1. Trang chủ
  2. » Khoa Học Tự Nhiên

Hindawi Publishing Corporation Fixed Point Theory and Applications Volume 2010, Article ID 296759, ppt

16 158 0

Đang tải... (xem toàn văn)

Tài liệu hạn chế xem trước, để xem đầy đủ mời bạn chọn Tải xuống

THÔNG TIN TÀI LIỆU

Thông tin cơ bản

Tiêu đề Strong Convergence Theorem for Equilibrium Problems and Fixed Points of a Nonspreading Mapping in Hilbert Spaces
Tác giả Somyot Plubtieng, Sukanya Chornphrom
Trường học Naresuan University
Chuyên ngành Mathematics
Thể loại Research article
Năm xuất bản 2010
Thành phố Phitsanulok
Định dạng
Số trang 16
Dung lượng 528,94 KB

Các công cụ chuyển đổi và chỉnh sửa cho tài liệu này

Nội dung

Volume 2010, Article ID 296759, 16 pagesdoi:10.1155/2010/296759 Research Article Strong Convergence Theorem for Equilibrium Problems and Fixed Points of a Nonspreading Mapping in Hilbert

Trang 1

Volume 2010, Article ID 296759, 16 pages

doi:10.1155/2010/296759

Research Article

Strong Convergence Theorem for Equilibrium

Problems and Fixed Points of a Nonspreading

Mapping in Hilbert Spaces

Somyot Plubtieng and Sukanya Chornphrom

Department of Mathematics, Faculty of Science, Naresuan University, Phitsanulok 65000, Thailand

Correspondence should be addressed to Somyot Plubtieng,somyotp@nu.ac.th

Received 30 June 2010; Revised 10 October 2010; Accepted 13 December 2010

Academic Editor: Brailey Sims

Copyrightq 2010 S Plubtieng and S Chornphrom This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited

We introduce an iterative method for finding a common element of the set of solutions of equilibrium problems and the set of fixed points of a nonspreading mapping in a Hilbert space Then, we prove a strong convergence theorem which is connected with the work of S Takahashi and W Takahashi2007 and Iemoto and Takahashi 2009

1 Introduction

Let H be a real Hilbert space with inner product ·, · and norm  · , respectively, and let C

be a closed convex subset of H Let F : C × C → Êbe bifunction, whereÊis the set of real

numbers The equilibrium problem for F : C × C → Êis to find x ∈ C such that

F

x, y

The set of solution of1.1 is denoted by EPF Given a mapping A : C → H, let

Fx, y  Ax, y − x for all x, y ∈ C Then, z ∈ EPF if and only if Az, y − z ≥ 0 for all

y ∈ C, that is, z is a solution of the variational inequality Numerous problems in physics,

optimization, and economics reduce to find a solution of1.1; see, for example, 1 9 and the references therein

A mapping T of C into itself is said to be nonexpansive if Tx − Ty ≤ x − y for all

x, y ∈ C, and a mapping F is said to be firmly nonexpansive if Fx − Fy2 ≤ x − y, Fx − Fy for all x, y ∈ C Let E be a smooth, strictly convex and reflexive Banach space, and let J be the

Trang 2

duality mapping of E and C a nonempty closed convex subset of E A mapping S : C → C is said to be nonspreading if

φ

Sx, Sy

 φSy, Sx

≤ φSx, y

 φSy, x

1.2

for all x, y ∈ C, where φx, y  x2−2x, Jyy2

for all x, y ∈ E; see, for instance, Kohsaka

and Takahashi10 In the case when E is a Hilbert space, we know that φx, y  x − y2

for all x, y ∈ E Then a nonspreading mapping S : C → C in a Hilbert space H is defined as

follows:

2Sx − Sy2≤Sx − y2x − Sy2 1.3

for all x, y ∈ C Let FQ be the set of fixed points of Q, and FQ nonempty; a mapping

Q : C → C is said to be quasi-nonexpansive if Qx − y ≤ x − y for all x ∈ C and y ∈ FQ.

