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R E S E A R C H Open AccessNon-Newtonian polytropic filtration systems with nonlinear boundary conditions Wanjuan Du*and Zhongping Li * Correspondence: duwanjuan28@163.com College of Mat

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R E S E A R C H Open Access

Non-Newtonian polytropic filtration systems with nonlinear boundary conditions

Wanjuan Du*and Zhongping Li

* Correspondence:

duwanjuan28@163.com

College of Mathematic and

Information, China West Normal

University, Nanchong 637002, PR

China

Abstract

This article deals with the global existence and the blow-up of non-Newtonian polytropic filtration systems with nonlinear boundary conditions Necessary and sufficient conditions on the global existence of all positive (weak) solutions are obtained by constructing various upper and lower solutions

Mathematics Subject Classification (2000) 35K50, 35K55, 35K65

Keywords: Polytropic filtration systems, Nonlinear boundary conditions, Global exis-tence, Blow-up

Introduction

In this article, we study the global existence and the blow-up of non-Newtonian poly-tropic filtration systems with nonlinear boundary conditions

(u k i

i )t= m i u i (i = 1, , n), x ∈ , t > 0,

m i u i · ν =n

j=1

u m ij

j (i = 1, , n), x ∈ ∂, t > 0,

u i (x, 0) = u i0 (x) > 0 (i = 1, , n), x ∈ ¯,

(1:1)

where

 m iu i= div(|∇ui|m i−1∇u i) =

N



j=1

(|∇ui|m i−1u ix j)x

j, ∇m iu i= (|∇ui|m i−1u ix1 , , |∇u i|m i−1u ix N),

Ω ⊂ ℝN

is a bounded domain with smooth boundary∂Ω, ν is the outward normal vector on the boundary∂Ω, and the constants ki, mi> 0, mij≥ 0, i, j = 1, , n; ui0(x) (i

= 1, , n) are positive C1functions, satisfying the compatibility conditions

The particular feature of the equations in (1.1) is their power- and gradient-depen-dent diffusibility Such equations arise in some physical models, such as population dynamics, chemical reactions, heat transfer, and so on In particular, equations in (1.1) may be used to describe the nonstationary flows in a porous medium of fluids with a power dependence of the tangential stress on the velocity of displacement under poly-tropic conditions In this case, the equations in (1.1) are called the non-Newtonian polytropic filtration equations which have been intensively studied (see [1-4] and the references therein) For the Neuman problem (1.1), the local existence of solutions in time have been established; see the monograph [4]

© 2011 Du and Li; licensee Springer This is an Open Access article distributed under the terms of the Creative Commons Attribution License (http://creativecommons.org/licenses/by/2.0), which permits unrestricted use, distribution, and reproduction in any medium,

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We note that most previous works deal with special cases of (1.1) (see [5-13]) For example, Sun and Wang [7] studied system (1.1) with n = 1 (the single-equation case)

and showed that all positive (weak) solutions of (1.1) exist globally if and only if m11≤

k1 when k1 ≤ m1; and exist globally if and only ifm11≤m1 (k1 +1)

m1+1 when k1>m1 In [13], Wang studied the case n = 2 of (1.1) in one dimension Recently, Li et al [5] extended

the results of [13] into more general N-dimensional domain

On the other hand, for systems involving more than two equations when mi = 1(i = 1, , n), the special case ki= 1(i = 1, , n) (heat equations) is concerned by Wang and

Wang [9], and the case ki≤ 1(i = 1, , n) (porous medium equations) is discussed in

[12] In both studies, they obtained the necessary and sufficient conditions to the

glo-bal existence of solutions The fast-slow diffusion equations (there exists i(i = 1, , n)

such that ki > 1) is studied by Qi et al [6], and they obtained the necessary and

suffi-cient blow up conditions for the special case Ω = BR(0) (the ball centered at the origin

in ℝN

with radius R) However, for the general domain Ω, they only gave some suffi-cient conditions to the global existence and the blow-up of solutions

The aim of this article is to study the long-time behavior of solutions to systems (1.1) and provide a simple criterion of the classification of global existence and nonexistence

of solutions for general powers kimi, indices mij, and number n

Define

b i= min{ki, m i (k i+1)

m i+1 }, b ij = b i δ ij, i, j = 1, , n,

B = (b ij)n ×n, M = (m ij)n ×n, A = B − M.

