Volume 2011, Article ID 929061, 17 pagesdoi:10.1155/2011/929061 Research Article Approximation of Solutions for Second-Order m-Point Nonlocal Boundary Value Problems via the Method of Ge
Trang 1Volume 2011, Article ID 929061, 17 pages
doi:10.1155/2011/929061
Research Article
Approximation of Solutions for Second-Order
m-Point Nonlocal Boundary Value Problems via
the Method of Generalized Quasilinearization
Ahmed Alsaedi
Department of Mathematics, Faculty of Science, King Abdulaziz University, P.O Box 80203,
Jeddah 21589, Saudi Arabia
Correspondence should be addressed to Ahmed Alsaedi,aalsaedi@hotmail.com
Received 11 May 2010; Revised 29 July 2010; Accepted 2 October 2010
Academic Editor: Gennaro Infante
Copyrightq 2011 Ahmed Alsaedi This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited
We discuss the existence and uniqueness of the solutions of a second-order m-point nonlocal
boundary value problem by applying a generalized quasilinearization technique A monotone sequence of solutions converging uniformly and quadratically to a unique solution of the problem
is presented
1 Introduction
The monotone iterative technique coupled with the method of upper and lower solutions
1 7 manifests itself as an effective and flexible mechanism that offers theoretical as well as constructive existence results in a closed set, generated by the lower and upper solutions In general, the convergence of the sequence of approximate solutions given by the monotone iterative technique is at most linear 8, 9 To obtain a sequence of approximate solutions converging quadratically, we use the method of quasilinearization10 This method has been developed for a variety of problems11–20 In view of its diverse applications, this approach
is quite an elegant and easier for application algorithms
The subject of multipoint nonlocal boundary conditions, initiated by Bicadze and Samarski˘ı 21, has been addressed by many authors, for instance, 22–32 The multipoint boundary conditions appear in certain problems of thermodynamics, elasticity and wave propagation, see 23 and the references therein The multipoint boundary conditions may
be understood in the sense that the controllers at the endpoints dissipate or add energy according to censors located at intermediate positions
Trang 2In this paper, we develop the method of generalized quasilinearization to obtain a sequence of approximate solutions converging monotonically and quadratically to a unique
solution of the following second-order m−point nonlocal boundary value problem
−xt ft, x t, xt, t ∈ 0, 1, 1.1
px 0 − qx0 m−2
i1 τix
ηi
, px 1 qx1 m−2
i1 σix
ηi
, ηi ∈ 0, 1, 1.2
where f : 0, 1 × R × R → R is continuous and τ i, σi i 1, 2, , m − 2 are nonnegative real
constants such thatm−2
i1 τi < 1,m−2
i1 σi < 1, and p, q > 0 with p > 1.
Here we remark that26 studies 1.1 with the boundary conditions of the form
δx 0 − γx0 0, x1 m−2
i1 αix
ηi
A perturbed integral equation equivalent to the problem1.1 and 1.3 considered in 26 is
x t
1
0
k t, sfs, x s, xsds
m−2
i1 αix
ηi
where
k t, s 1
δ γ
⎧
⎨
⎩
γ δt
1 − s, 0 ≤ t ≤ s,
δ γs
It can readily be verified that the solution given by1.4 does not satisfy 1.1 On the other hand, by Green’s function method, a unique solution of the problem1.1 and 1.3 is
x t
1
0
k t, sfs, x s, xsds
m−2
i1 αix
ηiγ δt
δ γ , 1.6
where kt, s is given by 1.5 Thus, 1.6 represents the correct form of the solution for the problem1.1 and 1.3
Trang 32 Preliminaries
For x ∈ C10, 1, we define x1 x x, where x max{|xt| : t ∈ 0, 1} It can easily
be verified that the homogeneous problem associated with1.1-1.2 has only the trivial solution Therefore, by Green’s function method, the solution of1.1-1.2 can be written as
x t
1
0
G t, sfs, x s, xsds
m−2
i1 τix
ηi −t 2q p q p
p
2q p
m−2
i1 σix
ηi t
p
2q p
,
2.1
where Gt, s is the Green’s function and is given by
G t, s 1
p
p 2q
⎧
⎨
⎩
q pt
q p 1 − s, 0 ≤ t ≤ s,
q ps
q p 1 − t, s ≤ t ≤ 1. 2.2
Note that Gt, s > 0 on 0, 1 × 0, 1.
