Volume 2009, Article ID 158408, 13 pagesdoi:10.1155/2009/158408 Research Article A New General Integral Operator Defined by Al-Oboudi Differential Operator Serap Bulut Civil Aviation Col
Trang 1Volume 2009, Article ID 158408, 13 pages
doi:10.1155/2009/158408
Research Article
A New General Integral Operator Defined by
Al-Oboudi Differential Operator
Serap Bulut
Civil Aviation College, Kocaeli University, Arslanbey Campus, 41285 ˙Izmit-Kocaeli, Turkey
Correspondence should be addressed to Serap Bulut,serap.bulut@kocaeli.edu.tr
Received 8 December 2008; Accepted 22 January 2009
Recommended by Narendra Kumar Govil
We define a new general integral operator using Al-Oboudi differential operator Also we introduce new subclasses of analytic functions Our results generalize the results of Breaz, G ¨uney, and S˘al˘agean
Copyrightq 2009 Serap Bulut This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited
1 Introduction
LetA denote the class of functions of the form
n2
which are analytic in the open unit diskU {z ∈ C : |z| < 1}, and S : {f ∈ A : f is univalent
inU}
Trang 2Iff is given by 1.1, then from 1.3 and 1.4 we see that
n2
1 n − 1λ k a n z n , k ∈ N0: N ∪ {0}, 1.5
Now we introduce new classesSk δ, b, λ and K k δ, b, λ as follows.
A functionf ∈ A is in the classes S k δ, b, λ, where δ ∈ 0, 1, b ∈ C−{0}, λ ≥ 0, k ∈ N0,
if and only if
Re
11
b
or equivalently
Re
1λ
b
for allz ∈ U.
A functionf ∈ A is in the classs K k δ, b, λ, where δ ∈ 0, 1, b ∈ C − {0}, λ ≥ 0, k ∈ N0,
if and only if
Re
1λ b z
for allz ∈ U.
We note thatf ∈ K k δ, b, λ if and only if zf
∈ Sk δ, b, λ.
S0δ, b, 1 ≡ S∗
introduced by Frasin3
ii For b 1 and λ 1, we have the class
iii In particular, the classes
Trang 3are the classes of starlike functions of orderδ and convex functions of order δ in U,
resp-ectively
iv Furthermore, the classes
are familiar classes of starlike and convex functions inU, respectively
v For λ 1, we get
Let us introduce the new subclassesUSk α, δ, b, λ, UK k α, δ, b, λ and SH k α, b, λ,
KHk α, b, λ as follows.
A functionf ∈ A is in the class US k α, δ, b, λ if and only if f satisfies
Re
11b
> α
1
b
or equivalently
Re
1λ b
> α
λ b
whereα ≥ 0, δ ∈ −1, 1, α δ ≥ 0, b ∈ C − {0}, λ ≥ 0, k ∈ N0
A functionf ∈ A is in the class UK k α, δ, b, λ if and only if f satisfies
Re
1λ b z
> α
λ b
whereα ≥ 0, δ ∈ −1, 1, α δ ≥ 0, b ∈ C − {0}, λ ≥ 0, k ∈ N0
We note thatf ∈ UK k α, δ, b, λ if and only if zf
∈ USk α, δ, b, λ.
USk 0, δ, b, λ ≡ S k δ, b, λ, UK k 0, δ, b, λ ≡ K k δ, b, λ. 1.17
ii For b 1 and λ 1, we have the class
iii For λ 1, we have
Trang 4iv For b 1 and λ 1, we have
Geometric Interpretation
and 1 λ/bzD k fz/D k fz, respectively, take all the values in the conic domain
R α,δ which is included in the right-half plane such that
From elementary computations we see that ∂R α,δ represents the conic sections symmetric about the real axis ThusR α,δ is an elliptic domain forα > 1, a parabolic domain
A functionf ∈ A is in the class SH k α, b, λ if and only if f satisfies
1
1
b
− 2α√2− 1
<Re
√ 2
11b
2α√2− 1 z ∈ U,
1.22
whereα > 0, b ∈ C − {0}, λ ≥ 0, k ∈ N0
A functionf ∈ A is in the class KH k α, b, λ if and only if f satisfies
1
λ b
√
2− 1
<Re
√ 2
1λ b z
2α√2− 1 z ∈ U,
1.23
whereα > 0, b ∈ C − {0}, λ ≥ 0, k ∈ N0
We note thatf ∈ KH k α, b, λ if and only if zf
∈ SHk α, b, λ.