Our main result is Theorem All positive solutions of (1.1) exist globally if and only if all of the principal minor determinants of A are non-negative

Remark The conclusion of Theorem covers the results of [5-13] Moreover, this article provides the necessary and sufficient conditions to the global existence and the

blow-up of solutions in the general domain Ω Therefore, this article improves the

results of [6]

The rest of this article is organized as follows Some preliminaries will be given in next section The above theorem will be proved in Section 3

Preliminaries

As is well known that degenerate and singular equations need not possess classical

solutions, we give a precise definition of a weak solution to (1.1)

Definition Let T > 0 and QT =Ω × (0, T] A vector function (u1(x, t), , un(x, t)) is called a weak upper (or lower) solution to (1.1) in QTif

(i).u i (x, t) (i = 1, , n) ∈ L(0, T; W1,∞()) ∩ W1,2(0, T; L2 ()) ∩ C(Q T); (ii) (u1(x, 0), , un(x, 0))≥ (≤)(u10(x), , un0(x));

(iii) for any positive functions ψi(i = 1, , n)Î L1

(0, T; W 1,2(Ω)) ∩ L2

(QT), we have

 

Q T [(u k i

i )t ψ i+∇m i u i · ∇ψ i ] dxdt≥ (≤)T

0



∂

n



j=1

u m ij

j ψ i dsdt (i = 1, , n).

In particular, (u1(x, t), , un(x, t)) is called a weak solution of (1.1) if it is both a weak upper and a lower solution For every T <∞, if (u1(x, t), , un(x, t)) is a solution of (1.1)

in Q , then we say that(u(x, t), , u (x, t)) is global

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Lemma 2.1 (Comparison Principle.) Assume that ui0(i = 1, , n) are positive

C1( ¯)functions and(u1, , un) is any weak solution of (1.1) Also assume that (u1, , un)

≥ (δ, , δ) > 0 and(¯u1, , ¯u n)are the lower and upper solutions of (1.1) in QT,

respec-tively, with nonlinear boundary flux (λ−n

j=1 um1j

j , , λ−n

j=1 um nj

j )and (¯λn

j=1 ¯u m1j

j , , ¯λn

j=1 ¯u m nj

j ), where 0< λ< 1 < ¯λ Then we have (¯u1, , ¯u n)≥ (u1, , u n)≥ (u− , , u− )in QT.

When n = 2, the proof of Lemma 2.1 is given in [5] When n > 2, the proof is similar

For convenience, we denote 0< λ< 1 < ¯λ, which are fixed constants, and let

δ = min1≤i≤n{min¯ u i0 (x) } > 0

In the following, we describe three lemmas, which can be obtained directly from Lemmas 2.7-2.9 in [6]

Lemma 2.2 Suppose all the principal minor determinants of A are non-negative If A

is irreducible, then for any positive constant c, there existsa = (a1, , an)Tsuch that A

a ≥ 0 and ai>c (i = 1, , n)

Lemma 2.3 Suppose that all the lower-order principal minor determinants of A are non-negative and A is irreducible For any positive constant C, there exist large positive

constants Li(i = 1, , n) such that

n



j=1

L a ij

j ≥ C (i = 1, , n).

Lemma 2.4 Suppose that all the lower-order principal minor determinants of A are non-negative and |A| < 0 Then, A is irreducible and, for any positive constant C, there

exists a = (a1, ,an)T, withai> 0 (i = 1, , n) such that

min{k i, m i (k i+1)

m i+1 }α i

n



j=1

m ij α j < −C (i = 1, , n).

