Solution manual for renewable and efficient electric power system reeps2 chapter 1 problems (gilbert masters)

Solution Manual for Renewable and Efficient electric Power System REEPS2 (Gilbert Masters)Solution Manual for Renewable and Efficient electric Power System REEPS2 (Gilbert Masters)Solution Manual for Renewable and Efficient electric Power System REEPS2 (Gilbert Masters)Solution Manual for Renewable and Efficient electric Power System REEPS2 (Gilbert Masters)Solution Manual for Renewable and Efficient electric Power System REEPS2 (Gilbert Masters)Solution Manual for Renewable and Efficient electric Power System REEPS2 (Gilbert Masters)

Heat rate =3412 Btu/kWh

3412

η=

3600

2

52%-efficient combined cycle gas

0.0963 kgC/kWh

P R( )kW ⋅8760h / yr =

1500

1⋅8760

6

2

2

2

24.5kgC

106

1.055kJ

tonne

5000¢/kWh tonne =1.36¢/kWh

24.5kgC

106

1.055kJ

tonne

5000¢/kWh tonne =1.10¢/kWh

24.5kgC

106

1.055kJ

tonne

5000¢/kWh tonne =1.16¢/kWh

13.7kgC

106

1.055kJ

tonne

5000¢/kWh tonne =0.51¢/kWh

13.7kgC

106

1.055kJ

tonne

5000¢/kWh tonne =0.687¢/kWh

Heat rate(conventional)= 3600 kJ/kWh

3600

2

106

10, 909kJ

3600

24.5kgC

106

$50

103

103

kg

24x106

10, 909kJ

kWh = $0.0182 / kWh

103

103kg

24x106

8571kJ

kWh = $0.0143 / kWh

2

P R(GW)⋅8760h / yr =

300GW ⋅8760

2

3600

NGCC emissions =7200kJ

13.7kgC

106

2x1012

kWh

44kgCO2 12kgC

= 0.723x10

12

tonne

1000kg x

Gt

109

2

Reduction=(2− 0.723)

5.8

CO2

1.10

( )30

3412

kWh/yr

106

6204Btu

6

6 6

LCOE = $ 19.93+14.26( )x106

/yr 438x106kWh/yr

Equivalent discount rate (A.14) = d ' = d − e

1+ e =

0.12− 0.04

1+ 0.04 = 0.07692

Levelization Factor, LF(A.25)= (1+ d ')n

−1

1+ d

( )n

−1

⎡

⎣

⎢

⎢

⎤

⎦

⎥

⎥

LF= (1.0769230−1)

(0.07692x1.0769230

)⋅(0.12x1.1230) 1.12

( )30

−1 =

8.237 0.710x

3.595 28.96 = 1.44

106

7, 000 Btu

Equivalent discount rate (A.14) = d ' = d − e

1+ e =

0.06

1 = 0.06

Levelization Factor, LF(A.25)= (1+ d ')n

−1

1+ d

( )n

−1

⎡

⎣

⎢

⎢

⎤

⎦

⎥

⎥

LF= (1.0610−1)

(0.06x1.0610)⋅(0.06x1.0610)

1.06 ( )10

−1 = 1.0

Equivalent discount rate (A.14) = d ' = d − e

1+ e =

0.06− 0.06 1+ 0.06 = 0

Levelization Factor, LF(A.25)= (1+ d ')n

−1

1+ d

( )n

−1

⎡

⎣

⎢

⎢

⎤

⎦

⎥

⎥

(0x1.0)⋅(0.06x1.0610)

1.06 ( )10

−1 =

0

0x

(0.06x1.0610

) 1.06 ( )10

−1 = ?blows up

( )n−1

⎡

⎣

⎢

⎢

⎤

⎦

⎥

⎥= n ⋅

d 1( + d)n

( )n −1

⎡

⎣

⎢

⎢

⎤

⎦

⎥

⎥

1.06

) 1.06

Equivalent discount rate (A.14) = d ' = d − e

1+ e =

0.06− 0.04

1+ 0.04 = 0.019231

Levelization Factor, LF(A.25)= (1+ d ')n

−1

1+ d

( )n

−1

⎡

⎣

⎢

⎢

⎤

⎦

⎥

⎥

LF= (1.01923110−1)

