Lecture 11 continue Building Atoms and Molecules +e r +e yeven yodd d Plane of hydrogen atoms Content Molecular Wavefunctions Example H + H H2 Atomic Configurations Building atoms with the Pau[.]
Trang 1Lecture 11_continue: Building
Atoms and Molecules
+e
r
+e
yeven
yodd
d
Plane of hydrogen atoms
Trang 2 Molecular Wavefunctions
Example: H + H H 2
Atomic Configurations
Building atoms with the Pauli exclusion principle
Selection rules
Trang 3 Therefore, electrons do not pile up in the lowest energy state, i.e,
the (1,0,0) orbital
They are distributed among the higher energy levels according to the Pauli Principle
Particles that obey the Pauli Principle are called “fermions”
Pauli Exclusion Principle
From spectra of complex atoms, Wolfgang Pauli (1925) deduced a new rule:
“In a given atom, no two electrons* can be in the same quantum state, i.e they cannot have the same set of quantum numbers n, l, ml , ms”
I.e., every “atomic orbital with n,l,m l” can hold 2 electrons: ()
“Pauli Exclusion Principle”
We now want to start building more complicated atoms to study the Periodic Table For atoms with many electrons (e.g., carbon: 6, iron: 26, etc.) - what energies do they have?
*Note: More generally, no two identical fermions (any particle with
spin of ħ/2, 3ħ/2, etc.) can be in the same quantum state
Trang 4Filling the atomic orbitals according to the
Pauli Principle
2 2
n
eV 6 13
is valid only for one electron in the Coulomb potential of Z
protons The energy levels shift
as more electrons are added, due to electron-electron
interactions Nevertheless, this hydrogenic diagram helps us
keep track of where the added electrons go.
Energy
n
4
3
2
1
l = 0 1 2 3 4
s p d f g Example: Na Z = 11 1s 2 2s 2 2p 6 3s 1 Z = atomic number = number of protons l label #orbitals (2l+1) 0 s 1
1 p 3
2 d 5
3 f 7
Trang 5exercise 1: Pauli Exclusion Principle
1 Which of the following states (n,l,ml,ms) is/are NOT allowed?
2 Which of the following atomic electron configurations violates the Pauli Exclusion Principle?
(a) (2, 1, 1, -1/2) (b) (4, 0, 0, 1/2) (c) (3, 2, 3, -1/2) (d) (5, 2, 2, 1/2) (e) (4, 4, 2, -1/2)
(a) 1s2, 2s2, 2p6, 3d10
(b) 1s2, 2s2, 2p6, 3d4
(c) 1s2, 2s2, 2p8, 3d8
(d) 1s1, 2s2, 2p6, 3d5 (e) 1s2, 2s2, 2p3, 3d11
Trang 62(2l +1) = 6 allowed electrons 2(2l +1) = 10 allowed electrons
exercise 1: Pauli Exclusion Principle
1 Which of the following states (n,l,ml,ms) is/are NOT
allowed?
2 Which of the following atomic electron configurations
violates the Pauli Exclusion Principle?
(a) (2, 1, 1, -1/2) (b) (4, 0, 0, 1/2) (c) (3, 2, 3, -1/2) (d) (5, 2, 2, 1/2) (e) (4, 4, 2, -1/2)
ml = -l, -(l -1), … (l-1), l
n > l
(a) 1s2, 2s2, 2p6, 3d10
(b) 1s2, 2s2, 2p6, 3d4
(c) 1s2, 2s2, 2p8, 3d8
(d) 1s1, 2s2, 2p6, 3d5 (e) 1s2, 2s2, 2p3, 3d11
Trang 7Filling Procedure for Atomic Orbitals
example: Bromine
Due to electron-electron interactions, the hydrogen levels fail to give
us the correct filling order as we go higher in the periodic table
The actual filling order is given in the table below Electrons are
added by proceeding along the arrows shown
Bromine is an element with Z = 35 Find its electronic configuration (e.g 1s2 2s2 2p6 …)
Trang 8As you learned in chemistry, the various behaviors of all the elements (and all the molecules made up from them) is all due to the way the electrons organize themselves, according to quantum mechanics
Trang 9Optical Transitions between Atomic Levels
Consider the
hydrogenic picture:
In the field of a photon, the electron may be considered as being in a
superposition of two stationary states The time-dependent solution of the SEQ shows the wave function oscillating between the two eigenstates Not all
transitions are possible must conserve angular momentum (and photon has ħ!)
1s 2s 2p
Stationary States: Superpositions :
1s ± 2s
couples to photons
No electric-dipole moment
Forbidden transition
Dl = 0
Allowed transition
Dl = ±1
E
nm eV
1240 E
hc
c h
E f
D D
D
n = 2
n = 1
DE
photon
r
U(r)
www.falstad.com/qmatomrad
Trang 10Allowed Transitions for H
Selection Rule for electric-dipole transitions:
1
Dl
(A few representative transitions are shown.)
Energy (eV)
0.00 -0.85 -1.51
-3.40
-13.6 eV
n
4
3
2
1
l = 0 1 2 3 4
2
6 13
n
eV
E n
s p d f g
(You observed some of these transitions in Lab 4.)
Selection Rule on m:
0, 1
m
D
photon is linearly polarized
photon is circularly polarized