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Volume 2010, Article ID 626054, 18 pagesdoi:10.1155/2010/626054 Research Article Existence of Positive Solutions of Nonlinear Second-Order Periodic Boundary Value Problems Ruyun Ma, Chen

Trang 1

Volume 2010, Article ID 626054, 18 pages

doi:10.1155/2010/626054

Research Article

Existence of Positive Solutions of

Nonlinear Second-Order Periodic Boundary

Value Problems

Ruyun Ma, Chenghua Gao, and Ruipeng Chen

Department of Mathematics, Northwest Normal University, Lanzhou 730070, China

Correspondence should be addressed to Ruyun Ma,ruyun ma@126.com

Received 31 August 2010; Revised 30 October 2010; Accepted 8 November 2010

Academic Editor: Irena Rach ˚unkov´a

Copyrightq 2010 Ruyun Ma et al This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited

This paper is devoted to study the existence of periodic solutions of the second-order equation x 

f t, x, where f is a Carath´eodory function, by combining a new expression of Green’s function

together with Dancer’s global bifurcation theorem Our main results are sharp and improve the main results by Torres2003

1 Introduction

Let us say that the following linear problem:

x atx  0, t ∈ 0, T, 1.1

x 0  xT, x0  xT 1.2

is nonresonant when its unique solution is the trivial one It is well known that1.1, 1.2

is nonresonant then, provided that h is a L1-function, the Fredholm’s alternative theorem implies that the inhomogeneous problem

x atx  ht, t ∈ 0, T,

x 0  xT, x0  xT 1.3

Trang 2

always has a unique solution which, moreover, can be written as

x t 

T

0

where Gt, s is the Green’s function related to 1.1, 1.2

In recent years, the conditions,

H Problem 1.1, 1.2 is nonresonant and the corresponding Green’s function Gt, s is

positive on0, T × 0, T;

H− Problem 1.1, 1.2 is nonresonant and the corresponding Green’s function Gt, s is

negative on0, T × 0, T,

have become the assumptions in the searching for positive solutions of singular second-order equations and systems; see for instance Chu and Torres2, Chu et al 3, Franco and Torres

4, Jiang et al 5, and Torres 6 Moreover, the positiveness of Green’s function implies that an antimaximum principle holds, which is a fundamental tool in the development of the monotone iterative technique; see Cabada et al.7 and Torres and Zhang 8

The classical condition implyingH is an L p-criteria proved in Torres9 and based

on an antimaximum principle given in8 For the sake of completeness, let us recall the following result

For any 1≤ α ≤ ∞, let Kα be the best Sobolev constant in the inequality

C u2

α ≤  ˙u2

2, u ∈ H : H1

given explicitly bysee 10

K α  inf

u∈H\{0}

 ˙u2 2

u2

α

,

K α 

αT12/α

 2

2 α

1−2/α

Γ1/α

Γ1/2  1/α

2

, 1 ≤ α < ∞,

4

1.6

Throughout the paper, “a.e.” means “almost everywhere” Given a ∈ L10, T, we write a  0

if a ≥ 0 for a.e t ∈ 0, T and it is positive in a set of positive measure Similarly, a ≺ 0 if

−a  0.

Theorem A see 9, Corollary 2.3 Assume that a ∈ Lp 0, T for some 1 ≤ p ≤ ∞ with a  0

and moreover

a p < K

with 1/p  1/p 1 Then Condition (H) holds.

For the case that a≺ 0, Torres 9 proved the following

Trang 3

Theorem B see 9, Theorem 2.2 Assume that a ∈ Lp 0, T for some 1 ≤ p ≤ ∞ with a ≺ 0.

Then Condition (H) holds.

To study the existence and multiplicity of positive solutions of the related nonlinear problem

x atx  gt, x, t ∈ 0, T,

x 0  xT, x0  xT, 1.8

it is necessary to find the explicit expression of Gt, s.