Proof of Theorem

First, we note that if A is reducible, then the full system (1.1) can be reduced to several

sub-systems, independent of each other Therefore, in the following, we assume that A

is irreducible In addition, we suppose that k1 - m1≤ k2- m2≤ · · · kn- mn

Letϕ m i (x)(i = 1, , n)be the first eigenfunction of

− m i ϕ m i=λϕ m i

with the first eigenvalueλ m i, normalized by||ϕ m i (x)||∞= 1, then λ m i > 0,ϕ m i (x) > 0

inΩ andϕ m i (x) ∈ W 1,m i+1

∂ν < 0on∂Ω (see [14-16]).

Thus, there exist some positive constants A m i,B m i,C m i, andD m isuch that

A m i ≤ −∂ϕ m i (x)

∂ν ≤ B m i, |∇ϕ m i (x) | ≥ C m i, x ∈ ∂; |∇ϕ m i (x) | ≤ D m i, x ∈ ¯.(3:2)

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We also have∇ϕ m i (x) ≥ E m i providedx ∈ {x ∈  : dist(x, ∂) ≤ ε m i}withE m i = C mi

2

and some positive constantε m i For the fixed ε m i, there exists a positive constant F m i

such thatϕ m i (x) ≥ F m iifx ∈ {x ∈  : dist(x, ∂) > ε m i}

Proof of the sufficiency We divide this proof into three different cases

Case 1 (ki<mi(i = 1, , n)) Let

¯u i (x, t) = P i e i tlog

 (1− ϕ m i (x))e

(k i −m i)α i t

m i + Q i



where QisatisfiesQ i log Q i2(m i −k i)

m i (i = 1, , n), and constants Pi,ai(i = 1, , n) remain to be determined Since Q i log Q i2(m i −k i)

m i , by performing direct calculations,

we have

(¯u k i

i)t ≥ k i α i P k i

i e k i α i t

 log((1− ϕ m i (x))e

(k i −m i)α i t

m i + Q i)

k i

+ k i α i P k i

i e k i α i t

 log((1− ϕ m i (x))e

(k i −m i)α i t

m i + Q i)

k i−1

×

k i −m i

m i (1− ϕ m i (x))e

(k i −m i)α i t

m i

(1− ϕ m i (x))e

(k i −m i)α i t

m i + Q i

k i α i

k i

i e k i α i t

 log((1− ϕ m i (x))e

(k i −m i)α i t

m i + Q i)

k i

k i α i

k i

i e k i α i t (log Q i)k i,

 m i ¯u i=

N



j=1

P

m i

i e k i α i t(−|∇ϕ m i (x)|m i−1(ϕ m i)x j) ((1− ϕ m i (x))e

(k i −m i)α i t

m i + Q i)

m i

x j

λ m i P m i

i e k i α i t

Q m i i

inΩ × ℝ+

By settingc m i = C m iif mi≥ 1,c m i = D m iif mi< 1, we have one the bound-ary that

m i u i · ν ≥ P

m i

i c m i−1

m i A m i (1 + Q i)m i e k i α i t (i = 1, , n),

n



j=1

¯u m ij

j

n



j=1 (P j log(1 + Q j))m ij en j=1 m ij α j t

(i = 1, , n).

we have

m i ¯u i · ν ≥ ¯λ

n



j=1

¯u m ij

j (i = 1, , n)

if

P mi i c mi−1 mi A mi

j=1

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k i α i≥n

j=1

Note that ki <mi(i = 1, , n) From Lemmas 2.2 and 2.3, we know that inequalities (3.4) and (3.5) hold for suitable choices of Pi,ai(i = 1, , n) Moreover, if we choose

