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Volume 2011, Article ID 913403, 6 pagesdoi:10.1155/2011/913403 Research Article Notes on Interpolation Inequalities Jiu-Gang Dong1 and Ti-Jun Xiao2 1 Department of Mathematics, Universit

Trang 1

Volume 2011, Article ID 913403, 6 pages

doi:10.1155/2011/913403

Research Article

Notes on Interpolation Inequalities

Jiu-Gang Dong1 and Ti-Jun Xiao2

1 Department of Mathematics, University of Science and Technology of China, Hefei 230026, China

2 Shanghai Key Laboratory for Contemporary Applied Mathematics, School of Mathematical Sciences, Fudan University, Shanghai 200433, China

Correspondence should be addressed to Ti-Jun Xiao,xiaotj@ustc.edu.cn

Received 3 October 2010; Accepted 16 November 2010

Academic Editor: Toka Diagana

Copyrightq 2011 J.-G Dong and T.-J Xiao This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited

An easy proof of the John-Nirenberg inequality is provided by merely using the Calder ´on-Zygmund decomposition Moreover, an interpolation inequality is presented with the help of the John-Nirenberg inequality

1 Introduction

It is well known that various interpolation inequalities play an important role in the study of operational equations, partial differential equations, and variation problems see, e.g., 1 6

So, it is an issue worthy of deep investigation

Let Q0be either R n or a fixed cube in R n For f ∈ L1

locQ0, write

f

BMO: sup

Q⊂Q0

1

|Q|



Q

where the supremum is taken over all cubes Q ⊂ Q0and fQ: 1/|Q|Q fdx.

Recall that BMOQ0 is the set consisting of all locally integrable functions on Q0

such thatfBMO < ∞, which is a Banach space endowed with the norm  · BMO It is clear

that any bounded function on Q0is in BMOQ0, but the converse is not true On the other

hand, the BMO space is regarded as a natural substitute for L∞in many studies One of the important features of the space is the John-Nirenberg inequality There are several versions

of its proof; see, for example,2,7 9 Stimulated by these works, we give, in this paper, an easy proof of the John-Nirenberg inequality by using the Calder ´on-Zygmund decomposition

only Moreover, with the help of this inequality, an interpolation inequality is showed for L p

and BMO norms

Trang 2

2 Results and Proofs

Lemma 2.1 John-Nirenberg inequality If f ∈ BMOQ0, then there exist positive constants c1,

c2such that, for each cube Q ⊂ Q0,

x ∈ Q :f x − fQ> t  ≤ c1exp



c2

f

BMO

t

|Q|, t > 0. 2.1

Proof Without loss of generality, we can and do assume that fBMO 1

For each t > 0, let Ft denote the least number for which we have

x ∈ Q :f x − fQ> t  ≤ Ft|Q|, 2.2

for any cube Q ⊂ Q0 It is easy to see that Ft ≤ 1t > 0 and Ft is decreasing.

Fix a cube Q ⊂ Q0 Applying the Calder ´on-Zygmund decompositioncf., e.g., 2,9

to|fx − fQ | on Q, with 2 n as the separating number, we get a sequence of disjoint cubes

{Qj} and E such that

Q 

j

Q j

f x − fQ ≤ 2 n , for a.e x ∈ E, 2.4

2n < Q1j



Q j

Using2.5, we have



j

Q j< 1

From2.3, 2.4, and 2.6, we deduce that for t > 4 n,

x ∈ Q :f x − fQ> t 

 j



x ∈ Q j:f x − fQ> t





≤

j

x ∈ Q j :f x − fQ> t − 4 n



j

Q j 1

Q jx ∈ Q j:f x − fQ> t − 4 n

≤ 1

2n F t − 4 n |Q|.

2.7

Trang 3

This yields that

F t ≤ 1

2n F t − 4 n , t > 4 n 2.8

Let γ  t − 14 −n  t > 4 n , μ  1  γ4 n Then 0 < μ ≤ t By iterating, we get

F t ≤ Fμ

 F1 γ4 n

≤ 2−nγ ≤ 2−nt−14 −n−1

 2n14 −nexp

−log 2

n4 −n t

, t > 4 n

2.9

Thus, letting

c1  2n14 −n, c2log 2

n4 −n 2.10 gives that

F t ≤ c1e −c2t , t > 0, 2.11 since

F t ≤ 1 ≤ c1e −c2t , 0 < t ≤ 4 n 2.12 This completes the proof

Remark 2.2. 1 As we have seen, the recursive estimation 2.8 justifies the desired

exponential decay of Ft.