Let ϕ be the unique solution of the initial value problem

ϕ atϕ  0, ϕ0  1, ϕ0  0, 1.9

and let ψ be the unique solution of the initial value problem

ψ atψ  0, ψ0  0, ψ0  1. 1.10 Let

D :  ϕT  ψT − 2. 1.11

Atici and Guseinov 11 showed that the Green’s function Gt, s of 1.1, 1.2 can be explicitly given as

G t, s  ψ T

D ϕ tϕs − ϕT

D ψ tψs



ψT − 1

D ϕ tψs − ϕ T − 1

D ϕ sψt, 0 ≤ s ≤ t ≤ T,

ψT − 1

D ϕ sψt − ϕ T − 1

D ϕ tψs, 0 ≤ t ≤ s ≤ T.

1.12

Torres9 also studied the Green’s function Gt, s of 1.1, 1.2 Let u be the unique solution

of the initial value problem

u atu  0, u0  0, u0  1, 1.13

and let v be the unique solution of the initial value problem

v atv  0, vT  0, vT  −1. 1.14 Let

α : 1

2 v0 − uT . 1.15

Trang 4

Then the Green’s function K of1.1, 1.2 given in 9 is in the form

K t, s  αut  vt − 1

v0

v tus, 0 ≤ s ≤ t ≤ T,

v sut, 0 ≤ t ≤ s ≤ T.

1.16

However, there is a mistake in1.16

It is the purpose of this paper to point out that the Green’s function in1.16, which

is induced by the two linearly independent solutions u and v of1.13 and 1.14, should be corrected to the form

G t, s  α us  vs

v0 ut  vt −

1

v0

v tus, 0 ≤ s ≤ t ≤ T,

v sut, 0 ≤ t ≤ s ≤ T.

1.17

This will be done in Section 2 Finally in Section 3, we study the existence of one-sign solutions of the nonlinear problem

x ft, x, t ∈ 0, T,

x 0  xT, x0  xT. 1.18

The proofs of the main results are based on the properties of G and the Dancer’s global

bifurcation theorem; see12

2 Preliminaries

Denote

Λ−: {a ∈ L p 0, T : a ≺ 0},

Λ : a ∈ L p 0, T : a  0, a p < K

2p∗ for some 1≤ p ≤ ∞ . 2.1

Recall that u is a unique solution of IVP1.13 and v is a unique solution of IVP 1.14

Lemma 2.1 Let a ∈ L p 0, T Then

Proof Since the Wronskian W u, vt is constant, it follows that

−uT  u T vT

uT vT

u t vt

ut vt

u 0 v0

u0 v0 v 0. 2.3 The following result follows from the classical theory of Green’s function

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Lemma 2.2 Let Gt, s be the Green’s function of 1.1, 1.2 Then

i G : 0, T × 0, T → R is continuous;

ii for a given s ∈ 0, T, G0, s  GT, s;

iii for a given s ∈ 0, T, G t 0, s  G t T, s;

iv for a given s ∈ 0, T, Gt, s as a function of t is a solution of 1.1 in the intervals

0, s and s, T.

Lemma 2.3 Let a ∈ Λ∪ Λ− Then the Green’s function G t, s induced by u and v is explicitly

given by1.17, that is,

G t, s  u s  vs

v 02  v0 − uT ut  vt −

1

v0

v tus, 0 ≤ s ≤ t ≤ T,

v sut, 0 ≤ t ≤ s ≤ T. 2.4

Remark 2.4 Notice that it is not necessary to assume that

In fact, if a∈ Λ, then from13, Remark in Page 3328, we have

λ1a ≥ π

T

2

1− a p

K

2p



> 0, 2.6

where λ1a is the first eigenvalue of the antiperiodic boundary value problem

x λ  atx  0, x0  −xT, x0  −xT. 2.7

Now, by the same method to prove8, Lemma 2.1, we may get that the solution v of the IVP

1.14 has at most one zero in 0, T Since vT  0, we must have that v0 / 0.