We say that α ∈ C20, 1 is a lower solution of the boundary value problem 1.1 and
1.2 if
−αt ≤ ft, α t, αt, t ∈ 0, 1,
pα 0 − qα0 ≤m−2
i1 τiα
ηi
, pα 1 qα1 ≤m−2
i1 σiα
ηi
,
2.3
and β ∈ C20, 1 is an upper solution of 1.1 and 1.2 if
−βt ≥ ft, β t, βt, t ∈ 0, 1,
pβ 0 − qβ0 ≥m−2
i1 τiβ
ηi
, pβ 1 qβ1 ≥m−2
i1 σiβ
ηi
Definition 2.1 A continuous function h : 0, ∞ → 0, ∞ is called a Nagumo function if
∞
λ
sds
for λ ≥ 0 We say that f ∈ C0, 1 × R × R satisfies a Nagumo condition on 0, 1 relative
to α, β if for every t ∈ 0, 1 and x ∈ min t∈0,1αt, maxt∈0,1βt, there exists a Nagumo
function h such that |ft, x, x| ≤ h|x|.
We need the following result33 to establish the main result
Trang 4Theorem 2.2 Let f : 0, 1 × R2 → R be a continuous function satisfying the Nagumo condition
on E {t, x, y ∈ 0, 1 × R2 : α ≤ x ≤ β} where α, β : 0, 1 → R are continuous functions such
that αt ≤ βt for all t ∈ 0, 1 Then there exists a constant M > 0 (depending only on α, β, the Nagumo function h) such that every solution x of 1.1-1.2 with αt ≤ xt ≤ βt, t ∈ 0, 1
satisfies |x| ≤ M.
If α, β ∈ C20, 1 are assumed to be lower and upper solutions of 1.1-1.2, respectively, in the statement of Theorem 2.2, then there exists a solution, xt of 1.1 and
1.2 such that αt ≤ xt ≤ βt, t ∈ 0, 1.
Theorem 2.3 Assume that α, β ∈ C20, 1 are, respectively, lower and upper solutions of 1.1-1.2.
If ft, x, y ∈ C0, 1 × R × R is decreasing in x for each t, y ∈ 0, 1 × R, then α ≤ β on 0, 1 Proof Let us define ut αt − βt so that u ∈ C20, 1 and satisfies the boundary
conditions
pu 0 − qu0 ≤m−2
i1 τiu
ηi
, pu 1 qu1 ≤m−2
i1 σiu
ηi
For the sake of contradiction, let u have a positive maximum at some t0∈ 0, 1 If t0 ∈ 0, 1, then ut0 0 and ut0 ≤ 0 On the other hand, in view of the decreasing property of
ft, x, y in x, we have
ut0 αt0 − βt0 ≥ −ft0, α t0, αt0 ft0, β t0, βt0> 0, 2.7
which is a contradiction If we suppose that u has a positive maximum at t0 0, then it follows from the first of boundary conditions2.6 that
pu 0 − qu0 ≤m−2
i1 τiu
ηi
which implies thatp − 1u0 ≤ qu0 Now as p > 1, q > 0, u0 > 0, u0 ≤ 0, therefore
we obtain a contradiction We have a similar contradiction at t0 1 Thus, we conclude that
αt ≤ βt, t ∈ 0, 1.
3 Main Results
Theorem 3.1 Assume that
A1 the functions α, β ∈ C20, 1 are, respectively, lower and upper solutions of 1.1-1.2
such that α ≤ β on 0, 1;
A2 the function f ∈ C20, 1 × R × R satisfies a Nagumo condition relative to α, β
and fx ≤ 0 on 0, 1 × min t∈0,1αt, maxt∈0,1βt × −M, M, where M is a positive constant depending on α, β, and the Nagumo function h Further, there exists
a function φ ∈ C20, 1 × R2 such that Ψf φ ≥ 0 with Ψφ ≥ 0 on 0, 1 ×
mint∈0,1αt, maxt∈0,1βt × −M, M, where
Ψ x − y2 ∂2
∂x2 2x − y
x− y ∂2
∂x∂xx− y2 ∂2
Trang 5Then, there exists a monotone sequence {α n } of approximate solutions converging uniformly to a
unique solution of the problems1.1-1.2.