Remark 1.1 In a Hilbert space, we know that every firmly nonexpansive mapping is

nonspreading and that if the set of fixed points of a nonspreading mapping is nonempty, the nonspreading mapping is quasi-nonexpansive; see10,11

In 1953, Mann12 introduced the iteration as follows: a sequence {x n} defined by

where the initial guess element x0 ∈ C is arbitrary and {α n} is a real sequence in

0, 1 Mann iteration has been extensively investigated for nonexpansive mappings In an

infinite-dimensional Hilbert space, Mann iteration can conclude only weak convergencesee

12,13 Fourteen years later, Halpern 14 introduced the following iterative scheme for

approximating a fixed point of T:

for all n ∈ Æ, where x1  x ∈ C and {α n } is a sequence of 0, 1 Strong convergence of this

type iterative sequence has been widely studied: Wittmann15 discussed such a sequence

in a Hilbert space

On the other hand, Kohsaka and Takahashi10 proved an existence theorem of fixed point for nonspreading mappings in a Banach space Recently, Lemoto and Takahashi16

studied the approximation theorem of common fixed points for a nonexpansive mapping T

of C into itself and a nonspreading mapping S of C into itself in a Hilbert space In particular, this result reduces to approximation fixed points of a nonspreading mapping S of C into itself

in a Hilbert space by using iterative scheme

Some methods have been proposed to solve the equilibrium problem and fixed point problem of nonexpansive mapping: see, for instance,1,2,6, 7,17–20 and the references

Trang 3

therein In 1997, Combettes and Hirstoaga 3 introduced an iterative scheme of finding the best approximation to the initial data when EPF is nonempty and proved a strong convergence theorem Recently, S Takahashi and W Takahashi8 introduced an iterative scheme by the viscosity approximation method for finding a common element of the set of solution of equilibrium problems and the set of fixed points of a nonexpansive mapping

in a Hilbert space Let S : C → H be a nonexpansive mapping In 2008, Plubtieng and

Punpaeng7 introduced a new iterative sequence for finding a common element of the set of solution of equilibrium problems and the set of fixed points of a nonexpansive mapping in a Hilbert space which is the optimality condition for the minimization problem Very recently,

S Takahashi and W Takahashi9 introduced an iterative method for finding a common element of the set of solutions of a generalized equilibrium problem and the set of fixed points

of a nonexpansive mapping in a Hilbert space and then obtain that the sequence converges strongly to a common element of two sets

In this paper, motivated by S Takahashi and W Takahashi 8 and Lemoto and Takahashi16, we introduce an iterative sequence and prove a strong convergence theorem for finding solution of equilibrium problems and the set of fixed points of a nonspreading mapping in Hilbert spaces

2 Preliminaries

Let H be a real Hilbert space When {x n } is a sequence in H, x n  x implies that xnconverges

weakly to x and x n → x means the strong convergence Let C be a nonempty closed convex subset of H For every point x ∈ H, there exists a unique nearest point in C; denote by P Cx,

such that

PC is called the metric projection of H onto C We know that P Cis nonexpansive Further, for

x ∈ H and z ∈ C,

z  PC x ⇐⇒

x − z, z − y

Moreover, P Cx is characterized by the following properties: PCx ∈ C and



x − PCx, y − PC y

≤ 0,

x − y2

for all x ∈ H, y ∈ C We also know that H satisfies Opial’s condition 21, that is, for any sequence{x n } ⊂ H with x n  x, the inequality

lim inf

n → ∞ x n − x < lim inf

n → ∞ xn − y 2.4

holds for every y ∈ H with x /  y; see 21,22 for more details

Trang 4

The following lemmas will be useful for proving the convergence result of this paper.

Lemma 2.1 see 23 Let E, ·, · be an inner product space Then for all x, y, z ∈ E and α, β, γ ∈

0, 1 with α  β  γ  1, one has

αx  βy  γz2

 αx2 βy2

 γz2− αβx − y2

− αγx − z2− βγy − z2

. 2.5

Lemma 2.2 see 10 Let H be a Hilbert space, C a nonempty closed convex subset of H Let S be

a nonspreading mapping of C into itself Then the following are equivalent.

1 There exists x ∈ C such that {S n x} is bounded;

2 FS is nonempty.

Lemma 2.3 see 10 Let H be a Hilbert space, C a nonempty closed convex subset of H Let S be

a nonspreading mapping of C into itself Then FS is closed and convex.

Lemma 2.4 Let H be a real Hilbert space Then for all x, y ∈ H,

1 x  y2≤ x2 2y, x  y;

2 x  y2≥ x2 2y, x.