SHk α, 1, 1 ≡ SH k α,
defined in5
ii For λ 1, we have
Trang 5D Breaz and N Breaz6 introduced and studied the integral operator
F n z z
0
t
μ1
· · ·
t
μ n
wheref i ∈ A and μ i > 0 for all i ∈ {1, , n}.
By using the Al-Oboudi differential operator, we introduce the following integral operator So we generalize the integral operatorF n
0, and μ i > 0, 1 ≤ i ≤ n One defines the integral
I k,n,l,μ
F,
0
t
μ1
· · ·
t
μ n
wheref1, , f n ∈ A and D is the Al-Oboudi differential operator.
i λ 1, then we have 7, Definition 1
ii λ 1, k 0 and l1 · · · l n 0, then we have the integral operator defined
by1.26
iii k 0, l1 · · · l n l ∈ N0, then we have8, Definition 1.1
2 Main Results
The following lemma will be required in our investigation
Lemma 2.1 For the integral operator I k,n,l,μ f1, , f n F, defined by 1.27, one has
n
i1
n
i1
z
μ1
· · ·
z
μ n
Also, using1.3 and 1.4, we obtain
Trang 6
On the other hand, from2.2 and 2.3, we find
i1
z
μ i
n
j1
j / i
z
μ j
Thus by2.2 and 2.4, we can write
n
i1
n
i1
D l i1f i z − D l i f i z
.
2.6
Finally, we obtain
n
i1
which is the desired result
Theorem 2.2 Let α i ≥ 0, δ i ∈ −1, 1, α i δ i ≥ 0 1 ≤ i ≤ n, and b ∈ C − {0}, λ ≥ 0 Also suppose
that
n
i1
i1
Re
11b
Trang 7
for allz ∈ U By 2.1, we get
11b λz
D k Fz 1
n
i1
b
1 n
i1
11b
−n
i1
2.11
So,2.10 and 2.11 give us
Re
11b λz
1 −n
i1
i1
1 1b
i1
i1
i 1 1 −
n
i1
1 α i
2.12
for allz ∈ U Hence, we obtain F ∈ K k γ, b, λ, where γ 1 −n i1 μ i 1 − δ i /1 α i
Corollary 2.3 Let α i ≥ 0, δ i ∈ −1, 1, α i δ i ≥ 01 ≤ i ≤ n, and b ∈ C − {0} Also suppose that
n
i1
FromCorollary 2.3, we immediately getCorollary 2.4
Corollary 2.4 Let α i ≥ 0, δ i ∈ −1, 1, α i δ i ≥ 0 1 ≤ i ≤ n, and b ∈ C − {0} Also suppose that
n
i1
an extension of Theorem 1
Corollary 2.6 Let δ i ∈ 0, 11 ≤ i ≤ n and b ∈ C − {0}, λ ≥ 0 Also suppose that
n
i1
Trang 8If f i∈ Sl i δ i , b, λ1 ≤ i ≤ n, then the integral operator I k,n,l,μ F, defined by 1.27, is in the class
Kk ρ, b, λ, where
i1
Corollary 2.7 Let δ i ∈ 0, 1 1 ≤ i ≤ n and b ∈ C − {0} Also suppose that
n
i1
Sk1 ρ, b, 1, where ρ is defined as in 2.16.
Corollary 2.8readily follows fromCorollary 2.7
Corollary 2.8 Let δ i ∈ 0, 1 1 ≤ i ≤ n, and b ∈ C − {0} Also suppose that
n
i1
Sk1 0, b, 1.
Theorem 2.10 Let α i ≥ 0, δ i ∈ −1, 1, α i δ i ≥ 0 1 ≤ i ≤ n and b ∈ C − {0}, λ ≥ 0 Also suppose
that
n
i1
Corollary 2.11 Let α i ≥ 0, δ i ∈ −1, 1, α i δ i ≥ 0 1 ≤ i ≤ n and b ∈ C − {0} Also suppose that
n
i1
Trang 9If f i∈ USl i α i , δ i , b, 1 1 ≤ i ≤ n, then the integral operator I k,n,l,μ F, defined by 1.27, is in the
Corollary 2.13 Let δ i ∈ 0, 11 ≤ i ≤ n and b ∈ C − {0}, λ ≥ 0 Also suppose that
n
i1
Kk ρ, b, λ, where ρ is defined as in 2.16.
Corollary 2.14 Let δ i ∈ 0, 11 ≤ i ≤ n and b ∈ C − {0} Also suppose that
n
i1
Sk1 ρ, b, 1, where ρ is defined as in 2.16.
