernelK(T, ·) is strictly positive in a dense open subset ofΩr(0,T) for every T,r >

0 (see [2, Lemma 2.3]) This property ofK(T, ·), together with thed λ-homogeneity ofᏸ, leads to the following Harnack-type inequality for entire solutions toᏸu =0

Theorem 2.1 Let u :RN+1 → R be a nonnegative solution to ᏸu = 0 inRN+1 Then, there exist two positive constants C = C(ᏸ) and θ = θ(ᏸ) such that

sup

C θr

u ≤ Cu(0,r2) ∀ r > 0, (2.4)

where, for ρ > 0, C ρ denotes the d λ -symmetric ball

C ρ:=z ∈ R N+1 | | z | < ρ

The proof of this theorem is contained in [2, page 310]

By using inequality (2.4) together with some basic properties of the fundamental solu-tionΓ, one easily gets the following a priori estimates for the positive solution to ᏸu = f

inRN+1

Corollary 2.2 Let f be a smooth function inRN+1 and let u be a nonnegative solution to

Then there exists a positive constant C independent of u and f such that

u(z) ≤ Cu

0,

|

z |

θ

 2

+| z |2 sup

| ζ |≤| z | /θ2

f (ζ) , (2.7)

where θ is the constant in Theorem 2.1

This result allows to use the Liouville-type theorem of Luo [5] to obtain our main result in this section

Theorem 2.3 Let u :RN+1 → R be a smooth function such that

ᏸu = p inRN+1,

Trang 5

where p and q are polynomial function Assume

u(0,t) = O

t m

Then, u is a polynomial function.

Proof We split the proof into two steps.

Step 1 There exists n > 0 such that

u(z) = O

| z | n

Indeed, lettingv : = u − q, we have

ᏸv = p − ᏸq inRN+1,

andv(0,t) = u(0,t) − q(0,t) = O(t n1) ast → ∞, for a suitablen1> 0 Moreover, since p

andᏸq are polynomial functions, (p − ᏸq)(z) = O( | z | m1) asz → ∞for a suitablem1> 0.

Then, by the previous corollary, there existsm2> 0 such that

v(z) = O

| z | m2 

From this estimate, sincev = u + q, and q is a polynomial function, the assertion (2.10) follows

Step 2 Since p is a polynomial function and ᏸ is d λ-homogeneous, there existsm ∈ N

such that

whereᏸ(m) =◦ ··· ◦ ᏸ is the mth iterated of ᏸ It follows that

Moreover, since ᏸ is d λ -homogeneous and hypoelliptic, the same properties hold for

ᏸ(m+1) On the other hand, byStep 1,u(z) = O(z m) as z → ∞, so thatu is a tempered distribution Then, by Luo’s paper [5, Theorem 1],u is a polynomial function. 

Remark 2.4 It is well known that hypothesis (2.9) in the previous theorem cannot be removed Indeed, ifᏸ=Δ− ∂ tis the classical heat operator andu(x,t) =exp(x1+···+

x N+Nt), x =(x1, ,x N)∈ R Nandt ∈ R, we have

andu is not a polynomial function.

In the previous theorem, the degree of the polynomial functionu can be estimated in

terms of the ones ofp and q For this, we need some more notation If α =(α1, ,α N,α N+1)

is a multi-index with (N + 1) nonnegative integer components, we let

| α | d := σ1α1+···+σ N α N+ 2α N+1, (2.16)

Trang 6

and, ifz =(x,t) =(x1, ,x N,t) ∈ R N+1,

z α:= x α1

1 ··· x α N

As a consequence, we can write every polynomial functionp inRN+1, as follows:

p(z) = 

| α | dλ ≤ m

withm ∈ Z,m ≥0, andc α ∈ Rfor every multi-indexα If



| α | dλ = m

c α z α ≡0 inRN+1, (2.19) then we set

Ifp is independent of t, that is, if p is a polynomial function inRN, we denote by

the degree of p with respect to the dilations (D λ)λ>0 Obviously, in this case, degD λ p =

degd λ p.

Proposition 2.5 Let u, p :RN+1 → R be polynomial functions such that

Assume u ≥ 0 Thus, the following statements hold.

(i) If p ≡ 0, then u = constant.

