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Lecture physics a2 particles in 3d potentials and the hydrogen atom huynh quang linh

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Tiêu đề Particles in 3D Potentials and the Hydrogen Atom
Trường học University of Physics and Quantum Studies
Chuyên ngành Physics
Thể loại Lecture
Năm xuất bản 2023
Thành phố Hanoi
Định dạng
Số trang 10
Dung lượng 376,76 KB

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“Anyone who can contemplate quantum mechanics without getting dizzy hasn’t understood it ” Neils Bohr Discussion Is there a particle flying faster than light speed ? Lecture 10 Particles in 3D Potenti[.]

Trang 1

“Anyone who can contemplate

quantum mechanics without getting dizzy hasn’t understood it.”

Neils Bohr Discussion: Is there a particle flying faster than light speed ?

Trang 2

Lecture 10: Particles in 3D Potentials and the Hydrogen

Atom

0 0.5

1 1

0 g( ) x

4

P(r)

0

1

r

r = a0

z

x

L

L L

 2 2 2 2

2

n

n

mL

h E

z

y

) ( ) ( ) ( )

, ,

( x y zxyz

3 o

e a

1 )

r

2

6 13

n

eV

E n  

Trang 3

3-Dimensional Potential Well

Product Wavefunctions

Concept of degeneracy

Early Models of the Hydrogen Atom

Planetary Model

Quantum Modifications

Schrödinger’s Equation for the Hydrogen Atom

Ground state solution

Spherically-symmetric excited states (“s-states”)

Trang 4

Quantum Particles in 3D Potentials

 One consequence of confining a quantum particle in two or three dimensions is “degeneracy” the occurrence of

several quantum states at the same energy level.

 So far, we have considered quantum particles

bound in one-dimensional potentials This

situation can be applicable to certain physical

systems but it lacks some of the features of

many “real” 3D quantum systems , such as

atoms and artificial quantum structures:

(www.kfa-juelich.de/isi/)

A real (3D)

“quantum dot”

 To illustrate this important point in a simple system, we

extend our favorite potential the infinite square well

to three dimensions.

Trang 5

Particle in a 3D Box (1)

outside box, x or y or z < 0

outside box, x or y or z > L

0 inside box U(x,y,z) =

Let’s solve this SEQ for the particle in a 3D box:

y

The extension of the Schrödinger Equation (SEQ) to 3D

is straightforward in cartesian (x,y,z) coordinates:

E )

z , y , x (

U dz

d dy

d dx

d

2

2 2

2 2

2 2

2

) , , ( x y z

 

where

This simple U(x,y,z) can be “separated”

U(x,y,z) = U(x) + U(y) + U(z)

z

x

L

L L

Kinetic energy term in the Schrödinger Equation

 2 2 2

2

1

z y

p m like  

Trang 6

Particle in a 3D Box (2)

So, the whole problem simplifies into three one-dimensional

equations that we’ve already solved in Lecture 7.

) ( )

( ) ( )

(

2 2

x E

x x

U dx

x d

m     x

 

) ( )

( ) (

) (

2 2

y E

y y

U dy

y d

m     y

 

L

n N

n

 ( ) sin

2 2

2

L

n m

h





L

n N

n

 ( ) sin

2 2

2

L

n m

h

Likewise for( z)

So the Schrödinger Equation becomes:

E )

z ( U ) y ( U ) x (

U dz

d dy

d dx

d

2

2 2

2 2

2 2

2

and the wavefunction can be “separated” into the product of three functions:    ( x , y , z )

) ( ) ( ) ( )

, ,

graphic

Trang 7

Particle in a 3D Box (3)

So, finally, the eigenstates and associated

x

y

L

L

L





L

n y

L

n x

L

n

 sin sin sin

where n x ,n y , and n z can each have values 1,2,3,….

This problem illustrates 2 important new points.

(1) Three ‘quantum numbers’ (n x ,n y ,n z ) are needed to completely identify the state of this three-dimensional system.

(2) More than one state can have the same energy:

“Degeneracy”.

Degeneracy reflects an underlying symmetry in U(x,y,z)

3 equivalent directions

 2 2 2

2

2

n n

mL

h E

z y

Trang 8

Consider a particle in a two-dimensional (infinite) well, with Lx = L y

1 Compare the energies of the (2,2), (1,3), and (3,1) states?

a E (2,2) > E (1,3) = E (3,1)

b E (2,2) = E (1,3) = E (3,1)

c E (1,3) = E (3,1) > E (2,2)

2 If we squeeze the box in the x-direction (i.e., L x < L y ) compare

E (1,3) with E (3,1) :

a E (1,3) < E (3,1)

b E (1,3) = E (3,1)

c E (1,3) > E (3,1)

Lecture 10, exercise 1

Trang 9

Consider a particle in a two-dimensional (infinite) well, with Lx = L y

1 Compare the energies of the (2,2), (1,3), and (3,1) states?

a E (2,2) > E (1,3) = E (3,1)

b E (2,2) = E (1,3) = E (3,1)

c E (1,3) = E (3,1) > E (2,2)

2 If we squeeze the box in the x-direction (i.e., L x < L y ) compare

E (1,3) with E (3,1) :

a E (1,3) < E (3,1)

b E (1,3) = E (3,1)

c E (1,3) > E (3,1)

Lecture 10, exercise 1

E (1,3) = E (1,3) = E 0 (1 2 + 3 2 ) = 10 E 0

The tighter confinement along x will increase the contribution to E The effect will be

greatest on states with greatest n x :

E (2,2) = E 0 (2 2 + 2 2 ) = 8 E 0

2

8

x y

y

h

mL

Example: L x = L y /2

2 2

2

8

x y

y x

n n

n n

h E

m L L

   

Trang 10

Energy levels (1)

Now back to a 3D cubic box:

Show energies and label (n x ,n y ,n z ) for the first

11 states of the particle in the 3D box, and

write the degeneracy D for each allowed energy

Use E o = h 2 /8mL 2

z

x

y

L

L L

E

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