Lemma 2.5 see 24 Let {a n }, {b n } ⊂ 0, ∞, and let {c n } ⊂ 0, 1 be sequences of real numbers

such that

an1 ≤ 1 − c n a n  b n, for all n ∈Æ,

∞

n1 cn  ∞ and∞

n1 bn < ∞.

Then, limn → ∞an  0

Lemma 2.6 see 16 Let H be a Hilbert space, C a closed convex subset of H, and S : C → C

a nonspreading mapping with FS /  ∅ Then S is demiclosed, that is, x n  u and xn − Sx n → 0

imply u ∈ FS.

Lemma 2.7 see 16 Let H be a Hilbert space, C a nonempty closed convex subset of a real Hilbert

space H, and let S be a nonspreading mapping of C into itself, and let A  I − S Then

Ax − Ay2≤x − y, Ax − Ay

1 2



Ax2Ay2

Lemma 2.8 see 25 Assume {a n } is a sequence of nonnegative real numbers such that

where {α n } is a sequence in 0, 1 and {δ n } is a sequence inÊsuch that

1∞

n1 αn  ∞;

2 lim supn → ∞ δ n/αn  ≤ 0 or∞n1 |δ n | < ∞.

Then limn → ∞an  0.

Trang 5

For solving the equilibrium problems for a bifunction F : C × C → Ê, let us assume

that F satisfies the following conditions:

A1 Fx, x  0 for all x ∈ C;

A2 F is monotone, that is, Fx, y  Fy, x ≤ 0 for all x, y ∈ C;

A3 for each x, y, z ∈ C, lim t↓0Ftz  1 − tx, y ≤ Fx, y;

A4 for each x ∈ C, y → Fx, y is convex and lower semicontinuous.

The following lemma appears implicitly in26

Lemma 2.9 see 26 Let C be a nonempty closed convex subset of H, and let F be a bifunction of

C × C intoÊsatisfying (A1)–(A4) Let r > 0 and x ∈ H Then, there exists z ∈ C such that

F

z, y

1

r



y − z, z − x

The following lemma was also given in4

Lemma 2.10 see 4 Assume that F : C × C → Ê satisfies (A1)–(A4) For r > 0 and x ∈ H, define a mapping Tr : H → C as follows:

Tr x  z ∈ C : F

z, y

 1

r



y − z, z − x

≥ 0, ∀y ∈ C

2.9

for all z ∈ H Then, the following hold:

1 T r is single-valued;

2 T r is firmly nonexpansive, that is, for any x, y ∈ H, Trx − Tr y2 ≤ T r x − Try, x − y;

3 FT r   EPF;

4 EPF is closed and convex.

Lemma 2.11 see 27 Let Γ n  be a sequence of real numbers that does not decrease at infinity, in

the sense that there exists a subsequencen jj≥0 ofn  which satisfies Γ n j < Γn j1for all j ≥ 0 Also consider the sequence of integers τn n≥n0defined by

Then τn n≥n0 is a nondecreasing sequence verifying limn → ∞τn  ∞, and the following properties are satisfied for all n ≥ n0:

Γτn ≤ Γτn1, Γn≤ Γτn1. 2.11

3 Main Result

In this section, we prove a strong convergence theorem for finding a common element of the set of fixed points of a nonspreading mapping and the set of solutions of the equilibrium problems

Trang 6

Theorem 3.1 Let C be a nonempty closed convex subset of a real Hilbert space H Let F be a

bifunctions from C × C → Êsatisfying (A1)–(A4), and let S be a nonspreading mapping of C into itself such that FS ∩ EP F /  ∅ Let u ∈ C, and let {x n } and {u n } be sequences generated by x1∈ C

and

F

un, y

 1

rn



y − un, un − x n



≥ 0, ∀y ∈ C,

xn1  β nxn1− β n



S α nu  1 − α n u n ,

3.1

for all n ∈Æ, where {α n }, {β n } ∈ 0, 1 and {r n } ∈ 0, ∞ satisfy

limn → ∞αn  0,∞

n1 αn  ∞, 0 < a ≤ β n ≤ b < 1,

∞

n1 |α n − α n−1 | < ∞,∞n1 |β n − β n−1 | < ∞,

lim infn → ∞rn > 0, and∞

n1 |r n1 − r n | < ∞.

