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kindai.ac.jp 2 Department of Mathematics, Kinki University, Higashi-Osaka, Osaka 577-8502, Japan Full list of author information is available at the end of the article Abstract For analy

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R E S E A R C H Open Access

Generalized conditions for starlikeness and

convexity of certain analytic functions

Neslihan Uyanik1and Shigeyoshi Owa2*

* Correspondence: owa@math.

kindai.ac.jp

2 Department of Mathematics, Kinki

University, Higashi-Osaka, Osaka

577-8502, Japan

Full list of author information is

available at the end of the article

Abstract

For analytic functions f(z) in the open unit diskUwith f (0) = 0 and f ’(0) = 1, Nunokawa et al (Turk J Math 34, 333-337, 2010)have shown some conditions for starlikeness and convexity of f(z) The object of the present paper is to derive some generalized conditions for starlikeness and convexity of functions f(z) with examples

2010 Mathematics Subject Classification: Primary 30C45

Keywords: Analytic function, starlike function, convex function

1 Introduction

LetAdenote the class of functions f(z) of the form

f (z) = z +



n=2

which are analytic in the open unit diskU = {z ∈ C:|z| < 1} LetS be the subclass of

A consisting of functions f(z) which are univalent inU A function f (z)S is said to

be starlike with respect to the origin inUif f (U)is the starlike domain We denote by

S∗the class of all starlike functions f(z) with respect to the origin inU Furthermore, if

a function f (z)S satisfies zf(z)S∗, then f(z) is said to be convex inU We also denote byKthe class of all convex functions inU Note thatK ⊂ S∗⊂S ⊂ A

To discuss the univalency of f (z)A, Nunokawa [1] has given Lemma 1.1 If f (z)Asatisfiesf(z) <1(z ∈ U), then f (z)S Also, Mocanu [2] has shown that

Lemma 1.2 If f (z)Asatisfies

|f(z) − 1| < √2

5 (zU),

then f (z)S∗.

In view of Lemmas 1.1 and 1.2, Nunokawa et al [3] have proved the following results

Lemma 1.3 If f (z)Asatisfies

|f(z)|  √2

Then f (z)S∗.

© 2011 Uyanik and Owa; licensee Springer This is an Open Access article distributed under the terms of the Creative Commons Attribution License (http://creativecommons.org/licenses/by/2.0), which permits unrestricted use, distribution, and reproduction in

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Lemma 1.4 If f (z)Asatisfies

|f(z)| √1

then f (z)K The object of the present paper is to consider some generalized conditions for func-tions f(z) to be in the classesS∗orK

2 Generalized conditions for starlikeness

We begin with the statement and the proof of generalized conditions for starlikeness

Theorem 2.1 If f (z)Asatisfies

|f (j) (z)|  √2

for some j(j = 2, 3, 4, ), then f (z)S∗, where

M =

j−1

Proof For j = 2, the inequality (2.1) becomes (1.2) of Lemma 1.2 Thus, the theorem

is hold true for j = 2 We need to prove the inequality for j≧ 3 Note that

f(z) =

z

 0

We suppose that|f(z) |  N3(zU).Then, (2.3) gives us that

|f(z)| 

|z|

 0

|f(ρe i θ)dρ| + |f(0)|

 N3|z| + |f(0)|

< N3+|f(0)|

(2:4)

Therefore, if f(z) satisfies

|f(z)| < N3+|f(0)|  √2

then f (z)S∗by Lemma 1.3 This means that if f(z) satisfies

|f(z) |  N3 √2

then f (z)S∗ Thus, the theorem is holds true for j = 3.

Next, we suppose that the theorem is true for j = 2, 3, 4, , (k - 1) Then, letting

|f (k) (z)|  N k (zU),we have that

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|f (k−1) (z)| =







z

 0

f (k) (t)dt + f (k−1)(0)







 N k |z| + |f (k−1)(0)|

< N k+|f (k−1)(0)|

(2:7)

Thus, if f(z) satisfies

|f (k−1) (z)| < N k+|f (k−1)(0)|

 √2

5−

k−2



n=2

then f (z)S∗ This is equivalent to

|f (k) (z)|  N k √2

5 −

k−1



n=2

Therefore, the theorem holds true for j = k Thus, applying the mathematical induc-tion, we complete the proof of the theorem

Example 2.1 Let us consider a function

Since

|f(z) | = 24|a4|,

if f(z) satisfies 24|a4|  √2

5− 2|a2| − 6|a3|, then f (z)S∗ This is equivalent to

5|a2| + 3√5|a3| + 12√5|a4|  1

Therefore, we put

a2= e

i θ1

2√

5, a3=

ei θ2

9√

5, a4=

ei θ3

72√

5. Consequently, we see that the function

f (z) = z + e

i θ1

2√

5z

2+ e

i θ2

9√

5z

3+ e

i θ3

72√

5z 4

is in the class S∗.