Pi,aito be large enough such that

P i log Q i ≥ ||u i0||∞, α i≥ 2λ mi P mi−ki i

k i Q mi i (log Q i)ki, then u i (x, 0) ≥ u i0, (¯u k i

i )t ≥  m i ¯u i (i = 1, , n) Therefore, we have proved that (¯u1, , ¯u n)is a global upper solution of the system (1.1) The global existence of

solu-tions to the problem (1.1) follows from the comparison principle

Case 2 (ki≥ mi(i = 1, , n)) Let

¯u i (x, t) = e α i t

⎝M + ¯λ

1

m i e −L i ϕ mi e

(k i −m i)α i t

m i+1

(2M)

n



j=1

m ij

m i L−1i A

1

m i i

⎠ (i = 1, , n), (3:6)

where A i = A m i C m i−1

m i if mi≥ 1, A i = A m i D m i−1

m i if mi < 1,ϕ m i, A m i, B m i,C m i are defined

in (3.1) and (3.2), ai(i = 1, , n) are positive constants that remain to be determined,

and

M = max1≤i≤n{1, ||u i0||∞}, L i= ¯λ m1i2

n

j=1 m ij

m i M

n

j=1 m ij −m i

m i A

1

m i

i max

1, 2(k i −m i)

m i+1



−L i ϕ m i e

(k i −m i)α i t

m i+1 e −L i ϕ mi e

(k i −m i)α i t

m i+1

≥ −e−1 Thus, for (x, t) Î Ω × ℝ+

, a simple computa-tion shows that

(¯uk i

i )t = k i α i e k i α i t

⎝M + ¯λ m1i e −L i ϕ mi e

(k i −m i)α i t

m i+1

(2M)

j=1 m ij

m i L−1i A

1

m i i

k i

+ k i e k i α i t

⎝M + ¯λ m1i e −L i ϕ mi e

(k i −m i)α i t

m i+1

(2M)

j=1 m ij

m i L−1i A

1

m i i

k i−1

× ¯λ m1i (2M)

j=1 m ij

m i L−1i A

1

m i i

(k i − m i)α i

m i+ 1 (−L i ϕ m i )e

(k i −m i)α i t

m i+1 e −L i ϕ mi e

(k i −m i)α i t

m i+1

2k i α i e k i α i t

In addition, we have

 m i ¯u i ≤ ¯λλ m i (2M)n j=1 m ij A−1i ϕ m i

m i e m i α i t e

m i (k i −m i)α i t

m i+1 e −L i m i ϕ mi e

(k i −m i)α i t

m i+1

+ ¯λL i m i (2M)n j=1 m ij A−1i e k i α i t

e −L i m i ϕ mi e

(k i −m i)α i t

m i+1 ∇ϕ m im i+1

≤ ¯λ(λ m i + L i m i D m i+1

m i )(2M)n j=1 m ij A−1i e k i α i t

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Notingϕ m i = 0 (i = 1, 2, , n)on∂Ω, we have on the boundary that

m i ¯u i · ν ≥ ¯λ(2M)

n



j=1

m ij

e

m i (k i −m i)α i t

m i+1 ,

n



j=1

¯u m ij

n



j=1

m ij

e

n



j=1

m ij α j t

Then, we have

m i ¯u i · ν ≥ ¯λn

j=1

¯u m ij

j (i = 1, , n)

if

m i (k i −1)α i

m i+1 ≥n

j=1

From Lemma 2.2, we know that inequalities (3.7) hold for suitable choices ofai(i = 1, , n) Moreover, if we choose ∞ito be large enough such that

α i ≥ 2¯λ(λ m i + L i m i D m i+1

m i )(2M)n j=1 m ij (k i A i)−1, then(¯u k i

i)t ≥  m i ¯u i (i = 1, , n) Therefore, we have shown that(¯u1, , ¯u n)is an upper solution of (1.1) and exists globally Therefore,(u1, , u n)≤ (¯u1, , ¯u n), and

hence the solution (u1, , un) of (1.1) exists globally

Case 3 (ki<mi (i = 1, , s); ki≥ mi (i = s + 1, , n)) Let ¯u i (x, t) (i = 1, , s)be as in (3.3) and

¯u i (x, t) = e α i t

⎝M i+ ¯λ m1i e −L i ϕ mi e

(k i −m i)α i t

m i+1

(2M i)

k i+1

m i+1L−1i A

1

m i i

⎠ (i = s + 1, , n),

whereϕ m i, and Aiare as in case 2 By Lemma 2.3, we choose Pi≥ (log Qi)-1||ui0||∞ (i