(0.019231x1.01923110)⋅(0.06x1.0610)

1.06 ( )10

−1 = 9.0188x0.13587 = 1.225

Equivalent discount rate (A.14) = d ' = d − e

1+ e =

0.05− 0.04

1+ 0.04 = 0.00962

Levelization Factor, LF(A.25)= (1+ d ')n

−1

1+ d

( )n

−1

⎡

⎣

⎢

⎢

⎤

⎦

⎥

⎥

LF= (1.0096220 −1)

(0.00962x1.0096220

)⋅(0.05x1.0520) 1.05

( )20

−1 = 18.1156x0.0.08024 = 1.454

1+ i

( )n

0.05 1.05( )20 1.05

( )20

106

8750 Btu

$0.004 kWh

⎛

Annualized fixed costs =$990/kW x 0.167/yr

106

9300 Btu

$0.004 kWh

⎛

106

6900 Btu

$0.004 kWh

⎛

10,500 Btu

$0.004 kWh

⎛

8760x0.4kWh / yr / kW

⎛

⎝⎜

⎞

CF= 600x3500 + 0.5x600 8760 − 3500( )

600x8760

0"

100"

200"

300"

400"

500"

600"

700"

800"

900"

1000"

0" 1000" 2000" 3000" 4000" 5000" 6000" 7000" 8000" 9000"

Hours/year"

8760"h/yr"

0"

100"

200"

300"

400"

500"

600"

700"

800"

900"

1000"

0" 1000" 2000" 3000" 4000" 5000" 6000" 7000" 8000" 9000"

Hours/year"

8760"h/yr"

6

9000 8000 7000 6000 5000 4000 3000 2000 1000 0

0 100

200

300

400

500

600

700

800

900

1000

Hours/year

8760 hr/yr

0"

100"

200"

300"

400"

500"

600"

700"

800"

900"

1000"

0" 0.1" 0.2" 0.3" 0.4" 0.5" 0.6" 0.7" 0.8" 0.9" 1"

Capacity"Factor"

Revenue/kWh = $120x10

6

/ yr 0.7x109kWh / yr

0"

2"

4"

6"

8"

10"

12"

0" 1000" 2000" 3000" 4000" 5000" 6000" 7000" 8000" 9000"

0"

2"

4"

6"

8"

10"

12"

0" 1000" 2000" 3000" 4000" 5000" 6000" 7000" 8000" 9000"

$1200%

$1000%

%$800%

%$600%

%$400%

%$200%

%%%%%0%

Equivalent%hrs/yr%at%Rated%Power%%(kWh/yr%Generated%

100%

%80%

%60%

%40%

%20%

%%0%

Hours/yr%of%demand%

Load%DuraCon%Curve%

CT%

NGCC% Coal%

CF(NGCC)=20x3000 + 0.5x20x3000

20x8760 = 90, 000

175, 200

$700/yr

CF(CT)=Triangular Area

Rectangle Area=

0.5 x 20x106kW x3000 h/yr 20x106

kW x 8760 h/yr = 0.171 which is equivalent to 0.171 x 8760 h/yr = 1498 h/yr

Rectangle Area

which is equivalent to 0.9479 x 8760 h/yr = 8300 h/yr

COAL NGCC CT

0"

100"

200"

300"

400"

500"

600"

700"

800"

900"

1000"

0" 1000" 2000" 3000" 4000" 5000" 6000" 7000" 8000" 9000"

Hours/year"

0"

40"

80"

120"

160"

200"

240"

280"

320"

360"

400"

0" 1000" 2000" 3000" 4000" 5000" 6000" 7000" 8000" 9000"

Hours/year"

COAL%

100"

200"

300"

400"

500"

600"

700"

800"

900"

1000"

0" 1000" 2000" 3000" 4000" 5000" 6000" 7000" 8000" 9000"

Hours/year"

0"

40"

80"

120"

160"

200"

240"

280"

320"

360"

400"

0" 1000" 2000" 3000" 4000" 5000" 6000" 7000" 8000" 9000"

Hours/year"

700#MW#coal#

100#MW#NGCC#

200#MW#CT#