If a∈ Λ−, we claim that vt > 0 for t ∈ 0, T Suppose on the contrary that there exists

τ ∈ 0, T such that

v τ  0, vt > 0, for t ∈ τ, T. 2.8 Then

vt  −atvt ≥ 0, t ∈ τ, T, 2.9 which means that

v t ≥ T − t, t ∈ τ, T. 2.10

In particular, vτ ≥ T − τ > 0, t ∈ τ, T This is a contradiction Therefore, δ  T, and accordingly, v0 ≥ 0.

Trang 6

Proof of Lemma 2.3 In the proof of9, Proposition 2.0.1, the Green function was assumed to

have the form

K t, s  αut  βvt − 1

v0

v tus, 0 ≤ s ≤ t ≤ T,

v sut, 0 ≤ t ≤ s ≤ T. 2.11 However, for above Kt, s, it is impossible to find constants α and β, such that

K t 0, s  K t T, s, s ∈ 0, T. 2.12

So, we have to assume that the Green’s function is of the form

G t, s  αsut  βsvt − 1

v0

v tus, 0 ≤ s ≤ t ≤ T,

v sut, 0 ≤ t ≤ s ≤ T. 2.13

ByLemma 2.2ii, we have that G0, s  GT, s for s ∈ 0, T Thus

β sv0  G0, s  GT, s  αsuT, s ∈ 0, T, 2.14 which together with2.2 imply that

β s  αs, s ∈ 0, T. 2.15 From2.13 and 2.15, we have

G t t, s  αsut  vt− 1

v0

vtus, 0 ≤ s < t ≤ T,

v sut, 0 ≤ t < s ≤ T, 2.16 and, for s ∈ 0, T,

G t 0, s  αs1 v0− v s

v0, G t T, s  αsuT − 1 u s

v0. 2.17 Applying this andLemma 2.2iii, it follows that

α s  2  v u0 − u s  vsTv0 2.18

Denote

M : max

0≤t,s≤TG t, s, m : min

0≤t,s≤TG t, s. 2.19

Trang 7

Finally, we state a result concerning the global structure of the set of positive solutions

of parameterized nonlinear operator equations, which is essentially a consequence of Dancer

12, Theorem 2

Suppose thatE is a real Banach space with norm · Let K be a cone in E A nonlinear mapping A : 0, ∞ × K → E is said to be positive if A0, ∞ × K ⊆ K It is said to be

K-completely continuous if A is continuous and maps bounded subsets of 0, ∞×K to precompact

subset ofE Finally, a positive linear operator V on E is said to be a linear minorant for A if

A λ, u ≥ λV x for λ, u ∈ 0, ∞ × K If B is a continuous linear operator on E, denote rB the spectrum radius of B Define

cK B  {λ ∈ 0, ∞ : ∃ x ∈ K with x  1, x  λBx}. 2.20

Lemma 2.5 see 14, Lemma 2.1 Assume that

i K has a nonempty interior and E  K − K;

ii A : 0, ∞ × K → E is K-completely continuous and positive, Aλ, 0  0 for λ ∈ R,

A 0, u  0 for u ∈ K, and

A λ, u  λBu  Fλ, u, 2.21

where B : E → E is a strongly positive linear compact operator on E with rB > 0, and F :

0, ∞ × K → E satisfies Fλ, u  ◦u as u → 0 locally uniformly in λ.

Then there exists an unbounded connected subsetC of

DK A  {λ, u ∈ 0, ∞ × K : u  Aλ, u, u / 0} ∪ r B−1, 0

2.22

such thatrB−1, 0 ∈ C

Moreover, if A has a linear minorant V , and there exists a

such thaty  1 and μV y ≥ y, then C can be chosen in

DK A ∩ 0, μ

3 Main Results

In this section, we consider the existence of positive solutions of nonlinear periodic boundary value problem

x ft, x, t ∈ 0, T,

x 0  xT, x0  xT, 3.1 where f : 0, 1 × R → R is satisfying Carath´eodory conditions.