Proof For y ∈ R, we define ωy max{−M, min{y, M}} and consider the following
modified m-point BVP
−xt ft, x t, ωxt, t ∈ 0, 1,
px 0 − qx0 m−2
i1 τix
ηi
, px 1 qx1 m−2
i1 σix
ηi
.
3.2
We note that α, β are, respectively, lower and upper solutions of 3.2 and for every t, x ∈
0, 1 × min t∈0,1αt, maxt∈0,1βt, we have
∞
0
sds
M
0
sds
h s
∞
M
sds
Nagumo function h such that
M
0
sds ≥
N
0
sds
h s >
max
β t : t ∈ 0, 1− min{αt : t ∈ 0, 1}, 3.5
where M > max{N, α, β} Thus, any solution x of 3.2 with αt ≤ xt ≤ βt, t ∈ 0, 1
satisfies|x| ≤ M on 0, 1 and hence it is a solution of 1.1-1.2
Let us define a function F : 0, 1 × R2 → R by
F
t, x, x
ft, x, x
φt, x, x− ωx
In view of the assumptionA2, it follows that F ∈ C20, 1 × R2 and satisfies ΨF ≥ 0 on
0, 1 × min t∈0,1αt, maxt∈0,1βt × −M, M Therefore, by Taylor’s theorem, we obtain
f
t, x, ω
x
≥ ft, y, ω
y
F x
t, y, ω
y
x − y
F x
t, y, ω
y
ω
x
− ωy
−φ t, x, 0 − φt, y, 0
≥ ft, y, ω
y
Fx
t, y, ω
y
− φ x
t, β, 0
x − y
F x
t, y, ω
y
ω
x
− ωy
.
3.7
Trang 6We set
H
t, x, x; y, y
ft, y, ω
y
Fx
t, y, ω
y
− φ x
t, β, 0
x − y
F x
t, y, ω
y
ω
x
− ωy
and observe that
f
t, x, ω
x
≥ Ht, x, x; y, y
,
f
t, x, ω
x
Ht, x, x; x, x
By the mean value theorem, we can find α ≤ c1 ≤ y and α ≤ c2 ≤ yc1, c2depend on y, y, resp., such that
f
t, y, ω
y
− ft, α t, αt f x t, c1, c2y − α t f xt, c1, c2ω
y
− αt 3.10
Letting
H1
t, x, x; y, y
ft, α t, αt f x t, c1, c2x − αt f xt, c1, c2ω
x
− αt,
3.11
we note that
f
t, y, ω
y
H1
t, y, y; y, y
,
f
t, α t, αt H1
t, α t, αt; y, y. 3.12 Let us define H as
H
⎧
⎨
⎩
H
t, x, x; y, y
, for x ≥ y,
H1
t, x, x; y, y
, for x ≤ y. 3.13
Clearly H is continuous and bounded on 0, 1×mint∈0,1αt, maxt∈0,1βt×R and satisfies
a Nagumo condition relative to α, β For every αt ≤ y ≤ βt and y ∈ R, we consider the
m-point BVP
−x H
t, x, x; y, y
, t ∈ 0, 1,
px 0 − qx0 m−2
i1 τix
ηi
, px 1 qx1 m−2
i1 σix
ηi
.
3.14
Trang 7Using3.9, 3.12 and 3.13, we have
H
t, α t, αt; y, y
H1
t, α t, αt; y, y
ft, α t, αt≥ −αt,
pα 0 − qα0 ≤m−2
i1 τiα
ηi
, pα 1 qα1 ≤m−2
i1 σiα
ηi
,
H
t, β t, βt; y, y
Ht, β t, βt; y, y
≤ ft, β t, βt≤ −βt,
pβ 0 − qβ0 ≥m−2
i1 τiβ
ηi
, pβ 1 qβ1 ≥m−2
i1 σiβ
ηi
.