(ii) If p ≡ 0, then

degd λ u =2 + degd λ p. (2.23) This proposition is a consequence of the following lemma

Lemma 2.6 Let u :RN+1 → R be a nonnegative polynomial function d λ -homogeneous of degree m > 0 Then ᏸu ≡ 0 inRN+1

Proof We argue by contradiction and assume ᏸu =0 Since u is nonnegative and d λ -homogeneous of strictly positive degree, we have

u(0,0) =0=min

Let us now denote byᏼ the ᏸ-propagation set of (0,0) inRN+1, that is, the set

ᏼ :=z ∈ R N+1: there exists anᏸ-admissible path η : [0,T] −→ R N+1,

s.t.η(0) =(0, 0),η(T) = z

Trang 7

From hypotheses (H2), we obtainᏼ= R N ×]− ∞, 0] so that, since (0, 0) is a minimum point ofu and the minimum spread all over ᏼ (see [7]), we have

u(z) = u(0,0) =0 ∀ z ∈ R N ×]− ∞, 0]. (2.26) Then, beingu a polynomial function, u ≡0 inRN+1 This contradicts the assumption

Proof of Proposition 2.5 Obviously, if u =constant, we have nothing to prove If we as-sumem : =degd λ u > 0 and prove that

m ≥2, p ≡0, degd λ p = m −2, (2.27) then it would complete the proof Let us writeu as follows:

u = u0+u1+···+u m, (2.28) whereu jis a polynomial functiond λ-homogeneous of degree j, j =0, ,m, and u m ≡0

inRN+1

Then

p = ᏸu = ᏸu0+ᏸu1+···+ᏸu m, (2.29) and, sinceᏸ is d λ-homogeneous of degree two,



ᏸu j

d λ(x)

= λ j −2ᏸu j(x) (2.30)

so thatᏸu0= ᏸu10 and degd λ ᏸu j = j −2 if and only ifᏸu j ≡0

On the other hand, the hypothesisu ≥0 impliesu m ≥0 so that, beingu m ≡0 andd λ -homogeneous of degreem > 0, byLemma 2.6, we getᏸu m ≡0 Hencem ≥2 Moreover,

by (2.29),p = ᏸu ≡0 and

degd λ p =degd λ ᏸu m = m −2. (2.31)

 This proposition allows us to make more precise the conclusion ofTheorem 2.3 In-deed, we have the following

Proposition 2.7 Let u, p,q :RN+1 → R be polynomial functions such that

ᏸu = p inRN+1,

Then

degd λ u ≤max

2 + degd λ p,deg d λ q

In particular, and more precisely, if q = 0, that is, if u ≥ 0, then

degd λ u =2 + degd λ p if p ≡0,

Trang 8

Proof If q ≡0, the assertion is the one ofProposition 2.5 Supposeq ≡0 By lettingv : =

u − q, we have

ByProposition 2.5, we have

degd λ v ≤2 + degd λ(p − ᏸq) ≤2 + max

degd λ p,deg d λ q −2

=max

2 + degd λ p,deg d λ q

(2.36)

Proposition 2.7, together withTheorem 2.3, extends and improves the Liouville-type theorems contained in [2,4] (precisely [2, Theorem 1.1] and [4, Theorem 1.2])

FromTheorem 2.3andProposition 2.7, we straightforwardly get the following poly-nomial Liouville theorem for the stationary operatorᏸ0in (1.3)

Theorem 2.8 Let P,Q :RN → R be polynomial functions and let U :RN → R be a smooth function such that

ᏸ0U = P, U ≥ Q, inRN (2.37)

Then, U is a polynomial function and

degD λ U ≤max

2 + degD λ P,deg D λ Q

In particular, and more precisely, if Q ≡ 0, that is, if U ≥ 0, then

degD λ U =2 + degD λ P if P ≡0,

Proof Let us define

u(x,t) = U(x), p(x,t) = P(x), q(x,t) = Q(x). (2.40) Thenp, q are polynomial functions inRN+1andu is a smooth solution to the equation

such thatu ≥ q Moreover,

u(0,t) = U(0) = O(1) as t −→ ∞ (2.42) Then, byTheorem 2.3,u is a polynomial function inRN+1 This obviously implies that

U is a polynomial inRN The second part of the theorem immediately follows from

Trang 9

Remark 2.9 The class of our stationary operatorsᏸ0also contains “parabolic”-type op-erators like, for example, the following “forward-backward” heat operator

ᏸ0:= ∂2x1+x1∂ x2 inR 2

Nevertheless, in Theorem 2.8, we do not require any a priori behavior at infinity, like condition (2.9) inTheorem 2.3

3 Asymptotic Liouville theorems in halfspaces

The operatorᏸ in our class do not satisfy the usual Liouville property Precisely, if u is a

nonnegative solution to

then we cannot conclude that u ≡constant without asking an extra condition on the solutionu (seeTheorem 2.3andRemark 2.4)

However, if we also assume thatᏸ is left translation invariant with respect to the com-position law of some Lie group inRN+1 , then we can show that every nonnegative solution

of ( 3.1 ) is constant at t = −∞

To be precise, let us fix the new hypothesis onᏸ and give the definition of ᏸ-parabolic trajectory.

