Volume 2010, Article ID 476913, 8 pagesdoi:10.1155/2010/476913 Research Article Viscosity Approximation to Common Fixed Points of Families of Nonexpansive Mappings with Weakly Contractiv
Trang 1Volume 2010, Article ID 476913, 8 pages
doi:10.1155/2010/476913
Research Article
Viscosity Approximation to Common Fixed
Points of Families of Nonexpansive Mappings with Weakly Contractive Mappings
A Razani1, 2 and S Homaeipour1
1 Department of Mathematics, Faculty of Science, Imam Khomeini International University,
P.O Box 34149-16818, Qazvin, Iran
2 School of Mathematics, Institute for Research in Fundamental Sciences,
P.O Box 19395-5746, Tehran, Iran
Correspondence should be addressed to S Homaeipour,s homaeipour@ikiu.ac.ir
Received 5 June 2010; Accepted 26 July 2010
Academic Editor: Brailey Sims
Copyrightq 2010 A Razani and S Homaeipour This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited
Let X be a reflexive Banach space which has a weakly sequentially continuous duality mapping In this paper, we consider the following viscosity approximation sequence x n λ n fx n 1−λ n T n x n,
where λ n ∈ 0, 1, {T n } is a uniformly asymptotically regular sequence, and f is a weakly contractive
mapping Strong convergence of the sequence{x n} is proved
1 Introduction
Let C be a nonempty closed convex subset of a Banach space X Recall that a self-mapping
T : C → C is nonexpansive if
T x − T
Rhoades2 showed that the result of 1 is also valid in the complete metric spaces as follows
Definition 1.1 Let X, d be a complete metric space A mapping T : X → X is called weakly
contractive if
d
Tx, Ty
≤ dx, y
− ψd
x, y
Trang 2where x, y ∈ X and ψ : 0, ∞ → 0, ∞ is a continuous and nondecreasing function such that ψt 0 if and only if t 0 and lim t → ∞ ψt ∞.
Theorem 1.2 Let T : X → X be a weakly contractive mapping, where X, d is a complete metric
space, then T has a unique fixed point.
in a reflexive Banach space X, as follows.
Theorem 1.3 see 3, Theorem 3.1 Let X be a reflexive Banach space which admits a weakly
sequentially continuous duality mapping J from X to X∗ Suppose that C is a nonempty closed convex subset of X and {T n }, n ∈ {1, 2, }, is a uniformly asymptotically regular sequence of nonexpansive
mappings from C into itself such that
F :
∞
n1
where Fix T n : {x ∈ C : x T n x}, n ∈ {1, 2, } Let {x n } be defined by 1.3 and λ n ∈ 0, 1,
such that lim n → ∞ λ n 0 Then as n → ∞, the sequence {x n } converges strongly to p, such that p is
the unique solution, in F, to the variational inequality:
f
p
− p, Jy − p
proved, where f is a weakly contractive mapping.
2 Preliminaries
A Banach space X is called strictly convex if
x y 1, x / y implies x y
A Banach space X is called uniformly convex, if for all ε ∈ 0, 2, there exist δ ε > 0 such that
x y 1 with x − y ≥ ε implies that x y
2 < 1 − δ ε 2.2
Trang 31 A uniformly convex Banach space X is reflexive and strictly convex.
2 If C is a nonempty convex subset of a strictly convex Banach space X and T : C → C
is a nonexpansive mapping, then the fixed point set FT of T is a closed convex subset of C.
By a gauge function we mean a continuous strictly increasing function ϕ defined on 0, ∞
J ϕ x x∗∈ X∗:x, x∗ x x∗ , x∗ ϕ x , for each x ∈ X, 2.3
which is the normalized duality mapping
Proposition 2.1 see 5 (1) J I if and only if X is a Hilbert space.
(2) J is surjective if and only if X is reflexive.
(3) J ϕ λx sign λϕ|λ| · x / x Jx for all x ∈ X \ {0}, λ ∈ R; in particular J−x
−Jx, for all x ∈ X.
We say that a Banach space X has a weakly sequentially continuous duality mapping
lim sup
n → ∞ x n − x < lim sup
n → ∞
satisfies Opial’s condition A space with a weakly sequentially continuous duality mapping
is easily seen to satisfy Opial’s condition8
Lemma 2.2 see 9, Lemma 4 Let X be a Banach space satisfying Opial’s condition and C a
nonempty, closed, and convex subset of X Suppose that T : C → C is a nonexpansive mapping Then
I − T is demiclosed at zero, that is, if {x n } is a sequence in C which converges weakly to x and if the
sequence x n − Tx n converges strongly to zero, then x − Tx 0.