3.15
Thus, α, β are lower and upper solutions of 3.14, respectively Since H satisfies a Nagumo
condition, there exists a constant M1 > max{α, β} depending on α, β and a Nagumo
function such that any solution x of 3.14 with αt ≤ xt ≤ βt satisfies |x| < M1on0, 1 Now, we choose α0 α and consider the problem
−x H
t, x, x; α0, α0
, t ∈ 0, 1,
px 0 − qx0 m−2
i1 τix
ηi
, px 1 qx1 m−2
i1 σix
ηi
.
3.16
UsingA1, 3.9, 3.12 and 3.13, we obtain
H
t, α0, α0; α0, α0
ft, α0, α0
≥ −α
0t,
pα00 − qα
00 ≤m−2
i1 τiα0
ηi
, pα01 qα
01 ≤m−2
i1 σiα0
ηi
,
H
t, β t, βt; α0, α0
Ht, β t, βt; α0, α0
≤ ft, β t, βt≤ −βt,
pβ 0 − qβ0 ≥m−2
i1 τiβ
ηi
, pβ 1 qβ1 ≥m−2
i1 σiβ
ηi
,
3.17
which imply that α0 and β are lower and upper solutions of 3.16 Hence by Theorems2.2
and2.3, there exists a unique solution α1of3.16 such that
α0 ≤ α1 ≤ βt, α
Trang 8Note that the uniqueness of the solution follows by Theorem 2.3 Using 3.9 and 3.13
together with the fact that α1is solution of3.16, we find that α1is a lower solution of3.2, that is,
−α
1 H
t, α1, α1; α0, α0
≤ ft, α1, ω
α1
, t ∈ 0, 1,
pα10 − qα
10 m−2
i1 τiα1
ηi
, pα11 qα
11 m−2
i1 σiα1
ηi
.
3.19
In a similar manner, it can be shown by usingA1, 3.12, 3.13, and 3.19 that α1and β are lower and upper solutions of the following m-point BVP
−x H
t, x, x; α1, α1
, t ∈ 0, 1,
px 0 − qx0 m−2
i1 τix
ηi
, px 1 qx1 m−2
i1 σix
ηi
.
3.20
Again, by Theorems2.2and2.3, there exists a unique solution α2of3.20 such that
α1t ≤ α2t ≤ βt, α
Continuing this process successively, we obtain a bounded monotone sequence {α n} of solutions satisfying
α1t ≤ α2t ≤ α3t ≤ · · · ≤ α n t ≤ βt, t ∈ 0, 1, 3.22
where α nis a solution of the problem
−x H
t, x, x; α n−1, αn−1
, t ∈ 0, 1,
px 0 − qx0 m−2
i1 τix
ηi
, px 1 qx1 m−2
i1 σix
ηi
,
3.23
and is given by
x t
1
0
G t, s H
s, αn, αn ; α n−1, αn−1
ds
m−2
i1 τix
ηi −t 2q p q p
p
2q p
m−2
i1
σix
ηi t
p
2q p
.
3.24
Since H is bounded on 0, 1 × mint∈0,1αt, maxt∈0,1βt × R × mint∈0,1αt,
maxt∈0,1βt × R, therefore it follows that the sequences {α j n }j 0, 1 are uniformly
bounded and equicontinuous on 0, 1 Hence, by Ascoli-Arzela theorem, there exist the subsequences and a function x ∈ C10, 1 such that α j n → x j uniformly on 0, 1 as
Trang 9n → ∞ Taking the limit n → ∞, we find that Ht, αn, αn ; α n−1, αn−1 → ft, x, ωx which consequently yields
x t
1
0
G t, sfs, x s, ωxsds
m−2
i1 τix
ηi −t 2q p q p
p
2q p
m−2
i1 σix
ηi t
p
2q p
.
3.25
This proves that x is a solution of 3.2
Theorem 3.2 Assume that A1 and A2 hold Further, one assumes that
A3 the function F ∈ C20, 1 × R × R satisfies y∂/∂xFt, x, y my2 ≤ 0 for |y| ≥
M, where m max{|Fxxt, x, y| : t, x, y ∈ 0, 1 × min t∈0,1αt, maxt∈0,1βt ×
−M, M}, and F f φ.
Then, the convergence of the sequence {α n } of approximate solutions (obtained in Theorem 3.1 ) is quadratic.