Theorem 2.16 Let α ≥ 0, δ ∈ −1, 1, α δ ≥ 0 and b ∈ C − {0}, λ ≥ 0 Also suppose that
n
i1
If f i ∈ USl i α, δ, b, λ 1 ≤ i ≤ n, then the integral operator I k,n,l,μ F, defined by 1.27, is in the
Re
11b
> α
1
b
for allz ∈ U.
Trang 10On the other hand, from2.1, we obtain
1λ b z
D k Fz 1
n
i1
b
1 −n
i1
i1
11b
.
2.25
Considering1.16 with the above equality, we find
Re
1 λ b z
− α
λ b
− δ
1 −n
i1
i1
11b
− α
n
i1
μ i b1
− δ
≥ 1 −n
i1
i1
11b
− αn
i1
1
b
− δ
i1
i1
1
b
δ
− αn
i1
1
b
− δ
1 − δ
1−n
i1
≥ 0
2.26 for allz ∈ U This completes proof.
Corollary 2.17 Let α ≥ 0, δ ∈ −1, 1, α δ ≥ 0, and b ∈ C − {0} Also suppose that
n
i1
If f i ∈ USl i α, δ, b, 1 1 ≤ i ≤ n, then the integral operator I k,n,l,μ F, defined by 1.27, is in the
Theorem 2.19 Let α ≥ 0, b ∈ C − {0}, and λ ≥ 0 Also suppose that
n
i1
If f i ∈ SHl i α, b, λ 1 ≤ i ≤ n, then the integral operator I k,n,l,μ F, defined by 1.27, is in the
Trang 11Proof Since f i∈ SHl i α, b, λ 1 ≤ i ≤ n, by 1.22 we have
Re
√
2
√
2
b
2α√2− 1−
1
1
b
− 2α√2− 1
>0
2.29 for allz ∈ U Considering this inequality and 2.1, we obtain
Re
√
2
√
2
b
2α√2− 1−
1
1
b
√
2− 1
Re
√
2
√ 2
b
n
i1
2α√2− 1
−
1
1
b
n
i1
− 2α√2− 1
√2n
i1
√
2
b
2α√2− 1
−
1
n
i1
b
− 2α√2− 1
√2n
i1
√
2
√ 2
b
−√2
n
i1
−
1
n
i1
11b
−2α√2−1
−n
i1
i1
√2
1−n
i1
2α√2− 1n
i1
√
2
√ 2
b
−
1− 2α√2− 1
1−n
i1
n
i1
11b
− 2α√2− 1
≥√2
1−n
i1
2α√2− 1n
i1
√
2
√ 2
b
− 1− 2α√
2− 1 1−n
i1
−n
i1
μ i
1
1
b
− 2α√2− 1
2α√2− 1n
i1
i1
Trang 12√2 2α√2− 1− 1− 2α√
2− 1 1−n
i1
n
i1
Re
√
2
√ 2
b
2α√2−1−
1
1
b
−2α√2−1
2− 1 1−n
i1
>
1−n
i1
min√
2− 11 4α,√2 1≥ 0
2.30
for allz ∈ U Hence by 1.23, we have F ∈ KH k α, b, λ.
Corollary 2.20 Let α ≥ 0 and b ∈ C − {0} Also suppose that
n
i1
If f i ∈ SHl i α, b, 1 1 ≤ i ≤ n, then the integral operator I k,n,l,μ F, defined by 1.27, is in the
Theorem 2.22 Let α ≥ 0, b ∈ C − {0} and λ ≥ 0 Also suppose that
1√2α√2− 1n
i1
If f i ∈ SHl i α, b, λ 1 ≤ i ≤ n, then the integral operator I k,n,l,μ F, defined by 1.27, is in the
Re
√
2
√
2
b
2α√2− 1>
1
1
b
− 2α√2− 1
2.33
Trang 13for allz ∈ U Considering this inequality and 2.1, we obtain
√
2Re
1λ b z
Re
√
2
√ 2
b
n
i1
√2−√2
n
i1
i1
√
2
√ 2
b
√2−√2
n
i1
i1
i1
Re
√ 2
√ 2
b
2α√2−1
1−1√2α√2− 1n
i1
> 0
2.34 for allz ∈ U Hence, by 1.8, we have F ∈ K k 0, b, λ.
Corollary 2.23 Let α ≥ 0 and b ∈ C − {0} Also suppose that
1√2α√2− 1n
i1
If f i ∈ SHl i α, b, 1 1 ≤ i ≤ n, then the integral operator I k,n,l,μ F, defined by 1.27, is in the
References
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