3 Generalized conditions for convexity

For the convexity of f(z), we derive

Theorem 3.1 If f (z)Asatisfies

|f (j) (z)|  1

j!

4

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for some j(j = 3, 4, 5, ), then f (z)K, where

P =

j−1



n=2

Proof We have to prove for j ≧ 3 Note that

(zf(z))= 2f(z) + zf(z) = 2

z

 0

f(t)dt + f(0)

⎠ + zf(z). (3:3)

If|f(z) |  N3 (zU),then we have that

|(zf(z))|  2







z

 0

f(t)dt + f(0)





+|zf(z)|

 2

|z|

 0

|f(ρe i θ)dρ| + 2|f(0)| + N3|z|

 3N3|z| + 2|f(0)|

< 3N3+ 2|f(0)|

(3:4)

We know that f (z)Kif and only if zf(z)S∗ Therefore, if

3N3+ 2f(0)  2√

then zf(z)S∗by means of Lemma 1.3 Thus, if

|f(z) |  N3 2

3

1

then f (z)K This shows that the theorem is true for j = 3

Next, we assume that theorem is true for j = 3, 4, 5, , (k - 1) Then, letting

|f (k) (z) |  N k (zU),we obtain that



(zf(z)) (k−1) = |(k − 1)f (k−1)(z) + zf (k) (z)|

=





(k− 1)

z

 0

f (k) (t)dt + f (k−1)(0)

⎠ + zf (k)

(z)







 (k − 1)

|z|

 0

|f (k)(ρe i θ)dρ| + |f (k−1)(0)|

⎠ + |z|f (k) (z)

(3:7)

Now, we consider|f (k) (z) |  N k (zU), Then, (3.7) implies that



(zf(z)) (k−1)  kN

k |z| + (k − 1)f (k−1)(0)

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Since, if



zf(z)(k−1)  1

(k− 1)!

 4

5−

k−2



n=2

n · n!f (n)(0), then f (z)K(orzf(z)S∗), if f(z) satisfies that

kN k + (k− 1)f (k−1)(0)  1

(k− 1)!

 4

5−

k−2



n=2

n · n!f (n)(0), (3:9)

that is, that

N k 1

k!

 4

5−

k−1



n=2

n · n!f (n)(0), (3:10)

then f (z)K Thus, the result is true for j = k Using the mathematical induction,

we complete the proof the theorem

Example 3.1 We consider the function

f (z) = z + a2z2+ a3z3+ a4z4 Then, if f(z) satisfies

24|a4|  1

24

4

5 − 8|a2| − 108|a3| , then f (z)K Since

2√

5|a2| + 27√5|a3| + 144√5|a4|  1,

we consider

a2= e

i θ1

4√

5, a3=

ei θ2

81√

5, a4=

ei θ3

864√

5. With this conditions, the function

f (z) = z + e

i θ1

4√

5z

2+ e

i θ2

81√

5z

3+ e

i θ3

864√

5z 4

belongs to the classK

If we use the same technique as in the proof of Theorem 2.1 applying Lemma 1.4, then we have

Theorem 3.2 If f (z)Asatisfies

|f (j) (z)|  √1

for some j (j = 2, 3, 4, ), then f (z)K, where M is given by (2.2)

Acknowledgements

This paper was completed when the first author was visiting Department of Mathematics, Kinki University,

Higashi-Osaka, Osaka 577-8502, Japan, from Atat ürk University, Turkey, between February 17 and 26, 2011.

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Author details

1 Department of Mathematics, Kazim Karabekir Faculty of Education, Atatürk University, 25240 Erzurum, Turkey

2

Department of Mathematics, Kinki University, Higashi-Osaka, Osaka 577-8502, Japan

Received: 4 June 2011 Accepted: 17 October 2011 Published: 17 October 2011

References

1 Nunokawa, M: On the order of strongly starlikeness of strongly convex functions Proc Jpn Acad 68, 234 –237 (1993)

2 Mocanu, PT: Some starlikeness conditions for analytic function Rev Roum Math Pures Appl 33, 117 –124 (1988)

3 Nunokawa, M, Owa, S, Polatoglu, Y, Caglar, M, Duman, EY: Some sufficient conditions for starlikeness and convexity.

Turk J Math 34, 333 –337 (2010)

doi:10.1186/1029-242X-2011-87 Cite this article as: Uyanik and Owa: Generalized conditions for starlikeness and convexity of certain analytic functions Journal of Inequalities and Applications 2011 2011:87.

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