Proof Let us set en1 t xt − α n1 t ≥ 0 so that e n1satisfies the boundary conditions
pen1 0 − qe
n10 m−2
i1 τien1
ηi
, pen1 1 qe
n11 m−2
i1 σien1
ηi
In view of the assumption A3, for every t, x ∈ 0, 1 × min t∈0,1αt, maxt∈0,1βt, it
follows that
Fxt, x, M 2mM ≤ 0, Fxt, x, −M − 2mM ≥ 0. 3.27 Now, by Taylor’s theorem, we have
−e
n1 t F
t, x, x
− φt, x, 0
−f
t, αn, ω
αn
F x
t, α, ω
αn
α n1 − α n
− φ x
t, β, 0
α n1 − α n F x
t, αn, ω
αn
ω
αn1
− ωαn
F x
t, αn, ω
αn
x − α n1 F x
t, αn, ω
αn
x− ωαn1
1
2
x − α n2Fxx t, z1, z2 2x − α nx− ωαn
Fxxt, z1, z2
x− ωαn2
Fxxt, z1, z2
−φ t, x, 0 − φt, α n, 0 − φ x
t, β, 0
α n1 − α n
≤ F x
t, αn, ω
αn
x− ωαn1
M2
2
|x − α n| x− ωαn 2 ρ1x − α n2,
3.28
Trang 10where α n ≤ z1 ≤ x, ωα
n ≤ z2 ≤ x, α n ≤ ξ ≤ β, M2 max{|F xx |, |F xx |, |F xx|} on
0, 1 × min t∈0,1αt, maxt∈0,1βt × −M, M and ρ1 ρ max{φ xx t, x, 0 : t, x, 0 ∈
0, 1 × min t∈0,1αt, maxt∈0,1βt} with ρ > 1 satisfying β − αn ≤ ρx − α n on 0, 1 Also,
in view of3.13, we have
−e
n1 t ft, x, x
− H
t, αn1, αn1 ; α n, αn
≥ ft, x, x
− ft, αn1, ω
αn1
f x t, c3, c4e n1 f xt, c3, c4x− ωαn1
≥ −γe n1 f xt, c3, c4x− ωαn1
,
3.29
where α n1 ≤ c3 ≤ x, ωα
n1 ≤ c4 ≤ x and γ max{|f x t, x, y| : t, x, y ∈ 0, 1 ×
mint∈0,1αt, maxt∈0,1βt × −M, M}.
Now we show that ωαn1 t α
n1 t By the mean value theorem, for every y1 ∈
−M, M and ωα
n1 t ≤ c5≤ y1, we obtain
Fx
t, αn t, y1
F x
t, αn t, ωαn1 t F xxt, α n t, c5y1− ωαn1 t. 3.30
Let αn1 > M for some t ∈ 0, 1 Then ωαn1 t M and 3.30 becomes
Fx
t, αn t, y1
F xt, α n t, M F xxt, α n t, c5y1− M
In particular, taking y1 −M and using 3.27, we have
Fxt, α n t, −M ≤ F xt, α n t, M 2mM ≤ 0, 3.32
which contradicts that F xt, α n t, −M ≥ 2mM > 0 Similarly, letting α
n1 < −M for some
t ∈ 0, 1, we get a contradiction Thus, it follows that |αn1 t| ≤ M for every t ∈ 0, 1, which implies that ωαn1 t α
n1 t and consequently, 3.28 and 3.29 take the form
−e
n1 t ≤ F x
t, αn, ω
αn ten1 t M3e n2
where M3 ρ1 M2/2 and
−e
n1 t ≥ −γe n1 t f xt, c3, c4e
Now, by a comparison principle, we can obtain e n1 t ≤ rt on 0, 1, where rt is a solution
of the problem
−rt F x
t, αn, ω
αn trt M3e n2
1,
pr 0 − qr0 m−2
i1 τien1
ηi
, pr 1 qr1 m−2
i1 σien1
ηi
.
3.35
... ωαn1 t αn1 t By the mean value theorem, for every y1 ∈
−M, M and ωα
n1... t. 3.30
Let αn1 > M for some t ∈ 0, 1 Then ωαn1 t M and 3.30 becomes
Fx...
n1 < −M for some
t ∈ 0, 1, we get a contradiction Thus, it follows that |αn1 t| ≤ M for every t ∈ 0, 1, which implies