Then {x n } converges strongly to z ∈ FS ∩ EPF, where z  P FS∩EPFu.

Proof Let p ∈ FS ∩ EPF From un  T r n xn, we have

un − p  T r n xn − T r n p  ≤ x n − p 3.2

for all n ∈Æ Put y n  α nu  1 − αn u n We divide the proof into several steps

Step 1 We claim that the sequences {x n }, {u n }, {y n }, and {Sy n} are bounded First, we note that

Syn − p ≤ y n − p

αnu  1 − α n u n − p

≤ α nu − p   1 − α nun − p

≤ α nu − p   1 − α nxn − p,

3.3

and so

xn1 − p  β nxn1− β n



Syn − p

≤ β nxn − p  1 − β nSyn − p

≤ β nxn − p  1 − β nyn − p

 β nxn − p  1 − β nαnu  1 − α n u n − p

≤ β nxn − p  1 − β n



αnu − p   1 − α nun − p

≤ β nxn − p  1 − β n



αnu − p   1 − α nxn − p

1− α n



1− β nxn − p  α n



1− β nu − p.

3.4

Trang 7

Putting M  max{x n − p, u − p}, we note that x n − p ≤ M for all n ∈ Æ In fact, it is obvious thatx1− p ≤ M Assume that x k − p ≤ M for all k ∈Æ Thus, we have

xk1 − p ≤ 1 − α k



1− β kxk − p  α k



1− β ku − p

≤1− α k



1− β k



M  αk

1− β k



M

 M.

3.5

By induction, we obtain thatx n − p ≤ M for all n ∈Æ So,{x n } is bound Hence, {u n }, {y n}, and{Sy n} are also bounded

Step 2 Put tn  β nyn  1 − β n Sy n We claim thatx n1 − t n  → 0 as n → ∞ We note that

x n1 − x n βnxn

1− β n



Syn

−βn−1xn−11− β n−1



Syn−1

βnxn − β nxn−1  β nxn−1 − β n−1xn−1

1− β n



Syn−1− β n



Syn−1

1− β n



Syn−1−1− β n−1



Syn−1

≤ β n x n − x n−1  βn − β n−1 x n−1 1− β nSyn − Sy n−1

 1− β n

−1− β n−1 Syn−1

≤ β n x n − x n−1  βn − β n−1 x n−1 1− β nyn − y n−1   β n−1 − β n Syn−1

 β n x n − x n−1  βn − β n−1 x n−1 1− β n



× α nu  1 − α n u n − α n−1u − 1 − α n−1 u n−1  βn − β n−1 Syn−1

≤ β n x n − x n−1  βn − β n−1 x n−1 1− β n



× α nu − αn−1u   1 − α n u n − 1 − α n−1 u n−1  βn − β n−1 Syn−1

 β n x n − x n−1  βn − β n−1 x n−1 1− β n



|α n − α n−1 |u

1− β n



1 − α n u n − 1 − α n u n−1  1 − α n u n−1 − 1 − α n−1 u n−1

 βn − β n−1 Syn−1

≤ β n x n − x n−1  βn − β n−1 x n−1 1− β n



|α n − α n−1 |u

1− β n



1 − α n u n − u n−1 1− β n



|1 − α n  − 1 − α n−1 |u n−1

 βn − β n−1 Syn−1

 β n x n − x n−1  βn − β n−1 x n−1 1− β n



|α n − α n−1 |u

1− β n



1 − α n u n − u n−1 1− β n



|α n − α n−1 |u n−1

 βn − β n−1 Syn−1

 β n x n − x n−1  βn − β n−1 K1

1− β n



|α n − α n−1 |K1

1− β n



1 − α n u n − u n−1 1− β n



|α n − α n−1 |K1 βn − β n−1 K1,

3.6

Trang 8

where K1 sup{x n   Sy n   u  u n−1  : n ∈Æ} On the other hand, from u n  T r n xnand

un1  T r n1 xn1, we have

F

un, y

 1

rn



y − un, un − x n



F

un1, y

rn1



y − un1, un1 − x n1



for all y ∈ C Putting y  u n1in3.7 and y  u nin3.8, we have

F u n, un1  1

rn u n1 − u n, un − x n  ≥ 0,

F u n1, un  1

rn1 u n − u n1, un1 − x n1  ≥ 0.