Trang 8

3.1. a ∈ Λ

By Theorem A, a∈ Λimplies Gt, s > 0 on 0, T × 0, T, and subsequently M > m > 0 Let

us define

P:



x ∈ C0, T | xt ≥ 0 on 0, T, min

t x t ≥ m

M x



. 3.2

Lemma 3.1 see 9, Theorem 3.2 Let us assume that there exist a ∈ Λand 0 < r < R such that

f t, x  atx ≥ 0, ∀x ∈



m

M r,

M

m R



, a.e t ∈ 0, T. 3.3

Then3.1 has a positive solution provided one of the following conditions holds

i

f t, x  atx ≥ M

Tm2x, ∀x ∈  m

M r, r



, a.e t ∈ 0, T,

f t, x  atx ≤ 1

TM x, ∀x ∈



R, M

m R



, a.e t ∈ 0, T;

3.4

ii

f t, x  atx ≤ 1

TM x, ∀x ∈  m

M r, r



, a.e t ∈ 0, T,

f t, x  atx ≥ M

Tm2x, ∀x ∈



R, M

m R



, a.e t ∈ 0, T.

3.5

Let

γt : f t, m/Mr  atm/Mr m/Mr , Γ∗t : f t, M/mR  atM/mR M/mR , 3.6



f t, x 

Γ∗tx, xM

m R,

f t, x  atx, m

M r ≤ x ≤ M

m R,

γtx, 0≤ x ≤ m

M r.

3.7

Let

γ t : min



f t, s  ats

s | s ∈ mr

M , r



, Γt : max



f t, s  ats

s | s ∈



R, MR m



,

γ t : max

f t, s  ats

s | s ∈ mr

M , r



, Γt : min

f t, s  ats

s | s ∈



R, MR m



.

3.8

Trang 9

Theorem 3.2 Assume that

(A1) There exist a∈ Λ∩ C0, T and 0 < r < R such that

f t, x  atx > 0, ∀x ∈



m

M r,

M

m R



, a.e t ∈ 0, T. 3.9

Then3.1 has a positive solution provided one of the following conditions holds

i μ0γ < 1 < μ0Γ;

ii μ0Γ < 1 < μ0γ.

Here μ0β denotes the principal eigenvalue of

x atx  μβtx, t ∈ 0, T,

x 0  xT, x0  xT. P

Remark 3.3 Let a ∈ Λ and β  0 Then μ0β > 0 Moreover, μ0β is simple and the corresponding eigenfunction ψ0∈ int P

In fact,3.10 is equivalent to

x t  μ

T

0

G t, sβsxsds : μAxt. 3.10

Since G > 0 on 0, T × 0, T, it follows that AP ⊂ int P From Krein-Rutman theorem, see15, Theorem 19.3, we may get the desired results

Remark 3.4. Theorem 3.2is a partial generalization ofLemma 3.1 It is enough to prove that the conditioni on f inTheorem 3.2holds when the conditioni inLemma 3.1holds First, we claim that

i μ0M/Tm2 < 1;

ii μ01/TM > 1.

To this end, let us denote by λ0the principal eigenvalue of the linear problem

u atu  λu, u0  uT, u0  uT, 3.11

and ϕ the corresponding eigenfunction with ϕ∈ int P Then applying the facts that G ≥ m and G / ≡ m,

λ0  μ0



M

Tm2



· M

ϕ

≥ ϕt

 λ0

T

0

G t, sϕsds

> λ0m m

M Tϕ∞,

3.13

Trang 10

which together with3.12, imply that

μ0



M

Tm2



By the same method, with obvious changes, we may show that μ01/TM > 1.

Now, we prove μ0γ < 1 < μ0Γ

Define the operators S1, S2: C0, T → C0, T by

S1u t  M

Tm2

T

0

G t, susds,

S2u t 

T

0

G t, sγsusds,

3.15

respectively

Since γt ≥ M/Tm2, by15, Theorem 19.3, we get rS2 ≥ rS1, where rS i , i  1, 2,

is the spectrum radius of S i Thus, μ0γ  1/rS2 ≤ 1/rS2  μ0M/Tm2 < 1.