Supposeᏸ satisfies (H2) of the introduction and, instead of (H1), the following con-dition

(H1)There exists a homogeneous Lie group inRN+1,

L =RN+1,,d λ

(3.2)

such thatᏸ is left translation invariant onLandd λ-homogeneous of degree two

We assume the composition lawis Euclidean in the time variable, that is,

(x,t) ◦(x ,t )=c(x,t,x ,t ),t + t 

wherec(x,t,x ,t ) denotes a suitable function of (x,t) and (x ,t )

It is a standard matter to prove the existence of a positive constantC such that

| z ◦ ζ | ≤ C

| z |+| ζ | ∀ z,ζ ∈ R N+1 (3.4) Letγ : [0, ∞[→ R Nbe a continuous function such that

lim sup

s →∞

γ(s) 2

(here| · |denotes theD λ-homogeneous norm (1.11))

Trang 10

Then, the path

s −→ η(s) =γ(s),T − s

will be called anᏸ-parabolic trajectory.

Obviously, the curve

s −→ η(s) =(α,T − s), α ∈ R N,T ∈ R (3.7)

is anᏸ-parabolic trajectory It can be proved that every integral curve of the vector fields

Y in (1.2) also is anᏸ-parabolic trajectory (see [3, Lemma 3])

Our first asymptotic Liouville theorem is the following one

Theorem 3.1 Let ᏸ satisfy hypotheses (H1) ∗ and (H2), and let u be a nonnegative solution

to the equation

in the halfspace

Then, for every ᏸ-parabolic trajectory η,

lim

s →∞ u

η(s)

=inf

In particular

lim

t →−∞ u(x,t) =inf

The proof of this theorem relies on a left translation and scaling invariant Harnack

inequality for nonnegative solutions toᏸu =0

For everyz0∈ R N+1andM > 0, let us put

P z0(M) : = z0◦ P(M), (3.12) where

P(M) : =(x,t) ∈ R N+1:| x |2≤ − Mt

Then, the following theorem holds

Theorem 3.2 (left and scaling invariant Harnack inequality) Let u be a nonnegative so-lution to

ᏸu =0 inRN ×]− ∞, 0[. (3.14)

Trang 11

Then, for every z0∈ R N ×]− ∞ , 0[ and M > 0, there exists a positive constant C = C(M), independent of z0and u, such that

sup

P z0(M)

u ≤ Cu

z0 

Proof It follows fromTheorem 2.1and the left translation invariance ofᏸ The details

From this theorem we obtain the proof ofTheorem 3.1

Proof of Theorem 3.1 We may assume inf S u =0 Letη(s) =(γ(s),s0− s), s00,s ≥ s0be

anᏸ-parabolic trajectory Then, there exists M0> 0 such that

γ(s) 2

wheres ∗ > 0 is big enough Let us put M =2C(M2+ 1)1/4whereC is the positive constant

in the triangular inequality (3.4) Letε > 0 be arbitrarily fixed and choose z ε =(x ε,t ε)∈ S

such that

u

z ε



Now, for everys ≥ s ∗, we have

z −1

ε ◦ η(s) ≤ C z −1

ε + η(s) 

≤ C z −1

ε +

M2+ 1 1/4 √

s

= C

s − s0+t ε z −1

ε

s − s0+t ε+



M2+ 1 1/4



s

s − s0+t ε .

(3.18)

Then, there existsT = T(ε) > 0 such that

z −1

ε ◦ η(s) ≤ M

s − s0+t ε ∀ s > T. (3.19) This implies that

η(s) ∈ z ε ◦ P(M) ≡ P z ε(M) ∀ s > T. (3.20)

On the other hand, by the Harnack inequality ofTheorem 3.2, there existsC ∗ = C ∗(M) >

0 independent ofz εandε such that

sup

P zε(M)

u ≤ C ∗ u

z ε

Therefore,

u

η(s)

SinceC ∗is independent ofε, this proves the theorem. 

... inRN+1,

Trang 5

where p and q are polynomial function Assume

u(0,t)... data-page ="9 ">

Remark 2.9 The class of our stationary operators< /i>ᏸ0also contains “parabolic”-type op-erators like, for example, the following “forward-backward” heat operator...

Trang 11

Then, for every z0∈ R N ×]− ∞ , 0[ and

Ngày đăng: 22/06/2014, 19:20

TỪ KHÓA LIÊN QUAN

TÀI LIỆU CÙNG NGƯỜI DÙNG

TÀI LIỆU LIÊN QUAN

🧩 Sản phẩm bạn có thể quan tâm