= 1, , s) and Mi≥ max{1, ||ui0||∞} (i = s + 1, , n) such that

P mi i c mi−1 mi A mi

s



j=1 (P j log(1 + Q j))m ij

n



j=s+1 (2M j)m ij (i = 1, , s),

¯λ(2M i)

m i (k i+1)

m i+1 ≥

s



j=1 (P j log(1 + Q j))m ij

n



j=s+1 (2M j)m ij (i = s + 1, , n).

(3:8)

Set

L i= ¯λ m1i2

k i+1

m i+1M

k i −m i

m i+1

1

m i

i max

1,2(k i −m i)

m i+1



(i = s + 1, , n).

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By similar arguments, in cases 1 and 2, we have on the boundary that

m i ¯u i · ν ≥ P mi i c mi−1 mi A mi

(1+Q i)mi e k i α i t (i = 1, , s),

m i ¯u i · ν ≥ ¯λ(2M i)

m i (k i+1)

m i+1 e

m i (k i −1)α i t

m i+1 (i = s + 1, , n),

n



j=1

¯u m ij

j

s



j=1 (P j log(1 + Q j))m ij

n



j=s+1 (2M j)m ij en j=1 m ij α j t (i = 1, , n).

Therefore employing (3.8), we see that

m i ¯u i · ν ≥ ¯λn

j=1

¯u m ij

j (i = 1, , n)

if we knew

k i α i≥n

j=1 m ij α j (i = 1, , s), m i (k i −1)α i

m i+1 ≥n

j=1 m ij α j (i = s + 1, , , n). (3:9)

We deduce from Lemma 2.2 that (3.9) holds for suitable choices of ai(i = 1, , n)

Moreover, we can choose ailarge enough to assure that

α i≥ 2λ mi P mi −ki i

k i Q mi i (log Q i)ki , (i = 1, , s),

α i ≥ 2¯λ(λ m i + L i m i D m i+1

m i )(2M i)

m i (k i+1)

m i+1 (k i A i)−1(i = s + 1, , n),

Then, as in the calculations of cases 1 and 2, we have(¯u k i

i)t ≥  m i ¯u i (i = 1, , n)

We prove that(¯u1, , ¯u n)is an upper solution of (1.1), so (u1, , un) exists globally

Proof of the necessity

Without loss of generality, we first assume that all the lower-order principal minor determinants of A are non-negative, and |A| < 0, for, if not, there exists some

lth-order (1≤ l <n) principal minor determinant detAl × l of A = (aij)n×nwhich is negative

Without loss of generality, we may consider that

A l ×l=

a11 a 1l

a12 a 2l

a l1 a ll

and all of the sth-order (1≤ s ≤ l - 1) principal minor determinants detAs × sof Al × l

are non-negative Then, we consider the following problem:

(w k i

i )t= m i w i (i = 1, , l), x ∈ , t > 0,

m i w i · ν = δn j=l+1 m ij

n



j=1

w m ij

j (i = 1, , l), x ∈ ∂, t > 0,

w i (x, 0) = u i0 (x) (i = 1, , l), x ∈ ¯.

(3:10)

Note thatδ = min1≤i≤n{min¯ u i0 (x) } > 0 If we can prove that the solution (w1, , wl)

of (3.10) blows up in finite time, then (w1, wl,δ, , δ) is a lower solution of (1.1) that

blows up in finite time Therefore, the solution of (1.1) blows up in finite time

We will complete the proof of the necessity of our theorem in three different cases

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Case 1 (ki<mi(i = 1, , n)) Let

u

i = Y ρ i

i and Y i = ah1+

1

where h(x) =N

i=1 x i + Nd + 1, d = max {|x||x ∈ ¯}, ρ i= m i+γ i

m i −k i

, γ i=(m i −k i)α i−1

m i , the ai

are as given in Lemma 2.4 and satisfyα i > 1

m i −k i,

b = max1≤i≤n{1, (1

2δ ρ1i)−

1

γ i }, a = min1≤i≤n



b −γ i (2Nd + 1)