2 There exists a gap in the proof of the John-Nirenberg inequality given in 2

Actually, for a decreasing function Gt : 0, ∞ → 0, 1, the following estimate:

G2 · 2n α ≤ 1

α G2n α , α > 1 2.13

does not generally imply such a property, that is, the existence of constants c1, c2 > 0 such

that

G t ≤ c1e −c2t , t > 0. 2.14

We present the following function as a counter example:

G t  exp



 log5 3

−1 log2t  1

Trang 4

In fact, it is easy to see that there are no constants c1, c2 > 0 such that 2.14 holds On the other hand, we have

G t

G t 



−log5 3

−1

2logt  1

t  1

Integrating both sides of the above equation from 2n α to 2 · 2 n α, we obtain

G2 · 2n α  exp



−2

 log5 3

−12·2n α

2n α

logt  1

t  1 dt

G2n α

 exp



 log5 3

−1 log22 · 2n α  1 − log22n α  1 G2n α

 exp



−log5 3

−1 log2 · 2n α  12n α  1 · log



2· 2n α  1

2n α  1



G2n α

≤ exp− log2 · 2n α  12n α  1G2n α

 2 · 2n 1

α  12n α  1G2n α

≤ 1

α G2n α ,

2.17

where the fact that

2· 2n α  1

2n α  1 >

5

3 α > 1 2.18

is used to get the first inequality above This means that

G2 · 2n α ≤ 1

α G2n α , α > 1. 2.19

Next, we make use of the John-Nirenberg inequality to obtain an interpolation

inequality for L pand BMO norms

Theorem 2.3 Suppose that 1 ≤ p < r < ∞ and f ∈ L p Q0 ∩ BMOQ0 Then we have

f

L r ≤ constfp/r

L p f1−p/r

Trang 5

Proof If fBMO  0, the proof is trivial; so we assume that fBMO/ 0 In view of the Calder ´on-Zygmund decomposition theorem, there exists a sequence of disjoint cubes{Qj}

and E such that

Q0

j

Q j

fxp≤fp

BMO for a.e x ∈ E, 2.22

fp

BMO< Q1j



Q j

f xp

dx ≤ 2 nfp

BMO. 2.23

From2.23, we get



j

Q j< 1

fp

BMO



Q0

fxp

dx 

fp

L p

fp

BMO

,

f

Q j  Q1j



Q j

f xdx ≤ 1

Q j



Q j

fxp

dx

1/p

≤ 2n/pf

BMO.

2.24

Using2.21–2.24, together withLemma 2.1, yields that, for λ > 2 n/p fBMO,

x ∈ Q0:f x> λ 

 j



x ∈ Q j:f x> λ





≤

j



x ∈ Q j: fx − fQ

j



 > λ −fQ

j





≤

j

Q j 1

Q jx ∈ Q j:fx − fQ

j



 > λ − 2 n/pf

BMO

≤

j

c1exp



c2

f

BMO



λ − 2 n/pf

BMO

 Qj

≤ c1exp



c2

f

BMO



λ − 2 n/pf

BMO

 fp

L p

fp

BMO

.

2.25

Trang 6

From2.25, we obtain

fr

L r  r

∞

0

λ r−1x ∈ Q0:f x> λ

 r

2n/p fBMO 0

λ r−1x ∈ Q0:f x> λ

 r

∞

2n/pfBMOλ

r−1x ∈ Q0:f x> λ

≤ r

2n/p fBMO 0

λ r−1fp

L p

λ p dλ

 r

∞

2n/pfBMOλ

r−1 c1exp



c2

f

BMO



λ − 2 n/pf

BMO

 ffp

L p

fp

BMO

 r

r − p2

n/pr−pfr−p

BMOfp

L prc1

c2

2n/pr−1fr−p

BMOfp

L p

≤ constfr−p

BMOfp

L p

2.26

Hence, the proof is complete

Acknowledgments

The authors would like to thank the referees for helpful comments and suggestions The work was supported partly by the NSF of China11071042 and the Research Fund for Shanghai Key Laboratory for Contemporary Applied Mathematics08DZ2271900

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