3.9

So, fromA2, we note that

un1 − u n, un − x n

rnun1 − x n1

rn1



and hence

un1 − u n, un − u n1  u n1 − x nrn

rn1 u n1 − x n1



Without loss of generality, let us assume that there exists a real number d such that r n > d > 0

for all n ∈Æ Thus, we have

u n1 − u n2≤ un1 − u n, xn1 − x n



1− rn

rn1



u n1 − x n1



≤ u n1 − u n x n1 − x n 

1 −rn1 rn u n1 − x n1

,

3.12

and hence

u n1 − u n  ≤ x n1 − x n  1

rn1 |r n1 − r n |u n1 − x n1

≤ x n1 − x n  1

d |r n1 − r n |L,

3.13

Trang 9

where L  sup{u n − x n  : n ∈Æ} So, from 3.6, we note that

x n1 − x n  ≤ β n x n − x n−1  2 βn − β n−1 K1 2

1− β n



|α n − α n−1 |K1

1− β n



1 − α n



x n − x n−1 1

d |r n − r n−1 |L



βn1− β n



1 − α nx n − x n−1  2 βn − β n−1 K1 2

1− β n



|α n − α n−1 |K1

1− β n



1 − α n1

d |r n − r n−1 |L

1−1− β n



αn

x n − x n−1  2 βn − β n−1 K1 2

1− β n



|α n − α n−1 |K1

1− β n



1 − α nL

d |r n − r n−1 |.

3.14

lim

n → ∞ x n1 − x n  0 3.15

for p ∈ FS ∪ EPF We note from u n  T r n xnthat

un − p2Tr

n xn − T r n p2 ≤Tr n xn − T r n p, xn − pun − p, x n − p

 1 2

u

n − p2xn − p2

− x n − u n2

,

3.16

and hence

un − p2≤xn − p2

Therefore, from the convexity of · 2, we have

xn1 − p2βnxn

1− β n



Syn − p2

≤ β nxn − p21− β nSyn − p2

≤ β nxn − p21− β nyn − p2

 β nxn − p21− β nαnu  1 − α n u n − p2

≤ β nxn − p2 α n



1− β nu − p21− β n



1 − α nun − p2

≤ β nxn − p2 α n



1− β nu − p21− β n



1 − α nx

n − p2

− x n − u n2

1−1− β n



αnxn − p2 α n



1− β nu − p21− β n



1 − α n x n − u n2

,

3.18

Trang 10

and hence



1− β n



1 − α n x n − u n2 ≤ α n



1− β nu − p2− α n



1− β nxn − p2

xn − p2−xn1 − p2

 α n



1− β nu − p2− α n



1− β nxn − p2

xn − p − x n1 − pxn − p  x n1 − p

≤ α n



1− β nu − p2− α n



1− β nxn − p2

 x n − x n1xn − p  x n1 − p.

3.19

So, we havex n − u n  → 0 Indeed, since y n  α nu  1 − αn u n, it follows that

lim

n → ∞xn − y n  lim

n → ∞ x n − α nu  1 − α n u n

 lim

n → ∞ α n  1 − α n x n − α nu  1 − α n u n

≤ lim

n → ∞ α n x n − u  1 − α n x n − u n

 lim

n → ∞ αn x n − u  lim

n → ∞ 1 − α n x n − u n

 0.

3.20

Then, we note that

x n1 − t n βnxn

1− β n



Syn

−βnyn1− β n



Syn

βn

xn − y n



1− β n



Syn − Sy n

Since, 0 < a ≤ β n ≤ b < 1 and x n − y n → 0, it follows that

lim

n → ∞ x n1 − t n   0. 3.22

Step 3 Put A  I − S From Ap  0, it follows byLemma 2.7that

tn − p2βnyn

1− β n



Syn

− p2

yn − p

−1− β n



yn − Sy n2

yn − p

−1− β n



Ayn2

yn − p2− 21− β n



yn − p, Ay n − Ap1− β n

2Ayn2

Ngày đăng: 21/06/2014, 06:20

TỪ KHÓA LIÊN QUAN

TÀI LIỆU CÙNG NGƯỜI DÙNG

TÀI LIỆU LIÊN QUAN

🧩 Sản phẩm bạn có thể quan tâm