1+m i

m i ,

⎝λ−−1[(1 + m i)ρ i N122ρ i−1

m i

]

m i

(2Nd + 1)

m1

i

b

n j=1 m ij α j

m i

⎪,

c = min1≤i≤n{a

m i ρ m i−1

i (1 +m1i)m i

N

m i+1 2

(3:12)

By direct computation for(x, t) ∈  × (0, b

c), we have

(uk i

i)t = ck i ρ i γ i Y k i ρ i−1

i (b − ct) −(γ i+1), ∇u

i = a ρ i(1 + m1

i )Y ρ i−1

1

m i (x)(1, , 1),

 m i u

i=N j=1



(a ρ i(1 + m1

i))m i

N m i2−1Y m i(ρ i−1)



x j

= (a ρ i(1 + m1

i))m i N

m i+1

2 Y m i(ρ i−1)

i +m i(ρ i − 1)ρ m i

i (a(1 + m1

i))m i+1N m i2+1h1+

1

i

≥ (aρ i(1 + m1

i))m i N

m i+1

i

≥ (uk i

i)t (i = 1, , n).

For(x, t) ∈ ∂ × (0, b

c), we have

m i u

i · ν ≤ (aρ i(1 +m1

i))m i N m2i (2Nd + 1)2 m i(ρ i−1)(b − ct) −m i(ρ i −1)γ i

= (a ρ i(1 + m1

i))m i N m2i (2Nd + 1)2 m i(ρ i−1)(b − ct) −(k i α i+1)(i = 1, , n),

n



j=1

um ij

j =

n



j=1

Y m ij ρ j

n



j=1 (b − ct)−n

j=1 m ij α j (i = 1, , n).

Thus, by (3.12) and Lemma 2.4, we have

m i u

i · ν ≤ λ−n

j=1

u

m ij

j (i = 1, , n).

We confirm that (u1, , un) is a lower solution of (1.1), which blows up in finite time

We know by the comparison principle that the solution (u1, , un) blows up in finite

time

Case 2 (ki≥ mi(i = 1, , n)) Letd m i = C m iif mi< 1,d m i = D m iif mi≥ 1 for ki≥ mi(i

= 1, , n), set

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i= (b −ct)1 αi e

(b−ct) βi

whereai(i = 1, , n) are to determined later and

β i= (k i −m i)α i+1

a = min1≤i≤n



1, λm1i (B m i d m i−1

m i )−

1

m i b

j=1 m ij α j

m i



c = min1≤i≤n



m i a m i+1E m i+1

m i

k i α i

, λ m i (k i − m i )a m i+1F m i+1

m i

k i α i



By a direct computation, for x Î Ω, 0 <t <c/b, we obtain that

(uk i

i )t = k i α i ce

−ak i ϕ mi (x) (b −ct) βi

(b − ct) −(k i α i+1)−e

−ak i ϕ mi (x) (b −ct) βi

ak i β i cϕ mi (x) (b−ct) kiαi (b−ct) βi+1

≤ k i α i ce

−ak i ϕ mi (x) (b −ct) βi

(b − ct) −(k i α i+1),

 m i u

i= λ mi a mi ϕ mi

e

−am i ϕ mi (x) (b−ct) βi

−am i ϕ mi (x) (b−ct) βi

|∇ϕ mi|mi+1

(3:17)

If x ∈ {x ∈  : dist(x, ∂) > ε m i}, we haveϕ m i ≥ F m i, and thus

 m i u

iλ m i a m i F m i

m i e

−a i m i ϕ mi (x) (b −ct) βi

On the other hand, since -ye-y≥ -e-1

for any y > 0, we have

(uk i

i)

t ≤ k i α i ce

−ak i ϕ mi (x) (b−ct) βi

(b − ct) −(k i α i+1)≤ k i α i ce

−am i ϕ mi (x) (b−ct) βi a(k i −m i )F mi e(b −ct) mi(αi+βi) (3:19)