Similarly, μ0Γ ≥ μ01/TM > 1.

Remark 3.5 The conditions μ0γ < 1 < μ0Γ and μ0Γ < 1 < μ0γ are optimal.

Let , 1, 2be positive constants with 1< 2, and

1

8 1≤ at ≤ 18 2. 3.16 Let us consider the problem

u atu  at  u, u0  uT, u0  uT. 3.17

Obviously, for f t, s  ats  at  s, we have that

γ t  Γt  at  ,

μ0

γ

 μ0



Γ μ0at  . 3.18 For j  1, 2, the principal eigenvalue μ01/8  j   of

x

 1

8 j



x  μ ·

 1

8 j 



· x, t ∈ 0, T,

x 0  xT, x0  xT

3.19

Trang 11

μ0

 1

8 j 



 1 8 j

8

j   1. 3.20 Applying the fact that

μ0

 1

8 1



≤ μ0



γ

 μ0



Γ≤ μ0

 1

8 2



though μ0Γ is a little bit smaller than 1, the existence of positive solutions of 3.17 will not

be guaranteed in this case

Proof of Theorem 3.2 We only provei ii can be proved by a similar method

To study the existence of positive solutions of3.1, let us consider the parameterized problem

x atx  μ  f t, x, t ∈ 0, T,

x 0  xT, x0  xT. 3.22

Notice that



f t, x  γtx  ξt, x, ft, s  Γts  ζt, s, 3.23 with

lim

x→ 0

ξ t, x

x  0, lim

s→ ∞

ζ t, s

s  0, a.e t ∈ 0, T. 3.24 Thus,3.22 can be rewritten as

x atx  μγtx  μξt, x, t ∈ 0, T,

x 0  xT, x0  xT. 3.25

Denote

E x ∈ C10, T | x0  xT, x0  xT 3.26 equipped with the norm ·   max{x, x∞} Let

Φ: x ∈ C10, T | xt > 0 on 0, T, x0  xT, x0  xT . 3.27

Trang 12

FromLemma 2.5, there exists a continuum Cof solutions of3.25 joining μ0, 0

to infinity inΦ Moreover, C\ {μ0, 0} ⊂ Φ

Now, we divide the proof into two steps

Step 1 We show that C joining0, 0 to μ0Γ∗, ∞ in Φ So, C ∩ {1} × E / ∅, and

accordingly,3.25 has at least one positive solution u.

Suppose thatη k , y k  ∈ Cwith

We firstly show that{η k} is bounded

In fact, it follows from the definition of f and Condition3.9 that



f t, s

s ≥ et, a.e t ∈ 0, T, s ∈ 0, ∞ 3.29

for some e ∈ L10, T with et > 0 a.e on 0, T.

We claim that y khas to change its sign in0, T if η k → ∞

In fact,

y kt  aty k  η k



f

t, y k

y k

yields that yk t > 0 as k is large enough However, this contradicts the boundary condition

yk 0  y

k T.

Therefore,{η k} is bounded

Now,{η k , y k } k ∈ N satisfy

y k aty k  η kΓ∗ty k  η k ζ

t, y k , t ∈ 0, T,

y k 0  y k T, y

k 0  y

Let

v k: y k

Then

vk  atv k  η kΓ∗tv k  η k

ζ

t, y k

y k v k , t ∈ 0, T,

v k 0  v k T, vk 0  v

k T.

3.33

...

3 Main Results

In this section, we consider the existence of positive solutions of nonlinear periodic boundary value problem

x ft, x, t ∈ 0,... result concerning the global structure of the set of positive solutions< /p>

of parameterized nonlinear operator equations, which is essentially a consequence of Dancer

12, Theorem 2

Suppose... μ0Γ is a little bit smaller than 1, the existence of positive solutions of 3.17 will not

be guaranteed in this case

Proof of Theorem 3.2 We only provei ii can

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