Definition 2.3see 3 Let C be a nonempty closed convex subset of a Banach space X and
asymptotically regular on C, if for all m ∈ {1, 2, } and any bounded subset K of C we have
lim
n → ∞sup
x∈K
3 Main Result
Trang 4Theorem 3.1 Let X be a reflexive Banach space which admits a weakly sequentially continuous
duality mapping J from X to X∗ Suppose that C is a nonempty closed convex subset of X and T m :
C → C, m ∈ {1, 2, }, is a uniformly asymptotically regular sequence of nonexpansive mappings such that
F :
∞
m1
Let f : C → C be a weakly contractive mapping Suppose that {t m } is a sequence of positive numbers
in 0, 1 satisfying lim m → ∞ t m 0 Assume that {x m } is defined by the following iterative process:
Then the above sequence {x m } converges strongly to a common fixed point p of {T m }, m ∈ {1, 2, }
such that p is the unique solution, in F, to the variational inequality
f
p
− p, Jy − p
Proof.
Step 1 We prove the uniqueness of the solution to the variational inequality3.3 Suppose
that p, q ∈ F are distinct solutions to 3.3 Then
f
p
− p, Jq − p
≤ 0,
f
q
− q, Jp − q
By adding up the above relations, we get
0≥p − f
p
−q − f
q
, J
p − q
≥ p − q, Jp − q
−f
p
− fq
, J
p − q
≥p − q2−f
p
− fqJ
p − q
≥p − q2−p − q2 ψp − qp − q.
3.5
Trang 5Step 2 We show that the sequence {x m } is bounded Let q ∈ F; from 3.2 we get then that
x m − q2t m
f x m − q 1 − t mT m x m − q, J
x m − q
t m
f x m − fq
f
q
− q, J
x m − q
1 − t mT m x m − T m q, J
x m − q
≤ t mf x m − f
qJ
x m − q t m
f
q
− q, Jx m − q
1 − t mT m x m − T m qJ
x m − q
≤ t m x m − q − ψx m − qx m − q fq − q,Jx m − q
1 − t mT m x m − T m qJ
x m − q
≤ t m
x
m − q2− ψx m − qx m − q fq − q,Jx m − q
1 − t mx m − q2
≤x m − q2− t mx m − qψx m − q t mf
q
− qx m − q.
3.6
Thus
or
Step 3 We prove that lim m → ∞ x m − T n x m 0, for all n ∈ {1, 2, } Since the sequence {x m}
is bounded, so{fx m } and {T m x m} are bounded Hence limm → ∞ t m T m x m − fx m 0, thus limm → ∞ x m − T m x m 0 Let K be a bounded subset of C which contains {x m} Since the
lim
m → ∞ T n T m x m − T m x m ≤ lim
m → ∞sup
x∈K
Let m → ∞, then
x m − T n x m ≤ x m − T m x m T m x m − T n T m x m T n T m x m − T n x m
Hence limm → ∞ x m − T n x m 0, for all n ∈ {1, 2, }.
Trang 6Step 4 We show that the sequence {x m } is sequentially compact Since X is reflexive and {x m}
to q ∈ C as k → ∞ Since lim k → ∞ x m k − T n x m k 0 for all n ∈ {1, 2, }, byLemma 2.2, we
have q T n q for all n ∈ {1, 2, } Thus q ∈ F.
Step 2implies that
x m
k − q2≤ t m k x m k − q − ψx m k − qx m
k − q fq − q,Jx m k − q
1 − t m kx m
k − q2
.
3.11
Hence
t m kx m
k − qψx m
k − q ≤ t m k
f
q
lim sup
k → ∞
x m
k − qψx m
k → ∞
f
q
Step 5 We now prove that q ∈ F is a solution to the variational inequality 3.3 Suppose that
y ∈ F, then
x m − y2 t m
f x m − x m
x m − y, J
x m − y
1 − t mT m x m − T m y, J
x m − y
≤ t m
f x m − x m
, J
x m − yx m − y2
.
3.14
Hence
f x m − x m
, J
y − x m
x m
k − fx m k−q − f
x m
k − fx m k, J
x m k − y−q − f
q
, J
q − y
x m
k − fx m k−q − f
q
, J
x m k − yq − f
q
, J
x m k − y− Jq − y
≤x m k − fx m k
−q − f
qx m k − y
q − f
q
, J
x m k − y− Jq − y −→ 0,
3.16
Trang 7as k → ∞ Hence
f
q
− q, Jy − q
lim
k → ∞
f x m k − x m k , J
y − x m k
p as m → ∞ The proof is completed.
Corollary 3.2 Let X be a real uniformly convex Banach space which admits a weakly sequentially
continuous duality mapping J from X to X∗and C a nonempty closed convex subset of X Suppose that T : C → C is a nonexpansive mapping, FT / ∅ and f : C → C is a weakly contractive
mapping Let {z m } be defined by
z m t m f z m 1 − t m 1
m 1Σm j0 T j z m , m ≥ 0, 3.18
where t m ∈ 0, 1 and lim m → ∞ t m 0 Then as m → ∞, {z m } converges strongly to a fixed point p
of T, where p is the unique solution in FT to the following variational inequality:
f
p
− p, ju − p
Acknowledgment
A Razani would like to thank the School of Mathematics of the Institute for Research in
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