We have by (3.16), (3.18), and (3.19) that(uk i

i)t ≤  m i u

i (i = 1, , n)

If x ∈ {x ∈  : dist(x, ∂) ≤ ε m i}, then|∇ϕ m i | ≥ E m i, and then

 m i u

im i a m i+1E m i+1

m i e

−ak i ϕ mi (x) (b −ct) βi

(b − ct) m i(α i+β i)+β i = m i a

m i+1E m i+1

m i e

−ak i ϕ mi (x) (b −ct) βi

It follows from (3.16), (3.17), and (3.20) that(uk i

i)t ≤  m i u

i (i = 1, , n)

We have on the boundary that

m i u

i · ν = a m i |∇ϕ m i|m i−1e

−am i ϕ mi (x) (b −ct) βi

(−∂ϕ mi

∂ν ) (b − ct) m i(α i+β i) ≤ a m i B m i d m i−1

m i

(b − ct) m i(α i+β i) (i = 1, , n),

n



j=1

um ij

(b − ct)n j=1 m ij α j (i = 1, 2, , n).

(3:21)

Trang 10

Moreover, by (3.14) and Lemma 2.4, we have that

m i(α i+β i)≤n

(3.15), (3.21), and (3.22) imply that ∇m i u

i · ν ≤ λ−n

j=1 um ij

j (i = 1, , n) Therefore,

(u1, , u1) is a lower solution of (1.1)

For ki= mi(i = 1, , n), let

u

i= (b −ct)1 αi e

(b−ct)

1

m i

For ki = mi(i = 1, , s) and ki>mi (i = s + 1, , n), let ¯u i (x, t)as in (3.13) and (3.23)

Using similar arguments as above, we can prove that (u1, , un) is a lower solution of

(1.1) Therefore, (u1, , un) ≤ (u1, , un) Consequently, (u1, , un) blows up in finite

time

Case 3 (ki<mi(i = 1, , s); ki≥ mi(i = s + 1, , n)) Let ¯u i (x, t) (i = 1, , s)be as in (3.11) and

u

(b − ct) α i e

(b −ct) βi

(i = s + 1, , n),

whereai’s are to determined later and

β i=(k i −m i)α i+1

m i+1 (i = s + 1, , n), b =max{1, max 1is {( 1δ ρ1i)−

1

γ i}, maxs+1 in {δα1i}},

a =min

 mins+1 in {λ

1

m i (B m i d m i−1

m i )−

1

m i b

−n j=1 m ij α j

m i }, min 1is{b −γ i (2Nd + 1)

1+m i

m i ,



λ− −1 [(1+m i)ρ i N

1

2 2ρi−1

m i ]

m i (2Nd + 1)

 −m1

i

b

n j=1 m ij α j

m i }

⎪,

c =min

⎩min1is{

a mi ρ mi−1

i (1+1

m i)mi

m i+1 2

k i γ i } , mins+1 in



m i a mi+1 E mi +1 mi

k i α i ,λ mi (k i −m i )a mi+1 F mi+1 mi

k i α i



.

Based on arguments in cases 1 and 2, we have (uk i

i )t ≤  m i u

i (i = 1, , n) for

(x, t) ∈  × (0, b

c) Furthermore, for(x, t) ∈ ∂ × (0, b

c), we have

m i u

i · ν ≤ (aρ i(1 +m1

i))m i N m2i (2Nd + 1)2 m i(ρ i−1)(b − ct) −(k i α i+1)(i = 1, , s),

m i u

i · ν ≤ a m i B m i d m i−1

m i (b − ct) −m i(α i+β i)(i = s + 1, , n),

n



j=1

um ij

j ≥ (b − ct)−n j=1 m ij α j (i = 1, , n).

Thus,

m i u

i · ν ≤ λ−n

j=1

um ij

j (i = 1, , n)

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